Solving an equation with a factorial in

If I wanted to perform a calculation like, to find y,
y = 1 + x + (x^2/2) + (x^3/6) + (x^4/24) + ........ (x^n/n!)
And I enter values for n, I'm thinking I should use the 'for' rule.
I can see how I get the numbers seperately but cannot see how I can 'integrate them together into a formula. Thanks. Matt

I was trying VERY hard not to piss anyone off by
posting the full solution so I was just showinghow
to get the NUMBERS and not how to use them.
There's no pleasing you guys is there. I meanit's
like you want me to just post the answer.I don't get this Norweed.
Why don't you post complete homework solutions? I
thought you were convinced that it helped the student
in question instead of giving hints and letting
him/her do some thinking of their own.
Are you not doing it anymore because of what others
think of such actions? Or have you changed your
opinion on the matter?
PS. Just curious, I'm not saying you should post
complete solutions!I never said that a full solution was always the best way to go. Just sometimes.

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You did not specify what kind of equations you have....
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I am working on a Windows Phone program that calculates taxes due. One of the calculations is a formula/equation with an unknown 'x'. I have searched a lot on solving equations with vb but this really exceeds my - admittedly small - math knob. Perhaps you
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Are you looking to code some super-intelligent maths equation solver that can solve any type of equation (if so - good luck!)? Or are the equations you want to solve all of the same type?
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I wasn't going to do that for him.
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Is there a limit on the size of the input for the Solve Linear Equations block?

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Well, the best way to show what I expect is to see the entire program. It's pretty evident that when looking at the graphs, something isn't right. What is supposed to happen is that the runout amplitudes are found, and then those sinusoids are subtracted from the initial data, leaving tooth to tooth data and noise. When I use the larger arrays, it seems as though not all of the data gets through (count the peaks on the product gear runout graph vs. initial) and the amplitudes are much to small, such that nothing is really taken out and the tooth to tooth data looks like the initial data.
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Attachments:
Full example.vi ‏139 KB

Equation with dynamic variable

Is it possible to use one equation with 2 or more variables and make one of these variable as an output without changing the equation?
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Go to Solution.

R = (x/(a+x)*(b/P) ... thx, this really will be helping me to make this Eq more understandable
Formula Node:
It seem that when i entered an equation(Eq), only the left side of the Eq can only be one variable thus producing a single output.
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pendulum.vi ‏14 KB

Hello;
Noise is a difficult issue to advise about.
There are some things you can try, but the result will depend on different factors, such as, environment, lenght of cables, equipment on vicinity, etc.
Anyways, you can try to hook up a BIAS resistor in between the ch- and AIGND on your BNC device. That resistor will bleed out the common voltage current and help on noise balancing. Another thing you can try is to hook up a simple RC low pass filter at the analog input. That might help to get rid of that noise.
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Hope this helps.
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Attachments:
Field_Wiring_and_Noise_Considerations.zip ‏196 KB

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I've traced the problem to the function "Solve Linear Equations" outputting NaN for one or more solution vectors (Not all) which then plays havok with my function.
I've located a data set which is initially OK, but which after solving the linear equations has NaN as the second element of the solution vector array. Changing the matrix type to something other than "generic" gets rid of the NaN for this particular data set, but gives problems with others which work with the "generic" matrix type.
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I've thought of leaving the matrix type to "generic" and checking the output to see if there's a NaN present, and if so, then re-calculate with another matrix type until there's no NaN. This is most likely not very sound mathematically, but it might reduce the number of rogue data sets.
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Using LV 6.1 and 8.2.1 on W2k (SP4) and WXP (SP2)

Hi Altenbach,
The data can have a significant amount of overlap. Typically three to four groups of peaks fully resolved, but each group can have up to 4-5 peaks in them, partially visible only as shoulders.
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I've got an approximate first-guess peak find running which does a pretty good job of finding the peaks I need, and I then fit the height and FWHM first before doing a full optimisation (The Sub-VI approach allows much more flexible fitting models).
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Using LV 6.1 and 8.2.1 on W2k (SP4) and WXP (SP2)
Attachments:
Spectra.zip ‏3 KB

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Hi vijayanandhtkp,
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How to solve this equation?

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x+y+z=8000;
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this gives a little more explanation, although doesn't actually complete for me there are too many permitations
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package
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                              // so in your case with maximum x is the maximum of 8000/1 and 960/0.17 =
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Zamjir,
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I want to solve an equation shown in below by the Newton Raphson zero finder vi:
z-a*b*c*exp(-z/a),
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Many thanks!
Solved!
Go to Solution.

A couple of points I usually feel compelled to make when I see the use of the NR method.
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Solving an equation with a factorial in

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