Switch/case limit

I am encountering a very strange problem.. after 39 cases in
my switch case statement the 40th case does not get executed.. the
code is in my go button and there are like 1000+ lines of code in
there.. if I replace my 39th case with the 40th it works but it
doesn't execute anything after that!! is there a limit on the
number of case statements we can use in action script??? I am
really confused with this problem...

no, but there is a byte limit on a single code block ... I
can't remember the number off hand. So that's probably what's going
on there, you might want to consider a looping test or using an
array.

Similar Messages

Troubles with a switch case and final expression?

Been developing C/C++ for quite a while and still new to Java, and struggling with even the simplest things ... Why isnt this switch/case working?
have some final "variable" declared in a class contating "constants" like this ...
public class CConstants {
public static final int MY_CONSTANT1 = 0x01;
}Now, If I'm trying to use "MY_CONSTANT1" in a case stateent, I get the error "constant expression required" ?
CConstants c = new CConstants();
switch(condition){
case c.MY_CONSTANT1: { //do some work; break; }
default: { }
}I thought this would be a nice idea to increase readability as there will be a long switch/case statement.
Please help!
Edited by: George.F on Sep 3, 2009 3:07 AM
Edited by: George.F on Sep 3, 2009 3:08 AM

You should refer to that constant as CConstants.MY_CONSTANT1.
Refering to it via a reference to CConstants is possible but strongly discouraged (infact I'd make CConstants non-instantiable by adding a private constructor).
Other than that your code should work.
Could you post a SSCCE that demonstrates your problem.

I would like to know how can i compare a switch case 1 and case 2 in C# is it possible to do that? obs i am a begginer :)

i would like to know how can i compare a switch case 1 and case 2 in C# is it possible to do that? obs i am a begginer :) I tried to do it with search and sort but it did not go well

let me give you an example if you add a word case 1( lagg ord) how can i compare that word with case 2 words ( in case 2 already exist 5 words)
here is the my program
using System;
namespace ConsoleApplication1
class Program
static void Main(string[] args)
//Meny
Console.WriteLine("\n HÄNGA GUBBE\n");
Console.WriteLine(" 1) Lägg till ord");
Console.WriteLine(" 2) Lista alla ord");
Console.WriteLine(" 3) Spela");
Console.WriteLine(" 4) Avsluta");
bool utgång = false;
do
int Valet;
Console.Write("\n\tVälj 1-4: \n ");
try
Valet = int.Parse(Console.ReadLine());
catch (Exception)
Console.WriteLine("Du skriver fel character!\n" +
"\nSkriv bara mellan 1 och 4");
continue;
switch (Valet)
case 1:
Console.WriteLine("\n lägg ett till ord! ");
var input = Console.ReadLine();
break;
case 2:
Console.WriteLine("\n Lista med alla ord :\n");
string[] array = { " Lev", " Skratta", " Gledje", " Gråt", " Njut" };
Array.Sort<string>(array);
foreach (var c in array)
Console.WriteLine(c);
Console.WriteLine("\n");
break;
case 3:
string guesses, bokstäver;
Console.Write("\n Hur många fel får man ha? ");
guesses = (Console.ReadLine());
Console.WriteLine(" Utmärkt, då spelar vi!\n");
Console.WriteLine(" Felgisningar :" + "0/" + guesses);
Console.Write(" Gissade bokstäver ");
bokstäver = (Console.ReadLine());
Console.WriteLine("Aktuellt ord");
Console.Write("Gissa bokstav : " + bokstäver + " \n");
break;
case 4:
Console.WriteLine("\n HEJ DÅ! \n");
Console.Beep();
utgång = true;
break;
//avbryter while loopen, avslutar spelet
} while (!utgång);

Switch/Case: How to test byte values in hex format

OK, this may be a silly question, but being new to Java, I can't seem to get this to work.
I have a byte value that I want to test in a switch/case statement. The value was assigned to the byte in hexadecimal format. However, testing only works if I use the decimal value of the byte!
What's even stranger: It does work in a simple if/else statement. In my debugging attempts, I discovered this using the following code:
//*temporary debug routine
memoryCells[0] = (byte) 0x86; //LDA
if(memoryCells[0] == (byte) 0x86)
    System.err.println("byte recognized as hexadecimal!");
else
    if(memoryCells[0] == -122)
        System.err.println("byte recognized as decimal!"); So, this works in an ordinary if/else statement, but why doesn't it also work in the complex switch/case statement? Snippet below:
       switch (currentOpcode)
            case (byte) 0x86:
                //*LDA immediate (2 bytes, 2 cycles)
                registerA = b;
                currentOpcode = 0x00;
                cycleCounter = 0;
            break;
        }Thanks in advance for any suggestions...

