Slow query problem

Hi
I got a parameterized query with 5 bind variables which I have made a viewobject based on it. When I run the query in PL/SQL Developer it is very fast but when I run the query inside the application in a page sometimes it runs fast but most of the time it takes a long time (maybe 3 min) to be executed. I run the query with parameters which will result in a single row to be returned. I am stuck and I have no idea what is happening.
Anyway, I am using JDev 11.1.1.4

may be you should try running your application with
-Djbo.debugoutput=consoleand see what query is getting fired.
you can set it by double clicking vc -> Run/Debug/Profile->select Default->Edit->and set Java Options to the above parameter and try shutting down server(integrated) and re-running application..

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SharePoint 2010 Slow query duration when setting metadata on folder

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Thanks in advance A

SharePoint and SQL Server installed on same server or how is the setup?
i would start to enable the developer dashboard, analyze the report of the developer dashboard...
you will see if any webpart, or page or sql server query taking too much time.
http://www.sharepoint-journey.com/developer-dashboard-in-sharepoint-2013.html
Please remember to mark your question as answered &Vote helpful,if this solves/helps your problem. ****************************************************************************************** Thanks -WS MCITP(SharePoint 2010, 2013) Blog: http://wscheema.com/blog

Very Slow Query with CTE inner join

I have 2 tables (heavily simplified here to show relevant columns):
CREATE TABLE tblCharge
(ChargeID int NOT NULL,
ParentChargeID int NULL,
ChargeName varchar(200) NULL)
CREATE TABLE tblChargeShare
(ChargeShareID int NOT NULL,
ChargeID int NOT NULL,
TotalAmount money NOT NULL,
TaxAmount money NULL,
DiscountAmount money NULL,
CustomerID int NOT NULL,
ChargeShareStatusID int NOT NULL)
I have a very basic View to Join them:
CREATE VIEW vwBASEChargeShareRelation as
Select c.ChargeID, ParentChargeID, s.CustomerID, s.TotalAmount, isnull(s.TaxAmount, 0) as TaxAmount, isnull(s.DiscountAmount, 0) as DiscountAmount
from tblCharge c inner join tblChargeShare s
on c.ChargeID = s.ChargeID Where s.ChargeShareStatusID < 3
GO
I then have a view containing a CTE to get the children of the Parent Charge:
ALTER VIEW [vwChargeShareSubCharges] AS
WITH RCTE AS
SELECT ParentChargeId, ChargeID, 1 AS Lvl, ISNULL(TotalAmount, 0) as TotalAmount, ISNULL(TaxAmount, 0) as TaxAmount,
ISNULL(DiscountAmount, 0) as DiscountAmount, CustomerID, ChargeID as MasterChargeID
FROM vwBASEChargeShareRelation Where ParentChargeID is NULL
UNION ALL
SELECT rh.ParentChargeID, rh.ChargeID, Lvl+1 AS Lvl, ISNULL(rh.TotalAmount, 0), ISNULL(rh.TaxAmount, 0), ISNULL(rh.DiscountAmount, 0) , rh.CustomerID
, rc.MasterChargeID
FROM vwBASEChargeShareRelation rh
INNER JOIN RCTE rc ON rh.PArentChargeID = rc.ChargeID and rh.CustomerID = rc.CustomerID
Select MasterChargeID as ChargeID, CustomerID, Sum(TotalAmount) as TotalCharged, Sum(TaxAmount) as TotalTax, Sum(DiscountAmount) as TotalDiscount
from RCTE
Group by MasterChargeID, CustomerID
GO
So far so good, I can query this view and get the total cost for a line item including all children.
The problem occurs when I join this table. The query:
Select t.* from vwChargeShareSubCharges t
inner join
tblChargeShare s
on t.CustomerID = s.CustomerID
and t.MasterChargeID = s.ChargeID
Where s.ChargeID = 1291094
Takes around 30 ms to return a result (tblCharge and Charge Share have around 3.5 million records).
But the query:
Select t.* from vwChargeShareSubCharges t
inner join
tblChargeShare s
on t.CustomerID = s.CustomerID
and t.MasterChargeID = s.ChargeID
Where InvoiceID = 1045854
Takes around 2 minutes to return a result - even though the only charge with that InvoiceID is the same charge as the one used in the previous query.
The same thing occurs if I do the join in the same query that the CTE is defined in.
I ran the execution plan for each query. The first (fast) query looks like this:
The second(slow) query looks like this:
I am at a loss, and my skills at decoding execution plans to resolve this are lacking.
I have separate indexes on tblCharge.ChargeID, tblCharge.ParentChargeID, tblChargeShare.ChargeID, tblChargeShare.InvoiceID, tblChargeShare.ChargeShareStatusID
Any ideas? Tested on SQL 2008R2 and SQL 2012

