Sorting String Value

Hi All,
i have a simple question but don't know how to resolve it
i have some files with name like abc_15-06-09 we need to sort these file based on the time stamp appended at the end of the file, in my example "15-06-09"
i am not sure how can i sort these string value provided i can just take these time stamp from the file using sub-string.i need to sort these file based on the stamp old time stamp will get preference
any help in this regard wil be mcuh appricaited
thnaks in advance,
umesh

umesh_awasthi wrote:
try
Date today;
ArrayList<Date> datetoComp=new ArrayList<Date>();
today = df.parse("12/10/2009/12/34/18");
datetoComp.add(today);
today = df.parse("12/10/2008/12/34/18");
datetoComp.add(today);
today = df.parse("12/10/2009/12/34/18");
datetoComp.add(today);
today = df.parse("11/10/2009/12/34/18");
datetoComp.add(today);
today = df.parse("12/10/2009/12/34/18");
datetoComp.add(today);
System.out.println(datetoComp.size());
Collections.sort(datetoComp);
for (Iterator i = datetoComp.iterator(); i.hasNext();)
          Date currentDate = (Date) i.next();
          System.out.println(currentDate);
} catch (ParseException e)
Result:
Sat Jan 12 00:34:18 IST 2008
Sun Jan 11 00:34:18 IST 2009
Mon Jan 12 00:34:18 IST 2009
Mon Jan 12 00:34:18 IST 2009
Mon Jan 12 00:34:18 IST 2009
not as expectedfirst learn to put your code in [{}{code}] format.

Similar Messages

Sorting string values

I have strings in a vector with values like "2-name","6-name2"...etc...what i want to do is sort them according to the number in the string.Is there any way we can do that using java api...or do we need to write a program to do that ....
thanks
satish

Write a custom Comparator class, then use it as part of a call to Collection.sort(List list, Comparator c). A Comparator tells Java how to compare two objects. Here is a suggestion:
public class CustomComparator implements Comparator
public int compare(Object o1, Object o2)
String s1 = (String) o1;
String s2 = (String) o2;
int pos1 = s1.indexOf('-');
int pos2 = s2.indexOf('-');
String value1 = s1.substring(0, pos1);
String value2 = s2.substring(0, pos2);
int v1 = Integer.parseInt(value1);
int v2 = Integer.parsetInt(value2);
return v2 - v1;
}

Sorting the values in Map

Hi,
In my application, i want to use Mapping in the case
Key -Value
A - 2
B - 3
C - 7
D - 5
For that I used HashMap. But I want to sort the values and place in map as from Highest order. For that in google it is suggested to refer SortedMap. But this SortedMap is sorting the Key content only not Value content.
For sorting the Value's what I have to do under Collection?
Any idea?

DHURAI wrote:
I will explain my concept in detail.
I am having a String array; a[]={qw,q,as,l,kj,q,q,l}
From this i am mapping
key value
qw 1
q 3
as 1
l 2
kj 1
using HashMap.
From this I want to fetch q whose value is greater. How can I do this?
Hope this explains better.You still haven't said how often you want to do that. What I explained will work, but it might not be what you want if you often change values.

[C] Trying to sort string into reverse order ... Blank. [SOLVED]

Here are the pre-processors:
#include <stdio.h>
#include <string.h>
Here are the global variables:
char output[999];
Here's the function to sort string to reverse order (I THINK THE PROBLEM IS HERE):
char output[999];
char *sort_reverse(const char *str)
int i, j = 0;
for (i = strlen(str); i > 0; i--)
output[j] = str[i];
j++;
return output;
And, function int main(void):
int main(void)
printf("Reverse of \"Hello\": %s\n", sort_reverse("Hello"));
return 0;
The output is:
Reverse of "Hello":
Why is that? how can i fix that?
Last edited by milo64 (2013-03-28 01:45:46)

Instead of the global char output[999] wich is really big, you could allocate a perfectly sized array with calloc - like this in the sort_reverse function:
char *output = calloc(strlen(input_string), sizeof(char));
and in main program:
char *reversed_string = sort_reverse("Whatever");
printf("%s\n", reversed_string);
//Remember to free reversed_string with
free(reversed_string);
//Since its allocated in the heap with calloc()
Try check man-page for calloc, it will zero out the bytes aswell, then you wont have to worry about setting the last element to '\0'.
NOTE: you have to iterate with "strlen(input_string) - 1" otherwise you will overwrite the needed '\0'
EDIT: As strlen excludes the '\0' in original string, then you have to make space for that by adding one to strlen return value so:
char *output = calloc(strlen(input_string) + 1, sizeof(char));
Last edited by Boogie (2013-04-05 09:46:12)

Error: Find criteria must contain at least one sort field value.

