Splitting a string when an integer is reached

Hi,
I'm trying to figure out how, if possible, to split a string when an integer comes in the strong. What I'm doing is reading from a web page and the output is "1930Stella" as an example. What I want to do is insert those into a table, so it's like this:
String | Integer
Stella 1930I'm not sure how I can go about doing this, please help!

YoungWinston wrote:
aeternaly wrote:
I'm trying to figure out how, if possible, to split a string when an integer comes in the strong. What I'm doing is reading from a web page and the output is "1930Stella" as an example.Another wrinkle for you. Could it ever be "-1930Stella"?
WinstonNo, it can't ever be anything other than "1930Stella" or "Stella1930", but it will always be integerString in the format that I'm reading from the site.
almightywiz wrote:
Just a thought...
Why not make this function return something like this:
>
"1930Stella" -> parseString -> "1930|Stella"
>
You're obviously halfway there, but right now if you want to get both the number and the string out of the input, you have to loop over the input twice. Why not just loop over the input once, insert a delimiter between your 'fields', and call split on the resulting string later? Then again, you know the overall requirements for the issue at hand.
Also, is the input string always a number followed by characters (i.e. 1930Stella), or can it be something ridiculous like "1234abc56d7e8"? I only ask because right now your method only handles the first case nicely, on the assumption that your result will always be "number followed by characters".As I said above, the method works for what I need (only integerString/stringInteger format). I was looking at the delimiter idea but couldn't quite fully understand it. I'll give it another go, though!

Similar Messages

Converting a string to an integer - NumberFormatException

Hello,
I have 2 string arrays, one that olds names and one that holds id numbers. They are both stored in a file as Strings. I then read this file into my program and put split the strings up into an array.
I then try to convert the id to integer inside my program like so:
public void make_array(String[] car_info) {
                // put in arraylist and change variable type to correct ones
                final int ID_INDEX = 0;
                final int TYPE = 1;
                int cust_id = 22;
                String type;
                //convert to correct variable types
                try {
                        //convert to string
                        cust_id = Integer.parseInt(car_info[ID_INDEX]);
                } catch (NumberFormatException e) { System.out.println(e); }
                type = car_info[TYPE];
}I then get the errors when i try this:
java.lang.NumberFormatException: For input string: "1"
So the id was stored as "1", but i want to convert it to an integer value. Any ideas on why this happends? Also before i try to convert i output the id from the array and it is correct, after the conversion it is 0, obviously it is not working. But i'm not sure what is wrong.
Any ideas?

only works when the string is a single number suchas
"1" or "4". If you try to use it with the input
string as a longer one like "123" or "12" itcreates
a NumberFormatExceptionYou must be mistaken. The value must not be what you
think it is. Do some debugging:
String strVal = car_info[ID_INDEX].trim();
System.out.println("This is the number to be
parsed -->" + strVal + "<--");
customer_id = Integer.parseInt(strVal);That is a good idea, but it seems as though the string is fine: I did:
gary@linuxbox# cat cars
this output:
1,5,Renault Clio,Small Car,25,4,false
As you can see the number 25 is a two figure number, and it looks good. I also output the number in the java program like this:
System.out.println("the number is ------>" + twodigitnumber + "<------");This output the number: ------->25<---------- So there doesn't seem to be any wierd spacing or characters there.