    public static void main(String[] args) throws Exception {
     byte test = (byte)0x86;
     switch(test)
     case (byte)0x86:
              System.out.println("Success");
          break;
     default:
              System.out.println("ooops");
    }This works for me.
~Tim

Problems with a result in a switch/case control statement

I am having troubles with a switch/case statement in which I am trying to get a result returned from different operators. The problem is that the result always returns 0 no matter what I put in the driver class.
The class where the result needs to be returned looks like this:
public class Calculator
     private int num1;
     private int num2;
     private char operator;
     private int result;
     public Calculator(int num1, char operator, int num2)
          this.num1 = num1;
          this.operator = operator;
          this.num2 = num2;
     } // end constructor
     public int getNum1()
          return num1;
     public char getOperator()
          return operator;
     public int getNum2()
          return num2;
     public int getResult()
          return result;
     public int calculate()
          switch(operator)
               case '+':
                    int result = num1 + num2;
                    break;
               } // end case '+'
               case '-':
                    int result = num1 - num2;
                    break;
               } // end case '-'
               case '*':
                    int result = num1 * num2;
                    break;
               } // end case '*'
               case '/':
                    int result = num1 / num2;
                    break;
               } // end case '/'
               case '%':
                    int result = num1 % num2;
                    break;
               } // end case '%'
          } // end switch
          return result;
     public String toString()
          String message = (num1) + " " + (operator)
                              + " " + (num2) + " " + "=" + " " + result + "\n";
          return message;
} // end class
The driver class looks like this:
import javax.swing.JOptionPane;
import java.lang.StringBuffer;
public class CalculatorApp
     public static void main (String[] args) // begin main
          String choice = "";
          while (!(choice.equalsIgnoreCase("x"))) // begin while loop
               String number1 = JOptionPane.showInputDialog(
                              "Enter a positive integer: ");
               String operatorInput = JOptionPane.showInputDialog(
                              "Enter operator (+, -, *, /, %): ");
               String number2 = JOptionPane.showInputDialog(
                              "Enter another positive integer: ");
               int num1;
               char operator;
               int num2;
               num1 = Integer.parseInt(number1);
               operator = operatorInput.charAt(0);
               num2 = Integer.parseInt(number2);
               Calculator calculator = new Calculator(num1, operator, num2);
               String message = calculator.toString() + "\n"
                                   + "Press Enter to conitnue or 'x' to exit.";
               choice = JOptionPane.showInputDialog(message);
          } // end while loop
          System.exit(0);
     } // end main
any help would be wonderful! I don't know why the result returned is always 0 but it is. Thanks!
dragwit

The previous poster is correct. You never call the calculate method. If you don't call it, no one's going to call if for you. This stuff doesn't work by magic. I think you've misunderstood your prof's intent in this regard.
However, it still won't work with the changes previously suggested, because declaring an int result in the calculate method will hide the instance field of the same name, which is what your getResult() method retrieves. Don't delare result at all in your calculate method.
That said, it would be architecturally a lot better if the calculate method returned the result rather than storing it back into the instance.

Break statement not working in switch case

Hi,
I've run into this problem multiple times and have looked up the syntax for a switch statement. The problem with the code below is that when it goes into the first case, it executes the break statement but still executes the next case instead of breaking out of the switch case. Can anyone see whats going wrong?
try
            switch (columnProps.getCellType())
                 case (ExcelConstants.CELL_TYPE_STRING):
                     excelCell.setCellValue(iterator.getCurrentColumnStringValue());
                     break;
                 case (ExcelConstants.CELL_TYPE_NUMERIC):
                     excelCell.setCellValue(iterator.getCurrentColumnIntValue());
                     break;
catch (Exception e)
System.out.println(e.toString()):


it executes the break statement but
still executes the next case instead of breaking out
of the switch case. Can anyone see whats going wrong?You can if you put in traces (print statements) in proper places. This will allow you to exactly follow the switch behaviour.

