Sorting the view using the file path.
I would like to be able to sort my music library using the full file path (directory name) as this sorts it in the way I have setup my files.
Unfortunately you can only sort using columns that iTunes will display in the browser window; file path is not one of those.
If you have any programming experience you can use an external program to generate a playlist sorted by path, but you still won't be able to display the path in the iTunes window. That is, unless your external program also does something like put the path in the comment field. I guess if the program does that, you can display the comment field and sort using iTunes.
Here is the SDK for iTunes on Windows:
http://developer.apple.com/sdk/itunescomsdk.html
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How to set the File Path to run a javascript using Plugin Code?
Hi All,
Im new to Indesign Plugin Development.Can any one help me out with my problem.
What i want to do is to run a javascript using Plugin Code.When i went through this forum i was able to find out that i should use the IscriptRunner Class to automate this.I could also figure out that the Member Function to use is "CanHandleFile" &"RunFile".
The first parameter in CanHandleFile & RunFile Member Function is to specify the path of the JavaScript File i suppose!I could also find out that IDFile has to used to set the file path Information.
But im clueless how to set the Javascript FilePath using IDFile.Can any one help me how to do this?Any Code Snippets Please?
Waiting for reply.
Thanks
myRiazHi, Andreas<br /><br /> Can you explain this in detail? I found it in your post before.<br /><br /> The content of elements are returned through the Characters callback function:<br /><br />From ISaxContentHandler.h:<br /><br />/**<br /> Receives character data<br /><br />The parser will call this method to report each chunk of<br /> character data. SAX parsers may return all contiguous<br /> character data in a single chunk, or they may split it into<br /> several chunks. But all characters in any single<br /> event must come from the same external entity so the<br /> Locator provides useful information.<br /><br />Note some parsers will report whitespace using the<br /> IgnorableWhitespace() method rather than this one (validating<br /> parsers must do so).<br /><br />@param Chars The characters from the XML document.<br /> */<br />virtual void Characters(const PMString& chars) = 0; <br /><br /> What i have done is implement my own SAXContentHandlerServiceBoss, and in my file XXXSAXContentHandler.cpp, I override the fonctions StartElement, EndElement, and Characters() like below: I add the PMString xmlData to collect the file content:<br /><br />class XXXSAXContentHandler : public CSAXContentHandler<br />{<br />void XXXSAXContentHandler::Characters(const WideString& chars)<br />{<br />xmlData.Append(chars);<br />}<br /><br />void XXXSAXContentHandler::StartElement(const WideString& uri, const WideString& localname, const WideString& qname, ISAXAttributes* attrs)<br />{<br />xmlData.Append("<"); xmlData.Append(localname); xmlData.Append(">");<br />}<br />void XXXSAXContentHandler::EndElement(const WideString& uri, const WideString& localname, const WideString& qname)<br />{<br />xmlData.Append("</"); xmlData.Append(localname); xmlData.Append(">");<br />}<br /><br />}<br /><br />and in my program, I use the code below to call the fonction I overrided, but I dont know how I can get the String xmlData I defined in the XXXSAXContentHandler.cpp<br /><br />InterfacePtr<IK2ServiceRegistry> serviceRegistry(gSession, UseDefaultIID());<br /><br />InterfacePtr<IK2ServiceProvider> xmlProvider(serviceRegistry->QueryServiceProviderByClassID(kXMLParserService, kXMLParserServiceBoss));<br /><br />InterfacePtr<ISAXServices> saxServices(xmlProvider, UseDefaultIID());<br />InterfacePtr<ISAXContentHandler> saxHandler(::CreateObject2<ISAXContentHandler>(kXXXSAXContentHandlerServiceBoss));<br />saxHandler->Register(saxServices);<br />bool16 parseFailed = saxServices->ParseStream(readStream, saxHandler);<br /><br />Can you give me any help?<br /><br />Thanks and regards!
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SIMPLE QUESTION, BROWNIE POINTS FOR ANSWERERS: changing the file path used for an audio recording
After changing the name of an audio recording in the .band Media folder, the .band file continues to use the previous file name to try to find the audio file. I want to update the file path so that it uses the same file but with the new name. I thought I might be able to change the file path by editing projectData, but it appears to be encoded.