Mapping issue: Split a string to multiple strings in an idoc

Hi,
I need to split a string with an undefined length into strings of 132 chars. The problem is, how to map from the source field to the target field,
which belong to an idoc segment. The segment has the occurence 1 to unbounded, and the field 0 to 1. Simplifying, i need to map one source field split it in 132
chars block and put the resultant blocks into an idoc field (maxLength = 132).
IDoc
Segment X
Segment (occurence 1..unbounded)
Field X
Source field SourceA (undefined length)----->-----Field TargetA (occurence 0..1) (maxLength = 132)
Segment Y

Ok...here is one way of achiving what u want - hope ur comfortable with working with context mapping...
Raise the context of ur source field one level higher and write a UDF funtionto do this -
Declare an array list
Read the source string and append it to the arraylist.
Then when u map ur target IDOC text...read from this array list and created ...By maintaining the context...there will be as many segments in the idocas there are in the arraylist..
regards,
arvind R

How to Split the string using Substr and instr using loop condition

Hi every body,
I have below requirement.
I need to split the string and append with single quotes('') followed by , (comma) and reassign entire values into another variable. so that i can use it where clause of update statement
for example I am reciveing value as follows
ALN varchar2(2000):=(12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434);
Note: In the above variable i see 8 transactions, where as in real scenario i donot how many transaction i may recive.
after modification i need above transactions should in below format
ALTR Varchar2(2000):=('12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434');
kindly help how to use substr and instr in normal loop or for loop or while loop while modifying the above transactions.
Please help me to sort out this issue.
Many Thanks.
Edited by: user627525 on Dec 15, 2011 11:49 AM

Try this - may not be the best way but...:
create or replace type myTableType as table of varchar2(255)
declare
v_array mytabletype;
v_new_str varchar2(4000);
function str2tbl
         (p_str   in varchar2,
          p_delim in varchar2 default '.')
         return      myTableType
    as
        l_str        long default p_str || p_delim;
         l_n        number;
         l_data     myTableType := myTabletype();
    begin
        loop
            l_n := instr( l_str, p_delim );
            exit when (nvl(l_n,0) = 0);
            l_data.extend;
            l_data( l_data.count ) := ltrim(rtrim(substr(l_str,1,l_n-1)));
            l_str := substr( l_str, l_n+length(p_delim) );
        end loop;
        return l_data;
   end;
begin
v_array := str2tbl ('12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434', ',');
      FOR i IN 1 .. v_array.COUNT LOOP
         v_new_str := v_new_str || ''''||v_array(i)||'''' || ',';
      END LOOP;
   dbms_output.put_line(RTRIM(v_new_str, ','));
end;
OUTPUT:
=======
'12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434'HTH
Edited by: user130038 on Dec 15, 2011 12:11 PM

OR ('|') in regular expressions (e.g. split a String into lines)

Which match gets used when you use OR ('|') to specify multiple possible matches in a regex, and there are multiple matches among the supplied patterns? The first one (in the order written) which matches? Or the one which matches the most characters?
To make this concrete, suppose that you want to split a String into lines, where the line delimiters are the same as the [line terminators used by Java regex|http://java.sun.com/javase/6/docs/api/java/util/regex/Pattern.html#lt] :
     A newline (line feed) character ('\n'),
     A carriage-return character followed immediately by a newline character ("\r\n"),
     A standalone carriage-return character ('\r'),
     A next-line character ('\u0085'),
     A line-separator character ('\u2028'), or
     A paragraph-separator character ('\u2029)
This problem has [been considered before|http://forums.sun.com/thread.jspa?forumID=4&threadID=464846] .
If we ignore the idiotic microsoft two char \r\n sequence, then no problem; the Java code would be:
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]");How do we add support for \r\n? If we try
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]|\\r\\n");which pattern of the compound (OR) regex gets used if both match? The
[\\n\\r\\u0085\\u2028\\u2029]or the
\\r\\n?
For instance, if the above code is called when
s = "a\r\nb";and if the first pattern
[\\n\\r\\u0085\\u2028\\u2029]is used for the match when the \r is encountered, then the tokens will be
"a", "", "b"
because there is an empty String between the \r and following \n. On the other hand, if the rule is use the pattern which matches the most characters, then the
\\r\\n
pattern will match that entire \r\n and the tokens will be
"a", "b"
which is what you want.
On my particular box, using jdk 1.6.0_17, if I run this code
String s = "a\r\nb";
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]|\\r\\n");
System.out.print(lines.length + " lines: ");
for (String line : lines) System.out.print(" \"" + line + "\"");
System.out.println();
if (true) return;the answer that I get is
3 lines: "a" "" "b"So it seems like the first listed pattern is used, if it matches.
Therefore, to get the desired behavior, it seems like I should use
"\\r\\n|[\\n\\r\\u0085\\u2028\\u2029]"instead as the pattern, since that will ensure that the 2 char sequence is first tried for matches. Indeed, if change the above code to use this pattern, it generates the desired output
2 lines: "a" "b"But what has me worried is that I cannot find any documentation concerning this "first pattern of an OR" rule. This means that maybe the Java regex engine could change in the future, which is worrisome.
The only bulletproof way that I know of to do line splitting is the complicated regex
"(?:(?<=\\r)\\n)" + "|" + "(?:\\r(?!\\n))" + "|" + "(?:\\r\\n)" + "|" + "\\u0085" + "|" + "\\u2028" + "|" + "\\u2029"Here, I use negative lookbehind and lookahead in the first two patterns to guarantee that they never match on the end or start of a \r\n, but only on isolated \n and \r chars. Thus, no matter which order the patterns above are applied by the regex engine, it will work correctly. I also used non-capturing groups
(?:X)
to avoid memory wastage (since I am only interested in grouping, and not capturing).
Is the above complicated regex the only reliable way to do line splitting?

