Tables with differing numbers of columns in subsequent rows

I'm trying to create a table that has say 3 columns in row one, 2 columns in row two, 5 columns in row 5. I've done it so far by merging cells and splitting them and then asking it to distribute columns evenly but the columns are not distributed evenly.
The column width button is greyed out so I can't set the width manually and so my table looks really unprofessional.
Is there a better way of creating such a table and getting equally distributed columns?
Many thanks
sekentious

an example of merging cells is here
[http://www.crionics.com/products/opensource/faq/swing_ex/JTableExamples4.html]
scroll down to 'Multi-Span Cell'
run the program, highlight some cells, click combine.
if that's the type of thing you're after, modify your code per what's in 'combine'
note: the original code (now) produces a stack overflow error (don't know if it's been fixed in the above link),
but if you get that error, in AttributiveCellTableModel's setDataVector( Vector newData, Vector columnNames )
change
setColumnIdentifiers(columnNames);
to
columnIdentifiers = columnNames;

Similar Messages

Table with varying number of columns

Hello experts,
my issue:
I need to print a table with varying number of columns. Depending on if all cells of a certain column are initial the
whole column should disappear. Hiding is not enough.
If this columns is in the middle of the table the following columns should move left to fill the gap.
my approach: (maybe there is an easier one)
There are 4 different possible situations. My approach was to create 4 different tables with different amount of
columns. In the interface I fill the table that is really needed from the source table data and fill a flag that characteristics
the situation, possible values (1,2,3,4).
In the form I'd like to print the appropriate table depending on the situations.
my problem:
How to place all 4 possible tables lying upon each other in the form and print only the needed one depending on the flag value?
my question:
Is my approach ok? Or is there an easier one?
If it is ok. How can I solve the problem regarding printing the right table.
Thanks in advance!
Heinz

Hi Heinz,
You can handle it with FormCalc Script at initialization.
Suppose you have a table with name TABLE having a header HEADER and data row DATA:
TABLE-->HEADER(Cell1...Cell2...Cell3...Cell4)
--->DATA(Cell1...Cell2...Cell3...Cell4)
Suppose you want to hide Cell3 for null values, then write below code at initialization of DATA:
if(DATA[*].Cell3.rawValue eq null)
then
DATA[*].Cell3.presence = "hidden"
HEADER.Cell3.presence = "hidden"
else
DATA[*].Cell3.presence = "visible"
HEADER.Cell3.presence = "visible"
endif
Hope it would help.
Regards,
Vaibhav

BI Answers - need 2 compound layouts with tables with different columns

Hi,
I need 2 tables in the same report with different columns displaying. Is this possible?
I wanted to put them in their own compound layout and call each one with a view selector,
but it seems impossible to create a 2nd table with different columns in the one report.
Each time I try and replace one of the columns in the 2nd table with a different column,
a message appears saying the deleted column will be deleted from all views.
Many thanks for anyone's help.
- Jenny

As per my knowledge - your requirement can be done with Pivot view but not with regular table view.
We dont have exclude column - functionality in table view.
Else, instead of creating in same report create the req. with 2 separ. reports but place them on single dashboard in 2 sep. sections.

Many to many join table with different column names

Hi have a joint table with different column names as foreign keys in the joining
tables...
e.g. i have a many to many reltnshp btwn Table A and Table B ..and join table
C
both have a column called pk.
and the join table C has columns call fk1 and fk2
does cmd require the same column name in the join table as in the joining table?
are there any workarounds?
thanks

HI,
No, the foreign key column names in the join table do not have to match the primary
key names in the joined tables.
-thorick

Performance between two partitionned tables with different structure

Hi,
I would like if there is a difference between two partitionned tables with different structure in term of performance (access, query, insertions, updates ).
I explain myself in detail :
I have a table that stores one value every 10 minutes in a day (so we have 144 values (24*6) in the whole day), with the corresponding id.
Here is the structure :
| Table T1 |
+ id PK |
+ date PK |
+ sample1 |
+ sample2 |
+ ... |
+ sample144 |
The table is partionned on the column date, with a partionned every months. The primary key is based on the columns (id, date).
There is an additionnal index on the column (id) (is it useful ?).
I would like to know if it is better to have a table with just (id, date, value) , so for one row in the first table we'll have 144 rows in the future? table. The partition will already be on the columns (id, date) with the index associated.
What are the gains or loss in performance with this new structure ( access, DMLs , storage ) ?
I discuss with the Java developers and they say it is simpler to manage in their code.
Oracle version : Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
Thanks & Regards
From France
Oliver
Edited by: 998239 on 5 avr. 2013 01:59