Hi
I am getting the followng error in Sort.as when I click on a column in a DataGrid that is bound to a nested property (e.g. parent.name)
Error: Find criteria must contain at least one sort field value.
I can see why this is failing.
In the findItem function of Sort.as the code tests whether there is data in line (456) hasFieldName = values[fieldName] !== undefined. This fails and so an error is raised later in the function by:
     if (fieldsForCompare.length == 0)     {
     message = resourceManager.getString("collections", "findRestriction");
          throw new SortError(message);     }
The code needs to traverse down the object hierarchy to get the field so that error is not thrown .
The code needs to traverse down the object hierarchy to get the field so that error is not thrown .
In the case of a non nested property, everything works fine.
There is lots of discussion about nested properties in DataGrid and there is this jira:
http://bugs.adobe.com/jira/browse/SDK-9801
There is talk of using a labelFunction or an itemRenderer and other third party solutions (extensions of DataGridColumn).
Is this a bug? is there a workaround using labelFunction or itemRenderer which can stop the error in Sort.as?
James
Here is the code of findItem in Sort.as of SDK 3..4.0.9271
public
function findItem(items:Array,values:Object,
mode:String,
returnInsertionIndex:Boolean =
false,compareFunction:Function =
null):int{
var compareForFind:Function;
var fieldsForCompare:Array;
var message:String;
if (!items){
message = resourceManager.getString(
"collections", "noItems");
throw new SortError(message);}
else if (items.length == 0){
return returnInsertionIndex ? 1 : -1;}
if (compareFunction == null){
compareForFind =
this.compareFunction;
// configure the search criteria
if (values && fieldList.length > 0){
fieldsForCompare = [];
//build up the fields we can compare, if we skip a field in the
//middle throw an error. it is ok to not have all the fields
//though
var fieldName:String;
var hadPreviousFieldName:Boolean = true;
for (var i:int = 0; i < fieldList.length; i++){
fieldName = fieldList[i];
if (fieldName){
var hasFieldName:Boolean;
try
hasFieldName = values[fieldName] !==
undefined;}
catch(e:Error){
hasFieldName =
false;}
if (hasFieldName){
if (!hadPreviousFieldName){
message = resourceManager.getString(
"collections", "findCondition", [ fieldName ]);
throw new SortError(message);}
else
fieldsForCompare.push(fieldName);
else
hadPreviousFieldName =
false;}
else
//this is ok because sometimes a sortfield might
//have a custom comparator
fieldsForCompare.push(
null);}
if (fieldsForCompare.length == 0){
message = resourceManager.getString(
"collections", "findRestriction");
throw new SortError(message);}
else
try
initSortFields(items[0]);
catch(initSortError:SortError){
//oh well, use the default comparators...
else
compareForFind = compareFunction;

I have tried a sortCompareFunction:
var sort:Sort = new Sort();
sort.compareFunction = compareFunction;sort.fields = [sortField];
data.sort = sort;
data.refresh();
this makes no difference.
James

Sorting the values of a map.

I have been stuck on this problem for a while. I have a TreeMap, which can be changed to a HashMap if needed, with a set of keys as Strings and values which are Integers.
EXAMPLE
String1, 123
String2, 333
String3, 222
String4, 758
I need the values sorted in decending order (9-0).
Thanks in advance for all your help.

I have been stuck on this problem for a while. I have
a TreeMap, which can be changed to a HashMap if
needed, with a set of keys as Strings and values which
are Integers.You must be the first one who changed a TreeMap into a HashMap and then lived to tell about it. -:)
Anyway a TreeMap is always sorted on key, not value. To have your dataset sorted on value you must reload into another TreeMap and invert the key/value pairs in the process. The values then become keys in the new TreeMap which means that the former values must be unique for this to work.
I'm sure there's a simple solution but it's better if you described what you want to accomplish in general terms than to let people struggle with a solution scenario that's probably suboptimal. How do you want to access your objects and why and when do you need them to be sorted.

