SQL Query for getting Row No for each group

Dear Oracle Gurus,
I want to allocate Rownum to each group. How we can do this with single SQL. Help me on this.
Thanks

select deptno, ename, row_number() over (partition by deptno order by ename) from emp order by 1,3;

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  • SQL Query to find missed nunmber from each group

    Hi,
    I have a set of records called "Level" and its values are A, B, C, D.
    From the below list, I want to identify the missed level for each group.
    ID          Level          Type
    1             A               Floor
    1             B                Floor
    2             A               Wind           
    2             C                Wind
    I need result like: [Missed level records]
    ID          Level          Type
    1               C             NULL     1- doesnt has C and D
    1               D             NULL
    2               B             NULL      2- doesnt has A and C
    2               D             NULL
    Pls suggest.
    Regards,
    -Sugumar Pannerselvam

    Hi,
    Got output with below code. may helpful for others.
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    INSERT INTO @TblLevel(Level) VALUES('A'),('B'),('C'),('D')
    DECLARE @TblRecords TABLE(ID INT, Level CHAR(1), Type VARCHAR(10))
    INSERT INTO @TblRecords(ID, Level, Type) VALUES(1,'A','Floor'),(1,'B','Floor'),(2,'A','Wind'),(2,'C','Wind')
    DECLARE @TblResult TABLE(ID INT, Level CHAR(1), Type VARCHAR(10))
    INSERT INTO @TblResult(ID, Level, Type)
    SELECT DISTINCT ID, TblLevel.Level, Type
    FROM @TblRecords TblRec
    CROSS JOIN @TblLevel TblLevel
    SELECT TblResult.* FROM @TblResult TblResult
    LEFT OUTER JOIN @TblRecords TblRec ON TblResult.ID = TblRec.ID AND TblResult.Level = TblRec.Level
    WHERE TblRec.Level IS NULL
    ORDER BY 1
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    Sugumar Pannerselvam.

  • Getting the first row for each group

    Hi Everyone,
    I have a query which returns a number of rows, all of which are valid. What I need to do is to get the first row for each group and work with those records.
    For example ...
    client flight startairport destairport stops
    A fl123 LGW BKK 2
    A fl124 LHR BKK 5
    B fl432 LGW XYZ 7
    B fl432 MAN ABC 8
    .... etc.
    I would need to return one row for Client A and one row for Client B (etc.) but find that I can't use the MIN function because it would return the MIN value for each column (i.e. mix up the rows). I also can use the rownum=1 because this would only return one row rather than one row per group (i.e. per client).
    I have been investigating and most postings seem to say that it needs a second query to look up the first row for each grouping. This is a solution which would not really be practical because my query is already quite complex and incorporating duplicate subqueries would just make the whole thing much to cumbersome.
    So what I really new is a "MIN by group" or a "TOP by group" or a "ROWNUM=1 by group" function.
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    Cologne, Germany

    Something like this:
    select *
    from (
       select table1.*
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    where rn = 1In the "partition by" clause you place what you normally would "group by".
    In the "order by" clause you define which will have row_number = 1.
    Edit:
    PS. The [url http://download.oracle.com/docs/cd/E11882_01/server.112/e17118/functions004.htm#i81407]docs have more examples on using analytical functions ;-)
    Edited by: Kim Berg Hansen on Sep 16, 2011 10:46 AM