Help with Switch-Case Statement

How do you get this in a switch-case statement or work with it?
          if (age < 70) {
                    JOptionPane.showMessageDialog(null, "People that are below the 70s are nothing special.");
          else if (age > 69 && age < 80) {
                    JOptionPane.showMessageDialog(null, "People that are in their 70s are called septuagenarian.");
          else if (age > 79 && age < 90) {
                    JOptionPane.showMessageDialog(null, "People that are in their 80s are called octogenarian.");
          else if (age > 89 && age < 100) {
                    JOptionPane.showMessageDialog(null, "People that are in their 90s are called nonagenarian.");
          else (age > 99 && age < 110) {
                    JOptionPane.showMessageDialog(null, "People that are in their 100s are called centenarian.");
               }Thanks~

As per Java Specification, swtich case expects an integer and boolean cannot be used as param for switch.
In your case switch can be used like this.
int index = age /10;
switch(index) {
case 1:
case 2:
case 3:
case 4:
case 5:
case 6:
Your First case
break;
case 7:
your second case
break;
case 8:
third case
break;
case 9:
fourth case
break;
default:
fifth case
break;
Take note of the break statements. Its very important. But I wont prefer in this case. Code looks awkward and is not so meaningful.....

DoGet method is called 2 times when a switch-case statement is used

Hello all,
I have a servlet that, when run from browser, runs the doGet method 2 times.
I have a switch case statement within the servlet and when I comment out this servlet, it runs 1 time as expected.
Here is the code:
public class RSSServlet extends HttpServlet {
    /** Processes requests for both HTTP <code>GET</code> and <code>POST</code> methods.
     * @param request servlet request
     * @param response servlet response
    protected void processRequest(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
        System.out.println("CALLED SERVLET");
        response.setContentType("text/xml;charset=UTF-8");
        PrintWriter out      = response.getWriter();
        DBQueriesRSS queries = new DBQueriesRSS();
        String queryType     = request.getParameter("queryType");
        String strCount      = request.getParameter("count");
        int count            = (strCount != null && !strCount.equalsIgnoreCase("null") && strCount.length() > 0) ?
            Integer.parseInt(strCount) : 25;
         if(queryType != null && !queryType.equalsIgnoreCase("null") && queryType.length() > 0) {
            System.out.println("IN IF STATEMENT");
            switch(Integer.parseInt(queryType)) {
                case 1 : out.println(queries.getDefault(count));System.out.println("1");       break;
                case 11: out.println(queries.getDefault(count));System.out.println("11");       break;
                case 21: out.println(queries.getTopDaily(count));System.out.println("21");      break;
                case 22: out.println(queries.getTopWeekly(count));System.out.println("22");     break;
                case 23: out.println(queries.getTopMonthly(count));System.out.println("23");    break;
                case 24: out.println(queries.getTopYearly(count));System.out.println("24");     break;
                case 31: out.println(queries.getTopNDailyBW(count));System.out.println("31");   break;
                case 32: out.println(queries.getTopNWeeklyBW(count));System.out.println("32"); break;
                case 33: out.println(queries.getTopNMonthlyBW(count));System.out.println("33"); break;
                case 34: out.println(queries.getTopNYearlyBW(count));System.out.println("34"); break;
                default: out.println(queries.getTopWeekly(25));System.out.println("default");    break;
            System.out.println("OUT OF SWITCH");
        System.out.println("OUT OF IF");
        out.close();
    // <editor-fold defaultstate="collapsed" desc="HttpServlet methods. Click on the + sign on the left to edit the code.">
    /** Handles the HTTP <code>GET</code> method.
     * @param request servlet request
     * @param response servlet response
    protected void doGet(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
        processRequest(request, response);
    /** Handles the HTTP <code>POST</code> method.
     * @param request servlet request
     * @param response servlet response
    protected void doPost(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {
       processRequest(request, response);
    /** Returns a short description of the servlet.
    public String getServletInfo() {
        return "Short description";
    // </editor-fold>
} The results from running this servlet are:
http://localhost/proxy/RSSServlet??queryType=34&count=66
CALLED SERVLET
IN IF STATEMENT
34
OUT OF SWITCH
OUT OF IF
CALLED SERVLET
IN IF STATEMENT
34
OUT OF SWITCH
OUT OF IFAnyone see anything obvious?
TIA!

in your case you want 'count' to be a class attribute rather than a local variable. But yes, incrementing it each time that the method is called will serve your purpose.

