String Count Occurence
i just want to count the number of occurence of character in string..
so i did this.. dont know whats wrong.. so someone help me
mport java.util.*;
public class CountChar {
public static void main(String[] args ) {
String input = args[0];
LinkedHashMap<Character, Integer> lhm = new LinkedHashMap<Character, Integer>();
for (int i =0; i<input.length(); i++) {
char currentChar = input.charAt(i);
if(lhm.containsKey(currentChar)) {
lhm.put(currentChar, lhm.get(currentChar) + 1);
} else {
lhm.put(currentChar, 1);
System.out.println(lhm.toString());
}
raji10 wrote:
yes i did itWell, as I wrote already: it works fine for me, there must be something else you're doing wrong. What exactly doesn't work?
kind regards,
Jos
Similar Messages
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Counting occurences of a string (in a cell)
This is a little like the topic "Counting occurences of a word," except I want to be able to count how many times a specified search string occurs in a cell, not count how many cells contain the string. I would also like a formula that gave the offset of the starting character of the search string into the cell, such that a zero signified that the search string did not occur.
Basically, I want a general set of tools to parse a cell's string data, enabling me to determine where in the cell's string data each occurrence of another string is located & to extract parts of the string data relative to where the search string occurs.
For example, if the cell contains the string, "1ab2cd2e" I want to be able to extract "cd" & "e" based on the characteristic that they follow "2."Here it is:
--(SCRIPT decoupeur.app]
Save the script as a Script, an Application or an Application Bundle named decoupeur
Put the file in the folder
<startup Volume>:Users:<yourAccount>:Library:Scripts:Applications:Numbers:
Maybe you would have to create the folder Numbers and even the folder Applications by yourself.
To use it,
Select the group of cells to convert
Copy to the clipboard
Select the destination cell
Goto Scripts > Numbers > decoupeur
You will be asked to define the separator to use.
Given the separator "2", the strings of the kind "1zer6sd2az2rt8aa2er7kkk5uu2a"
would be parsed and return az TAB rt TAB er TAB a
The converted values will be pasted at the cursor.
Yvan KOENIG 30juin 2008
property theApp : "Numbers"
property menuFenetre : 10
property premierNom : 6
property nomDuDocActif : ""
property theDelim : ""
property listeLignes : {}
property listeTemp : {}
property msg90 : ""
property msg91 : ""
property msg92 : ""
--=============
on run
tell application "System Events" to if not (UI elements enabled) then set (UI elements enabled) to true (*
Active le GUI scripting
• Enable GUI scripting *)
my nettoie()
my controleVersion()
set nomDuDocActif to my getFrontDoc()
if nomDuDocActif = "" then return
my prepareMessages()
try
set txtDatas to the clipboard as Unicode text
on error (*
The clipboard was empty *)
return
end try
set my listeLignes to every paragraph of txtDatas
set srcNbRows to count of my listeLignes
if txtDatas contains tab then (*
several columns *)
error "Can't treat several columns" number 8001
else (*
single column *)
tell application theApp
set choix to choose from list {"1", "2", "3", "4", "5", "6", "7", "8", "9", "0"} with prompt msg90 default items {"2"} OK button name msg91 cancel button name msg92
end tell
if choix is false then error -128
set theDelim to item 1 of choix
repeat with i from 1 to srcNbRows
if item i of my listeLignes is not "" then set item i of my listeLignes to my decipher(item i of my listeLignes)
end repeat
end if
set the clipboard to my recolle(listeLignes, return)
my pasteIt()
my nettoie()
end run
--=============
on pasteIt()
tell application theApp to activate
tell application "System Events" to tell (first process whose title is theApp)
click menu item nomDuDocActif of menu 1 of menu bar item menuFenetre of menu bar 1
keystroke "v" using {command down}
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end pasteIt
--=============
on decoupeur(n)
local d, ms, m
set d to n div 1
set ms to (n - d) * 60
set m to round (ms)
return (d as text) & "°" & m & "’" & (round ((ms - m) * 60)) & "”"
end decoupeur
--=============
on decipher(source)
local i, itm, shortimem, j
set my listeTemp to my decoupe(source, theDelim)
set my listeTemp to items 2 thru -1 of my listeTemp
repeat with i from 1 to count of my listeTemp
set itm to item i of my listeTemp
set shortItem to ""
repeat with j from 1 to length of itm
if character j of itm is not in "1234567890" then
set shortItem to shortItem & character j of itm
else
exit repeat
end if
end repeat
set item i of my listeTemp to shortItem
end repeat
return my recolle(my listeTemp, tab)
end decipher
--=============
on getMinutesSeconds(t, d)
local ll
set ll to my decoupe(t, d)
return {(item 1 of ll) as integer, (item 2 of ll) as text}
end getMinutesSeconds
--=============
on decoupe(t, d)
local l
set AppleScript's text item delimiters to d
set l to text items of t
set AppleScript's text item delimiters to ""
return l
end decoupe
--=============
on recolle(l, d)
local t
set AppleScript's text item delimiters to d
set t to l as text
set AppleScript's text item delimiters to ""
return t
end recolle
--=============
on nettoie()
set AppleScript's text item delimiters to ""
set my listeLignes to {}
set my listeTemp to {}
set nomDuDocActif to ""
end nettoie
--=============
Get the name of the active document
on getFrontDoc()
local nw, mm
tell application theApp to activate
tell application "System Events" to tell (first process whose title is theApp)
