Sum function on a column

Hi,
I created a report with few columns and one cash column where I gave the function as sum. when I dont do a sum for that column there are four rows coming up. Three rows for 'income' and one row for 'Principal'. The value for principal is coming correct when I tally with the sql query. But when I add the function sum to that column the 'income' total is summing up correct but for some reason the 'principal' amount is not showin the value that it showed when I did not add the sum function. It is showing a different value. I am not sure what's happening here. Any advices please.

Hi Sandeep,
I am not selecting any columns from fact table. I am just selecting columns from two dimesion tables. One dimension table has Account number, date and meaning. The other dimension table has cash column. When i pull these columns and run it gives correct values. For example for one account number we have two meanings income and principal. For that account number we have three values for income and one value for principal. When I run the query it is running good. But when I goto Critera and say edit formula on cash and put function as sum and then run the report it is not giving me the principal value correct. The sum of incomes are coming correct. The principal value was 2781.32 and after addig sum function it gives me 119596.76. Not sure why?

Similar Messages

  • SUM function for a column made 'on the fly'

    I have access to a database, however only SELECT statements can be run on the database. Basically the database lists switches, these switches can have up to 20 computers connected to them but some do not. I need to know the switches which contail less than 20 computers so I know where there is space for more computers (I've wrote the code for this already). I also need something to keep a tally/total for the number of spare spaces left so I can run the script and go 'ok we have a total of 20 spare places for computers theres 10 on this switch and 10 on this one'.
    I just need to get the sum funtion working for the column that I've created 'on the fly', the column revealing the number of spare slots, heres the code I've got so far:
    SELECT switch, COUNT(*) as "Servers", 20 - COUNT(*) as "Spare slots"
    from dedicated_servers
    where switch like 'rs%'
    GROUP by switch
    HAVING COUNT(switch) < 20
    order by Servers;
    Which gives the following:
    | switch | Servers | Spare slots |
    | rsj14-1.dc | 12 | 8 |
    | rsj12-1.dc | 15 | 5 |
    | rsi2-2.dc | 16 | 4 |
    | rsj13-1.dc | 16 | 4 |
    | rsi2-1.dc | 16 | 4 |
    Just need something at the end saying TOTAL=25

    OK I'll have to make em up though, but they are something like this for one switch:
    INSERT INTO dedicated_servers (switch, server_number, switch_socket)
    VALUES (rsj-1.dc, 100, 18)
    On switch rsj-1.dc there can be upto 20 servers (the server_number is the primary key)
    Message was edited by:
    slowpoke115

  • Splitting up sum function into 2 columns

    There are only 2 possible values for t1_type (1 or 2)
    create table t1 (id number, t1_type number, amount number);
    insert into t1 values (1,1,5);
    insert into t1 values (1,1,10);
    insert into t1 values (1,2,35);
    insert into t1 values (1,2,20);
    insert into t1 values (2,1,5);
    insert into t1 values (2,1,10);
    insert into t1 values (2,2,35);
    insert into t1 values (2,2,20);
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    id, sum(amount) /*for t1_type 1*/,sum(amount)/*for t1_type 2*/
    Desired output from above data would be:
    1,15,55
    2,15,55
    Thanks
    Sam.

    Is this you wanted?
    sql>
    select id,sum(decode(type,1,amt,0)) sum_type1,sum(decode(type,2,amt,0)) sum_type2
    from t1
    group by id;
    ID SUM_TYPE1 SUM_TYPE2 
    1  15  55 
    2  15  55
    jeneesh                                                                                                                                                                                                                                                                                                                                                                                                                           

  • I use Function Sum to add a column and a new column pops up filled with 0s

    In one of my spreadsheets, every time I try to add a column of numbers using the Sum Function, a new column is added filled with 0s. What's happening? And How do I get it to just add the column?

    can't you just write an SQL script to update the new column?
    Perhaps you can use the integration_id for this? or just another column(s)..

  • Problem with group by and sum function

    In one of the report I'm using grioup by clause on one column. However when I use this function the sum function on other column is not working.
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    Hi Tintin,
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    Thanks,
    -Amith.