bbatman wrote:
Which match gets used when you use OR ('|') to specify multiple possible matches in a regex, and there are multiple matches among the supplied patterns? The first one (in the order written) which matches? Or the one which matches the most characters?
The longest match wins, normally. Except for alternation (or) as can be read from the innocent sentence
The Pattern engine performs traditional NFA-based matching with ordered alternation as occurs in Perl 5.
in the javadocs. More information can be found in Friedl's book, the relevant page of which google books shows at
[http://books.google.de/books?id=GX3w_18-JegC&pg=PA175&lpg=PA175&dq=regular+expression+%22ordered+alternation%22&source=bl&ots=PHqgNmlnM-&sig=OcDjANZKl0VpJY0igVxkQ3LXplg&hl=de&ei=Dcg7S43NIcSi_AbX-83EDQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CA0Q6AEwAA#v=onepage&q=&f=false|http://books.google.de/books?id=GX3w_18-JegC&pg=PA175&lpg=PA175&dq=regular+expression+%22ordered+alternation%22&source=bl&ots=PHqgNmlnM-&sig=OcDjANZKl0VpJY0igVxkQ3LXplg&hl=de&ei=Dcg7S43NIcSi_AbX-83EDQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CA0Q6AEwAA#v=onepage&q=&f=false]
If this link does not survive, search google for
regular expression "ordered alternation"
My first hit went right into Friedl's book.
Harald.

How to split a string in jsp?

I have a set of strings or names in ${form.temp.name}Is there anyway I can split a string in jsp or jstl by a newline "\n" or space "\\s" character and print them separately. Or Do i have to do something in my controller as I am using spring with jsp and jstl for my web application?
Thanks.

Yes I did the work as below. When I use some delimiters like ";", the code works. But for the newline character of carriage return it does nto work.
<c:set var="str" value="${form.temp.name}"/>
                 <c:set var="delim" value=" \r\n|\\n"/>
                 <c:set var="array" value="${fn:split(str, delim)}"/>
                 <c:forEach var="token" items="${array}">
                     <p><c:out value="${token}"/> </p>
                 </c:forEach>                Icidentally for the same element, when I try to split in java with the same delimiters, it is working. I am surprised why it is not working?