set nw to name of every menu item of menu 1 of menu bar item menuFenetre of menu bar 1
if (count of nw) < premierNom then
set mm to ""
else
repeat with i from premierNom to count of nw
set mm to item i of nw
if (value of attribute "AXMenuItemMarkChar" of menu item mm of menu 1 of menu bar item menuFenetre of menu bar 1) is not in {"", "•"} then exit repeat
end repeat
end if -- (count of nw)…
end tell
return mm
end getFrontDoc
--=============
on controleVersion()
local v
try
set v to version of application theApp
set menuFenetre to 10 (* index of the Windows menu *)
set premierNom to 6 (* index of the first docName in the list of menu names
The list contains one more item than the displayed menu *)
on error (*
• We are here if Numbers ignores the instruction get version *)
tell application "System Events" to set v to get version of (get (application file of (get first process whose title is theApp)))
if v starts with "1" then
set menuFenetre to 10
set premierNom to 6
else (* ready for a Numbers v2 ignoring AppleScript *)
set menuFenetre to 10
set premierNom to 6
end if
end try
end controleVersion
--=============
on parleAnglais()
local z
try
tell application theApp to set z to localized string "Cancel"
on error
set z to "Cancel"
end try
return (z = "Cancel")
end parleAnglais
--=============
on prepareMessages()
if my parleAnglais() is false then
set msg90 to "Choisir le séparateur"
set msg91 to " OK "
set msg92 to "Annuler"
else
set msg90 to "Choose a separator"
set msg91 to " OK "
set msg92 to "Cancel"
end if
end prepareMessages
--=============
--[/SCRIPT]
Yvan KOENIG (from FRANCE lundi 30 juin 2008 11:16:52) -
Hello Experts,
I have the following query related to counting occurences of a particular characteristic related to the Calendar month
1) When I choose the option "Average of all values" within exception aggregation for the calculated keyfigure that I am using for the count, it counts all the values including duplicates .i.e. if the charcteristic has repeated occurences for a given month, then it is counted distinct occurence. However, in this case it is not showing me "0" for no occurence but just displaying a blank
2) But when I choose the option "Counting all values" within exception aggregation for the calculated keyfigure that I am using for the count, it does provides me "0" for no occurences but it counts the repeated value as single occurence
How can I get around this? I mean to get repeated values to be counted as separate occurences and also being able to show "0" for no occurence.
Any help will be appreciated
Thanks,
RishiHi ,
Please use exception aggregation as you already did with count all values.
But you need to select a specific reference chars to select the unique count.Plant or the Month can be a option.
In BI7.0 U have concept of nested aggregation:
Create a CKF1 with reference to one Char. and craete another CKF2 using the earlier CKF1 and put again a reference on some other char.
that will solve the problem.
Please take care of the selection of Char while doing reference char. -
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Problem synopsis:
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Thanks!
PS: even if you are to late (after 25) post anyway!
Why:
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Thanks again!
Attachments:
BexusII_groundstation.vi 46 KBI have a valid example data file attached to this thread.
If you open BEXTEST.bin in a hex-editor of your choice, you'll see the BEXUS as 42 45 58 55 53 and then the time as 00 28 09 etc.
I couldn't get Joe Guo's VI to work. It doesn't count packages correctly, and the time is not displayed correctly either.
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The data is from actual launching area tests performed a few mintues ago. The time displayed is "On time" e.g. how long the gondola has been powered up.
I have a spare T-junction, so I can hook into the balloon real-time data as we fly, in case anyone care to see if they can figure out why the latest version of Joe Guo's program is not displaying correctly.
I will monitor this
thread during and after flight to see if anyone can make it in time!
Thanks for the great effort!!
Attachments:
bextest.bin 53 KB -
Read Text file and count occurences of certain string
Hello,
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(2) how do word frequency and word occurrence
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//I want this program to throw exception if the user enters numbers
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http://home.cogeco.ca/~ve3ll/jatutor7.htm
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Hello everyone :)
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import java.lang.Math;
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}the throwDie method has to be used in main method but I'm stuck as for what to do next I'm afraid.Hello Looce and thank you for the welcome,
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An update of the code:
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public static int throwDie()
double x = Math.random();
double x2 = Math.random();
double x3 = Math.random();
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x2 = (x2 * 6.0) +1.0;
x3 = (x3 * 6.0) +1.0;
int dice1 = (int)Math.floor(x);
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int dice3 = (int)Math.floor(x3);
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public static void main(String args[])
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} -
Count Occurences within in an Array
Hi,
I have an array with numbers, I want to count how often the number 5 is stored in it, does anyone know the syntax?
