Substitution variable in a select statement

I have a cursor as follows:
cursor c2 is select'word',cuel.curricular_component_name,cuel.curricular_element_name,phase,cuel.curricular_type,student_contact_hours,faculty_name,objective,cuel.curricular_component_id,cuel.curricular_element_id
from v_cuel cuel,v_cuelse_facu facu
where cuel.objective like '%'||vTopic||'%'
and cuel.phase in (:CONTROL1.PHASE)
and cuel.curriculum_year = :CONTROL1.CURRICULUM_YEAR
and cuel.curricular_element_id = facu.curricular_element_id
and facu.session_nbr = 1
and faculty_name =
(select min(faculty_name)
from v_cuelse_facu
where curricular_element_id = cuel.curricular_element_id
and faculty_name not like 'TBA%')
and cuel.curricular_element_name not in (select cuel_name from topic_search where cuel_name is not null)
union
select 'word',curricular_component_name,null,phase,null,null,null,objective,curricular_component_id,null
from curricular_components cuco
where objective like '%'||vTopic||'%'
and cuco.phase in (:CONTROL1.PHASE)
and cuco.curriculum_year = :CONTROL1.CURRICULUM_YEAR;
The problem I'm having is with the bind variable :CONTROL1.PHASE. The substitution is not happening. If I replace the bind variable with an acceptable value, the query works properly. If I let forms do the substitution, I get no results from the query. Just to be sure the bind variable is correct, I copied it from one debug pass and pasted into the select statement. It's correct.
Does anyone have any ideas about what could be happening?
Thanks,
Meg Colby

> and cuco.phase in (:CONTROL1.PHASE)
You can change the above to:
and cuco.phase
in(:Control1.Phase1, :Control1.Phase2, :Control1.Phase3, :Control1.Phase4)And set each of the four Phase values to the values you want (but without the quotes):
Phase1 = I-1
Phase2 = I-2
Phase3 = II
Phase4 = III
If you want, you can create a number of :Control.Phase(n) fields, and if any one is null, it won't matter.

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Hi,
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the procedure is given below:
create or replace procedure test(tablename in varchar2, fieldname IN varchar2)
authid current_user
is
type poicurtype is ref cursor;
poi_cur poicurtype;
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THEVALUE NUMBER;
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Best Regards,

So you want to amend each row individually? Is there some reason you're trying to make this procedure run as slow as possible?
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authid current_user
is
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Hi,
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[php+mysql] how to use variables in a select statement?

Hi all,
I'm searching for a way to use a variable in the select
statement of mysql
query.
I have this variable that can contain:
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or
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so, the variable content is not always the same.
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Hi all,
I'm searching for a way to use a variable in the select
statement of mysql
query.
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or
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so, the variable content is not always the same.
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Here is my Select statement:
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declare @companyID char(6)
declare c_company cursor for
select INTERID from dbo.GP_Interid
open c_company fetch next from c_company into @companyID
while @@fetch_status = 0
begin
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exec ('select ' + @companyID + ' , [Year],[Period ID],[Account Number],[Account Description],[Credit Amount],[Debit Amount]
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fetch next from c_company into @companyID
end
close c_company
deallocate c_company

Try
- retrieves a list of gl balances from all companies
truncate table sap_glsummary
declare @companyID char(6)
declare c_company cursor for
select INTERID from dbo.GP_Interid
open c_company fetch next from c_company into @companyID
while @@fetch_status = 0
begin
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close c_company
deallocate c_company
For every expert, there is an equal and opposite expert. - Becker's Law
My blog
My TechNet articles

Using variable in select statement (php)

I am having difficulty using a variable in a select
statement.
The following manual query (using a static date) works fine:
$query_Recordset1 = "SELECT * FROM academyClasses WHERE
classDate > '2006-06-01' ";
However, If I use the following:
$dateVar = date('Y-m-d');
mysql_select_db($database_mw, $mw);
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ALL records are returned, which means the $dateVar variable
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field <?php echo $row_Recordset1['classDate']; ?> in my
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My date field "classDate" is of a "date" type within the
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I'm sure this is just a syntax problem, at least I hope it
is.
Any help is greatly appreciated.

On Wed, 7 Jun 2006 04:49:57 +0000 (UTC), "mgwaters"
<[email protected]> wrote:
>Thanks Gary. That did seem to get the select statement
working, but I had to
>enter a manual date as before $dateVar = '2006-06-01'; on
the previous line of
>code to actually get it to filter my records. So... it
looks like my setting of
>the date variable:
> $dateVar = date('Y-m-d');
> does not seem to be recognized within the SELECT
statement.
Try this:
$query_Recordset1 = "SELECT * FROM academyClasses WHERE
classDate>'$dateVar'";
print $query_Recordset1;
See what is in the SQL statement.
Gary

Storing variable from select statement

I need to store a variable from a select statement into a session. Before I was taken what was passed from another page and throwing it into a session.--
String Password= request.getParameter("Password");
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session.setAttribute("USER",Password);
Now though I need to put in Web_User_Id and cannot find the proper syntax. Can someone help
session.setAttribute("User",???????);

WEB_USER_ID is unidentified because it is a column name, not a variable name. You should first assign its value to a variable and then put the variable name into the setAttribute statement instead.
Your query may return more than one result based on the way it is written. It sounds like you are trying to find all users with a password that is equal to the value of Password. If this is correct, then are you trying to create an attribute for each user?
If your intention is to locate a user, then the user id and password should have been provided. A variable should be defined for both the password and user id. You should then add the user id to the where clause. After a successful search, the attributes can be created using the same syntax.

