Status report 404 on tomcat

Question

I have hit a bit of a wall with regard to deploying a servlet using tomcat.
I have followed and endless list of instructions I found on various web sites, but still I am having trouble.
The versions of tomcat I have is 5.0 with the j2sdk1.4.2_03.
My project allows for a user to enter a url in a form, which is then processed by a java servlet, and links within the url are validated. The problem I�m having is that when the form is submitted, tomcat returns the status report: 404 requested resource unavailable.
The url entered is http://localhost:8080/sitevalidation/INDEX.HTM - this works fine and the home page appears.
When the form is submitted, the url changes to http://localhost:8080/sitevalidation/SiteValidation - which I assume is then looking for the servlet declared in the web.xml file, this is when the problems start!
I think I have the correct file structure as I have included the application dir �sitevalidation� in the webapps directory of tomcat. Sitevalidation contains the web-inf dir, which in turn contains the web.xml file, and the classes dir, which contains SiteValidation.class.
my web.xml file reads:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<display-name>Site Validation</display-name>
<description>
This is the Site Validation Program Written in Java
</description>
<servlet>
<servlet-name>SiteValidation</servlet-name>
<servlet-class>SiteValidation</servlet-class>
</servlet>
          <servlet-mapping>
<servlet-name>SiteValidation</servlet-name>
<url-pattern>/SiteValidation</url-pattern>
</servlet-mapping>
</web-app>
Any suggestions to where I might be going wrong would be most appreciated.
Many thanks,
Dan Williams

Answer 1

Hello.
Uncomment the InvokerServlet in the $CATALINA_HOME/conf/web.xml.
<servlet>
<servlet-name>invoker</servlet-name>
<servlet-class>
org.apache.catalina.servlets.InvokerServlet
</servlet-class>
<init-param>
<param-name>debug</param-name>
<param-value>0</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
and
<servlet-mapping>
<servlet-name>invoker</servlet-name>
<url-pattern>/servlet/*</url-pattern>
</servlet-mapping>
Then your target URL will http://localhost:8080/sitevalidation/servlet/SiteValidation .
Good luck.