  • How can I sum up raws? the sum function seems to work for columns only and right now I have to create a separate formula for each raw

    How can I sum up raws? the Sum function seems to work only on columns. Right now I have to create a separate formula for each raw

    Hi dah,
    "Thanks, but can I do one formula for all present and future raws? as raws are being added, I have to do the sum function again and again"
    You do need a separate formula for each group of values to be summed.
    If the values are in columns, you need a copy of the formula for each column.
    If the values are in rows, you need a copy of the formula for for each row.
    If you set up your formulas as SGIII did in his example (shown below), where every non-header row has the same formula, Numbers will automtically add the formula to new rows as you add them.
    "Same formula" in this context means exactly the same as all the formulas above, with one exception: the row reference in each formula is incremented (by Numbers) to match the row containing the formula.
    Here the formula looks like this in the three rows shown.
    B2: =SUM(2)
    B3: =SUM(3)
    B4: =SUM(4)
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    Also, because the row token (2) references all of the non-header cells in row 2, the formula will automatically include new columns as they are added to the table.
    Regards,
    Barry

  • Why does the sum function not work when I try to add a column of decimal numbers?  The value is always returned as 0.  No problem with whole numbers but decimals do not work!

    just bought a MacBook Air and using Numbers to make a spreadsheet for financial purposes.  The sum function is working ok for whole numbers but when I try to sum a column of 2 decimal place numbers the result always comes back as 0.  Can anyone help?

    Hi laura,
    I suspect that your 2 decimal place numbers are formatted as text. Change the format of the column to currency and see it that works.
    Also You might want to update your profile to reflect your current systems!
    quinn

  • Can I get multiple sums in a single column based on a "code" I place.

    After importing a file of check/debit card activity from my bank, can I 'code' the line items based on tax categories ie Utilities, Medical expenses, Auto expenses, etc. and then get sums for each based on that code I placed in a single column? That would mean multiple sums in a single column based on the code used for each tax related expense. For instance, I would put UT in the column for utilities expenses and MED in the same column if it were a medical expense. I would then want the sum for all items in that column for each item code. Is this possible or do I need to use a different approach to get this information.

    My guess is that the SUMIF function may be your friend.
    It's well described in the *iWork Formulas and Functions User Guid*e which every user may download from the Help menu.
    Yvan KOENIG (VALLAURIS, France) samedi 2 janvier 2010 21:56:39

  • Error when using SUM function in Excel template

    I am trying to use the XDO_METADATA to create a sum of a column from my XML data and I am getting the following error in the Template Viewer:
    [111412_104246459][][PROCEDURE] Log Level is changed to PROCEDURE
    [111412_104246553][oracle.xdo.common.xml.XSLTWrapper][ERROR] XSL error:
    Time: 0.125 sec.
    FO Formatting failed.
    <Line 317, Column 116>: XML-23029: (Error) FORG0001: invalid value for cast/constructor
    @Line 317 ==> <Cell Index="2" Style="R7C3" Field="XDO_?SUM_V_CR_MO_IDD1?"><xsl:value-of select="sum(.//G_CR_MST_D/V_CR_MO_IDD)"/>
    when I use:
    XDO_?SUM_V_CR_MO_IDD1?     <?sum(.//G_CR_MST_D/V_CR_MO_IDD)?>
    or
    [111412_104048508][][PROCEDURE] Log Level is changed to PROCEDURE
    [111412_104048554][oracle.xdo.common.xml.XSLTWrapper][ERROR] XSL error:
    Time: 0.078 sec.
    FO Formatting failed.
    <Line 317, Column 105>: XML-23029: (Error) FORG0001: invalid value for cast/constructor
    @Line 317 ==> <Cell Index="2" Style="R7C3" Field="XDO_?SUM_V_CR_MO_IDD1?"><xsl:value-of select="sum(.//V_CR_MO_IDD)"/>
    when I use:
    XDO_?SUM_V_CR_MO_IDD1?     <?sum(.//V_CR_MO_IDD)?>
    I believe the XSL to be correct because when I change it to a count it works and when I go into BI Publisher 11g and create the query in the data model and then create a summary from it, the summary is created.
    Can anyone help?