>> The database is linked [sic] to an established app and the column and table names can't be changed. <<
Link? That is a term from pointer chains and network databases, not SQL. I will guess that means the app came back in the old pre-RDBMS days and you are screwed.
>> I am not too worried about the money field [sic], this is used for money and money based calculations so the precision and rounding are acceptable at this level. <<
Field is a COBOL concept; columns are totally different. MONEY is how Sybase mimics the PICTURE clause that puts currency signs, commas, period, etc in a COBOL money field.
Using more than one operation (multiplication or division) on money columns will produce severe rounding errors. A simple way to visualize money arithmetic is to place a ROUND() function calls after
every operation. For example,
Amount = (Portion / total_amt) * gross_amt
can be rewritten using money arithmetic as:
Amount = ROUND(ROUND(Portion/total_amt, 4) *
gross_amt, 4)
Rounding to four decimal places might not seem an
issue, until the numbers you are using are greater
than 10,000.
BEGIN
DECLARE @gross_amt MONEY,
@total_amt MONEY,
@my_part MONEY,
@money_result MONEY,
@float_result FLOAT,
@all_floats FLOAT;
SET @gross_amt = 55294.72;
SET @total_amt = 7328.75;
SET @my_part = 1793.33;
SET @money_result = (@my_part / @total_amt) *
@gross_amt;
SET @float_result = (@my_part / @total_amt) *
@gross_amt;
SET @Retult3 = (CAST(@my_part AS FLOAT)
/ CAST( @total_amt AS FLOAT))
* CAST(FLOAT, @gross_amt AS FLOAT);
SELECT @money_result, @float_result, @all_floats;
END;
@money_result = 13525.09 -- incorrect
@float_result = 13525.0885 -- incorrect
@all_floats = 13530.5038673171 -- correct, with a -
5.42 error
>> The keys are ChargeID(int, identity) and ChargeShareID(int, identity). <<
Sorry, but IDENTITY is not relational and cannot be a key by definition. But it sure works just like a record number in your old COBOL file system.
>> .. these need to be int so that they are assigned by the database and unique. <<
No, the data type of a key is not determined by physical storage, but by logical design. IDENTITY is the number of a parking space in a garage; a VIN is how you identify the automobile.
>> What would you recommend I use as keys? <<
I do not know. I have no specs and without that, I cannot pull a Kabbalah number from the hardware. Your magic numbers can identify Squids, Automobile or Lady Gaga! I would ask the accounting department how they identify a charge.
>> Charge_Share_Status_ID links [sic] to another table which contains the name, formatting [sic] and other information [sic] or a charge share's status, so it is both an Id and a status. <<
More pointer chains! Formatting? Unh? In RDBMS, we use a tiered architecture. That means display formatting is in a presentation layer. A properly created table has cohesion – it does one and only one data element. A status is a state of being that applies
to an entity over a period time (think employment, marriage, etc. status if that is too abstract).
An identifier is based on the Law of Identity from formal logic “To be is to be something in particular” or “A is A” informally. There is no entity here! The Charge_Share_Status table should have the encoded values for a status and perhaps a description if
they are unclear. If the list of values is clear, short and static, then use a CHECK() constraint.
On a scale from 1 to 10, what color is your favorite letter of the alphabet? Yes, this is literally that silly and wrong.
>> I understand what a CTE is; is there a better way to sum all children for a parent hierarchy? <<
There are many ways to represent a tree or hierarchy in SQL. This is called an adjacency list model and it looks like this:
CREATE TABLE OrgChart
(emp_name CHAR(10) NOT NULL PRIMARY KEY,
boss_emp_name CHAR(10) REFERENCES OrgChart(emp_name),
salary_amt DECIMAL(6,2) DEFAULT 100.00 NOT NULL,
<< horrible cycle constraints >>);
OrgChart
emp_name boss_emp_name salary_amt
==============================
'Albert' NULL 1000.00
'Bert' 'Albert' 900.00
'Chuck' 'Albert' 900.00
'Donna' 'Chuck' 800.00
'Eddie' 'Chuck' 700.00
'Fred' 'Chuck' 600.00
This approach will wind up with really ugly code -- CTEs hiding recursive procedures, horrible cycle prevention code, etc. The root of your problem is not knowing that rows are not records, that SQL uses sets and trying to fake pointer chains with some
vague, magical non-relational "id".
This matches the way we did it in old file systems with pointer chains. Non-RDBMS programmers are comfortable with it because it looks familiar -- it looks like records and not rows.
Another way of representing trees is to show them as nested sets.
Since SQL is a set oriented language, this is a better model than the usual adjacency list approach you see in most text books. Let us define a simple OrgChart table like this.
CREATE TABLE OrgChart
(emp_name CHAR(10) NOT NULL PRIMARY KEY,
lft INTEGER NOT NULL UNIQUE CHECK (lft > 0),
rgt INTEGER NOT NULL UNIQUE CHECK (rgt > 1),
CONSTRAINT order_okay CHECK (lft < rgt));
OrgChart
emp_name lft rgt
======================
'Albert' 1 12
'Bert' 2 3
'Chuck' 4 11
'Donna' 5 6
'Eddie' 7 8
'Fred' 9 10
The (lft, rgt) pairs are like tags in a mark-up language, or parens in algebra, BEGIN-END blocks in Algol-family programming languages, etc. -- they bracket a sub-set. This is a set-oriented approach to trees in a set-oriented language.
The organizational chart would look like this as a directed graph:
Albert (1, 12)
Bert (2, 3) Chuck (4, 11)
/ | \
/ | \
/ | \
/ | \
Donna (5, 6) Eddie (7, 8) Fred (9, 10)
The adjacency list table is denormalized in several ways. We are modeling both the Personnel and the Organizational chart in one table. But for the sake of saving space, pretend that the names are job titles and that we have another table which describes the
Personnel that hold those positions.
Another problem with the adjacency list model is that the boss_emp_name and employee columns are the same kind of thing (i.e. identifiers of personnel), and therefore should be shown in only one column in a normalized table. To prove that this is not
normalized, assume that "Chuck" changes his name to "Charles"; you have to change his name in both columns and several places. The defining characteristic of a normalized table is that you have one fact, one place, one time.
The final problem is that the adjacency list model does not model subordination. Authority flows downhill in a hierarchy, but If I fire Chuck, I disconnect all of his subordinates from Albert. There are situations (i.e. water pipes) where this is true, but
that is not the expected situation in this case.
To show a tree as nested sets, replace the nodes with ovals, and then nest subordinate ovals inside each other. The root will be the largest oval and will contain every other node. The leaf nodes will be the innermost ovals with nothing else inside them
and the nesting will show the hierarchical relationship. The (lft, rgt) columns (I cannot use the reserved words LEFT and RIGHT in SQL) are what show the nesting. This is like XML, HTML or parentheses.
At this point, the boss_emp_name column is both redundant and denormalized, so it can be dropped. Also, note that the tree structure can be kept in one table and all the information about a node can be put in a second table and they can be joined on employee
number for queries.
To convert the graph into a nested sets model think of a little worm crawling along the tree. The worm starts at the top, the root, makes a complete trip around the tree. When he comes to a node, he puts a number in the cell on the side that he is visiting
and increments his counter. Each node will get two numbers, one of the right side and one for the left. Computer Science majors will recognize this as a modified preorder tree traversal algorithm. Finally, drop the unneeded OrgChart.boss_emp_name column
which used to represent the edges of a graph.
This has some predictable results that we can use for building queries. The root is always (left = 1, right = 2 * (SELECT COUNT(*) FROM TreeTable)); leaf nodes always have (left + 1 = right); subtrees are defined by the BETWEEN predicate; etc. Here are
two common queries which can be used to build others:
1. An employee and all their Supervisors, no matter how deep the tree.
SELECT O2.*
FROM OrgChart AS O1, OrgChart AS O2
WHERE O1.lft BETWEEN O2.lft AND O2.rgt
AND O1.emp_name = :in_emp_name;
2. The employee and all their subordinates. There is a nice symmetry here.
SELECT O1.*
FROM OrgChart AS O1, OrgChart AS O2
WHERE O1.lft BETWEEN O2.lft AND O2.rgt
AND O2.emp_name = :in_emp_name;
3. Add a GROUP BY and aggregate functions to these basic queries and you have hierarchical reports. For example, the total salaries which each employee controls:
SELECT O2.emp_name, SUM(S1.salary_amt)
FROM OrgChart AS O1, OrgChart AS O2,
Salaries AS S1
WHERE O1.lft BETWEEN O2.lft AND O2.rgt
AND S1.emp_name = O2.emp_name
GROUP BY O2.emp_name;
4. To find the level and the size of the subtree rooted at each emp_name, so you can print the tree as an indented listing.
SELECT O1.emp_name,
SUM(CASE WHEN O2.lft BETWEEN O1.lft AND O1.rgt
THEN O2.sale_amt ELSE 0.00 END) AS sale_amt_tot,
SUM(CASE WHEN O2.lft BETWEEN O1.lft AND O1.rgt
THEN 1 ELSE 0 END) AS subtree_size,
SUM(CASE WHEN O1.lft BETWEEN O2.lft AND O2.rgt
THEN 1 ELSE 0 END) AS lvl
FROM OrgChart AS O1, OrgChart AS O2
GROUP BY O1.emp_name;
5. The nested set model has an implied ordering of siblings which the adjacency list model does not. To insert a new node, G1, under part G. We can insert one node at a time like this:
BEGIN ATOMIC
DECLARE rightmost_spread INTEGER;
SET rightmost_spread
= (SELECT rgt
FROM Frammis
WHERE part = 'G');
UPDATE Frammis
SET lft = CASE WHEN lft > rightmost_spread
THEN lft + 2
ELSE lft END,
rgt = CASE WHEN rgt >= rightmost_spread
THEN rgt + 2
ELSE rgt END
WHERE rgt >= rightmost_spread;
INSERT INTO Frammis (part, lft, rgt)
VALUES ('G1', rightmost_spread, (rightmost_spread + 1));
COMMIT WORK;
END;
The idea is to spread the (lft, rgt) numbers after the youngest child of the parent, G in this case, over by two to make room for the new addition, G1. This procedure will add the new node to the rightmost child position, which helps to preserve the idea
of an age order among the siblings.
6. To convert a nested sets model into an adjacency list model:
SELECT B.emp_name AS boss_emp_name, E.emp_name
FROM OrgChart AS E
LEFT OUTER JOIN
OrgChart AS B
ON B.lft
= (SELECT MAX(lft)
FROM OrgChart AS S
WHERE E.lft > S.lft
AND E.lft < S.rgt);
7. To find the immediate parent of a node:
SELECT MAX(P2.lft), MIN(P2.rgt)
FROM Personnel AS P1, Personnel AS P2
WHERE P1.lft BETWEEN P2.lft AND P2.rgt
AND P1.emp_name = @my_emp_name;
I have a book on TREES & HIERARCHIES IN SQL which you can get at Amazon.com right now. It has a lot of other programming idioms for nested sets, like levels, structural comparisons, re-arrangement procedures, etc.
--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
in Sets / Trees and Hierarchies in SQL