I mean storage in tablespaces and datafiles on disk.
Can you justify please and give me concrete arguments why the two structures are equivalent ( except inserting data in T(id, date,value))
because i have to make a report.i didnt say any thing like
two structures are equivalent ( except inserting data in T(id, date,value)i said
About structure : TABLE1(id, date, value) is better than TABLE1(id, date, sample1, .... sample144)because
1) oracle has restriction for numbers of column. Ok you can have 144 columns now but for future if you must have more than 1000 columns , what will you do?
2) Restrictions on Table Compression (Table compression is not supported for tables with more than 255 columns.)
3) store same type values on diffrent columns is bad practise
http://docs.oracle.com/cd/B28359_01/server.111/b28318/schema.htm#i4383
i remember i seen Toms article about this but now i cant find it sorry ((( if i found i will post here

Joining two fact tables with different dimensions into single logical table

Hi Gurus,
I try to accomplish in Oracle Business Intelligence 11.1.1.3.0:
F1 (D1, D2 and D3)
F2 (D1 and D2 and D4)
And we want to build a report F1 F2 D1 D2 D3 D4 to have data for:
F1 that match only for D1-D2-D3
and data for
F2 that match only D1-D2-D4
all that in one row, so D3 and D4 are not common dimensions.
I can only do:
F3 (D1, D2)
F4 (D1, D2 and D4)
And report
F3 F4 D1,D2,D4 (all that in one row, and only D4 is not a common dimension)
Here is the very good example how to accomplish the scenario 1
http://108obiee.blogspot.com/2009/08/joining-two-fact-tables-with-different.html
But looks like it does not work in 11.1.1.3.0
I get
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 14025] No fact table exists at the requested level of detail: [,,Clients,,Day,ROI,,,,EW_Names,,,,,,,,,,,,,,,,,]. (HY000)
I am sure I set up everything correctly as advised in the blog but it works with only one not a common dimension
Is it a bug in 11.1.1.3.0 or something?
Thanks,
Kate

Thanks for all your replies.
Actually, I've tried the solutions you guys mentioned. Generally speaking, the result should be displayed. However, my scenario is a little bit tricky.
table Y's figures are not the aggregation of table X for D dimension. Instead, table Y's figures include not only D dimension total, but also others (others do not mean A, B, C dimension). For example, table Y stores all food's figure, while table X stores only drink's figure. D dimension is only about drink's detail. In my scenario, other foods' figure is not provided.
So, even if I set D dimension to all/total for table X, table X's result is still not the same as table Y.
Indeed, table Y does not have a column key to join to D dimension's key. So, if I select D dimension and table Y's measures at the same time in BI Answer, result returns no data. Hence, I can't compare table X and table Y's results with selection of D dimension.
Is there any solution to solve this problem?
Edited by: TomChan on Jun 3, 2009 9:36 AM

Row chaining in table with more than 255 columns

Hi,
I have a table with 1000 columns.
I saw the following citation: "Any table with more then 255 columns will have chained
rows (we break really wide tables up)."
If I insert a row populated with only the first 3 columns (the others are null), is a row chaining occurred?
I tried to insert a row described above and no row chaining occurred.
As I understand, a row chaining occurs in a table with 1000 columns only when the populated data increases
the block size OR when more than 255 columns are populated. Am I right?
Thanks
dyahav