    I went back to basics and created reports (via EXCEL templates) like I was asking based on good old EMP and DEPT and I found exactly the same problems I was mentioning. I looked at the templates provided but they were not calculating totals, like me they were selecting them and then just displaying them on the page.
    Anyway, I have narrowed it down to the fact that when you do aggregates like sum(.//SAL) this works if you have a salary for every value. I did an outer join with DEPT so I did have empty rows and why I still experienced the problems.
    Basically XSL does not like adding (including using the sum function) values that effectively have nulls in them which is why I get the cast/constructor errors because it is trying to turn a NaN value to a number and does not (or cannot) do it.
    You need to either have a value in every row of your column (maybe possible by selecting nvl in your query) and make sure that you check the "create empty nodes" checkbox in the data model of BI Publisher.,
    the other solution is an xsl solution where you would have to make sure that you only added non null values and for that you would have to investigate xsl blogs.
    It is, by the way, why my count worked because it is just counting that the record exists it does not care what the element content is or isn't.
    Closing thread.

  • Issues using SUM Function in query

    I have pasted two queries Query1 (calculating counts for total_ships and ships_released) and Query2 (calculating the two same counts and then calculating SUM for total_shipments and I am having problem in this)
    Query 1:
    select  b.loc , b.week, b.vvalue2, b.Total_ships, nvl(a.up_date,'None') as datee , nvl( a.ships_rel_total,0) as Total_released
    from (
          SELECT l.loc  , sr1.vvalue1 as Week, sr.vvalue2 , to_char(ss.udate, 'YYYY-MM-DD') as up_date ,  count(distinct s.ship_id ) as ships_rel_total
          FROM ship s, loct l,
             ship_num sr1,  ship_num sr, ship_stat ss, ship_stat ss1
          WHERE ......
          Group by l.loc , sr1.vvalue1, sr.vvalue2 , to_char(ss.udate, 'YYYY-MM-DD')
          ) A,
    ( SELECT distinct l.loc  , sr1.vvalue1 as Week, sr.vvalue2 , count(s.ship_id ) as Total_Ships
          FROM ship s, loct l,
              ship_num sr1,  ship_num sr, ship_stat ss, ship_stat ss1
          WHERE ......
          Group by c.loc , c.week , c.vvalue2  ) B
    where a.loc (+) = b.loc
    and a.vvalue2  (+) = b.vvalue2
    order by b.loc, b.week , b.vvalue2,a.up_date; Query 1 Output:
    *OUTPUT*
    LOC         WEEK          VALUE2        TOTAL_SHIPS       DATEE         TOtAL_SHIPS_RELEASED
    AA          111              BB              12                  10-05-12            2
    AA          111              BB              12                  11-05-12            4
    AA          111              CC              2                    14-05-12            1Then I added sum function for total_ships and its not giving me result what I need :(
    Query 2:
    select  b.loc , b.week, b.vvalue2, b.sum_ships, nvl(a.up_date,'None') as datee , nvl( a.ships_rel_total,0) as Total_released
    from (
          SELECT l.loc  , sr1.vvalue1 as Week, sr.vvalue2 , to_char(ss.udate, 'YYYY-MM-DD') as up_date ,  count(distinct s.ship_id ) as ships_rel_total
          FROM ship s, loct l,
             ship_num sr1,  ship_num sr, ship_stat ss, ship_stat ss1
          WHERE ......
          Group by l.loc , sr1.vvalue1, sr.vvalue2 , to_char(ss.udate, 'YYYY-MM-DD')
    ) A,
    ( Select  c.loc, c.week , c.vvalue2 ,  sum(c.total_ships) sum_ships 
    from
        ( SELECT distinct l.loc  , sr1.vvalue1 as Week, sr.vvalue2 , count(s.ship_id ) as Total_Ships
          FROM ship s, loct l,
              ship_num sr1,  ship_num sr, ship_stat ss, ship_stat ss1
          WHERE ......
          Group by l.loc , sr1.vvalue1 , sr.vvalue2  ) C
    Group by c.loc , c.week , c.vvalue2  ) B
    where a.loc (+) = b.loc
    and a.vvalue2  (+) = b.vvalue2
    order by b.loc, b.week , b.vvalue2,a.up_date;  my query is giving me this :(
    Query 2 Output:
    LOC         WEEK          VALUE2        *SUM_SHIPS*       DATEE         TOtAL_SHIPS_RELEASED
    AA          111                BB              26                 10-05-12            2
    AA          111                BB              26                 11-05-12            4
    AA          111                CC              26                 14-05-12            1
    But I need a result like this:
    LOC         WEEK          VALUE2        SUM_SHIPS       DATEE         TOtAL_SHIPS_RELEASED
    AA          111                BB              14              10-05-12            2
    AA          111                BB              14              11-05-12            4
    AA          111                CC              14              14-05-12            1