Select statement from "v_filename_txt" inside cursor

Hi,
I've got a store procedure procedure that create parametric tables to upload from csv files. I have collect into v_filename_txt variable the parametric table name where I would like to make some select.
I have write the following code but I can't use a variable into a select statement :
select field
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Paolo.

You could rcreate an external table. Then select the values from this external table.
You can switch the source of the external table to a new file with the
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Problem setting the value of a substitution variable in a calc script

Hi, All.
I'm trying to update the value of a substitution variable inside an IF statement and I'm having trouble.
Here's the code:
*"Jan"(*
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ENDIF;)
the error I get back from EAS is:
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I know CL knows a lot about HBR, if he's around today... LOL
As a matter of fact, I just used an HBR (not using Calc Manager till I have to)'s macro functionality to drive fx for different Scenarios in a Planning app. Here's how I call the macro:
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Cameron Lackpour
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Hello!
I'm wondering if its possible to get the username of the current user logged in and pass it as a variable into a select statement used in a dynamic LOV in Oracle AS Portal?
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Substitution variable in BR Graphical Interface

Hi,
we have a business rule using a prompt that we would like to change to a subtitution variable. But we can't just enter "&AnCour" (for current year).
I didn't found any place where I could select my substitution variables (I can select prompts and local variables but not substitution variables).
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Thanks

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http://john-goodwin.blogspot.com/

Bind Variable in SELECT statement and get the value in PL/SQL block

Hi All,
I would like pass bind variable in SELECT statement and get the value of the column in Dynamic SQL
Please seee below
I want to get the below value
Expected result:
select distinct empno ,pr.dept   from emp pr, dept ps where   ps.dept like '%IT' and pr.empno =100
100, HR
select distinct ename ,pr.dept   from emp pr, dept ps where   ps.dept like '%IT' and pr.empno =100
TEST, HR
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NYC, HR
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Please suggest
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EMPNO NUMBER,
ENAME VARCHAR2(255),
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COLUMNAME VARCHAR2(255)
INSERT INTO COLUMNAMES(COLUMNAME) VALUES ('EMPNO');
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INSERT INTO COLUMNAMES(COLUMNAME) VALUES ('LOC');
COMMIT;
CREATE TABLE DEPT(
DEPT VARCHAR2(255),
DNAME VARCHAR2(255)
INSERT INTO DEPT(DEPT,DNAME) VALUES ('IT','INFORMATION TECH');
INSERT INTO DEPT(DEPT,DNAME) VALUES ('HR','HUMAN RESOURCE');
INSERT INTO DEPT(DEPT,DNAME) VALUES ('MR','MARKETING');
INSERT INTO DEPT(DEPT,DNAME) VALUES ('IT','INFORMATION TECH');
COMMIT;
PL/SQL BLOCK
DECLARE
TYPE EMPCurTyp IS REF CURSOR;
v_EMP_cursor    EMPCurTyp;
l_col_val           EMP.ENAME%type;
l_ENAME_val       EMP.ENAME%type;
l_col_ddl varchar2(4000);
l_col_name varchar2(60);
l_tab_name varchar2(60);
l_empno number ;
b_l_col_name VARCHAR2(255);
b_l_empno NUMBER;
begin
for rec00 in (
select EMPNO aa from EMP
loop
l_empno := rec00.aa;
for rec in (select COLUMNAME as column_name from columnames
loop
l_col_name := rec.column_name;
begin
l_col_val :=null;
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LOOP
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    EXIT WHEN v_EMP_cursor%NOTFOUND;
      dbms_output.put_line('l_col_name='||l_col_name ||' empno ='||l_empno);
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CLOSE v_EMP_cursor;
END;
END LOOP;
END LOOP;
END;

user1758353 wrote:
Thanks Billy, Would you be able to suggest any other faster method to load the data into table. Thanks,
As Mark responded - it all depends on the actual data to load, structure and source/origin. On my busiest database, I am loading on average 30,000 rows every second from data in external files.
However, the data structures are just that - structured. Logical.
Having a data structure with 100's of fields (columns in a SQL table), raise all kinds of questions about how sane that structure is, and what impact it will have on a physical data model implementation.
There is a gross misunderstanding by many when it comes to performance and scalability. The prime factor that determines performance is not how well you code, what tools/language you use, the h/w your c ode runs on, or anything like that. The prime factor that determines perform is the design of the data model - as it determines the complexity/ease to use the data model, and the amount of I/O (the slowest of all db operations) needed to effectively use the data model.

How to use bind variable value for table name in select statement.

Hi everyone,
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Following is error msg:
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Substitution variable in a select statement

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