user10952094 wrote:
Hi,
I have a table with 1000 columns.
I saw the following citation: "Any table with more then 255 columns will have chained
rows (we break really wide tables up)."
If I insert a row populated with only the first 3 columns (the others are null), is a row chaining occurred?
I tried to insert a row described above and no row chaining occurred.
As I understand, a row chaining occurs in a table with 1000 columns only when the populated data increases
the block size OR when more than 255 columns are populated. Am I right?
Thanks
dyahavYesterday, I stated this on the forum "Tables with more than 255 columns will always have chained rows." My statement needs clarification. It was based on the following:
http://download.oracle.com/docs/cd/B28359_01/server.111/b28318/schema.htm#i4383
"Oracle Database can only store 255 columns in a row piece. Thus, if you insert a row into a table that has 1000 columns, then the database creates 4 row pieces, typically chained over multiple blocks."
And this paraphrase from "Practical Oracle 8i":
V$SYSSTAT will show increasing values for CONTINUED ROW FETCH as table rows are read for tables containing more than 255 columns.
Related information may also be found here:
http://download.oracle.com/docs/cd/B10501_01/server.920/a96524/c11schem.htm
"When a table has more than 255 columns, rows that have data after the 255th column are likely to be chained within the same block. This is called intra-block chaining. A chained row's pieces are chained together using the rowids of the pieces. With intra-block chaining, users receive all the data in the same block. If the row fits in the block, users do not see an effect in I/O performance, because no extra I/O operation is required to retrieve the rest of the row."
http://download.oracle.com/docs/html/B14340_01/data.htm
"For a table with several columns, the key question to consider is the (average) row length, not the number of columns. Having more than 255 columns in a table built with a smaller block size typically results in intrablock chaining.
Oracle stores multiple row pieces in the same block, but the overhead to maintain the column information is minimal as long as all row pieces fit in a single data block. If the rows don't fit in a single data block, you may consider using a larger database block size (or use multiple block sizes in the same database). "
Why not a test case?
Create a test table named T4 with 1000 columns.
With the table created, insert 1,000 rows into the table, populating the first 257 columns each with a random 3 byte string which should result in an average row length of about 771 bytes.
SPOOL C:\TESTME.TXT
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
INSERT INTO T4 (
COL1,
COL2,
COL3,
COL255,
COL256,
COL257)
SELECT
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3)
FROM
DUAL
CONNECT BY
LEVEL<=1000;
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SET AUTOTRACE TRACEONLY STATISTICS
SELECT
FROM
T4;
SET AUTOTRACE OFF
SELECT
SN.NAME,
SN.STATISTIC#,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SPOOL OFFWhat are the results of the above?
Before the insert:
NAME                      VALUE
table fetch continue        166
After the insert:
NAME                      VALUE
table fetch continue        166
After the select:
NAME                 STATISTIC#      VALUE
table fetch continue        252        332 Another test, this time with an average row length of about 12 bytes:
DELETE FROM T4;
COMMIT;
SPOOL C:\TESTME2.TXT
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
INSERT INTO T4 (
COL1,
COL256,
COL257,
COL999)
SELECT
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3)
FROM
DUAL
CONNECT BY
LEVEL<=100000;
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SET AUTOTRACE TRACEONLY STATISTICS
SELECT
FROM
T4;
SET AUTOTRACE OFF
SELECT
SN.NAME,
SN.STATISTIC#,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SPOOL OFFWith 100,000 rows each containing about 12 bytes, what should the 'table fetch continued row' statistic show?
Before the insert:
NAME                      VALUE
table fetch continue        332
After the insert:
NAME                      VALUE
table fetch continue        332
After the select:
NAME                 STATISTIC#      VALUE
table fetch continue        252      33695The final test only inserts data into the first 4 columns:
DELETE FROM T4;
COMMIT;
SPOOL C:\TESTME3.TXT
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
INSERT INTO T4 (
COL1,
COL2,
COL3,
COL4)
SELECT
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3),
DBMS_RANDOM.STRING('A',3)
FROM
DUAL
CONNECT BY
LEVEL<=100000;
SELECT
SN.NAME,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SET AUTOTRACE TRACEONLY STATISTICS
SELECT
FROM
T4;
SET AUTOTRACE OFF
SELECT
SN.NAME,
SN.STATISTIC#,
MS.VALUE
FROM
V$MYSTAT MS,
V$STATNAME SN
WHERE
SN.NAME = 'table fetch continued row'
AND SN.STATISTIC#=MS.STATISTIC#;
SPOOL OFFWhat should the 'table fetch continued row' show?
Before the insert:
NAME                      VALUE
table fetch continue      33695
After the insert:
NAME                      VALUE
table fetch continue      33695
After the select:
NAME                 STATISTIC#      VALUE
table fetch continue        252      33695 My statement "Tables with more than 255 columns will always have chained rows." needs to be clarified:
"Tables with more than 255 columns will always have chained rows +(row pieces)+ if a column beyond column 255 is used, but the 'table fetch continued row' statistic +may+ only increase in value if the remaining row pieces are found in a different block."
Charles Hooper
IT Manager/Oracle DBA
K&M Machine-Fabricating, Inc.
Edited by: Charles Hooper on Aug 5, 2009 9:52 AM
Paraphrase misspelled the view name "V$SYSSTAT", corrected a couple minor typos, and changed "will" to "may" in the closing paragraph as this appears to be the behavior based on the test case.

