Simple java pgm - question

Hallo,
to the following pgm I had question:
static void printPrimes (int max) (= wavy bracket;
boolean(should be angular brackets) sieve = new booolean (angular br max+1
angular br)
int i,j;
for (i=2; i = max;i++)sieve(angluarbr i angular br)= true
i= 2
while (i= <= max;) (=wavy bracket Out.println (i+ " "); // is prime
for (j=i; j <= j+i) sieve(angular br j angularb.) = false;
while (i <= maxAmpersandAmpersand !sieve (angular br angular br)I++;
) wavy br ) wavy br.
I hope this is still kind of readable.
Q's are:
after the first "for" there is a new i=2, which seems to staty at 2 all the time; the following while does not change this value ( the beginning for i++ does not change this) and so seems to print 2 at all times (??)
then the inner loop seems to count up all the doubbles of the new prime number and thrwoes it out as false at the end of it;
the i values (increased with i++ seemsto refere at all times to the unit numbers and only indirect to the un it values, which are written/ assigned to it (??)
I seem to wonder how the pgm can print out anythings else the 2's.
I would appreciate any help to that.
ml
griz

I hope this is still kind of readable.No, it's not. http://forum.java.sun.com/help.jspa?sec=formatting
Why are you omitting the braces and brackets? And why don't you type "program"? Aren't we worth the additional time it takes?
Q's are:
after the first "for" there is a new i=2, which
seems to staty at 2 all the time; the following
while does not change this value Why should it? You don't tell it to.
( the beginning for
i++ does not change this)It does. It just gets re-set to 2 after the for loop-
and so seems to print 2 at
all times (??)Yeah. What else?
then the inner loop seems to count up all the
doubbles of the new prime number and thrwoes it out
as false at the end of it; That part is definitely unreadable.

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