Regex to split a String

Hi,
Here's a little regex problem Jos e-mailed me the other day, to which I didn't find a satisfactory answer (I found one, but it's rather verbose). Chances are that there is no short (or simple) solution, but when this is the case with a certain problem, I usually know why there is no simple solution because of some limitation with the regex flavor I am using. However, I can't think of one with this problem.
Also note that this problem can be easily (and far more efficiently) solved by writing a custom method, but I happen to like regex and am curious to know if there's some solution to this I missed.
So, without further a due, here is the questions:
Split a String T into parts with a maximum size N without splitting T on a certain sub string S. In other words: try to split a String in as large as possible parts (equal or less than N) without splitting it on a certain sub string.
You can use only one split(...) call!
Lets say S = abc and N = 5 then here are a couple of examples:
T            = xyabcdefgabc
T.split(...) = [xyabc, defg, abc]
T            = xyzabcbbzzzabcabcbcacbyyy
T.split(...) = [xyz, abcbb, zzz, abc, abcbc, acbyy, y]
T            = xyzzzzabcbabczabcabcabcacbyyy
T.split(...) = [xyzzz, zabcb, abcz, abc, abc, abcac, byyy]

uncle_alice wrote:
Okay, I give up. I can see how to do this with find(), but not with split(). I hope you haven't been waiting for me all this time... :DTo be frank, yes I have. You, sabre and maybe Darryl (in a good mood ; )). Ah well, I am now convinced I didn't overlook some easy shortcut.
This is what I've cooked up:
class Main {
    public static void main(String[] args) {
        String[] tests = {"xyabcdefgabc", "xyzabcbbzzzabcabcbcacbyyy", "xyzzzzabcbabczabcabcabcacbyyy"};
        String sub = "abc";
        int max = 5;
        String regex = String.format("(?<=\\G.{%d,%d})(?=%s)|(?<=\\G.{%d})", max-sub.length()+1, max-1, sub, max);
        System.out.println("regex = "+regex+"\n");
        for(String test: tests) {
            System.out.println(test);
            System.out.println(" -> "+Arrays.toString(test.split(regex))+"\n");
}B.t.w. uncle_alice, this *\G* (previous match) functionality, is this some Java thing or does it exist in other regex flavors as well?

How to split a string in LabView?

Hello everyone,
I'm using the LabView to control a robot named SHRIMP |||. The robot gets commands in hexadecimal format. I need to process info from the command line and therefore I want to split the string of the command line.
In order to make myself clear this is the case: the command (in hex) is 040100 when 04 is the command itself (set velocity and steering angle), 01 is the velocity to set and 00 is the steering angle. When I read it in Labview I see - /04/01/00. I need to separate the velocity and angle from the string so I used the "search/split string" VI but it doesn't seem to help get rid of the "/" delimiter. I can get only the string before the delimiter or the string with the delimiter inside. When I tried to use offset, it seems that the LabView recognize each part of the command as one char in the string ("/04","/01","/00" are the 3 parts of the string) so I can't use it also. I tried to change the display of the string to hexadecimal format but still no luck- I couldn't convert the string to a number.
Any ideas?
Thanks,
Rap Master

RapMaster,
What you probably want in this case is Scan From String. This takes in an input string, a formatter string similar to the ones used in C (here is a refresher if you are not familiar with printf formatters: http://www.psych.upenn.edu/~saul/parasite/man/man3/printf.3.html), as well as some other parameters that are not as important to this project, and then outputs a number for each field that was represented by a formatter (i.e. %x). Double clicking on the VI brings up a window that will walk you through making the formatters, in case you feel more comfortable that way.
I'm attaching a VI that does exactly what you requested, using Scan From String. To expand the functionality of this VI, just modify the formatter, and more outputs will appear for each formatter.
David M.
Applications Engineer
National Instruments
Attachments:
ScanString.vi ‏8 KB

How to split a string delimitted by vertical bar(|)