Slow query execution time

Hi,
I have a query which fetches around 100 records from a table which has approximately 30 million records. Unfortunately, I have to use the same table and can't go ahead with a new table.
The query executes within a second from RapidSQL. The problem I'm facing is it takes more than 10 minutes when I run it through the Java application. It doesn't throw any exceptions, it executes properly.
The query:
SELECT aaa, bbb, SUM(ccc), SUM(ddd), etc
FROM MyTable
WHERE SomeDate= date_entered_by_user AND SomeString IN ("aaa","bbb")
GROUP BY aaa,bbbI have an existing clustered index on SomeDate and SomeString fields.
To check I replaced the where clause with
WHERE SomeDate= date_entered_by_user AND SomeString = "aaa"No improvements.
What could be the problem?
Thank you,
Lobo

It's hard for me to see how a stored proc will address this problem. I don't think it changes anything. Can you explain? The problem is slow query execution time. One way to speed up the execution time inside the RDBMS is to streamline the internal operations inside the interpreter.
When the engine receives a command to execute a SQL statement, it does a few things before actually executing the statement. These things take time. First, it checks to make sure there are no syntax errors in the SQL statement. Second, it checks to make sure all of the tables, columns and relationships "are in order." Third, it formulates an execution plan. This last step takes the most time out of the three. But, they all take time. The speed of these processes may vary from product to product.
When you create a stored procedure in a RDBMS, the processes above occur when you create the procedure. Most importantly, once an execution plan is created it is stored and reused whenever the stored procedure is ran. So, whenever an application calls the stored procedure, the execution plan has already been created. The engine does not have to anaylze the SELECT|INSERT|UPDATE|DELETE statements and create the plan (over and over again).
The stored execution plan will enable the engine to execute the query faster.
/>

Weird Slow Connectivity Problem

Hi guys
We are facing a slow connection problem and we cant seem to find an answer
as to whats happening.
Our application has
1. An app server hosting EJBs , datasources etc
2. A webserver on different box hosting servlets and command classes.
3.A Sql server 7 database on a different box.
All these boxes are on a secured network ; which means that access to them
is given on a requirement basis.
We have JSPs on the web box which get a datasource connection from the app
box to run queries against the database server.Our problem is that even to
run a very simple query ; it takes a long long time (in order of minutes)
and the same query runs lightening fast in the test environment where all
the boxes are on the same network.
We use type 4 SQL driver.We initially thought that this could be a network
problem as it doesnt make sense that the same query runs very fast on the
test boxes.But the network settings seem ok.
The network settings are this way :
Appserver box has access to database server box.
Webserver box has access to Appserver box.
So you can see that webserver doesnt have direct access to database
server.Is it needed to run queries ; since I am taking a connection from the
appserver.How does the whole business of running queries work when I take a
connection from a datasource on an app server.
I had this question posted to the BEA weblogic customer support ; but they
really couldnt help me.
Any ideas would be appreciated.
Thanks
Pankaj Vij

This has many possible troubleshooting paths. You don't mention if this is a workgroup or domain based Windows network. Checking the "Directory Access" settings as appropriate may yield the solution.
If this is a domain/active directory network the issue may lay with the machine account on the domain server.
Create a new user account on the Mac and see if the problem follows when you log in to that account and try to access the SMB share.
If the problem goes away, then you should look at the original user's startup items to see what might be launching at startup or simply move all files to the new user and delete the old account (not the preferred method).
If the problem persists with a second user on the same machine, then I'd take another Mac, boot it to target disk mode (laptop is good for this), using a firewire cable, boot the troublesome mac to the target mac and try to replicate the issue.
If issue persists, this is a network permissions issue on the server, if it goes away it is a local software issue on the Mac and a clean install of the OS may be needed if you can't locate the meddlesome settings/software.

Find a slow query

Hi all,
I have two questions about the SQL tuning:
There are many open sessions for an Oracle database,
(1) How to find the session that runs a slow query?
(2) How to locate / find this slow query so that the query can be tuned?
Thanks a lot.

Hi,
(1) How to find the session that runs a slow query?This can be coming up from the wait events that the sessions are waiting for.So you can check V$session_wait to see that which are the sessions which are waiting for some thing to happen and for that reason have become slow.Also you can take the advantage of ASH in 10g to tell you the same if you want to drill down your search for last few minutes.
(2) How to locate / find this slow query so that the query can be tuned?IF you read Optimizing OralcePerformance, this is the first thing that Carry asks to address and take extreme caution in doing it.Ask the user that which business process is slow.It will vary depending upon the business.There is nothing called ,"we are slow" and there is no such thing that "tune it all".We have to tune the main area or the maximum benefit giving area only.Ask the user which query/report he is running which he wants to get optimized.You can also take advantage or statspack/AWR report to go for the particular query depending upon the wait event.If you know the query than trace the query to see what is happening.I shall suggest 10046 trace forthe query as its more wider and imparts mch more info as compared to tkprof but you can pick what you want/like.
HTH
Aman....

