Sum of two columns

Hi guys
i need to insert one column in a row with forumla as col1+col2. how can i do that in simple tabular report. My two columns in XML are like this:-
<T_AMT>240.6</T_AMT>
<TAX_AMT>0</TAX_AMT>
Can i use substring function while creating template in word or i need to use substring while writing query...
thanks
Edited by: ObieeUser on 28-May-2010 03:07

Hi Vetsrini
thanks for your reply...
for showing sum of two columns:-
is it possible to do with GUI instead of writing code or doing tweaks in the sql... the main drawback of doing tweaks in sql is after i make changed in sql and then i click on sql builder it doesn't show me the changes which i have done....
Use of Substr/Decode/Case When or other oracle function
another question is like if i need to use substr function in sql can't i do it in SQL builder if yes then how as i have seen function drop down in sql builder but it doesn't show such function?
regards

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Hello Friends,
I have the below 5 tables
1. STUDENT (STUDENT_ID, NAME)
2. DEPARTMENT (DEPT_ID, NAME, CONTACT_PERSON, PHONE)
3. SECTION (SECTION_ID,SNAME,DEPT_ID,Acad_LEVEL,SHIFT,TIME,ROOM)
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5. TUITION_PAYMENT (Seq_No,RECEIPT_NO,STUDENT_ID,DEPT_ID,Acad_Level,SECTION_ID,SEMESTER,Acad_Year,SCHOLARSHIP,PAYMENT_DATE,PAYMENT_AMT,REFERENCE,REMARKS)
I wrote the following query
SELECT T.Seq_No,T.STUDENT_ID,S.NAME As STUDENT_NAME,d.name As DEPT,T.Acad_Level,c.SNAME As SECTION,
T.SEMESTER,T.[Acad_Year],BILL_DATE,GROSS_AMT_DUE,
COALESCE(SUM(T.GROSS_AMT_DUE),0)-COALESCE(SUM(PAY.PAYMENT_AMT),0)- COALESCE(SUM(PAY.SCHOLARSHIP),0) As BALANCE
FROM TUITION_BILL T JOIN STUDENT S ON S.STUDENT_ID=T.STUDENT_ID join DEPARTMENT d on d.DEPT_ID=T.DEPT_ID
join SECTION c on c.SECTION_ID=T.SECTION_ID LEFT JOIN (SELECT DISTINCT STUDENT_ID,COALESCE(SUM(p.PAYMENT_AMT),0) As PAYMENT_AMT,
COALESCE(SUM(P.SCHOLARSHIP),0) As SCHOLARSHIP FROM TUITION_PAYMENT p GROUP BY p.STUDENT_ID) As PAY ON PAY.STUDENT_ID=T.STUDENT_ID
WHERE s.STUDENT_ID='138218' GROUP BY T.Seq_No,T.STUDENT_ID,S.NAME,d.NAME,T.[Acad_Level],c.SNAME,T.SEMESTER,
T.[Acad_Year],BILL_DATE,GROSS_AMT_DUE,PAYMENT_AMT,SCHOLARSHIP
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Seq_No
STUDENT_ID
STUDENT_NAME
DEPT
Acad_Level
SECTION
SEMESTER
Acad_Year
BILL_DATE
GROSS_AMT_DUE
BALANCE
1
138218
Abdirahman Dhuh Gamadid
Agriculture and Veterinary
Year 2
2A
One
2014-2015
1/10/2014
200
0
5638
138218
Abdirahman Dhuh Gamadid
Agriculture and Veterinary
Year 2
2A
Two
2014-2015
3/20/2015
200
0
There are two records in the TUITION_BILL table with different Semesters and bill dates for the specified student_id and there is only one record in the TUITION_PAYMENT table which is the semester one payment record. Semester two payment record
is not recorded yet and I want to display the balance like the following output instead of the above output.
Seq_No
STUDENT_ID
STUDENT_NAME
DEPT
Acad_Level
SECTION
SEMESTER
Acad_Year
BILL_DATE
GROSS_AMT_DUE
BALANCE
1
138218
Abdirahman Dhuh Gamadid
Agriculture and Veterinary
Year 2
2A
One
2014-2015
1/10/2014
200
0
5638
138218
Abdirahman Dhuh Gamadid
Agriculture and Veterinary
Year 2
2A
Two
2014-2015
3/20/2015
200
200
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Please help me in getting the desired result.
Any help would be appreciated.
Thanks in advance,
Mohamoud

