Take only the last 10 letters

Hi Experts,
How can you say take only the last 10 letters of a char(32).
e.g. here only 2222222222.
data lv_1(32) type c.
lv_1 = 'yyyyyyyyyyyyyyyyyyyyyy2222222222'.
Thx
Sas Erdem

Hi,
just by taking hardcoded offset would not solve your purpose dynamically as for an example if the string is of 22 characters then last 10 will be space....
if you want dynamically last 10 characters then use the code given below.
data : lv_1(32) type c,
lv_len type i.
lv_len = strlen( lv_1 ).
if lv_len < 10.
write lv_len.
else
lv_len = lv_len - 10.
write lv_1+lv_len(10).
endif.
This will surely resolve your issue for dynamic purpose
Regards,
Siddarth

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