This is a common, crucial feature present in virtually all DAWs. Surely there must be a feasible way to do this in GarageBand?you can't change the names of GB's assets behind its back
if you want to change the name of the region that GB displays: double click the region within GB to open the track editor, then double click the name of the region (in the track editor) to change its name -
Issue with Getting the file path from InputFile component
Hi,
One of our requirement is like below:
I am working on ADF 11g (latest release R1) page. User will select the file and when he/she clicks on the Save button we need to store the file path in the database.
In the database file_path is varchar2(300). We need to store just the file path. I am using InputFile component but filepath is not getting inserted.
This is really urgent. It would be really appreciate if anyone can guide me on this.
Thanks
MCHi Mahesh,
I have manage to store the file path from the InputFile component in Jdev 11g. I found the file upload script from this forum and manage to alter it so that i could save the file path to the database. But my problem is to retrieve it back to view as a document. Hope this will help you :)
This is an example of what I have manage to save to my DB :
(CLOB) //192.168.238.53/c$/Research/Docs/0906160744/EyeCandyLog.txt
In my form, I save the file path first before I update the other fields. My code is something like this :
public void uploadFile(ValueChangeEvent valueChangeEvent) {
// Add event code here...
InputStream in;
FileOutputStream out;
if(tanda == 0){
try {
// final Context context = getInitialContext();
RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
id = rS01Proposal.dptProposalid();
tanda = tanda + 1;
System.out.println("tanda"+ tanda);
} catch (Exception ex) {
ex.printStackTrace();
System.out.println("id"+id);
proposal = id.substring(6);
System.out.println("proposal"+proposal);
UploadedFile file = (UploadedFile)valueChangeEvent.getNewValue();
String fileUploadLoc = "//192.168.238.53/c$/Research/Docs/"+id+"/";//The place where file will saved
//create upload directory
boolean exists = (new File(fileUploadLoc)).exists();
if (!exists) {
(new File(fileUploadLoc)).mkdirs();
if (file != null && file.getLength() > 0) {
FacesContext context = FacesContext.getCurrentInstance();
FacesMessage message =
new FacesMessage("File Uploaded " + file.getFilename() +
" (" + file.getLength() + " bytes)");
*// extracting the file message to get the path*
context.addMessage(valueChangeEvent.getComponent().getClientId(context), message);
columnL = valueChangeEvent.getComponent().getClientId(context);
column = columnL.substring(9);
System.out.println(column);
columnLengkap = "RS01"+column.toUpperCase();
System.out.println("columnLengkap"+columnLengkap);
*try {*
out = new FileOutputStream(fileUploadLoc + "" + file.getFilename());
in = file.getInputStream();
*for (int bytes = 0; bytes < file.getLength(); bytes++) {*
out.write(in.read());
in.close();
out.close();
} catch (IOException e) {
e.printStackTrace();
} else {
String filename = file != null ? file.getFilename() : null;
String byteLength = file != null ? "" + file.getLength() : "0";
FacesContext context = FacesContext.getCurrentInstance();
FacesMessage message =
new FacesMessage(FacesMessage.SEVERITY_WARN, " " + " " +
filename + " (" + byteLength + " bytes)",
null);
context.addMessage(valueChangeEvent.getComponent().getClientId(context),
message);
System.out.println(fileUploadLoc+file.getFilename());
a = fileUploadLoc+file.getFilename();
b = b + 1;
if (flagInsert == 0){
try {
// final Context context = getInitialContext();
RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
rS01Proposal.insertDoc(id,proposal,columnLengkap,a);
flagInsert = flagInsert + 1;
System.out.println("tanda"+ tanda);
//session
ProposalSession.storeCurrentProposalId(id);
} catch (Exception ex) {
ex.printStackTrace();
}else{
// update proses
try {
// final Context context = getInitialContext();
RS01Proposal rS01Proposal = (RS01Proposal)new InitialContext().lookup("Phase2-RS01Proposal#sr.model.RS01Proposal");
rS01Proposal.updateDoc(id,proposal,columnLengkap,a);
flagInsert = flagInsert + 1;
//session
ProposalSession.storeCurrentProposalId(id);
System.out.println("tanda"+ tanda);
} catch (Exception ex) {
ex.printStackTrace();
} -
Can I change the file path that itunes reads my music files from?