Slow Query Using index. Fast with full table Scan.

Hi;
(Thanks for the links)
Here's my question correctly formated.
The query:
SELECT count(1)
from ehgeoconstru ec
where ec.TYPE='BAR'
AND ( ec.birthDate <= TO_DATE('2009-10-06 11:52:12', 'YYYY-MM-DD HH24:MI:SS') )
and deathdate is null
and substr(ec.strgfd, 1, length('[CIMText')) <> '[CIMText'Runs on 32 seconds!
Same query, but with one extra where clause:
SELECT count(1)
from ehgeoconstru ec
where ec.TYPE='BAR'
and ( (ec.contextVersion = 'REALWORLD')     --- ADDED HERE
AND ( ec.birthDate <= TO_DATE('2009-10-06 11:52:12', 'YYYY-MM-DD HH24:MI:SS') ) )
and deathdate is null
and substr(ec.strgfd, 1, length('[CIMText')) <> '[CIMText'This runs in 400 seconds.
It should return data from one table, given the conditions.
The version of the database is Oracle9i Release 9.2.0.7.0
These are the parameters relevant to the optimizer:
SQL> show parameter optimizer
NAME                                 TYPE        VALUE
optimizer_dynamic_sampling           integer     1
optimizer_features_enable            string      9.2.0
optimizer_index_caching              integer     99
optimizer_index_cost_adj             integer     10
optimizer_max_permutations           integer     2000
optimizer_mode                       string      CHOOSE
SQL> Here is the output of EXPLAIN PLAN for the first fast query:
PLAN_TABLE_OUTPUT
| Id | Operation                     | Name               | Rows | Bytes | Cost |
|   0 | SELECT STATEMENT     |                         |           |       |       |
|   1 | SORT AGGREGATE       |                         |           |       |       |
|* 2 |   TABLE ACCESS FULL   | EHCONS            |       |       |       |
Predicate Information (identified by operation id):
PLAN_TABLE_OUTPUT
   2 - filter(SUBSTR("EC"."strgfd",1,8)<>'[CIMText' AND "EC"."DEATHDATE"
              IS NULL AND "EC"."BIRTHDATE"<=TO_DATE('2009-10-06 11:52:12', 'yyyy
-mm-dd
              hh24:mi:ss') AND "EC"."TYPE"='BAR')
Note: rule based optimizationHere is the output of EXPLAIN PLAN for the slow query:
PLAN_TABLE_OUTPUT
   |       |
|   1 | SORT AGGREGATE              |                             |       |
   |       |
|* 2 |   TABLE ACCESS BY INDEX ROWID| ehgeoconstru      |       |
   |       |
|* 3 |    INDEX RANGE SCAN          | ehgeoconstru_VSN |       |
   |       |
PLAN_TABLE_OUTPUT
Predicate Information (identified by operation id):
2 - filter(SUBSTR("EC"."strgfd",1,8)<>'[CIMText' AND "EC"."DEATHDATE" IS
NULL AND "EC"."TYPE"='BAR')
PLAN_TABLE_OUTPUT
   3 - access("EC"."CONTEXTVERSION"='REALWORLD' AND "EC"."BIRTHDATE"<=TO_DATE('2
009-10-06
              11:52:12', 'yyyy-mm-dd hh24:mi:ss'))
       filter("EC"."BIRTHDATE"<=TO_DATE('2009-10-06 11:52:12', 'yyyy-mm-dd hh24:
mi:ss'))
Note: rule based optimizationThe TKPROF output for this slow statement is:
TKPROF: Release 9.2.0.7.0 - Production on Tue Nov 17 14:46:32 2009
Copyright (c) 1982, 2002, Oracle Corporation. All rights reserved.
Trace file: gen_ora_3120.trc
Sort options: prsela exeela fchela
count    = number of times OCI procedure was executed
cpu      = cpu time in seconds executing
elapsed = elapsed time in seconds executing
disk     = number of physical reads of buffers from disk
query    = number of buffers gotten for consistent read
current = number of buffers gotten in current mode (usually for update)
rows     = number of rows processed by the fetch or execute call
SELECT count(1)
from ehgeoconstru ec
where ec.TYPE='BAR'
and ( (ec.contextVersion = 'REALWORLD')
AND ( ec.birthDate <= TO_DATE('2009-10-06 11:52:12', 'YYYY-MM-DD HH24:MI:SS') ) )
and deathdate is null
and substr(ec.strgfd, 1, length('[CIMText')) <> '[CIMText'
call     count       cpu    elapsed       disk      query    current        rows
Parse        1      0.00       0.00          0          0          0           0
Execute      1      0.00       0.00          0          0          0           0
Fetch        2      0.00     538.12     162221    1355323          0           1
total        4      0.00     538.12     162221    1355323          0           1
Misses in library cache during parse: 0
Optimizer goal: CHOOSE
Parsing user id: 153
Rows     Row Source Operation
      1 SORT AGGREGATE
27747   TABLE ACCESS BY INDEX ROWID OBJ#(73959)
2134955    INDEX RANGE SCAN OBJ#(73962) (object id 73962)
alter session set sql_trace=true
call     count       cpu    elapsed       disk      query    current        rows
Parse        0      0.00       0.00          0          0          0           0
Execute      1      0.00       0.02          0          0          0           0
Fetch        0      0.00       0.00          0          0          0           0
total        1      0.00       0.02          0          0          0           0
Misses in library cache during parse: 0
Misses in library cache during execute: 1
Optimizer goal: CHOOSE
Parsing user id: 153
OVERALL TOTALS FOR ALL NON-RECURSIVE STATEMENTS
call     count       cpu    elapsed       disk      query    current        rows
Parse        1      0.00       0.00          0          0          0           0
Execute      2      0.00       0.02          0          0          0           0
Fetch        2      0.00     538.12     162221    1355323          0           1
total        5      0.00     538.15     162221    1355323          0           1
Misses in library cache during parse: 0
Misses in library cache during execute: 1
OVERALL TOTALS FOR ALL RECURSIVE STATEMENTS
call     count       cpu    elapsed       disk      query    current        rows
Parse        0      0.00       0.00          0          0          0           0
Execute      0      0.00       0.00          0          0          0           0
Fetch        0      0.00       0.00          0          0          0           0
total        0      0.00       0.00          0          0          0           0
Misses in library cache during parse: 0
    2 user SQL statements in session.
    0 internal SQL statements in session.
    2 SQL statements in session.
Trace file: gen_ora_3120.trc
Trace file compatibility: 9.02.00
Sort options: prsela exeela fchela
       2 sessions in tracefile.
       2 user SQL statements in trace file.
       0 internal SQL statements in trace file.
       2 SQL statements in trace file.
       2 unique SQL statements in trace file.
      94 lines in trace file.Edited by: PauloSMO on 17/Nov/2009 4:21
Edited by: PauloSMO on 17/Nov/2009 7:07
Edited by: PauloSMO on 17/Nov/2009 7:38 - Changed title to be more correct.