Thanks a lot Pituach for your reply; below I posted the script for the database and table creation and inserting sample data into the tables.
CREATE
DATABASE TESTdb
GO
USE TESTdb
CREATE
TABLE [dbo].[STUDENT](
      [STUDENT_ID] [int]
NOT NULL,
      [NAME] [varchar](40)
NULL,
PRIMARY
KEY CLUSTERED
      [STUDENT_ID]
ASC
)WITH
(PAD_INDEX
= OFF,
STATISTICS_NORECOMPUTE
= OFF,
IGNORE_DUP_KEY =
OFF, ALLOW_ROW_LOCKS
= ON,
ALLOW_PAGE_LOCKS =
ON)
ON [PRIMARY]
ON [PRIMARY]
GO
SET
ANSI_PADDING OFF
GO
CREATE
TABLE [dbo].[DEPARTMENT](
      [DEPT_ID] [int]
IDENTITY(1,1)
NOT NULL,
      [NAME] [varchar](30)
NULL,
      [CONTACT_PERSON] [varchar](40)
NULL,
      [PHONE] [int]
NULL,
CONSTRAINT [PK__DEPARTME__512A59AC03317E3D]
PRIMARY KEY
CLUSTERED
      [DEPT_ID]
ASC
)WITH
(PAD_INDEX
= OFF,
STATISTICS_NORECOMPUTE
= OFF,
IGNORE_DUP_KEY =
OFF, ALLOW_ROW_LOCKS
= ON,
ALLOW_PAGE_LOCKS =
ON)
ON [PRIMARY]
ON [PRIMARY]
GO
SET
ANSI_PADDING OFF
GO
CREATE
TABLE [dbo].[SECTION](
      [SECTION_ID] [int]
IDENTITY(1,1)
NOT NULL,
      [SNAME] [varchar](40)
NOT NULL,
      [DEPT_ID] [int]
NOT NULL,
      [Acad_Level] [varchar](30)
NULL,
      [SHIFT] [varchar](20)
NULL,
      [TIME] [varchar](20)
NULL,
      [ROOM] [varchar](20)
NULL,
CONSTRAINT [PK__SECTION__92F8069507020F21]
PRIMARY KEY
CLUSTERED
      [SECTION_ID]
ASC,
      [DEPT_ID]
ASC
)WITH
(PAD_INDEX
= OFF,
STATISTICS_NORECOMPUTE
= OFF,
IGNORE_DUP_KEY =
OFF, ALLOW_ROW_LOCKS
= ON,
ALLOW_PAGE_LOCKS =
ON)
ON [PRIMARY]
ON [PRIMARY]
GO
SET
ANSI_PADDING OFF
GO
CREATE
TABLE [dbo].[TUITION_BILL](
      [Seq_No] [int]
IDENTITY(1,1)
NOT NULL,
      [STUDENT_ID] [int]
NOT NULL,
      [DEPT_ID] [int]
NOT NULL,
      [Acad_Level] [varchar](50)
NOT NULL,
      [SECTION_ID] [int]
NOT NULL,
      [SEMESTER] [varchar](50)
NOT NULL,
      [Acad_Year] [varchar](50)
NOT NULL,
      [BILL_DATE] [date]
NULL,
      [GROSS_AMT_DUE] [decimal](18, 2)
NULL,
CONSTRAINT [PK_TUITION_BILL]
PRIMARY KEY
CLUSTERED
      [STUDENT_ID]
ASC,
      [DEPT_ID]
ASC,
      [Acad_Level]
ASC,
      [SEMESTER]
ASC,
      [Acad_Year]
ASC
)WITH
(PAD_INDEX
= OFF,
STATISTICS_NORECOMPUTE
= OFF,
IGNORE_DUP_KEY =
OFF, ALLOW_ROW_LOCKS
= ON,
ALLOW_PAGE_LOCKS =
ON)
ON [PRIMARY]
ON [PRIMARY]
GO
SET
ANSI_PADDING OFF
GO
CREATE
TABLE [dbo].[TUITION_PAYMENT](
      [Seq_No] [int]
IDENTITY(1,1)
NOT NULL,
      [RECEIPT_NO] [int]
NOT NULL,
      [STUDENT_ID] [int]
NOT NULL,
      [DEPT_ID] [int]
NOT NULL,
      [Acad_Level] [varchar](50)
NOT NULL,
      [SECTION_ID] [int]
NOT NULL,
      [SEMESTER] [varchar](50)
NOT NULL,
      [Acad_Year] [varchar](50)
NOT NULL,
      [SCHOLARSHIP] [decimal](18, 2)
NULL,
      [PAYMENT_DATE] [date]
NULL,
      [PAYMENT_AMT] [decimal](18, 2)
NULL,
      [REFERENCE] [varchar](50)
NULL,
      [REMARKS] [varchar](max)
NULL,
CONSTRAINT [PK_TUITION_PAYMENT]
PRIMARY KEY
CLUSTERED
      [Seq_No]
ASC
)WITH
(PAD_INDEX
= OFF,
STATISTICS_NORECOMPUTE
= OFF,
IGNORE_DUP_KEY =
OFF, ALLOW_ROW_LOCKS
= ON,
ALLOW_PAGE_LOCKS =
ON)
ON [PRIMARY]
ON [PRIMARY]
GO
SET
ANSI_PADDING OFF
GO
USE TESTdb
INSERT
INTO STUDENT(STUDENT_ID,NAME)VALUES(138218,'Abdirahman
Dhuh Gamadid')
INSERT
INTO DEPARTMENT(NAME,CONTACT_PERSON,PHONE)VALUES('Agriculture
and Veterinary','Mohamoud Abdilahi','065')
INSERT
INTO SECTION(SNAME,DEPT_ID,Acad_Level,SHIFT,[TIME],ROOM)VALUES('2A',1,'Year
2','Morning','8:00-10:00','Room 1')
INSERT
INTO TUITION_BILL(STUDENT_ID,DEPT_ID,Acad_Level,SECTION_ID,SEMESTER,Acad_Year,BILL_DATE,GROSS_AMT_DUE)
VALUES(138218,1,'Year
2',1,'One','2014-2015','2014-09-10',200.00)
INSERT
INTO TUITION_BILL(STUDENT_ID,DEPT_ID,Acad_Level,SECTION_ID,SEMESTER,Acad_Year,BILL_DATE,GROSS_AMT_DUE)
VALUES(138218,1,'Year
2',1,'Two','2014-2015','2015-01-10',200.00)
INSERT
INTO TUITION_PAYMENT(RECEIPT_NO,STUDENT_ID,DEPT_ID,Acad_Level,SECTION_ID,SEMESTER,Acad_Year,SCHOLARSHIP,
PAYMENT_DATE,PAYMENT_AMT,REFERENCE,REMARKS)VALUES(1,138218,1,'Year
2',1,'One','2014-2015',0.00,'2014-10-10',200.00,'N','N')