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Sorry, I think I am mising something really basic here,
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In my main report I want to count the occurneces of say the number 5. But I was expecting to drop the array name only (RespondentArray1) into where you have {@Array}. But I get an error if I do that. The formula where the array is declared and populates is in a subreport.
Can you please advise of what I should be replacing in your code?
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Counting Occurences over multiple columns
I have searched the forums and found how to calculate the number of occurrences of a word in a single column.
I am working on a sales project and I need to calculate the number of occurrences for a specific sales agent in multiple columns. Then a total of the sales next to the occurrences
Column 1 will be the sales agent for a home buyer.
Column 2 will be the sales agent for a home seller.
I need to find out how many times a specific agent represents both buyers and sellers.
Then I need a total of all the sales for each of the agents.
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Yvan you seem to be the guru.
Please help.
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Jerry has given you a good solution in general terms but there are some ambiguities in your question.
For example, your question suggests there is transaction amount column, as one might expect, but did not specify if these amounts are listed in separate buyer/seller columns. The solution below assumes they are in a single column.
An auxiliary column (hidden) was added to the Data Table to determine whether or not an agent represented both buyer and seller. The agent's name appears in this column if he/she did, and the formula is:
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The Summary table raises the question of whether the agent's amount is doubled when he/she represents both buyer and seller. Here again, an assumption was made, namely, that it does not. If this is incorrect, the last segment (after the "-" sign) of the formula below can be dropped:
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And finally, the number of times an agent represented both buyer and seller:
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I hope this represents your situation and that it answers your questions.
pw -
Even after deleting the string "Counting to five: one 2 three 4. five." from the string control and replacing it with another string the original string returns after the VI is saved then reopened. Where is this string data coming from? I've attached a copy of the library function. I've been able in my application to get around the problem by replacing the string control with a string constant. But I'm still curious as to what's going on.
Thanks,
Chuck
Solved!
Go to Solution.
Attachments:
Extract Numbers Test.vi 9 KBChuck,
String control has been set to default with the string you are seeing. To change this, enter the new string, right click the control and select
Data Operations>>Make Current Value Default
Now save your vi. -
Find the nth occurrence of a string in a string
Hi,
I'm wondering if there is a method like indexOf, but finds the nth occurrence of a string
public static int occurrence(java.lang.String str,
java.lang.String toFind,
int occurrence)Cheers
Jonnyphdk wrote:
calypso was refering to promes pseudo code.What is promes? I don't understand the word. Sorry!
I put the global variable 'count' now in the method occurence
public static int occurence(String str, String toFind, int occurence){
int origLength = str.length();
int count = 0;
while(str.length()>0){
str = contains(str, toFind, count);
if(count == occurence){
int length = str.length();;
int actualPos = origLength-(length+1);
return actualPos;
count++;
return -1;
public static String contains(String str, String toFind, int count){
int occurence = str.indexOf(toFind);
if(occurence != -1 ){
count = count+1;
return str.substring(occurence+1,str.length());
}else{
return "";
}The output is 1 position to high.
I still don't get which part of the code to replace with this pseudo code: s'.indexOf('toFind', 'index'+1)
Sorry for being dimwitted!
Thanks
jonny -
J2ME has got no StringTokenizer or .split method for string manipulation, i came up with an algorithm to do something of the sort. Here is my problem, the string i want to split is a string of midi files got from Oracle via a servlet.
The String is:
Beverly Knight - Shoulda Woulda Coulda.mid DB Boulevard - Different Point Of View.mid Kylie Minogue - In Your Eyes.mid Lasgo - Something.mid PPK - Resurection.mid Shouda.mid U2 - Walk On.midI wish to have output like this
Beverly Knight - Shoulda Woulda Coulda.mid
DB Boulevard - Different Point Of View.mid
Kylie Minogue - In Your Eyes.mid
Lasgo - Something.mid
PPK - Resurection.mid
Shouda.mid
U2 - Walk On.midThe output im getting is
Beverly Knight - Shoulda Woulda Coulda.mid
midDB Boulevard - Different Point Of View.mid
midKylie Minogue - In Your Eyes.mid
midLasgo - Something.mid
midPPK - Resurection.mid
midShouda.mid
midU2 - Walk On.midIm splitting the string up based on the '.'(dot) thats why Im getting output like the above, would any of you know how to remove the mid from the start of each of the strings, please keep in mind this is an array of strings.
My code:
private void format(String s)
int[] tmp;
int count = 0,count1= 0;
for(int i=0; i<s.length(); i++)
if(s.charAt(i) == '.')
count++;
tmp = new int[count];
takin = new String[count];
for(int i=0;i< s.length();i++)
if(s.charAt(i) == '.')
tmp[count1]=i;
count1++;
int y=0;
for(int i=0;i<takin.length;i++)
if(i==0)
takin[i] = s.substring(0,tmp)+".mid";
y=tmp[i] + 1;
else
takin[i] = s.substring(y,tmp[i])+".mid";
y=tmp[i] + 1;
midlet.forwardResults(takin);
The output is generated in the midlet.forwardResults method.
Help?Suggestions?Code?
Best Regards
BodFredIts alright now, got it sorted myself
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