Although your optimizer_mode is choose, it appears that there are no statistics gathered on ehgeoconstru. The lack of cost estimate and estimated row counts from each step of the plan, and the "Note: rule based optimization" at the end of both plans would tend to confirm this.
Optimizer_mode choose means that if statistics are gathered then it will use the CBO, but if no statistics are present in any of the tables in the query, then the Rule Based Optimizer will be used. The RBO tends to be index happy at the best of times. I'm guessing that the index ehgeoconstru_VSN has contextversion as the leading column and also includes birthdate.
You can either gather statistics on the table (if all of the other tables have statistics) using dbms_stats.gather_table_stats, or hint the query to use a full scan instead of the index. Another alternative would be to apply a function or operation against the contextversion to preclude the use of the index. something like this:
SELECT COUNT(*)
FROM ehgeoconstru ec
WHERE ec.type='BAR' and
      ec.contextVersion||'' = 'REALWORLD'
      ec.birthDate <= TO_DATE('2009-10-06 11:52:12', 'YYYY-MM-DD HH24:MI:SS') and
      deathdate is null and
      SUBSTR(ec.strgfd, 1, LENGTH('[CIMText')) <> '[CIMText'or perhaps UPPER(ec.contextVersion) if that would not change the rows returned.
John

Designing LOV Query Problem

Hello APEX people,
I posted my problem here:
Designing LOV Query Problem
What I have is a sequence like this:
CREATE SEQUENCE
DR_SEQ_FIRST_SCHEDULE_GROUP
MINVALUE 1 MAXVALUE 7 INCREMENT BY 1 START WITH 1
CACHE 6 ORDER CYCLE ;
What I need would be a SQL query returning all possible values oft my sequence like:
1
2
3
4
5
6
7
I want to use it as a source for a LOV...
The reason why I use the cycling sequence is: My app uses it to cycle scheduling priorities every month to groups identified by this number (1-7).
In the Admin Form, I want to restrict the assignment in a user friendly way - a LOV.
Thanks
Johann

Here ist the solution (posted by michales in the PL/SQL forum):
SQL> CREATE SEQUENCE
dr_seq_first_schedule_group
MINVALUE 1 MAXVALUE 7 INCREMENT BY 1 START WITH 1
CACHE 6 ORDER CYCLE
Sequence created.
SQL> SELECT LEVEL sn
FROM DUAL
CONNECT BY LEVEL <= (SELECT max_value
FROM user_sequences
WHERE sequence_name = 'DR_SEQ_FIRST_SCHEDULE_GROUP')
SN
1
2
3
4
5
6
7
7 rows selected.

SQL+-MULTI TABLE QUERY PROBLEM

HAI ALL,
ANY SUGGESTION PLEASE?
SUB: SQL+-MULTI TABLE QUERY PROBLEM
SQL+ QUERY GIVEN:
SELECT PATIENT_NUM, PATIENT_NAME, HMTLY_TEST_NAME, HMTLY_RBC_VALUE,
HMTLY_RBC_NORMAL_VALUE, DLC_TEST_NAME, DLC_POLYMORPHS_VALUE,
DLC_POLYMORPHS_NORMAL_VALUE FROM PATIENTS_MASTER1, HAEMATOLOGY1,
DIFFERENTIAL_LEUCOCYTE_COUNT1
WHERE PATIENT_NUM = HMTLY_PATIENT_NUM AND PATIENT_NUM = DLC_PATIENT_NUM AND PATIENT_NUM
= &PATIENT_NUM;
RESULT GOT:
&PATIENT_NUM =1
no rows selected
&PATIENT_NUM=2
no rows selected
&PATIENT_NUM=3
PATIENT_NUM 3
PATIENT_NAME KKKK
HMTLY_TEST_NAME HAEMATOLOGY
HMTLY_RBC_VALUE 4
HMTLY_RBC_NORMAL 4.6-6.0
DLC_TEST_NAME DIFFERENTIAL LEUCOCYTE COUNT
DLC_POLYMORPHS_VALUE     60
DLC_POLYMORPHS_NORMAL_VALUE     40-65
ACTUAL WILL BE:
&PATIENT_NUM=1
PATIENT_NUM 1
PATIENT_NAME BBBB
HMTLY_TEST_NAME HAEMATOLOGY
HMTLY_RBC_VALUE 5
HMTLY_RBC_NORMAL 4.6-6.0
&PATIENT_NUM=2
PATIENT_NUM 2
PATIENT_NAME GGGG
DLC_TEST_NAME DIFFERENTIAL LEUCOCYTE COUNT
DLC_POLYMORPHS_VALUE     42
DLC_POLYMORPHS_NORMAL_VALUE     40-65
&PATIENT_NUM=3
PATIENT_NUM 3
PATIENT_NAME KKKK
HMTLY_TEST_NAME HAEMATOLOGY
HMTLY_RBC_VALUE 4
HMTLY_RBC_NORMAL 4.6-6.0
DLC_TEST_NAME DIFFERENTIAL LEUCOCYTE COUNT
DLC_POLYMORPHS_VALUE     60
DLC_POLYMORPHS_NORMAL_VALUE     40-65
4 TABLES FOR CLINICAL LAB FOR INPUT DATA AND GET REPORT ONLY FOR TESTS MADE FOR PARTICULAR
PATIENT.
TABLE1:PATIENTS_MASTER1
COLUMNS:PATIENT_NUM, PATIENT_NAME,
VALUES:
PATIENT_NUM
1
2
3
4
PATIENT_NAME
BBBB
GGGG
KKKK
PPPP
TABLE2:TESTS_MASTER1
COLUMNS:TEST_NUM, TEST_NAME
VALUES:
TEST_NUM
1
2
TEST_NAME
HAEMATOLOGY
DIFFERENTIAL LEUCOCYTE COUNT
TABLE3:HAEMATOLOGY1
COLUMNS:
HMTLY_NUM,HMTLY_PATIENT_NUM,HMTLY_TEST_NAME,HMTLY_RBC_VALUE,HMTLY_RBC_NORMAL_VALUE
VALUES:
HMTLY_NUM
1
2
HMTLY_PATIENT_NUM
1
3
MTLY_TEST_NAME
HAEMATOLOGY
HAEMATOLOGY
HMTLY_RBC_VALUE
5
4
HMTLY_RBC_NORMAL_VALUE
4.6-6.0
4.6-6.0
TABLE4:DIFFERENTIAL_LEUCOCYTE_COUNT1
COLUMNS:DLC_NUM,DLC_PATIENT_NUM,DLC_TEST_NAME,DLC_POLYMORPHS_VALUE,DLC_POLYMORPHS_
NORMAL_VALUE,
VALUES:
DLC_NUM
1
2
DLC_PATIENT_NUM
2
3
DLC_TEST_NAME
DIFFERENTIAL LEUCOCYTE COUNT
DIFFERENTIAL LEUCOCYTE COUNT
DLC_POLYMORPHS_VALUE
42
60
DLC_POLYMORPHS_NORMAL_VALUE
40-65
40-65
THANKS
RCS
E-MAIL:[email protected]
--------