  • Oracle SQL query for getting specific special characters from a table

    Hi all,
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    Table Name- Table1
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    1          aaaaaaaa
    2          a1234sgjghb
    3          a@3$%jkhkjn
    4          abcd-dfghjik
    5          bbvxzckvbzxcv&^%#
    6          ashgweqfg/gfjwgefj////
    7          sdsaf$([]:'
    8          <-fdsjgbdfsg
    9           dfgfdgfd"uodf
    10         aaaa  bbbbz#$
    11         cccc dddd-/mnm
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    3          a@3$%jkhkjn
    5          bbvxzckvbzxcv&^%#
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    You can achieve it in multiple ways. Here are few.
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      2  as
      3  (
      4  select 1 id, 'aaaaaaaa' name from dual union all
      5  select 2 id, 'a1234sgjghb' name from dual union all
      6  select 3 id, 'a@3$%jkhkjn' name from dual union all
      7  select 4 id, 'abcd-dfghjik' name from dual union all
      8  select 5 id, 'bbvxzckvbzxcv&^%#' name from dual union all
      9  select 6 id, 'ashgweqfg/gfjwgefj////' name from dual union all
    10  select 7 id, 'sdsaf$([]:''' name from dual union all
    11  select 8 id, '<-fdsjgbdfsg' name from dual union all
    12  select 9 id, 'dfgfdgfd"uodf' name from dual union all
    13  select 10 id, 'aaaa  bbbbz#$' name from dual union all
    14  select 11 id, 'cccc dddd-/mnm' name from dual
    15  )
    16  select *
    17    from t
    18   where regexp_like(translate(name,'a-/" ','a'), '[^[:alnum:]]');
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             3 a@3$%jkhkjn
             5 bbvxzckvbzxcv&^%#
             7 sdsaf$([]:'
             8 <-fdsjgbdfsg
            10 aaaa  bbbbz#$
    SQL> with t
      2  as
      3  (
      4  select 1 id, 'aaaaaaaa' name from dual union all
      5  select 2 id, 'a1234sgjghb' name from dual union all
      6  select 3 id, 'a@3$%jkhkjn' name from dual union all
      7  select 4 id, 'abcd-dfghjik' name from dual union all
      8  select 5 id, 'bbvxzckvbzxcv&^%#' name from dual union all
      9  select 6 id, 'ashgweqfg/gfjwgefj////' name from dual union all
    10  select 7 id, 'sdsaf$([]:''' name from dual union all
    11  select 8 id, '<-fdsjgbdfsg' name from dual union all
    12  select 9 id, 'dfgfdgfd"uodf' name from dual union all
    13  select 10 id, 'aaaa  bbbbz#$' name from dual union all
    14  select 11 id, 'cccc dddd-/mnm' name from dual
    15  )
    16  select *
    17    from t
    18   where translate
    19         (
    20            lower(translate(name,'a-/" ','a'))
    21          , '.0123456789abcdefghijklmnopqrstuvwxyz'
    22          , '.'
    23         ) is not null;
            ID NAME
             3 a@3$%jkhkjn
             5 bbvxzckvbzxcv&^%#
             7 sdsaf$([]:'
             8 <-fdsjgbdfsg
            10 aaaa  bbbbz#$
    SQL>

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  • I want sql query for this output

    hi guys
    could u tell how can i write sql query for this out put
    i have one table like this
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    1 1 A
    2 1 B
    3 2 C
    4 2 D
    5 3 E
    7 NULL F
    8 NULL G
    MY OUT PUT MUST BE LIKE THIS
    ID AID TAX
    2 1 A
    4 2 D
    7 NULL F
    8 NULL G
    HERE IN THIS OUTPUT I SHOULD HAVE
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    AND
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    I KNOW ONE SOLUTION LIKE THIS
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    COULD U PLZ TELL A SOL.

