Simple question.. about synchronizing

what's the difference between these two?
synchronized myMethod () {
code
myMethod() {
code1
synchronized(this){
code2
code3
and on the second format, is it always 'this' in synchronized()?
thank you

Hi.
In your first implementation of myMethod(), the lock (on 'this') is acquired upon entry to the method and released upon exit. Only one thread at a time may execute myMethod().
In your second implementation, 'code1' and 'code3' are not synchronized so that many threads could execute 'code1' and/or 'code3' concurrently. You acquire the lock (once again, on 'this') when executing code2.
Regards,
Lance
Lance Walton - [email protected]
Team In A Box - Software without Tragedy
http://www.teaminabox.co.uk

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Kaj,
Hi, pls see my post above - I replied to the same question in the other forum and I was pretty sure about my answer until I found it different from ur reply here.
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tx,
ram.

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