I have about 65000 music files that i have transferrd from my external to a new laptop internal HD.
I have organised the folders myself as I use a PC and do not want itunes to organise the folders because when I'm searching through music on windows it is sorted out by artists/albums with 'the...(eg The Beatles)' under 'T' instead of 'B'.
Long story short.... Is there any way that I can keep my itunes library as it is on the external HD and copy it to the new laptops C drive, keep all the info (playlists etc) and still have the same folder structure as on the external HD?
Or, is there any way of making windows sort things in alphabetical order like it is in itunes (eliminating the 'the' issue)?The files that weren't inside the media folder on the original machine need to be copied over to exactly the same paths as they had on the source machine. See this thread for an ongoing discussion of a similar problem. See also this post on migrating the iTunes library.
tt2 -
What can the file path tell me about a photo?
I am a Police Detective. I used a Cellebrite UFED to dump an Iphone 4. I am interested in a few images on the phone. I'm curious what the file path can tell me about the image. I also noticed that there are two versions of each image, an original and another duplicate photo. Here are the paths of the original photos -
1. "Path: /PhotoStreamsData/1322802356/101APPLE/"
2. "Path: /PhotoStreamsData/1322802356/101APPLE/"
Here are the paths of the dupplicate photos -
1. "Path: /PhotoData/Thumbnails/V2/PhotoStreamsData/1322802356/101APPLE/IMG_1435"
2. "Path: /PhotoData/Thumbnails/V2/PhotoStreamsDAta/1322802356/101APPLE/IMG_1436"
Thanks in advanceYou're not looking at original photos. You're looking at photos streamed to the phone from PhotoStream. They may or may not have been taken on the phone. They may have been taken or saved to another iOS device or to a Mac or PC, or they may have been shared with the owner of the phone.
The thumbnails are (obviously) thumbnails... small versions of photos scaled to view multiple pictures at once for easy navigation.
Basically, the information above tells you absolutely nothing of any value at all. -
Can not sort the files in JFileChooser if the files are from remote machine
Hi All,
Let me set the context of the question.
I have extended the JFileChooser to support the listing/view of files.dirs etc of remote location through CORBA.To achieve that i have customized
my FileSystemView to support it. In general ,the current JFileChooser sorts the file when we have details view .My question is related to this.The default
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Any pointer towards this will be highly appreciated.
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PraveenCan anyone help me out to solve this problem or any suggestion regarding this ?
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How to get the file path in adf application
hii all,
i have a txt file that i am using in my adf application,
i am passing this txt file through a File Reader, for which i have to mention the file path.
The file is in web-content and when i am hard coding the complete file path i.e C:/JDeveloper/myApp/ViewController/public_html/log.txt
the application is working fine when run on integrated weblogic server.
My requirement is to access this file without giving the static file path, as in case i have to use this application on any other machine..
for that how to mention the file path-
i tried using FacesContext to get the context path :-
FacesContext.getCurrentInstance().getExternalContext().getRequestContextPath();
which gives me
\myApp-ViewController-context-root
after appending public_html\log.txt
I am using the following path to access the file :-
\myApp-ViewController-context-root\public_html\log.txt
again i am getting the java.io.FileNotFoundException
Does anyone know how to use file from inside the web-content without giving the complete path..???
ThanksHi,
If you put your file under public_html folder, you can use this code to access the file:
For example file is : log.txt
FacesContext.getCurrentInstance().getExternalContext().getRealPath('/log.txt').toString().trim();
Thanks.
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I am experiencing this error with one of our cluster environment. Can anyone help me in this issue.
The Cluster Service function call 'ClusterResourceControl' failed with error code '1008(An attempt was made to reference a token that does not exist.)' while verifying the file path. Verify that your failover cluster is configured properly.
Thanks,
Venu S.