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Hi All,
I have developed an ALV Report which will display Invoices and other details.
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Regards
Pavan

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When the GET events are processed, the logical database automatically writes hexadecimal zeros in all the fields of a node when it returns to an upper-level node in the hierarchy. Since the HEADER normally contains sort fields for all field groups, these hexadecimal zeros in the HEADER serve as a type of hierarchy key: The more zeros there are, the further up in the control level hierarchy you go.
The SORT statement sorts the extract dataset in accordance with the defined field sequence in field group HEADER. The addition BY ... sets a new sort key.
Each must be either a field of field group HEADER or a field group that consists only of fields of the field group HEADER. You can use the additions ASCENDING and DESCENDING to determine whether the fields are sorted in ascending (default) or descending order.
Fields containing X'00' in the logical databases are always displayed before all other values during a SORT.
Processing of an extract dataset always takes places within a LOOP. The contents of the extract dataset field are placed in program fields with the same names.
The group change always involves the fields of the HEADER. Single record processing for extract datasets is performed using language element AT ( = field group).
CNT() is not a statement, but instead a field that is automatically create d and filled when is a non-numeric field from field group HEADER and is part of the sort key. At the end of the group, CNT() contains the number of different values that the field recorded in this group level.
SUM() is not a statement, but instead a field that is automatically created and filled when is a numeric field of an extract dataset. At the end of the group, SUM() contains the control total of field .
*** and CNT are only available at the end of the group level or at AT LAST.
Single record processing for extract datasets AT WITH is only performed when field group is immediately followed by field group in the temporary dataset.
Loops over an extract dataset cannot be nested. However, several contiguous loops are permitted.
The sequence of the control level changes within the LOOP must correspond to the sort sequence.
Totals can only be calculated within control footer processing.
Extracts allow only appends (EXTRACT), sorting (SORT) and sequential processing (LOOP).
Once a SORT or LOOP has occurred, the intermediate dataset is frozen and cannot be expanded with EXTRACT. Operations that insert into or delete from EXTRACT datasets are not supported.
Extracts allow for several record types (FIELD-GROUPS) with fields that can be set dynamically (INSERT is not a declarative statement!). Internal tables have a single, statically-defined line type.
Internal tables use the sequence of table fields according to the declaration for the hierarchy of the control leve l. The control level structure for internal tables is therefore static, and is independent of which criteria were used to sort the internal table.
Extracts do not depend on the field sequence for control level processing: a re-sort or a completely different control level process can take place. The control level structure for extract datasets is therefore dynamic. It corresponds exactly to the sort key of the extract dataset. The sort key is the sequence of fields from the field group HEADER, and is used to sort the extract dataset.
Extracts rely on the compiler to determine which combinations of group levels and a cumulating field the control level totals desire. The desired control level totals are determined by the processing of LOOP ... ENDLOOP blocks. Internal tables build the control level total with the SUM statement.
This procedure leads to high resource depletion for totaling control levels in internal tables.
Regards,
Chandru