I think you want an OUTER JOIN
SELECT PATIENT_NUM, PATIENT_NAME, HMTLY_TEST_NAME, HMTLY_RBC_VALUE,
HMTLY_RBC_NORMAL_VALUE, DLC_TEST_NAME, DLC_POLYMORPHS_VALUE,
DLC_POLYMORPHS_NORMAL_VALUE
FROM PATIENTS_MASTER1, HAEMATOLOGY1, DIFFERENTIAL_LEUCOCYTE_COUNT1
WHERE PATIENT_NUM = HMTLY_PATIENT_NUM (+)
AND PATIENT_NUM = DLC_PATIENT_NUM (+)
AND PATIENT_NUM = &PATIENT_NUM;Edited by: shoblock on Nov 5, 2008 12:17 PM
outer join marks became stupid emoticons or something. attempting to fix

Stumbled on the slow query, Can any one look into it, Y it is so slow

I just stumbled on the slow query . Can any one please guess why this querie is so slow, do i need to change anything in it
Pid=32521 Tid=2884070320 03/26/2011 07:54:19.176 - Cursor wm09_2_49107 took 27996 ms elapsed time and 27995 ms db time for 1 fetches. sql string:
SELECT ALLOC_INVN_DTL.ALLOC_INVN_DTL_ID, ALLOC_INVN_DTL.WHSE, ALLOC_INVN_DTL.SKU_ID, ALLOC_INVN_DTL.INVN_TYPE, ALLOC_INVN_DTL.PROD_STAT, ALLOC_INVN_DTL.BATCH_NBR, ALLOC_INVN_DTL.SKU_ATTR_1, ALLOC_INVN_DTL.SKU_ATTR_2, ALLOC_INVN_DTL.SKU_ATTR_3, ALLOC_INVN_DTL.SKU_ATTR_4, ALLOC_INVN_DTL.SKU_ATTR_5, ALLOC_INVN_DTL.CNTRY_OF_ORGN, ALLOC_INVN_DTL.ALLOC_INVN_CODE, ALLOC_INVN_DTL.CNTR_NBR, ALLOC_INVN_DTL.TRANS_INVN_TYPE, ALLOC_INVN_DTL.PULL_LOCN_ID, ALLOC_INVN_DTL.INVN_NEED_TYPE, ALLOC_INVN_DTL.TASK_TYPE, ALLOC_INVN_DTL.TASK_PRTY, ALLOC_INVN_DTL.TASK_BATCH, ALLOC_INVN_DTL.ALLOC_UOM, ALLOC_INVN_DTL.ALLOC_UOM_QTY, ALLOC_INVN_DTL.QTY_PULLD, ALLOC_INVN_DTL.FULL_CNTR_ALLOCD, ALLOC_INVN_DTL.ORIG_REQMT, ALLOC_INVN_DTL.QTY_ALLOC, ALLOC_INVN_DTL.DEST_LOCN_ID, ALLOC_INVN_DTL.TASK_GENRTN_REF_CODE, ALLOC_INVN_DTL.TASK_GENRTN_REF_NBR, ALLOC_INVN_DTL.TASK_CMPL_REF_CODE, ALLOC_INVN_DTL.TASK_CMPL_REF_NBR, ALLOC_INVN_DTL.ERLST_START_DATE_TIME, ALLOC_INVN_DTL.LTST_START_DATE_TIME, ALLOC_INVN_DTL.LTST_CMPL_DATE_TIME, ALLOC_INVN_DTL.NEED_ID, ALLOC_INVN_DTL.STAT_CODE, ALLOC_INVN_DTL.CREATE_DATE_TIME, ALLOC_INVN_DTL.MOD_DATE_TIME, ALLOC_INVN_DTL.USER_ID, ALLOC_INVN_DTL.PKT_CTRL_NBR, ALLOC_INVN_DTL.REQD_INVN_TYPE, ALLOC_INVN_DTL.REQD_PROD_STAT, ALLOC_INVN_DTL.REQD_BATCH_NBR, ALLOC_INVN_DTL.REQD_SKU_ATTR_1, ALLOC_INVN_DTL.REQD_SKU_ATTR_2, ALLOC_INVN_DTL.REQD_SKU_ATTR_3, ALLOC_INVN_DTL.REQD_SKU_ATTR_4, ALLOC_INVN_DTL.REQD_SKU_ATTR_5, ALLOC_INVN_DTL.REQD_CNTRY_OF_ORGN, ALLOC_INVN_DTL.PKT_SEQ_NBR, ALLOC_INVN_DTL.CARTON_NBR, ALLOC_INVN_DTL.CARTON_SEQ_NBR, ALLOC_INVN_DTL.PIKR_NBR, ALLOC_INVN_DTL.PULL_LOCN_SEQ_NBR, ALLOC_INVN_DTL.DEST_LOCN_SEQ_NBR, ALLOC_INVN_DTL.TASK_CMPL_REF_NBR_SEQ, ALLOC_INVN_DTL.SUBSTITUTION_FLAG, ALLOC_INVN_DTL.MISC_ALPHA_FIELD_1, ALLOC_INVN_DTL.MISC_ALPHA_FIELD_2, ALLOC_INVN_DTL.MISC_ALPHA_FIELD_3, ALLOC_INVN_DTL.CD_MASTER_ID FROM ALLOC_INVN_DTL WHERE ( ( ( ( ( ( ALLOC_INVN_DTL.TASK_CMPL_REF_CODE = :1 ) AND ( ALLOC_INVN_DTL.TASK_CMPL_REF_NBR = :2 ) ) AND ( ALLOC_INVN_DTL.SKU_ID = :3 ) ) AND ( ALLOC_INVN_DTL.CNTR_NBR = :4 ) ) AND ( ALLOC_INVN_DTL.STAT_CODE < 1 ) ) AND ( ALLOC_INVN_DTL.PULL_LOCN_ID IS NULL ) )
input variables
1: Address(0xabe74300) Length(0) Type(8) "2" - No Indicator
2: Address(0x8995474) Length(0) Type(8) "PERP014119" - No Indicator
3: Address(0xab331f1c) Length(0) Type(8) "MB57545217" - No Indicator
4: Address(0xab31e32c) Length(0) Type(8) "T0000000000000078257" - No Indicator