    Hi,
    It sounds like you have a Fan Trap , where a one-to-many relationship is causing some items to be counted many times.
    The usual solution is to compute the aggregates before doing the one-to-many join. Analytic functions may make this simpler.
    Sorry, I can't show you exactly how to do it without the exact data.
    Post CREATE TABLE and INSERT statements for all tables involved, and also post the results you want from that data (if different from what you've already posted).
    Explain, using specific examples, how you get those results from that data.
    Simplify the problem as much as possible. If the problem only concerns the total_ships column, then only post the data needed to compute total_ships. This includes all the columns involved in the joins and GROUP BY clauses.
    Always say which version of Oracle you're using (e.g., 11.2.0.2.0).
    See the forum FAQ {message:id=9360002}

  • Count function on months column gives wrong result

    Hi,
    I am on OBIEE 11.1.1.7.150120.
    I used the count function on the month column and rather than getting 12 as the answer i get 365. (i used a filter on the year column to restrict it to one year)
    How could this happen?
    Any help would be appreciated.

    I was able to get the answer as 12 on the month column in the Dim_Time using the count distinct.
    The main reason i was trying this is because i have a VALUE column in VIew_A. I am trying to sum the values of these, but when i use the sum function, the output is quite huge and wrong. I dosen't match with the monthly figures.
    For eg:
    Month
    Income Cost
    JAN
    186.96
    FEB
    309.29
    MAR
    246.82
    APR
    247.95
    998.76
    1,462.74
    MAY
    160.27
    645.60
    1,643.84
    JUN
    172.19
    693.61
    927.12
    JUL
    150.27
    605.32
    855.89
    AUG
    133.61
    483.66
    538.20
    789.22
    SEP
    144.56
    412.42
    582.34
    824.84
    OCT
    264.96
    315.66
    364.00
    631.32
    1,067.32
    1,466.22
    NOV
    240.39
    832.10
    968.32
    1,058.73
    1,638.38
    DEC
    215.81
    857.30
    869.31
    24005.34
    But if i use the sum function on the Income/cost column, the value i get is
    C_MONTH
    SUM(INCOME_COST)
    JAN
    5,795.86
    FEB
    8,660.21
    MAR
    7,651.52
    APR
    81,283.62
    MAY
    75,941.13
    JUN
    53,787.67
    JUL
    49,955.96
    AUG
    60,285.39
    SEP
    58,924.80
    OCT
    127,394.01
    NOV
    142,137.76
    DEC
    60,215.18
    This just doesn't work out. I need the answer to be 24005 by using the sum function