Can I create a table with more than 40 columns ?

Hello,
I need to organize my work with a table and need about 66 columns. I am not very good with Numbers but I know a little bit of Pages. I cannot find a way to create a table with more than 40 columns... Is it hopeless ? (Pages '08 v. 3.0.3)
Thank you all

It's never too late to try to teach users that the Search feature is not only for helpers.
The number of columns allowed in Numbers is not a relevant value when the question is about Pages '08 tables.
I tried to copy a 256 columns Numbers table into a Pages '09 document.
I didn't got a table but values separated by TABs.
I tried to convert this text range in a table and got this clear message :
If I remember well, in Pages '08, the limit is 40 columns.
It seems that you are a specialist of inaccurate responses, but I'm not a moderator so I'm not allowed to urtge you to double check what you wrote before posting.
Yvan KOENIG (VALLAURIS, France) vendredi 29 avril 2011 14:57:58
Please :
Search for questions similar to your own before submitting them to the community

How to compare two rows from two table with different data

how to compare two rows from two table with different data
e.g.
Table 1
ID   DESC
1     aaa
2     bbb
3     ccc
Table 2
ID   DESC
1     aaa
2     xxx
3     ccc
Result
2

Create
table tab1(ID
int ,DE char(10))
Create
table tab2(ID
int ,DE char(10))
Insert
into tab1 Values
(1,'aaa')
Insert
into tab1 Values
(2,'bbb')
Insert
into tab1 Values(3,'ccc')
Insert
into tab1 Values(4,'dfe')
Insert
into tab2 Values
(1,'aaa')
Insert
into tab2 Values
(2,'xx')
Insert
into tab2 Values(3,'ccc')
Insert
into tab2 Values(6,'wdr')
SELECT
tab1.ID,tab2.ID
As T2 from tab1
FULL
join tab2 on tab1.ID
= tab2.ID
WHERE
BINARY_CHECKSUM(tab1.ID,tab1.DE)
<> BINARY_CHECKSUM(tab2.ID,tab2.DE)
OR tab1.ID
IS NULL
OR
tab2.ID IS
NULL
ID column considered as a primary Key
Apart from different record,Above query populate missing record in both tables.
Result Set
ID ID
2 2
4 NULL
NULL 6
ganeshk

HT4528 Can I put the same information on two different i-phones with different numbers and different ID's?

Can I put the same information on two different i-phones with different numbers and different ID's?

Yes and no it really depends on what information you are putting on the devices.

How to create a table with varied number of columns?

I am trying to create a balance table. The colunms should include years between the start year and end year the user will input at run time. The rows will be the customers with outstanding balance in those years.
If the user input years 2000 and 2002, the table should have columns 2000, 2001, 2002. But if the user input 2000 and 2001, the table will only have columns 2000 and 2001.
Can I do it? How? Thanka a lot.

Why did you create a new thread for this?
How to create a table with varied number of columns?

How to create a table with more tan 20 columns

I created a A4 landscape document to make a calendar for the next year.
To add the date information I need to insert a table with 32 columns (name of month + 31 days). It should be possible to create a table with a over all width of 29.7 cm (consisting of 1 column of 4.9 cm and 31 columns with 0.8 cm)?
Remark: Yet reduced all indention's (? German: Einzug) and other spacers and the size of used font of the table.

Hello Till,
unfortunatly Pages connot create a table with more than 20 columns. This is no question of size or place.
But you can create two tables, set the most right border of the fist table to "no line" and align the second table (with the other 12 columns) at the right side of the first table. Now you have "one" table with 32 columns.
I have done this with my driving book (Fahrtenbuch, um es korrekt zu schreiben and it works fine.
Frank.

How can i export the data to excel which has 2 tables with same number of columns & column names?