Regular expression in a switch case

Hey guys,
I have a string "52x + 60" and i want to extract 52x and 60 using regular expressions and a switch case
Is this the right way of doing it?
var equation:String = "32x + 5"
var numberExract:RegExp = /\d+/
var xExtract:RegExp = /d+/x/
for(var i:Number=0; i<equation.length; i++)
                    switch(equation.charAt(i))
                              case numberExtract.exec(equation):
                              trace("number");
               break;
               case xExtract.exec(equation):
               trace("x");
               break;
Because it's not tracing anything when i try

Here is a quick and dirty approach - can be customized, optimized and more elegant expressions used:
// equation
var string:String = "x^2 + 5x + 5 - x7 + 8 / 4";
// value replacing xs
var value:Number = 60;
// replace xs with value
// if x comes after digit
string = string.replace(/(?<=\d)x/g, String("*" + value));
// if x comes before digit
string = string.replace(/x(?=\d)/g, String(value + "*"));
// all other xs
string = string.replace(/x/g, String(value));
// remove spaces
string = string.replace(/\s/g, "");
// get pairs with first level math
var pattern:RegExp = /(\d+[\*\^\/]\d+)|\D|\d+/g;
var result:Number = stringToMath(string.match(pattern));
trace("result", result);
function stringToMath(match:Array):Number
    // digits surrounding operator
    var pattern:RegExp = /\d+\D\d+/;
    for (var i:int = 0; i < match.length; i++)
        if (match[i].match(pattern))
            match[i] = String(calculate(match[i]));
    trace("loop result", match);
    return calculteSum(match);
* Calculates sums
* @param    array
* @return
function calculteSum(array:Array):Number
    var result:Number = array[0];
    for (var i:int = 1; i < array.length - 1; i++)
        if (array[i] == "+")
            result += array[i + 1];
        else if (array[i] == "-")
            result -= array[i + 1];
    return result;
* First level math
* @param    string
* @return
function calculate(string:String):Number
    var operator:RegExp = /[\+\*\/\^\-]/g;
    var digits:Array = string.match(/\d+/g);
    var num:Number = 0;
    if (digits && string.match(operator) && digits.length > 1)
        switch (string.match(operator)[0])
            case "*":
                num = digits[0] * digits[1];
                break;
            case "/":
                num = digits[0] / digits[1];
                break;
            case "+":
                num = digits[0] + digits[1];
                break;
            case "-":
                num = digits[0] - digits[1];
                break;
            case "^":
                num = Math.pow(digits[0], digits[1]);
                break;
    return num;

Can I test (junit) default case of switch-case statement ?

Hi,
I have a class which has switch-case statements and I am trying to junit test with 100% coverage. My switch-case workes based on enum values.
say my enum values are 1, 2.
switch(getEnumValues) {
case 1:
return "some value";
case 2:
return "some value";
default:
throw new UnsupportedOperationException("No such enum value supported.");
I have test case to test the case 1 and 2 but I am not able to test default case. Can anyone please let me know how can I right a junit test case for default case.
Edited by: TUIJAVADEV on Nov 4, 2008 4:15 PM

yawmark wrote:
TUIJAVADEV wrote:
I have test case to test the case 1 and 2 but I am not able to test default case. Can anyone please let me know how can I right a junit test case for default case.If your enum values are ONE and TWO, and you have cases for both, then there is no "default case". There is nothing to test.
~If I'm reading the OP correctly, they're 1 and 2, not ONE and TWO. That is, not values of a Java enum.
If this is the case, then the easiest way to test the default case is to break the swtich out into a separate, package-accessible method that takes and arg and passes that onto the switch. (There may be variations on this, depending on how your code is structured.)
However, in a similar vein to what the others are saying, if you already know that you'll only ever have 1 and 2 by the time you get to the switch (maybe because the value comes from an argument to the enclosing method, and you've already unit tested that it appropriately throws an IllegalArgumentException when other values are passed, then there's no need to test the default.
Finally, though if it is ints 1 and 2, rather than a true enum, why not switch to an enum?

BPEL-Instanz dies silent if switch case is true boolean

Hello,
it is very curios. I have the following switch case:
xp20:compare('string1', 'string2') = 0
or
string(xp20:compare('string1', 'string2')) = '0'
The validation is ok, and the compiler compiles with 0 errors / 0 warnings.
If I try to invoke the process, the instance dies silent.
If i write 'string1' = 'string' the behavior is as expected and the instance is running.
What's the reason
I am using the last stable release version.
Best regards
Harald
Message was edited by:
user570114
Message was edited by:
user570114

i just tested your case in 10.1.3.x, it works fine for me. i can see "'two strings do not match" in output variable as expected. can you please copy and past your entire switch block.
here is my test case ( i took the Switch.bpel sample under references directory):
<switch>
<case condition="xp20:compare('string1', 'string2') = 0">
<assign>
<copy>
<from expression="'Value is greater than zero'"/>
<to variable="output" part="payload" query="/tns:resultMsg/tns:valueResult"/>
</copy>
</assign>
</case>
<otherwise>
<assign>
<copy>
<from expression="'two strings do not match'"/>
<to variable="output" part="payload" query="/tns:resultMsg/tns:valueResult"/>
</copy>
</assign>
</otherwise>
</switch>

OSB - XQuery - Sample Switch Case

Hi,
Can some one pls give me a sample XQ, with Switch Case statement in it, which [Syntax] works in OSB.
Regards,
Kaleem...

