Software not available from software update server

I have a MacBook Pro, mid-2009, 2.53 GHz; 8 GB memory, running OS X 10.9 (13A603). Yes, I upgraded to Mavericks just this afternoon. And now I want to use Boot Camp to install Windows 7. This is the first time I've tried to do this.
I read through all the information I could find about using BCA. I know my machine won't run Win 8, so I'm going with Win 7. I finally found a thumb drive that was big enough for the job and reformatted it. I launched BCA, and it headed for the download thing. But then it hit a snag: a little error box that reads, "Can't install the software becase it is not currently available from the Software Update server."
I have no idea what that means, so please ... someone tell me what to do next. Please, please don't tell me that I can't get there from here.
For what it's worth, my machine started out running Snow Leopard, and I've dutifully upgraded every time a new OS comes out.

I got past this problem with help from another post in this forum. Now I have another problem: an error that interrupts the partitioning. I'll ask about that in a new post if I can't find an answer here.

Similar Messages

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    Hi @keatonj 
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    Please click the Thumbs up icon below to thank me for responding.
    ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    Please click “Accept as Solution” if you feel my post solved your issue, it will help others find the solution.
    Sunshyn2005 - I work on behalf of HP

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  • HP Printer Driver not currently available from Software Update server

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    Hi Drew, see if this helps...
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    Please remember to rate helpful posts.

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  • Exception "algorithm ARC4 is not available from Provider Cryptix "

    hi all
    i am developing the application in which i am using two encryption/decryption algorithms one is "RC4" and second is "AES(256 bit key)".
    1.first i am taking the credit card number from database which is in
    the encrypted format using 'RC4".
    2.After taking the Credit card number from database i am decrypting them using RC4.
    3. After decrypting them i am encrypting them using "AES(256 bit key") and putting the paymentid and encrypted credit card number in HashMap.
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    import java.security.Security;
    import java.sql.*;
    import java.util.*;
    import java.util.HashMap;
    import javax.crypto.SecretKey;
    import cryptix.jce.provider.key.RawSecretKey;
    import cryptix.provider.Cryptix;
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         DbAccess db=null;
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         private int paymantid;
         private byte[] b;
         private byte[] aesencrypted;
         public RC4EncMemory()
         {db=new DbAccess();}
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              try
              {rs=db.getResultSet(qry);
              if(rs!=null)
              {     crypt=getInstance();
                   while(rs.next())
                        System.out.println("In while");
                        paymantid=rs.getInt("paymentid");
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                        originalCCnumber=DecryptCCNumber(b);
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                   Set key=allccnumber.keySet();
                   Iterator i=key.iterator();
                   while(i.hasNext())
                   {System.out.println(" Payment id from HashMap " +(Integer)i.next());
                   System.out.println("Size of the HashMap: >>" + allccnumber.size());
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              allccnumber.clear();
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                             try{          rs.close();
                                       pstmt.close();
                                       db.conn.close();
                             }catch(Exception er){}
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              {     String decrypted=null;
                   if(encryptedCCNumber!=null)
                   {decrypted = decrypt(encryptedCCNumber);
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         public String decrypt(byte data[])
              if(data == null || data.length == 0)
              return null;
              try
                   xjava.security.Cipher cipher = xjava.security.Cipher.getInstance("RC4", "Cryptix");
                   cipher.initDecrypt(rsaKey);
                   byte out[] = cipher.crypt(data);
                   return new String(out);
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              { System.out.println("SecurityException in decrypt method: " + se);
              return null;
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              if(_rc4decryption == null)
                   Security.addProvider(new Cryptix());
                   _rc4decryption = new RC4EncMemory();
                   makeRC4Key();
              return _rc4decryption;
    private static void makeRC4Key()
    {          String seed = "CvMjSpVrGsTnAj";
              rsaKey = new RawSecretKey("RC4", seed.getBytes());
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    {     aes=AESEccryption.getInstance();
         return aes.encrypt(originalCCNumber);
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         RC4EncMemory mem1=new RC4EncMemory();
         mem1.selectAllCCNumber();
         private static SecretKey rsaKey = null;
         private static RC4EncMemory _rc4decryption = null;
    In the above programs i am getting the output as follows
    output:-
    in while
    paymantid >>> 3338157
    decrypted original >>> 5856373015065936
    inside encrypt method
    Original Data----->5856373015065936
    Encrypted Data----->[B@3cc0bc
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    paymantid >>> 3338169
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    In while
    paymantid >>> 3338290
    SecurityException in decrypt method: java.security.NoSuchAlgorithmException: algorithm ARC4 is not available from provider Cryptix
    decrypted original >>> null
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    AESEccryption.java(which helps to encrypt the credit card number in AES using encrypt method )
    import java.security.GeneralSecurityException;
    import java.security.Security;
    import java.sql.*;
    import javax.crypto.spec.SecretKeySpec;
    import org.bouncycastle.jce.provider.BouncyCastleProvider;
    import cryptix.provider.Cryptix;
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         AESEccryption cryptAES1=null;
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                        //Security.addProvider(new BouncyCastleProvider());
                        //Security.addProvider(new Cryptix());
                        _aesEncryption = new AESEccryption();
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                   return _aesEncryption;
         private static void makeAESKey()
                   String seed = "FFF3454D1E9CCDE00101010101010101";
                   int length=seed.length();
                   if(length!=32)
                   {     System.out.println("Key size must be 32 characters only");
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                   skeySpec = new SecretKeySpec(seed.getBytes(),0,32,"AES");
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         {     if(data == null)
              return null;
              try
              {     System.out.println("inside encrypt method");
                   javax.crypto.Cipher cipher = javax.crypto.Cipher.getInstance("AES");
                   cipher.init(javax.crypto.Cipher.ENCRYPT_MODE,skeySpec);
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                   return out;
              catch(GeneralSecurityException se)
                   System.out.println("SecurityException: " + se);
              return null;
         public static void main(String args[])throws Exception
         {     AESEccryption aesenc=new AESEccryption();
              aesenc.selectAllCCNumber();
              if(flag)
                   System.out.println("Flag " + flag);
         private static SecretKeySpec skeySpec = null;
         private static AESEccryption _aesEncryption = null;
    Regards
    Pandurang
    Message was edited by:
    andylimp12
    Message was edited by:
    andylimp12
    Message was edited by:
    andylimp12

    Hi Nith,
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