SQL query to get the Datetime 06 hours prior to the table Datetime value

Question

Hi Experts,
                I'm just trying to create a SQL query to get the Datetime which should be 06 hours prior to my Table column value(Executiontime),
Eg: my Executiontime(column) value is 07:00AM means, this query should fetch the detail of first VMName from table at 01:00AM, 
SQL Table Name: TestTable
Columns: VMName(varchar),status(varchar) Executiontime(Datetime)
SQL Query : Select Top 1 VMName from
TestTable where convert(date,Exeutiontime)=convert(date,getdate()) and
status='0' and ExecutionTime > dateadd(hour,6,getdate())
Request someone to alter this Query to my requirement or give me the new one.
Regards,
Sundar
Sundar

Answer 1

Hi All,
        Thanks for your Prompt response. I tried the below queries, but still I don't have any luck. Actually the queries are returning the value before the condition met (say when the time difference is more than 06 hours). I want the
query to return exactly @ 06 hour difference or less than 06 hours,
Query 01: Select Top 1 VMName from TestTable where
convert(date,Exeutiontime)=convert(date,getdate())
and status='0'
and ExecutionTime >
dateadd(hour,-6,getdate())
Query 02: Select
Top 1 VMName from TestTable where
status='0'
and ExecutionTime >
dateadd(hour,-6,getdate())
Query 03: Select
Top 1 VMName from TestTable where status='0'
and ExecutionTime >
dateadd(hour,-6,ExecutionTime)
          Can someone point out the mistake please.
Regards,
Sundar
Sundar