Venugopal S ----------------------------------------------------------- Please click the Mark as Answer button if a post solves your problem!Hi Venu S,
Based on my research, you might encounter a known issue, please try the hotfix in this KB:
http://support.microsoft.com/kb/928385
Meanwhile since there is less information about this issue, before further investigation, please provide us the following information:
The version of Windows Server you are using
The result of SELECT @@VERSION
The scenario when you get this error
If anything is unclear, please let me know.
Regards,
Tom Li -
How to force the File Path Control Browser button to the RT Target instead of the host machine?
I am building an application on a RT PXI system, and for one of the functions I would like the user to be able to use the browser button of the File Path Control to choose a directory on the PXI. However the browser button seems to only want open a file on the host PC, even though the application is fully deployed on the target. Note that I am controlling the PXI from a host PC.
If anyone has any suggestions that would be great. Thanks.Hi,
Unfortunately, there is not a VI to do this. Are you browsing to these files from your host VI? In order to access the files on your PXI RT target, you'll need to FTP in and browse to them that way. You could programmatically do this, but there is not a simple VI to do so.
Amanda Howard
Americas Services and Support Recruiting Manager
National Instruments -
How to get the file path from HTML input form in Firefox 3...
In IE7 (and probably all famous browsers, including old Firefox 2), if we submit a file like 'C:\folder1\folder2\folder3\filename' it works properly and gives the full path to the file and the filename.
In Firefox 3, it returns only 'filename', because of their new 'security feature' to truncate the path, as explained in Firefox bug tracking system (https://bugzilla.mozilla.org/show_bug.cgi?id=143220)
I have no clue how to overcome this 'new feature' because it causes all upload forms in my webapp to stop working on Firefox 3.
Can anyone help to find a single solution to get the file path both on Firefox 3 and IE7?
Thanks in advance....As you're posting this in the JSF forum and looking at your [previous topic|http://forums.sun.com/thread.jspa?threadID=5342365], I assume that you're using Tomahawk's t:inputFileUpload. In this case, just use UploadedFile#getInputStream(). You may find this article useful: [http://balusc.blogspot.com/2008/02/uploading-files-with-jsf.html].
By the way, are you lazy or just dumb? You wasted one week to this! I've posted the aforementioned article one week ago. How did you stuck? -
File browse : How to keep the file path in the file browse field?
Hello,
I have
1) file browse field called P2_FILE_PATH.
2) a select list with submit : P2_REGION
If i upload some file d:\abc.gif , then select some region in the P2_REGION,
P2_FILE_PATH will become empty. But in the session, i can find the blob value. but not the "d:\abc.gif "
Using the following script I could capture the value of P2_FILE_PATH in a field
P2_TEST.
onload="javascript:document.getElementById(P2_FILE_PATH').value = document.getElementById('P2_TEST').value;"
P2_TEST contains d:\abc.gif .
How to retain the file path, though some other field is selected and submitted?
Thanks in advance.
Regards,
ArchanaHello Archana,
You can't do what you want because of some HTML security restrictions – nothing to do with APEX. As you found out, You can capture the value of this item. You can't set it. After submitting the page, the browser is the one to clear the item.
The only workaround is to work with AJAX and not submit the page until the end of the user input phase.
Regards,
Arie. -
How to give the file path in adf application
Hii all,
I want to use castor xml framework in adf application..
for which i have to un- marshaller the xml file..
by using following method-
Person person = (Person)
Unmarshaller.unmarshal(Person.class,
new FileReader("src/com/person.xml"));
if i use this method in a java class inside a main method directly it works fine,
but when i try to initiate the java class through a jspx page deployed on integrated server..
it gives the file not found exception..
how to define the file path so it can be properly used even when application is deployed on server.
Thanksduplicate {thread:id=2418158} ?
I guess the path you are using is wrong. It works on your mashiene as the src path is available. When you run the app on a server (jspx file) there is no src path as long as you don't include it in your WAR wich you should not do anyway.
If you need to access such data you can create a folder in your webroot folder and the the resources from there as /xml_folder_name or if the xml files shouldn't be visible from the outside put the folder under hte web-inf folder.
