Simple EJB Question

Question

Given the following example, what is the result of the System.out.println? MyBean is a stateless session bean and is deployed on a separate machine than the client code and the Customer class is deployed on both machines. Notice that MyBean modifies the Customer object by calling its setName() method.
// Client code
Customer cust = new Customer();
cust.setName("Mickey Mouse");
Context initial = new InitialContext();
Object objref = initial.lookup("MyBean");
MyBeanHome home = (MyBeanHome)PortableRemoteObject.narrow(objref, MyBeanHome.class);
MyBean bean = home.create();
bean.foo(cust);
System.out.println("name=" + cust.getName());
public class Customer implements java.io.Serializabale {
��private String name = null;
��public String getName() { return name; }
��public void setName(String aName) { name = aName; }
public class MyBeanEJB implements SessionBean, SessionSynchronization {
��public void foo(Customer cust) {
����cust.setName("Donald Duck");
��}

Answer 1

The value will be "Mickey Mouse".
If you want to know the value in the EJB you'll need to code
System.out.println("name=" + bean.getName());assuming that name is exposed on the EJB.
Your Customer instance is passed to the EJB by value not by reference. So changing any value on the client or server is not going to affect the values on the server or client.
Dave