I am really afraid that OSB 11g supports XQuery 1.0
http://download.oracle.com/docs/cd/E21764_01/doc.1111/e15867/xquery.htm
while the switch statement is introduced only in XQuery 1.1
http://www.w3.org/TR/2009/WD-xquery-11-20091215/#id-switch
for the time being, you will have to resort to a cascade of if - then - else :o(

How can i subtract two numeric numeric numbers from two switch cases ?

I have two switch cases in my labView program. I can see them individually on front panel but i need to subtract them and see the result on front panel.
Can someone please help me out...
I am trying to display (Result1 - Result 2) on my front panel. Result1 and Result2 will change with time.
Regards,
Awais
Attachments:
play4.vi ‏122 KB

Move result 1 and result 2 out of the case structures and subract them.
Right now result 1 or result 2 only get written to if its respective comparison is true. What do you want to do with the math if either comparison is false? You haven't defined your problem clearly enough.

Switch case list UI

Hi!
For pedagocial and c-like reasons i'd like there to be a "Case-unbundle", which would be very nice if you're only calling sub-vi's in a case e.g.
Is there any way to create such a thing?
Instead of the Case-square i want it to be a "Unbundle by name" where i connect each output to my sub-vi's (like a multiplexer) and the appropriate one is called.
Any ideas?
/Y
LabVIEW 8.2 - 2014
"Only dead fish swim downstream" - "My life for Kudos!" - "Dumb people repeat old mistakes - smart ones create new ones."
G# - Free award winning reference based OOP for LV

Well, nice asumptions, but i have another one:
LabVIEW has a case structure where only one single case is visible at a time. This is a huge difference to C-based languages where a switch-case displayes every case at the same time in a "list".
I think the question from the OP is: "Is it possible to display a case-structure in LabVIEW 'flattened' so that every case is visible at the same time?"
And to answer this question: No it is currently not possible, was never possible and hopefully will never be. But you can create a "report" using the print-function and this can automatically create screenshots of each case and display them next to each other.....
just my 2cents
Norbert
CEO: What exactly is stopping us from doing this?
Expert: Geometry
Marketing Manager: Just ignore it.

Map Vs Switch Case

I am having an Enum where I have two types of implementation to retreive the enum based on input parameter with getJobFrequency() :
1st implementation of getJobFrequency() with Switch case:
public enum JobFrequency {
     Daily(1),Weekly(2),Monthly(3), Yearly(4);
     private int value;
     private JobFrequency(intvalue) {
          this.value= value;
     public int getValue(){
          return value;
     public static JobFrequency getJobFrequency(int frequencyId){
          switch(frequencyId){
          case 1:
               return JobFrequency.Daily;
          case 2:
               return JobFrequency.Weekly;
          case 3:
               return JobFrequency.Monthly;
          case 4:
               return JobFrequency.Yearly;
          default:
               return null;
2nd implementation of getJobFrequency() with MAP:
public enum JobFrequency {
     Daily(1),Weekly(2),Monthly(3), Yearly(4);
     private int value;
private static final Map<Integer,JobFrequency > lookup
= new HashMap<Integer,JobFrequency >();
static {
for(JobFrequency s : EnumSet.allOf(JobFrequency .class))
lookup.put(s.getValue(), s);
     private JobFrequency(intvalue) {
          this.value= value;
     public int getValue(){
          return value;
     public static JobFrequency getJobFrequency(int frequencyId){
          return lookup.get(frequencyId);
Let me know which one is correct to use and why. Thanks a lot for the input

They are both correct because they both work.
Any other type of answer for which is "better" depends on the person and the situation. If there are only a few values I'd use the switch statement. If there are lots of values or they can be dynamic, I'd use the map. But I would also dig a little deeper and see if that "frequencyId" cannot be removed and to just use the enum values everywhere.
BTW: use \ tags to format your code.

Switch/case limit

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