How to add two columns in OBIEE report?

Hi to All,
Can anyone tell me how to add two columns in OBIEE report and get that result in a new column?
Thanks in Advance,
Thenmozhi

Assume you already have two columns SalesAmt1 and SalesAmt2, and you want to derive 3rd column say SalesAmt3 which would be the sum of SalesAmt1 and SalesAmt2.
For this, as I mentioned above pull SalesAmt1 and SalesAmt2 columns in Report. Now pull another column (say SalesAmt1) and open the fx. Clear the contents of fx. Now locate the columns button in the bottom of the fx. From Here, first select SalesAmt1 and + sign and the select SalesAmt2.
Now in this new column, the fx should look like SalesAmt1 + SalesAmt2.
Let me know if you are looking for something else.
Thanks

How to find the sum of a column

I need to find the sum of a column and use it in a different column. The following is the example.
Column names: Feedback(Good, Avg, Poor), Count(no of good, no of avg, no of poor) and %age(Feedback/sum(feedback))
I want to find the sum in Java class and also calculate the last column in java class.
Please tell me some way to do it.

oh.. ok ..thanks for letting me know.. i will formulate the question in a proper way:
This is what my UI should look like:
Rating Count Percent
Excellent 2 20
Good 6 60
Poor 1 10
Bad 1 10
Now i have the following columns in the data base:
Meaning and feedback_rating.
So the following SQL Query:
SELECT hrl.meaning rating,
sum(decode(bcpi.feedback_rating, null, 0, 1)) counted
from cmp_cwb_person_info bcpi ,
hr_lookups hrl
group by hrl.meaning
will give me the result as
rating counted
Excellent 2
Good 6
Poor 1
Bad 1
Now I want a third column as percentage : Earlier we were doing this calculation in the sql query itself, so the query was like
SELECT hrl.meaning rating,
sum(decode(bcpi.feedback_rating, null, 0, 1)) counted,
sum(decode(bcpi.feedback_rating, null, 0, 1))/(max (select count (*) from cmp_cwb_person_info bcpi ,
hr_lookups hrl )) percent
from cmp_cwb_person_info bcpi ,
hr_lookups hrl
group by hrl.meaning
Hence the third column (percent) was calculated in the sql query itself.
But now i feel that the performance of the query could be improved if we get the first two columns from the database and the calculate the third column programatically in the java code.
So this is what I want to know. How can i do that?

How can I sum every other column in the same row?

I have, for each employee, two columns: Planned and Worked.
I would like to sum the values in each Planned column. There are 25 employees, each with their own Planned and Worked columns, on the same row.
How can I do a SUM of every other column, starting with Planned?
Thank you.

