Strange behavior in Double value multiplication

hi
can you please check this double value multiplication?
this gives different out put for different numbers
          double t = 81.6; //10.12
          double result = (double)t * 100.0;
          System.out.println("Result:"+ result);
from 64.6 to 81.6 the value after multiplication is 6459.999999999999 to 8159.999999999999.And also i found the same problem for 10.12
why only for these numbers it is giving different output?
Plz help me to solve this issue.
ShemJos

At a more fundamental level:
Binary numbers are base two. The units are not the problem. It is the fractions that are a problem. Binary deals with numbers like 1/2, 3/4 and 5/8 just fine. If the denominator of the reduced fraction is not a power of two, then you get some kind of repeating fraction that gets trucated in order to fit into a finite number of bits.
Based 10 has the same issues except that the denominator can also have factors of five. as well as two E.g. 1/5, 1/2, 1/10, 3/50 . Now take 1/3 and write it out in decimal: 0.333... That dot-dot-dot is where all the problems start.
If you are computing money and facing accountants who want to see the ledgers add up to the penny, then compute in pennies. If you must compute the pennies as 1/100 of a dollar, then BigDecimal will help. For most other requirements, all bets are off.
BTW: Many hand-held calculators are implemented in BCD (binary coded decimal) just to avoid all those 9 9 9's and 0 0 0's in a row and some junk at the end because the calculator-makers know how much it upsets some people.

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