  • SUM function issue

    Hi everyone,
    I have a problem with SUM function in SQL query on Oracle 11g database. Maybe you will be able to help me.
    Problem:
    I want to shows summary costs for shipments separately for each service provider and for each month they did the shipments.
    Data is stored in SHIPMENT AND SHIPMENT_COST table as shown below. The problem is that summary function I use sums base costs (marked as B in SHIPMENT_COST table) for each accessorial cost (marked as A in SHIPMENT_COST table). In example for shipment 10005031 we have 4 accessorial costs so it shows 6120 in BASE_COST column. I tried to use distinct in summary but then we have a problem with shipment id 201307133713_0383 which has 3 base costs equal to 221.54 so with distinct it will show 221.54 instead of 221.54x3.
    SHIPMENT table:
    START_TIME               SHIPMENT_GID               SERVPROV_GID
    2013-06-25                    10005031                         T222176
    2013-06-15                    201307133713_0383          T76180
    SHIPMENT_COST table:
    SHIPMENT_GID                        COST                                       COST_TYPE
    10005031                                 1530                                        B
    10005031                                  30.6                                        A
    10005031                                  120                                         A
    10005031                                  400                                         A
    10005031                                  100                                         A
    201307133713_0383                   221.54                                    B
    201307133713_0383                   221.54                                    B
    201307133713_0383                   221.54                                    B
    RESULT table:
    SHIPMENT_START_DATE
    SERVPROV
    BASE_COST
    CLAIM_COST
    06/2013
    T76180
    664.62
    null
    06/2013
    T222176
    6120
    650.6
    Query:
    SELECT DISTINCT TO_CHAR(SH.START_TIME,'MM/YYYY') AS SHIPMENT_START_DATE,
            SH.SERVPROV_GID AS SERVPROV,
            SUM(SHCOST.COST) AS BASE_COST,
            SUM(SHCOST_CLAIM.COST) AS CLAIM_COST
    FROM    SHIPMENT SH,
            SHIPMENT SHC
            LEFT OUTER JOIN SHIPMENT_COST SHCOST ON (SHC.SHIPMENT_GID = SHCOST.SHIPMENT_GID AND SHCOST.COST_TYPE = 'B'),
            SHIPMENT SHC_CLAIM
            LEFT OUTER JOIN SHIPMENT_COST SHCOST_CLAIM ON (SHC_CLAIM.SHIPMENT_GID = SHCOST_CLAIM.SHIPMENT_GID AND SHCOST_CLAIM.COST_TYPE = 'A')
    WHERE 1=1
            AND SHC.SHIPMENT_GID = SH.SHIPMENT_GID
            AND SHC_CLAIM.SHIPMENT_GID = SH.SHIPMENT_GID
            AND    SH.SHIPMENT_GID IN ('10005031','201307133713_0383')
            GROUP BY TO_CHAR(SH.START_TIME,'MM/YYYY'),
            SH.SERVPROV_GID
    Best Regards,
    Łukasz

    with SHIPMENT (START_TIME,SHIPMENT_GID,SERVPROV_GID) as
    select to_date('2013-06-25','yyyy-mm-dd'),'10005031','T222176' from dual union all
    select to_date('2013-06-15','yyyy-mm-dd'),'201307133713_0383','T76180' from dual
    SHIPMENT_COST(SHIPMENT_GID,COST,COST_TYPE)
    as
    select '10005031','1530','B' from dual union all
    select '10005031','30.6','A' from dual union all
    select '10005031','120','A' from dual union all
    select '10005031','400','A' from dual union all
    select '10005031','100','A' from dual union all
    select '201307133713_0383','221.54','B' from dual union all
    select '201307133713_0383','221.54','B' from dual union all
    select '201307133713_0383','221.54','B' from dual
    select *
      from (select to_char(t.START_TIME, 'mm/yyyy'),
                   t.SERVPROV_GID,
                   c.COST,
                   c.COST_TYPE
              from SHIPMENT t
              join SHIPMENT_COST c
                on t.SHIPMENT_GID = c.SHIPMENT_GID)
    pivot(sum(COST) for COST_TYPE in('A' CLAIM_COST,'B' BASE_COST))
    TO_CHAR(T.START_TIME,'MM/YYYY'
    SERVPROV_GID
    CLAIM_COST
    BASE_COST
    06/2013
    T76180
    664.62
    06/2013
    T222176
    650.6
    1530
    Ramin Hashimzade

  • Help with SUM function ??