Timo
Edited by: Timo Hahn on 23.07.2012 16:20 -
Function module to get the file path in the system for TEMP folder
Hi All,
Is there any function module that I can use to get the file path in the system for TEMP folder.
I mean, i am supposed to give only TEMP as the input for that function module and I need to get the path of that in the system as the output.
I am unsing 4.0 version.
Please advice.
Regards
RameshIn Higher versions, we can use the below code:
call method CL_GUI_FRONTEND_SERVICES=>ENVIRONMENT_GET_VARIABLE
exporting
VARIABLE = 'TEMP'
importing
VALUE = LV_TMP
exceptions
CNTL_ERROR = 1
others = 2.
if SY-SUBRC <> 0.
message id SY-MSGID type SY-MSGTY number SY-MSGNO
with SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
endif.
call method CL_GUI_CFW=>FLUSH
exceptions
CNTL_SYSTEM_ERROR = 1
CNTL_ERROR = 2
others = 3.
if SY-SUBRC <> 0.
Error handling
endif.
concatenate lv_tmp '\' into folder_path.
But need to know in the lower versions like 3.1h and 4.0, -
Enable and Disable the file paths
Hai i have two file paths one logical file path and other is physical file path.
I took two radio buttons.
How can i enable and disable the file paths by using these radio buttons.
When i select the 1st radio button then 1st file path is in enable and second file path in disable mode similarly for the second radio button also.
It is very urgent .
With Regards,
Prasad.Tallapudi.i answered in your other post....here is the code again....
SELECTION-SCREEN BEGIN OF BLOCK B1 WITH FRAME TITLE TEXT-001.
PARAMETERS: logfile type string default 'Z_DATALOAD',
FILE(128) TYPE C DEFAULT 'nittest.txt' LOWER CASE.
SELECTION-SCREEN END OF BLOCK B1.
SELECTION-SCREEN BEGIN OF BLOCK B2 WITH FRAME TITLE TEXT-001.
PARAMETERS: P_LFILE RADIOBUTTON GROUP G1 USER-COMMAND C1 DEFAULT 'X',
P_PFILE RADIOBUTTON GROUP G1.
SELECTION-SCREEN END OF BLOCK B2.
at selection-screen output.
if p_lfile eq 'X'.
loop at screen.
if screen-name = 'LOGFILE'.
screen-input = '1'.
endif.
if screen-name = 'FILE'.
screen-input = '0'.
endif.
modify screen.
endloop.
endif.
if p_pfile eq 'X'.
loop at screen.
if screen-name = 'LOGFILE'.
screen-input = '0'.
endif.
if screen-name = 'FILE'.
screen-input = '1'.
endif.
modify screen.
endloop.
endif.
if the problem gets solved...please close both the posts -
Set the file path of get image method
I have a program that takes multiple IV curves of some nano-devices and saves each set of the IV curve data into a CSV file. I also have a graph on the main screen that gives me a visual representation of the data after each IV curve is taken.
My program automatically names each IV curve with a different file path and at the end of the program execution I could have 50-60 IV curves. What i'm trying to do is have LabVIEW export an image file of the graph on my front panel and save it with the save file path as the CSV file.
Currently i'm using "Invoke Node -> Export Image" method, which is working fine and doing exactly what I want because i can tell it what file path to save to....however it is just a black and white image.
There is another method that I found here: http://digital.ni.com/public.nsf/allkb/5AE4ADCBB65A6D8F86256FBF007A1AC1
That talks about a "Invoke Node -> Get Image Method" which physically captures the colorful chart on the front panel. However I cannot figure out a way to tell it the file path to save to. So when I run my program, after each IV curve, it takes the image from the front panel and then on the next IV curve, it interrupts my program to ask me to overwrite the previous file because it's using the same name.
Is there a way to tell the Get Image Method to save to a specific file path?Hi Puneet_K,
Thanks for the code....I didn't know you could wire the output of the image data to a write VI. It makes sense in theory and i thought it would work....but it's not actually writing the PNG. I even tried BMP and JPEG but no results.
I'm posting an image of my code with the before and after. The before uses export image and it works, the after uses the get image and it doesn't create the file.
Attachments:
before.PNG 71 KB
after.PNG 71 KB
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