Simple Transformation - ABAP 2 XML

Question

Dear all,
Finally I was able to transform an internal table to xml using ST. The question is: Can I create different structured XML-files using the same (structured) internal table. Or is there some kind of a 1:1 relationship (between an ITAB structure + XML structure)?
1) Data declaration
TYPES: BEGIN OF ty_curr,
       tcurr  TYPE tcurr_curr,
       gdatu  TYPE gdatu_inv,
       ukurs  TYPE ukurs_curr.
TYPES: END OF ty_curr.
DATA: gt_tcurr TYPE TABLE OF ty_curr.
2) Data selection
Select * into corresponding fields of table gt_tcurr from tcurr where...
3) Transformation ABAP 2 XML
      CALL TRANSFORMATION z_tcurr
        SOURCE root = gt_tcurr
        RESULT XML    g_xml_string.
<?sap.transform simple?>
<tt:transform xmlns:tt="http://www.sap.com/transformation-templates">
  <tt:root name="ROOT"/>
  <tt:template>
    <tt:serialize>
      <rates>
        <tt:loop name="line" ref=".ROOT">
          <currency>
            <tt:value ref="$line.tcurr"/>
          </currency>
          <date>
            <tt:value ref="$line.gdatu"/>
          </date>
          <rate>
            <tt:value ref="$line.ukurs"/>
          </rate>
        </tt:loop>
      </rates>
    </tt:serialize>
  </tt:template>
</tt:transform>
Result (XML)
  <?xml version="1.0" encoding="utf-8" ?>
- <rates>
  <currency>USD</currency>
  <date>01.01.2010</date>
  <rate>-1.1868</rate>
  <currency>EUR</currency>
  <date>01.01.2010</date>
  <rate>-1.1791</rate>
  <currency>USD</currency>
  <date>02.01.2010</date>
  <rate>-1.1864</rate>
  <currency>EUR</currency>
  <date>02.01.2010</date>
  <rate>-1.1864</rate>
  </rates>:
so far so good... BUT; if I want to get another XML structure
Example 1)  -> sorted by currency
<?xml version="1.0" encoding="utf-8" ?>
- <rates>
  <currency>USD
  <date>01.01.2010</date>
  <rate>-1.1868</rate>
  <date>02.01.2010</date>
  <rate>-1.1868</rate>
  </currency>
  <currency>EUR
  <date>01.01.2010</date>
  <rate>-1.1868</rate>
  <date>02.01.2010</date>
  <rate>-1.1868</rate>
  </currency>
  </rates>
Example 2) -> sored by date
<?xml version="1.0" encoding="utf-8" ?>
- <rates>
  <date>01.01.2010</date> 
   <currency>USD</currency>
  <rate>-1.1868</rate>
   <currency>EUR</currency>
  <rate>-1.1868</rate>
  <date>02.01.2010</date>
   <currency>USD</currency>
  <rate>-1.1868</rate>
   <currency>EUR</currency>
  <rate>-1.1868</rate>
  </rates>
How can I achieve output example 1+2  using the same internal table as a source? Is this possible? I guess this can be solved within the transformation, right? Any help appreciated.
Best regards
Benno

Answer 1

Thanks for all answers so far. Changing the sequence is not a "problem". What I want to achieve is to change hierarchy of the xml. I'll try to explain again with a simple example:
ITAB (structure):
name; birthday; ***; first name
ITAB (content):
Smith; 01.01.1970; M; Paul
Smith; 01.01.1970; F; Stefanie
Smith; 01.02.1980; F; Barbara
White; 01.02.1980; M; Steve
I want to pass the itab exactly the way it is (ok, sorting is allowed). Question: Can I achieve the following XML's using ST? I guess/hope this can be solved with variables/groups/condition statements within the transformation coding?
Example xml- 1) Sorted/Grouped by Name/***
<person>
                <name>Smith
                             <***>M    
                                   <birthday>01.01.1970</birthday><first name>Paul</first name>                            
                             </***>
                             <***>F 
                                   <birthday>01.01.1970</birthday><first name>Stefanie</first name>   
                                   <birthday>01.02.1980</birthday><first name>Barbara</first name>                                  
                             </***>
                </name>
                <name>White
                             <***>M    
                                   <birthday>01.02.1980</birthday><first name>Steve</first name>                            
                             </***>
                </name>
</person>
Exampe xml-2 ) Sorted/Grouped by Birthday (Names only)
<person>
                <birthday>01.01.1970
                             <first name>Paul</first name>
                             <first name>Stefanie</first name>                                 
                </birthday>
                <birthday>01.02.1980
                             <first name>Barbara</first name>
                             <first name>Steve</first name>                                 
                </birthday>                        
</person>