784786 wrote:
I just stumbled on the slow query . Can any one please guess why this querie is so slow, do i need to change anything in it
Pid=32521 Tid=2884070320 03/26/2011 07:54:19.176 - Cursor wm09_2_49107 took 27996 ms elapsed time and 27995 ms db time for 1 fetches. sql string:
SELECT ALLOC_INVN_DTL.ALLOC_INVN_DTL_ID, ALLOC_INVN_DTL.WHSE, ALLOC_INVN_DTL.SKU_ID, ALLOC_INVN_DTL.INVN_TYPE, ALLOC_INVN_DTL.PROD_STAT, ALLOC_INVN_DTL.BATCH_NBR, ALLOC_INVN_DTL.SKU_ATTR_1, ALLOC_INVN_DTL.SKU_ATTR_2, ALLOC_INVN_DTL.SKU_ATTR_3, ALLOC_INVN_DTL.SKU_ATTR_4, ALLOC_INVN_DTL.SKU_ATTR_5, ALLOC_INVN_DTL.CNTRY_OF_ORGN, ALLOC_INVN_DTL.ALLOC_INVN_CODE, ALLOC_INVN_DTL.CNTR_NBR, ALLOC_INVN_DTL.TRANS_INVN_TYPE, ALLOC_INVN_DTL.PULL_LOCN_ID, ALLOC_INVN_DTL.INVN_NEED_TYPE, ALLOC_INVN_DTL.TASK_TYPE, ALLOC_INVN_DTL.TASK_PRTY, ALLOC_INVN_DTL.TASK_BATCH, ALLOC_INVN_DTL.ALLOC_UOM, ALLOC_INVN_DTL.ALLOC_UOM_QTY, ALLOC_INVN_DTL.QTY_PULLD, ALLOC_INVN_DTL.FULL_CNTR_ALLOCD, ALLOC_INVN_DTL.ORIG_REQMT, ALLOC_INVN_DTL.QTY_ALLOC, ALLOC_INVN_DTL.DEST_LOCN_ID, ALLOC_INVN_DTL.TASK_GENRTN_REF_CODE, ALLOC_INVN_DTL.TASK_GENRTN_REF_NBR, ALLOC_INVN_DTL.TASK_CMPL_REF_CODE, ALLOC_INVN_DTL.TASK_CMPL_REF_NBR, ALLOC_INVN_DTL.ERLST_START_DATE_TIME, ALLOC_INVN_DTL.LTST_START_DATE_TIME, ALLOC_INVN_DTL.LTST_CMPL_DATE_TIME, ALLOC_INVN_DTL.NEED_ID, ALLOC_INVN_DTL.STAT_CODE, ALLOC_INVN_DTL.CREATE_DATE_TIME, ALLOC_INVN_DTL.MOD_DATE_TIME, ALLOC_INVN_DTL.USER_ID, ALLOC_INVN_DTL.PKT_CTRL_NBR, ALLOC_INVN_DTL.REQD_INVN_TYPE, ALLOC_INVN_DTL.REQD_PROD_STAT, ALLOC_INVN_DTL.REQD_BATCH_NBR, ALLOC_INVN_DTL.REQD_SKU_ATTR_1, ALLOC_INVN_DTL.REQD_SKU_ATTR_2, ALLOC_INVN_DTL.REQD_SKU_ATTR_3, ALLOC_INVN_DTL.REQD_SKU_ATTR_4, ALLOC_INVN_DTL.REQD_SKU_ATTR_5, ALLOC_INVN_DTL.REQD_CNTRY_OF_ORGN, ALLOC_INVN_DTL.PKT_SEQ_NBR, ALLOC_INVN_DTL.CARTON_NBR, ALLOC_INVN_DTL.CARTON_SEQ_NBR, ALLOC_INVN_DTL.PIKR_NBR, ALLOC_INVN_DTL.PULL_LOCN_SEQ_NBR, ALLOC_INVN_DTL.DEST_LOCN_SEQ_NBR, ALLOC_INVN_DTL.TASK_CMPL_REF_NBR_SEQ, ALLOC_INVN_DTL.SUBSTITUTION_FLAG, ALLOC_INVN_DTL.MISC_ALPHA_FIELD_1, ALLOC_INVN_DTL.MISC_ALPHA_FIELD_2, ALLOC_INVN_DTL.MISC_ALPHA_FIELD_3, ALLOC_INVN_DTL.CD_MASTER_ID FROM ALLOC_INVN_DTL WHERE ( ( ( ( ( ( ALLOC_INVN_DTL.TASK_CMPL_REF_CODE = :1 ) AND ( ALLOC_INVN_DTL.TASK_CMPL_REF_NBR = :2 ) ) AND ( ALLOC_INVN_DTL.SKU_ID = :3 ) ) AND ( ALLOC_INVN_DTL.CNTR_NBR = :4 ) ) AND ( ALLOC_INVN_DTL.STAT_CODE < 1 ) ) AND ( ALLOC_INVN_DTL.PULL_LOCN_ID IS NULL ) )
input variables
1: Address(0xabe74300) Length(0) Type(8) "2" - No Indicator
2: Address(0x8995474) Length(0) Type(8) "PERP014119" - No Indicator
3: Address(0xab331f1c) Length(0) Type(8) "MB57545217" - No Indicator
4: Address(0xab31e32c) Length(0) Type(8) "T0000000000000078257" - No IndicatorWithout more information I cannot tell you why it is slow, but I can certainly tell you why it is impossible to read.
Just because sql allows unformatted query text does not mean it is a good idea. Why not bring some sanity to this for your own sake, not to mention that of people from whom you are expecting to actually read and analyze this mess. I wish someone could explain to me why people write these long stream-of-consciousness queries.
When posting to this forum you should use the code tags to bracket your code and preserve the formatting. Then the code should actually be formatted:
SELECT
     ALLOC_INVN_DTL.ALLOC_INVN_DTL_ID,
     ALLOC_INVN_DTL.WHSE,
     ALLOC_INVN_DTL.SKU_ID,
     ALLOC_INVN_DTL.INVN_TYPE,
     ALLOC_INVN_DTL.PROD_STAT,
     ALLOC_INVN_DTL.BATCH_NBR,
     ALLOC_INVN_DTL.SKU_ATTR_1,
     ALLOC_INVN_DTL.SKU_ATTR_2,
     ALLOC_INVN_DTL.SKU_ATTR_3,
     ALLOC_INVN_DTL.SKU_ATTR_4,
     ALLOC_INVN_DTL.SKU_ATTR_5,
     ALLOC_INVN_DTL.CNTRY_OF_ORGN,
     ALLOC_INVN_DTL.ALLOC_INVN_CODE,
     ALLOC_INVN_DTL.CNTR_NBR,
     ALLOC_INVN_DTL.TRANS_INVN_TYPE,
     ALLOC_INVN_DTL.PULL_LOCN_ID,
     ALLOC_INVN_DTL.INVN_NEED_TYPE,
     ALLOC_INVN_DTL.TASK_TYPE,
     ALLOC_INVN_DTL.TASK_PRTY,
     ALLOC_INVN_DTL.TASK_BATCH,
     ALLOC_INVN_DTL.ALLOC_UOM,
     ALLOC_INVN_DTL.ALLOC_UOM_QTY,
     ALLOC_INVN_DTL.QTY_PULLD,
     ALLOC_INVN_DTL.FULL_CNTR_ALLOCD,
     ALLOC_INVN_DTL.ORIG_REQMT,
     ALLOC_INVN_DTL.QTY_ALLOC,