    Will this help:
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      2    (
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      4      select 2, 1, 'B' from dual union all
      5      select 3, 2, 'C' from dual union all
      6      select 4, 2, 'D' from dual union all
      7      select 5, 3, 'E' from dual union all
      8      select 7, NULL, 'F' from dual union all
      9      select 8, NULL, 'G' from dual
    10    )
    11  --
    12  select id, ACCOUTID AID, Tax
    13  from
    14  (
    15    select t.*
    16          ,count(1)       over (partition by t.ACCOUTID) cn
    17          ,row_number()   over (partition by t.ACCOUTID order by id desc) rn
    18    from t
    19  )
    20  where cn > 1
    21  and (rn = 1 or ACCOUTID is null)
    22  /
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             2          1 B
             4          2 D
             8            G
             7            F
    -- If I leave out the OR condition then you'll get this:
    SQL> ed
    Wrote file afiedt.buf
      1  with t as
      2    (
      3      select 1 ID, 1 ACCOUTID, 'A' TAX from dual union all
      4      select 2, 1, 'B' from dual union all
      5      select 3, 2, 'C' from dual union all
      6      select 4, 2, 'D' from dual union all
      7      select 5, 3, 'E' from dual union all
      8      select 7, NULL, 'F' from dual union all
      9      select 8, NULL, 'G' from dual
    10    )
    11  --
    12  select id, ACCOUTID AID, Tax
    13  from
    14  (
    15    select t.*
    16          ,count(1)       over (partition by t.ACCOUTID) cn
    17          ,row_number()   over (partition by t.ACCOUTID order by id desc) rn
    18    from t
    19  )
    20  where cn > 1
    21* and rn = 1
    SQL> /
            ID        AID T
             2          1 B
             4          2 D
             8            G
    --which follows the description you've given, but not the output

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    A.CARRIED_ITEM_TYPE=B.CARRIED_ITEM_TYPE and
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              19 PX COORDINATOR                                              
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                                       13 TABLE ACCESS BY INDEX ROWID TABLE PARALLEL_COMBINED_WITH_PARENT CST_DSA.HIERARCHY_MISMATCHES :Q1002Cost: 0 Bytes: 905 Cardinality: 1                     
                                            12 INDEX RANGE SCAN INDEX PARALLEL_COMBINED_WITH_PARENT SYS.HIERARCHY_MISMATCHES_IDX3 :Q1002Cost: 0 Cardinality: 1                
                             16 INDEX RANGE SCAN INDEX PARALLEL_COMBINED_WITH_PARENT CST_DSA.IDX$$_06EF0001 :Q1002Cost: 1 Bytes: 5 Cardinality: 1

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    <<if COLA IS MANAGER THEN CONSIDER MANGER RECORD>>
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  • How to write sql query for below mentioned eaxmple.

    Hi,
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    I need output as below.
    COLB COLC COLD COLE COLF
    5(manager) 3(sr.manger) 4(vp) 3(manger) 3(vp)
    Please provide the for above mentioned output.
    Thanks

    Duplicate thread. please view the answer posted in your first thread.
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    Regards.
    Satyaki De.

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  • Problem writing a sql query for a select list based on a static LOV

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    APPROVED     Date          
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    A report on the columns of the Validations table is shown based on the values in the search form. So far, my sql query for the report is...
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    v.REQUESTED,
    v.APPROVED,
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    Thanks.

    Hello !
    Let's have a look at my example:create table test
    id        number
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    insert into test values( 1, sysdate-3 );
    insert into test values( 2, sysdate-2 );
    insert into test values( 3, sysdate-1 );
    insert into test values( 4, sysdate );
    insert into test values( 5, sysdate+1 );
    insert into test values( 6, sysdate+2 );
    commit;
    select * from test;
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    select *
      from test
      where decode(sign(trunc(valid_til)-trunc(sysdate)),1,1,0,1,-1)
           =decode('&til','yes',1,-1);
    def til=no
    select *                                                                               
      from test                                                                            
      where decode(sign(trunc(valid_til)-trunc(sysdate)),1,1,0,1,-1)
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    1.) TRUNC removes the time part of DATE
    2.) The difference of to date-values is the number of days between.
    3.) SIGN is the mathematical function and gives -1,0 or +1 according to an negative, zero or positiv argument.
    4.) DECODE is like an IF.
    Inspect your LOV for the returning values. According to my example they shoul be 'yes' and 'no'. If your values are different, you may have to modify the DECODE.
    Good luck,
    Heinz

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