[SOLVED]sed: regex repeated pattern

Hi all,
Currently I'm struggling with bash script for automatic presorting and converting of photos from camera.
While man page says that {} is repeated of previous pattern it does not work for me. Here is the example (basically I want extract year of the timestamp).
% exiv2 20080930--DCIM/100CANON/IMG_0002.JPG| grep timestamp
Image timestamp : 2008:05:09 10:25:02
% exiv2 20080930--DCIM/100CANON/IMG_0002.JPG| grep timestamp | sed 's@.*$[0-9]{4}$.*@\1@'
Image timestamp : 2008:05:09 10:25:02
% exiv2 20080930--DCIM/100CANON/IMG_0002.JPG| grep timestamp | sed 's@.*$[0-9]{3}$.*@\1@'
Image timestamp : 2008:05:09 10:25:02
And this one works
% exiv2 20080930--DCIM/100CANON/IMG_0002.JPG| grep timestamp | sed 's@.*$[0-9][0-9][0-9][0-9]$.*@\1@'
2008
If I need repeated m times this is not acceptable. How to deal with this?
Last edited by ogronom (2010-04-05 16:26:54)

Escaping '{' and '}' helps:
sed 's@.*$[0-9]\{4\}$.*@\1@'
Last edited by karol (2010-04-05 16:24:22)

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[SOLVED]sed: regex repeated pattern

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