SQL agent job schedule

Question

Hi, 
I have multiple  SQL agent jobs , i need to schedule these jobs to run one after other , below explanation should give you more info 
job 1  scheduled every day @ 12 : 00  am 
job 2 scheduled every day @ 2 : 00 am 
job 3  scheduled every day @ 3 : 00 am
 Issue here is some times my job 2 is starting before job 1 finishes . Which is causing  problems 
i want  job 2 run only after job 1 is done  and job 3 after job 2 and goes on 
can some one please help how to do this ,any help will be appreciated 

Answer 1

If you want the process to be sequential why not merge all of the processes into same job itself as different consecutive steps? That would be the easiest to ensure they run in sequence
If thats not possible then way to do this is as follows
1.Add a new first step to Job 2 and Job 3 as follows
IF EXISTS(
select 1
from msdb.dbo.sysjobs_view job
inner join msdb.dbo.sysjobactivity activity on job.job_id = activity.job_id
where
activity.run_Requested_date is not null
and activity.stop_execution_date is null
and job.name = <Previous Job Name Here>
RAISERROR 'Previous Job Not Completed Yet!',16,1
Replace job name correctly based on your case
Then in advanced tab make On Failure Action as quit the job reporting failure and OnSuccessAction
to default. Also set retry attempts to non zero number (say 10) and
retry interval to say 15 minutes
Once this is done Job 2 will start and keep on failing until Job 1 gets finished and it will retry itself in 15 minutes for 10 times. When Job 1 finishes in the interim the next retry will be a success and job will quit.
Do the same for Job 3 too replacing name of the job as that of Job2
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