Hi
I would like to split a string delimitted by verticl bar using String.split("|") functionality. When I used split functionality for other delimitters like "-" or ":" or ";" it worked perfectly but if I use vertical bar it is splitting all the individual characters in thet string
Is it because verical bar is having some significance in regular expressions
Can some body please shed light on this

joningle wrote:
I've looked in the documentation and I don't understand why two slashes need to precede the vertical bar "|". Can you explain the reason this is the case?
Thanks
Jonfrom my understanding (i just taught myself this stuff in my regex lesson yesterday), the double '\ \' is to escape from the meta-character '|' , (meaning OR) ... just like if you put '\n' into a string, it's considered a newline character, if you want to denote the String "\n" you need "\ \n"
edit: i'm being really slow today...
Edited by: redfalconf35 on Nov 9, 2007 2:36 PM

How To Split the String for "."

Hi Friends
I am Using Following Code to Split one String.
String str = "Jeetendra.choudhary";
String[] sp_str = str.split(".");
wdComponentApi.getMessageManager.reportSuccess(str[0]);
wdComponentApi.getMessageManager.reportSuccess(str[1]);
but its throwing null pointer exception.
when i am using following code its working fine.
String str = "Jeetendra/choudhary";
String[] sp_str = str.split("/");
wdComponentApi.getMessageManager.reportSuccess(str[0]);
wdComponentApi.getMessageManager.reportSuccess(str[1]);
what may be the issue and how to split the string with "." ?
Thanks & Regards
Jeetendra

"." is a special character.
Use
str.split("\\.");
Regards
Benjamin
Edited by: Benjamin Hansen on Dec 29, 2009 7:52 AM

How to split a string with linefeed character ( LF ) as a delimiter in VB6?

Hi. I am writing a small program in VB 6.0.
I have a string named Data and it contains few characters along with <LF> in it. ( <LF> is a new line/line feed character).
I want to split this string with <LF> as delimiter and store the tokens in an array. I tried with split function and its giving me type mismatch error. Can anyone tell me how to do it?
I am giving the pseudo-code below.
Dim Data as string
Data = "hello, how are you<LS>good morning guys <LS> hi"
Dim strarray() as stringMsgbox(Data)
strarray = split(Data, "<LS>")
When i see the Data in message box before split function, it shows up in different lines like this:
hello, how are you
good morning guys
hi
I want the final array strarray to be like this: strarray(0) = "hello, how are you"
strarray(1) = "good morning guys "
strarray(2) = " hi"
The spaces can be as it is. Just i need the string to be delimited wherever <LS> is there.
Please help me as soon as possible. Though it is small one, i am stuck here.
Thanks in advance,
Satya.

Hello,
This forum is for VB.NET, please check the following resources
http://www.vbforums.com/forumdisplay.php?1-Visual-Basic-6-and-Earlier
http://social.msdn.microsoft.com/Forums/vstudio/en-US/6a0719fe-14af-47f7-9f51-a8ea2b9c8d6b/where-to-post-your-vb-6-questions?forum=vbgeneral
Please remember to mark the replies as answers if they help and unmark them if they provide no help, this will help others who are looking for solutions to the same or similar problem.

How to split a string using sql

Hi All,
I've to write a query where I need to split a string, how this can be done? So let's say a column has value as 1,2,3,4,5 and I want to split this string and output it as:
1
2
3
4
5
Please advise.

Lots of articles:
Snap this user defined function too:
CREATE FUNCTION [dbo].[ufn_SplitString_Separator](@InputStr VARCHAR(MAX), @Separator VARCHAR(1))
RETURNS @tmpTable TABLE (OutputStr VARCHAR(MAX))
AS BEGIN
DECLARE @TmpPOS integer
SET @TmpPOS = CHARINDEX(@Separator,@InputStr)
WHILE @TmpPos > 0 BEGIN
IF @TmpPos > 0 BEGIN
INSERT INTO @tmpTable VALUES (LTRIM(RTRIM(SUBSTRING(@InputStr,1,@TmpPos-1))))
SET @InputStr = SUBSTRING(@InputStr, @TmpPOS + 1, LEN(@InputStr) - @TmpPos)
SET @TmpPOS = CHARINDEX(@Separator,@InputStr)
END ELSE BEGIN
INSERT INTO @tmpTable VALUES (LTRIM(RTRIM(@InputStr)))
SET @TmpPos = 0
END
END
IF LEN(@InputStr) > 0 BEGIN
INSERT INTO @tmpTable VALUES (LTRIM(RTRIM(@InputStr)))
END
RETURN
END
GO
And you can use like this:
SELECT * FROM DBO.[ufn_SplitString_Separator]('1,2,3,4,5',',')
"If there's nothing wrong with me, maybe there's something wrong with the universe!"