     ALLOC_INVN_DTL.DEST_LOCN_ID,
     ALLOC_INVN_DTL.TASK_GENRTN_REF_CODE,
     ALLOC_INVN_DTL.TASK_GENRTN_REF_NBR,
     ALLOC_INVN_DTL.TASK_CMPL_REF_CODE,
     ALLOC_INVN_DTL.TASK_CMPL_REF_NBR,
     ALLOC_INVN_DTL.ERLST_START_DATE_TIME,
     ALLOC_INVN_DTL.LTST_START_DATE_TIME,
     ALLOC_INVN_DTL.LTST_CMPL_DATE_TIME,
     ALLOC_INVN_DTL.NEED_ID,
     ALLOC_INVN_DTL.STAT_CODE,
     ALLOC_INVN_DTL.CREATE_DATE_TIME,
     ALLOC_INVN_DTL.MOD_DATE_TIME,
     ALLOC_INVN_DTL.USER_ID,
     ALLOC_INVN_DTL.PKT_CTRL_NBR,
     ALLOC_INVN_DTL.REQD_INVN_TYPE,
     ALLOC_INVN_DTL.REQD_PROD_STAT,
     ALLOC_INVN_DTL.REQD_BATCH_NBR,
     ALLOC_INVN_DTL.REQD_SKU_ATTR_1,
     ALLOC_INVN_DTL.REQD_SKU_ATTR_2,
     ALLOC_INVN_DTL.REQD_SKU_ATTR_3,
     ALLOC_INVN_DTL.REQD_SKU_ATTR_4,
     ALLOC_INVN_DTL.REQD_SKU_ATTR_5,
     ALLOC_INVN_DTL.REQD_CNTRY_OF_ORGN,
     ALLOC_INVN_DTL.PKT_SEQ_NBR,
     ALLOC_INVN_DTL.CARTON_NBR,
     ALLOC_INVN_DTL.CARTON_SEQ_NBR,
     ALLOC_INVN_DTL.PIKR_NBR,
     ALLOC_INVN_DTL.PULL_LOCN_SEQ_NBR,
     ALLOC_INVN_DTL.DEST_LOCN_SEQ_NBR,
     ALLOC_INVN_DTL.TASK_CMPL_REF_NBR_SEQ,
     ALLOC_INVN_DTL.SUBSTITUTION_FLAG,
     ALLOC_INVN_DTL.MISC_ALPHA_FIELD_1,
     ALLOC_INVN_DTL.MISC_ALPHA_FIELD_2,
     ALLOC_INVN_DTL.MISC_ALPHA_FIELD_3,
     ALLOC_INVN_DTL.CD_MASTER_ID
FROM ALLOC_INVN_DTL
WHERE (
             ( ALLOC_INVN_DTL.TASK_CMPL_REF_CODE = :1
                AND ( ALLOC_INVN_DTL.TASK_CMPL_REF_NBR = :2
              AND ( ALLOC_INVN_DTL.SKU_ID = :3
            AND ( ALLOC_INVN_DTL.CNTR_NBR = :4
          AND ( ALLOC_INVN_DTL.STAT_CODE < 1
        AND ( ALLOC_INVN_DTL.PULL_LOCN_ID IS NULL
      )Now, since you are only selecting from one table, there is no need to clutter up the query by qualifying every column name with the table name. Let's simplify with this:
SELECT
     ALLOC_INVN_DTL_ID,
     WHSE,
     SKU_ID,
     INVN_TYPE,
     PROD_STAT,
     BATCH_NBR,
     SKU_ATTR_1,
     SKU_ATTR_2,
     SKU_ATTR_3,
     SKU_ATTR_4,
     SKU_ATTR_5,
     CNTRY_OF_ORGN,
     ALLOC_INVN_CODE,
     CNTR_NBR,
     TRANS_INVN_TYPE,
     PULL_LOCN_ID,
     INVN_NEED_TYPE,
     TASK_TYPE,
     TASK_PRTY,
     TASK_BATCH,
     ALLOC_UOM,
     ALLOC_UOM_QTY,
     QTY_PULLD,
     FULL_CNTR_ALLOCD,
     ORIG_REQMT,
     QTY_ALLOC,
     DEST_LOCN_ID,
     TASK_GENRTN_REF_CODE,
     TASK_GENRTN_REF_NBR,
     TASK_CMPL_REF_CODE,
     TASK_CMPL_REF_NBR,
     ERLST_START_DATE_TIME,
     LTST_START_DATE_TIME,
     LTST_CMPL_DATE_TIME,
     NEED_ID,
     STAT_CODE,
     CREATE_DATE_TIME,
     MOD_DATE_TIME,
     USER_ID,
     PKT_CTRL_NBR,
     REQD_INVN_TYPE,
     REQD_PROD_STAT,
     REQD_BATCH_NBR,
     REQD_SKU_ATTR_1,
     REQD_SKU_ATTR_2,
     REQD_SKU_ATTR_3,
     REQD_SKU_ATTR_4,
     REQD_SKU_ATTR_5,
     REQD_CNTRY_OF_ORGN,
     PKT_SEQ_NBR,
     CARTON_NBR,
     CARTON_SEQ_NBR,
     PIKR_NBR,
     PULL_LOCN_SEQ_NBR,
     DEST_LOCN_SEQ_NBR,
     TASK_CMPL_REF_NBR_SEQ,
     SUBSTITUTION_FLAG,
     MISC_ALPHA_FIELD_1,
     MISC_ALPHA_FIELD_2,
     MISC_ALPHA_FIELD_3,
     CD_MASTER_ID
FROM ALLOC_INVN_DTL
WHERE (
             ( TASK_CMPL_REF_CODE = :1
                AND ( TASK_CMPL_REF_NBR = :2
              AND ( SKU_ID = :3
            AND ( CNTR_NBR = :4
          AND ( STAT_CODE < 1
        AND ( PULL_LOCN_ID IS NULL
      )And finally, your WHERE clause is a simple string of AND conditions, there was no need to complicate it with all of the nested parentheses. Much simpler:
WHERE ALLOC_INVN_DTL.TASK_CMPL_REF_CODE = :1
   AND ALLOC_INVN_DTL.TASK_CMPL_REF_NBR = :2
   AND ALLOC_INVN_DTL.SKU_ID = :3
   AND ALLOC_INVN_DTL.CNTR_NBR = :4
   AND ALLOC_INVN_DTL.STAT_CODE < 1
   AND ALLOC_INVN_DTL.PULL_LOCN_ID IS NULL
           None of the above makes a whit of difference in your query performance, but if you worked in my office, I would make you clean it up before I even attempted to do a performance analysis.
Edited by: EdStevens on Mar 26, 2011 2:14 PM

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Thanks.

user632535 wrote:
Hi,
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http://jonathanlewis.wordpress.com
http://www.jlcomp.demon.co.uk
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