Thank you, Yellowbox!
The exact formula didn't work; however, it gave me a precise path to follow and come up with this: =SUMIF(E2:BB2,"=Planned",E3:BB3)
Week
Ending Date
Planned Subtotal
Worked Subtotal
Employee1
Employee2
Employee3
Planned
Worked
Planned
Worked
Planned
Worked
1
01/04/2014
120
40
38
40
44
40
50
2
01/11/2014
If not for your starting point, I'd have wasted many more hours on this.
Thanks again!
BB

How to get the difference between two columns in a column group

Hi All,
My first time here and really new to programming. I would like to get the difference between 2 columns that are inside
a column group.
Here is my sample table below: The Column Group is PeriodNumber and can only choose 2. like 1 and 2.. I would like to have a third row which will simply calculate the difference between the amounts in PeriodNumber 1 and 2.
PeriodNumber
Account 1 2
1) Cash 10,000 15,000
2) Receivables 12,000 11,500
3) Equipment 5,000 5,500
Total Assets 27,000 32,000

Hi yabgestopa,
From your description, you want to get the difference between two columns in a column group. After testing it in my environment, we can use custom code to achieve your requirement. For more details, you can refer to the following steps:
Copy the custom code below and paste it to your report. (Right-click report>Report Properties>Code)
Dim Shared Num1 As Integer
Dim shared Num2 As Integer
Public Function GetAmount(Amount as Integer, Type as String)
If Type = "1" Then
Num1=Amount
Else
Num2=Amount
End If
Return Amount
End Function
Public Function GetDif()
Return Num1-Num2
End function
Right-click the second column to insert a third column with Outside Group-Right.
Then use the expressions below in the matrix.
=Code.GetAmount(Fields!Amount.Value,Fields!PeriodNumber.Value)
=code.GetAmount(Sum(Fields!Amount.Value),Fields!PeriodNumber.Value)
=Code.GetDif()
The report looks like below.
If you have any questions, please feel free to ask.
Thanks,
Katherine Xiong
Katherine Xiong
TechNet Community Support

Find the difference between two columns in an ssrs matrix ? MSCRM

Hi All,
I am working in reporting part of our project (On-line MSCRM 2013) & in reporting services.
I am trying to create report using fetch xml based. Below is the snap what we required the result.
Kindly help me, how to get the difference in both column. (Its a matrix table where year is grouped).
We need difference between both year Like (Plan Revenue of 2013 & Plan Revenue of 2014 difference in Plan Revenue Diff section) and same for Actual
Revenue.
https://social.microsoft.com/Forums/en-US/054d5ca4-0d38-4dc6-84a8-88866cc228fe/find-the-difference-between-two-columns-in-an-ssrs-matrix-mscrm?forum=crmdevelopment
Thanks,
Mohammad Sharique

Hi Bro,
I used parametrized option for year and done the report,Currently we are getting values in Difference column now i want to show
that value in percentage. How can we show the percentage based on that value. Means i want to show the Difference in Percentage.
Kindly help me i tried but getting some issue. Below i am mentioning the code and snap with result.
Below expression using to showing Plan Revenue in Percentage for year.
=
Sum(IIF(Fields!new_year.Value =Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
- Sum(IIF(Fields!new_year.Value =Parameters!EndYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
/IIF(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))>0,
(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0))))
,1)
)*100))
Result issue is as below in snap with highlighted in red colour.
Kindly help me on this issue also :)

Qualified list item based on two columns

- fact table inludes following columns
key1
key2
measure1
In segment designer, update counts:
the query must counts two columns "key1 and key2" that key1 and key2 together must be distinct.

Here you go:
SQL> WITH bill AS
2 (
3          SELECT 1000 AS billno, 101 AS advertiserid, 102 AS agencyid, 5000 AS total_value FROM DUAL UNION ALL
4          SELECT 1001, 101, 103, 5000 FROM DUAL UNION ALL
5          SELECT 1002, 101, 102, 1000 FROM DUAL
6 ), account AS
7 (
8          SELECT 101 AS account1_id, 102 AS account2_id, 'John' AS name, 50 AS empid FROM DUAL UNION ALL
9          SELECT 101, 103, 'James', 40 FROM DUAL UNION ALL
10          SELECT 101, 105, 'Joe', 60 FROM DUAL
11 )
12 /* End Sample Data */
13 SELECT a.name
14       , a.empid
15       , a.account1_id
16       , a.account2_id
17       , SUM(b.total_value)
18 FROM   account a
19 JOIN   bill    b ON a.account1_id = b.advertiserid
20                   AND a.account2_id = b.agencyid
21 GROUP BY a.name
22         , a.empid
23         , a.account1_id
24         , a.account2_id
25 ;
NAME                 EMPID          ACCOUNT1_ID          ACCOUNT2_ID   SUM(B.TOTAL_VALUE)
John                    50                  101                  102                 6000
James                   40                  101                  103                 5000

Sum of two columns

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