Splitting a string on new lines...

If I want to split string on whitespaces, I do:
StringTokenizer st = new StringTokenizer(a, " ");If I want to split a string on new lines, (I think the ascii values are "13", "10") how can I do it?
Thanks a lot!

does "\n" represents both chr(13) and chr(10) ?No, it does not.
KajI solved with "\r\n"Did you read the other replies? They are correct when they say that you shouldn't use StringTokenizer.
Kaj

Splitting a string -- 2 variables

I'm trying to split a string into 2 variables
One variable (exString) being a string, the other variable (exInt)integer
For example, I want to split JSPCool.006
the variables would contain:
exString = JSPCool
exInt = 006

Whoops. Sorry there's an error. Try this instead:
String var = "JSPCool.006";
int splitLocation = var.indexOf(".");
String exString = var.substring(0,splitLocation);
int exInt = Integer.parseInt(var.substring(splitLocation+1, var.length()));only problem is that number will not be left as 006....it will be converted to just 6.

Need Help in Splitting a String Using SQL QUERY

Hi,
I need help in splitting a string using a SQL Query:
String IS:
AFTER PAINT.ACOUSTICAL.1..9'' MEMBRAIN'I would like to seperate this string into multiple lines using the delimeter .(dot)
Sample Output should look like:
SNO       STRING
1            AFTER PAINT
2            ACOUSTICAL
3            1
4
5            9" MEMBRAIN
{code}
FYI i am using Oracle 9.2

There's this as well:
with x as ( --generating sample data:
           select 'AFTER PAINT.ACOUSTICAL.1..9" MEMBRAIN' str from dual union all
           select 'BEFORE PAINT.ELECTRIC.2..45 caliber MEMBRAIN' str from dual)
select str,
       row_number() over (partition by str order by rownum) s_no,
       cast(dbms_xmlgen.convert(t.column_value.extract('//text()').getstringval(),1) as varchar2(100)) res
from x,
     table(xmlsequence(xmltype('<x><x>' || replace(str,'.','</x><x>') || '</x></x>').extract('//x/*'))) t;
STR                                                S_NO RES
AFTER PAINT.ACOUSTICAL.1..9" MEMBRAIN                 1 AFTER PAINT
AFTER PAINT.ACOUSTICAL.1..9" MEMBRAIN                 2 ACOUSTICAL
AFTER PAINT.ACOUSTICAL.1..9" MEMBRAIN                 3 1
AFTER PAINT.ACOUSTICAL.1..9" MEMBRAIN                 4
AFTER PAINT.ACOUSTICAL.1..9" MEMBRAIN                 5 9" MEMBRAIN
BEFORE PAINT.ELECTRIC.2..45 caliber MEMBRAIN          1 BEFORE PAINT
BEFORE PAINT.ELECTRIC.2..45 caliber MEMBRAIN          2 ELECTRIC
BEFORE PAINT.ELECTRIC.2..45 caliber MEMBRAIN          3 2
BEFORE PAINT.ELECTRIC.2..45 caliber MEMBRAIN          4
BEFORE PAINT.ELECTRIC.2..45 caliber MEMBRAIN          5 45 caliber MEMBRAIN
{code}

Splitting a string when an integer is reached

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