Hi everyone, again landed up with a problem.
After trying a lot to do it myself, finally decided to post here..
I have created a form in form builder 6i, in which on clicking a button the data gets exported to excel sheet.
It is working fine with a single table. The problem now is that i am unable to do the same with 2 tables.
Because both the tables have same number of columns & column names.
Below are 2 tables with column names:
Table-1 (MONTHLY_PART_1)
Table-2 (MONTHLY_PART_2)
SL_NO
SL_NO
COMP
COMP
DUE_DATE
DUE_DATE
U-1
U-1
U-2
U-2
U-4
U-4
U-20
U-20
U-25
U-25
Since both the tables have same column names, I'm getting the following error :
Error 402 at line 103, column 4
alias required in SELECT list of cursor to avoid duplicate column names.
So How can i export the data to excel which has 2 tables with same number of columns & column names?
Should i paste the code? Should i post this query in 'SQL and PL/SQL' Forum?
Help me with this please.
Thank You.

You'll have to *alias* your columns, not prefix it with the table names:
$[CHE_TEST@asterix1_impl] r
1 declare
2    cursor cData is
3      with data as (
4        select 1 id, 'test1' val1, 'a' val2 from dual
5        union all
6        select 1 id, '1test' val1, 'b' val2 from dual
7        union all
8        select 2 id, 'test2' val1, 'a' val2 from dual
9        union all
10        select 2 id, '2test' val1, 'b' val2 from dual
11      )
12      select a.id, b.id, a.val1, b.val1, a.val2, b.val2
13      from data a, data b
14      where a.id = b.id
15      and a.val2 = 'a'
16      and b.val2 = 'b';
17 begin
18    for rData in cData loop
19      null;
20    end loop;
21* end;
for rData in cData loop
ERROR at line 18:
ORA-06550: line 18, column 3:
PLS-00402: alias required in SELECT list of cursor to avoid duplicate column names
ORA-06550: line 18, column 3:
PL/SQL: Statement ignored
$[CHE_TEST@asterix1_impl] r
1 declare
2    cursor cData is
3      with data as (
4        select 1 id, 'test1' val1, 'a' val2 from dual
5        union all
6        select 1 id, '1test' val1, 'b' val2 from dual
7        union all
8        select 2 id, 'test2' val1, 'a' val2 from dual
9        union all
10        select 2 id, '2test' val1, 'b' val2 from dual
11      )
12      select a.id a_id, b.id b_id, a.val1 a_val1, b.val1 b_val1, a.val2 a_val2, b.val2 b_val2
13      from data a, data b
14      where a.id = b.id
15      and a.val2 = 'a'
16      and b.val2 = 'b';
17 begin
18    for rData in cData loop
19      null;
20    end loop;
21* end;
PL/SQL procedure successfully completed.
cheers

Table with more than 35 columns

Hello All.
How can one work with a table with more than 35 columns
on JDev 9.0.3.3?
My other question is related to this.
Setting Entities's Beans properties from a Session Bean
bought up the error, but when setting from inside the EJB,
the bug stays clear.
Is this right?
Thank you

Thank you all for reply.
Here's my problem:
I have an AS400/DB2 Database, a huge and an old one.
There is many COBOL Programs used to communicate with this DB.
My project is to transfer the database with the same structure and the same contents to a Linux/ORACLE System.
I will not remake the COBOL Programs. I will use the existing one on the Linux System.
So the tables of the new DB should be the same as the old one.
That’s why I can not make a relational DB. I have to make an exact migration.
Unfortunately I have some tables with more than 5000 COLUMNS.
Now my question is:
can I modify the parameters of the ORACE DB to make it accept Tables and Views with more than 1000 columns, If not, is it possible to make a PL/SQL Function that simulate a table, this function will insert/update/select data from many other small tables (<1000 columns). I want to say a method that make the ORACLE DB acting like if it has a table with a huge number of columns;
I know it's crazy but any idea please.

REMOVE_ELEMENT in a Table with ( tree by key Column )

Hi all,
Designed a table with Tree by key column ( a Normal table with tree )
In one of the row there is a Drop down field provided for selection.
We have delete button provided to the customer.
In this delete button handeled removing the Lead selected row using the method REMOVE_ELEMENT of COntext_node.
so in the context node if we are having 15 elements. The particluar hierarchy selected can have minimun 4 elements
In the UI display the total node( total hierarchy node) is getting deleted but in the debugging mode the node is having 14 elements.
Kindly suggest how to handle it so that in the node also i have the total hierarchy deleted.
Thank you,
Usha

Hello Usha,
For this you need write the logic. If you are deleting a context element of ID say 'ROW1', then you need to take care of deleting all the context element which has parent key as 'ROW1'.
BR, Saravanan

Tables with differing numbers of columns in subsequent rows

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