Problem to get max string value

Hi
my problem is i don't get correct result when i get max string value from my table. for example, it returns '9' as max value while i have some bigger string values like 73, 80,65, ...
i found
some solutions to handle this problem (like converting to char or adding some zero in the begining of my value) but it does not appropriate for my situation because my string value maybe everything (some of my customers can use numbers while some other
else can use alphabetical+numbers)!.
can anybody help me ?
thanks in advance
http://www.codeproject.com/KB/codegen/DatabaseHelper.aspx

When I see NVARCHAR(50)(50) I am pretty sure the data was declared by an ACCESS programmer who has no idea what he is doing. Do you really have first
and last names that need fifty UNICODE characters ? You will get them! If you invite garbage data, it will come. The USPS uses VARCHAR(20) for names; this has to do with the size of mailing labels and the fact
that Latin-1 is required by ISO in ALL languages.
lease read the "Stairway to Data" series and pay attention to last sections on the design of encoding schemes. What you have is useless and dangerous because it has no data integrity. Tag
numbers (learn what that means, please) need a regular expression and I like to have a check digit. My first guess, without an specs is that you need something like this:
patient _case_nbr CHAR() NOT NULL PRIMARY KEY
CHECK (patient _case_nbr
LIKE '[ ABC][0-9][0-9][0-9][0-9][0-9]')
Fixed length for the forms and display, characters limtied to the Latin-1 Unicode set, and easy to sort.
http://www.sqlservercentral.com/articles/Database+Design/72612/)
--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
in Sets / Trees and Hierarchies in SQL

How to sort alphanumeric values in datagrid numerically

Hi all,
I have a datagrid column which contains AlphaNumeric values.Is there a way i can sort these values in a numerical order
eg:
having d1,d11,12,13,d2,d3,d4
d2 should come after d1..
order should be d1,d2,d3,d4,d11,d12,d13
Please help me out..if any have any idea..giving below thw code which is sorting as string
protected function ColumnSortCompare( obj1:Object, obj2:Object ):int
        if ( !obj1 && !obj2 )
            return 0;
        if ( !obj1 )
            return 1;
        if ( !obj2 )
            return -1;
        var obj1Data:String = ComplexColumnData( obj1 ).toString();
        var obj2Data:String = ComplexColumnData( obj2 ).toString();
        if ( obj1Data < obj2Data )
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Thanx in advance
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Hi,
Thanks for the reply. Please dont mind if the question is simple,as I am new to flex.
While I am using
return ObjectUtil.stringCompare(obj1[fieldName], obj2[fieldName]);
it is throwing error as, undefined property fieldName.
I am calling as this
<mx:DataGridColumn headerText=""
                           editable="false"
                           sortCompareFunction="ColumnSortCompare"
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How I can resolve this.Please guide me.
Thanks,
Raj

Is there a standard map sorted by values

Tree Map is sorted by keys..Is there standard jdk map sorted by values ?

You can also use a method similar to the following:
private static final Collator PL_COLLATOR = Collator.getInstance(new Locale("PL"));
     public static <E> Map<E, String> sortMapByValue(Map<E, String> unordered) {
          Map<E, String> ret = new LinkedHashMap<E, String>();
          Set<Entry<E, String>> sort = new TreeSet<Entry<E, String>>(new Comparator<Entry<E, String>>() {
               public int compare(Entry<E, String> o1, Entry<E, String> o2) {
                    Entry<E, String> e1 = o1;
                    Entry<E, String> e2 = o2;
                    String s1 = e1.getValue();
                    String s2 = e2.getValue();
                    return PL_COLLATOR.compare(s1.toLowerCase(), s2.toLowerCase());
          sort.addAll(unordered.entrySet());
          for (Iterator<Entry<E, String>> iterator = sort.iterator(); iterator.hasNext();) {
               Entry<E, String> e = iterator.next();
               ret.put(e.getKey(), e.getValue());
          return ret;
     }

Parameters To Include Null Or Empty String Values

I have a table that has both Nulls & Empty Strings that I want to use as a Dynamic Parameter. Even though there is an indication of the Null/Empty String value when the parameter prompt comes up, selecting the value of Null/Empty String results in no records being returned. I have a formula to display the values in the report (where I substitute "Unknown" for the Null/Empty String values), but I am not able to do a parameter on that formula.
I guess in general, this is a situation of needing to be able to use a Dynamic Parameter based on a formula field.
Thanks for any assistance!
Edited by: Dragon77 on Apr 2, 2010 9:39 AM

I'd use a SQL Command as the data source for the list of values. Something like this... (MS SQL Server)
SELECT DISTINCT
CASE WHEN t.StringField IS NULL OR t.StringField LIKE ''
THEN 'Unknown' ELSE t.StringField END AS StringField
FROM TableName AS t
ORDER BY StringField
Then use a formula like this in the selection criteria.
IF {?Parameter} = "Unknown"
THEN (ISNULL ({TableName.StringField}) OR {TableName.StringField} LIKE "")
ELSE {TableName.StringField} = {?Parameter}
HTH,
Jason

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As I said in the other thread, this really isn't the place to ask questions about a database API unrelated to the Illustrator SDK. You're far more like to find people familliar with your problem on a forum that is dedicated to answering those kinds of questions instead.

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Sorting String Value

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