    Hi,
    I am trying to build a SUM function into the following SELECT statement;
    SELECT   emp_code "EmployeeCode", trn_date "TransactionDate", project "ProjectCode",
    phase_code "PhaseCode", task_code "TaskCode", reg_hrs "RegularHoursAmt", rate_reg "RegularHoursRate", ot_hrs "OvertimeHoursAmt", rate_ot "OvertimeHoursRate"
    Currently when i do the extract to xls I manually compile the "RegularHoursAmt" and "RegularHoursRate" manually and it's quite a task. I'm sure it can be completed in teh SELECT but I'm not clear on how and it's been quite some time since my last foray into SQL. Any assistance appreciated.
    I need to sum "RegularHoursAmt" and "RegularHoursRate"
    per "EmployeeCode"
    by "TransactionDate"
    with unique combo of "ProjectCode", "PhaseCode", "TaskCode"
    Cheers, Peter

    Hi, Peter,
    PJS5 wrote:
    Thanks Frank for the quick response. Ok, here goes;
    The TABLES already exist and I am only pulling the data for the columns in my SELECT statement so no CREATE of INSERT as such.Post CREATE TABLE and INSERT statements so that the people who want to help you can re-create the problem and test their ideas.
    The data is in Oracle 10g 10.1.0.2.0Perfect!
    So you want totals that represent the entire day for a given employee.
    Yes, but rows are by the unique combo per employee of "ProjectCode", "PhaseCode", "TaskCode"So a row of output will represent a distinct combination of employee, day, ProjectCode, PhaseCode and TaskCode, and that one output row may correspond to more than one row of input; is that right?
    eg Tom works on 4 unique "ProjectCode/PhaseCode/TaskCode" efforts on "TransactionDate"What does "effort" mean here? If I could look at some actaul data (or actual fake data; don't post anything like real credit card numbers) and the results you want from that data, perhaps it would be clear.
    One of those unique "ProjectCode/PhaseCode/TaskCode" efforts however has 3 timesheet entries as he has added unique Descriptions of what his efforts were aimed at achieving.
    We are not extracting the Descriptions and thereby want to SUM those 3 timesheet entries into one row.
    Do you also want a total for each employee, over all days? No thanks
    Do you want a grand total for all employees and all days? No thanks
    Do you want the totals on the same output rows as your current reuslts? That would be handy
    If so, use the analytic SUM function. I'm not familiar with this
    Do you want separate rows for the the totals? That could helpPost the exact results you want from a small set of given data. It's fine to describe the results, as you did above, but describe them in addition to (not instead of) actually showing them.
    Does that make my questions easier to follow?It looks good, but without some sample data and the results you want from that data, I can't say for sure.
    Please post CREATE TABLE and INSERT statements (relevant columns only) for a little sample data, so that I (and the others who want to help you) can see exactly what your tables are like, and actually try our solutions. Simplify as much as possible. For example, if the data is actually coming from a multi-table join, but you already know how to join all the tables perfectly, then pretend all the data is in one table, and post CREATE TABLE and INSERT statements for that one table that looks sort of like your current result set. Post just enough data to show what you want to do. Based on what you've said so far, I'm guessing that 10 to 20 rows of raw data, resulting in 3 to 7 rows of output could give a nice example.
    Also, post the exact results you want from the sample data you post. Explain, with specific examples, how you get those results from that data.
    If parts of your desired output are optional (that is, if some parts "would be handy" or "could help") then post a couple of different sets of results from the same data, and explain, something like this:
    "What I'd really love to get for results is" ...
    but, if that makes things really complicated or inefficient, I don't absolutely need ... or ...,
    so I'd settle for these results: ..."
    I know it's a lot of work to post all this information, but it's really necessary. If I could help you without making you do all this, then I would. Unfortunately, I really don't have a good idea of where you're coming from or where you want to go.
    Edited by: Frank Kulash on Oct 19, 2010 8:01 PM

  • Decimal places diferent in BO SUM function than from DB

    Hi,
    I have a column from a Netezza database with 2 decimal places, if I apply a sum() function in BO (report) the decimal places are 4.
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    There is some configuration regarding the database i'm using to set the decimal places in the report level to be the same than in DB?
    Edited: I've been studing the problem and I found using a odbc instead of a jdbc makes all the columns have 2 decimal places, and the sum problem doesn't happen. Now my issue is the division. How is possible that with the exact same values with two decimal positions, in BO and exporting to excel the last decimal place is different in some cases
    Example:
    Lets say A/B with A=13549678065,560000 and B= 21629484348,690000. With Netezza result is 62,6444803173527 and Db2  62,6444803173528
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