The I from the file name is gone.
This is a weird one, look:
Instead of I before the M I'm getting an underscore.
Actully, just notice, is coming from Camera, that way, from the Canon Mark 2d. still anyone might know why?
I do not have that Canon, so am only guessing here, but most digital cameras have a Menu option to set the file naming conventions. What does your Canon show in that section of its Menu?
Good luck, and wish that I could do more than just guess here.
Hunt
Similar Messages
-
Where has the File Name sort gone in PSE11 ?
I have recently migrated to PSE 11 from PS 9 and am annoyed that the filename sort seems to have disappeared in PSE 11 Organizer (it was Display-Folder Location in PS 9). Does anyone know how to sort images by filename in Organzier 11?
Now the only sort is chronological which is a pain for building a story-board for eventual migration of images to non-Adobe apps such as Pinnacle Studio. While the labelling features of Organizer are wonderful for those that like to spend days micro-managing their images, the reality of the native (ie Windows) file structure remains and is the only compatible file structure understood by other apps. There is no reason for Adobe to drop the filename sort option in Organizer - please bring it back !!My iPad is a first generation so it on IOS 5 and I am running iTunes 11. Shows up for me as I said above. Maybe somebody else knows whay it doesn't work for you.
Probably try all the usual suspects Power on and Off for ipad 9 Not Standby, hold down Power button until a red slider appears. The when off keep it pressed for 2-3 secs and iPad will reboot.
Also switch of iTunes and Computer and the switch back on.
Never know it might help certainly wouldn't hurt -
Would someone be able to explain to me the following issue with Iphoto?
I ordered 8 same calendars for my soccer team and received them fine. Although a couple of pictures on it are a little off (out of focus). I need to order two more of the same calendars but when I go thru the process ireceive an error message saying:
"Unable to to assemble calendar" There is a problem with the photo with the file name "(Null)" The full resolution version of this photo either cannot be located or is corrupt. Please replace this photo or delete it from your calendar.
How can I fine this "corrupt" photo? How did it go thru with the first batch of calendars but won't go thru now?
Thank you for your help.Apply the two fixes below in order as needed:
Fix #1
Launch iPhoto with the Command+Option keys held down and rebuild the library.
Since only one option can be run at a time start
with Option #4 and then #1 as needed.
Fix #2
Using iPhoto Library Manager to Rebuild Your iPhoto Library
1 - download iPhoto Library Manager and launch.
2 - click on the Add Library button, navigate to your Home/Pictures folder and select your iPhoto Library folder.
3 - Now that the library is listed in the left hand pane of iPLM, click on your library and go to the File ➙ Rebuild Library menu option.
4 - In the next window name the new library and select the location you want it to be placed.
5 - Click on the Create button.
Note: This creates a new library based on the LIbraryData.xml file in the library and will recover Events, Albums, keywords, titles and comments. However, books, calendars, cards and slideshows will be lost. The original library will be left untouched for further attempts at fixing the problem or in case the rebuilt library is not satisfactory.
OT -
can not transfer date from one hard drive to another, I keep getting an error because I have two of the same file names and one file name is in caps and I cant change the file name. My original external has an error and needs to be reformatted but I dont want to lose this informations its my entire Itunes library.
Sounds like the source drive is formatted as case sensitive and the destination drive is not. The preferred format for OS X is case insensitive unless there is a compelling reason to go case sensitive.
Why can't you change the filename? Is it because the source drive is having problems? If so is this happening with only one or two or a few files? If so the best thing would be to copy those over individually and then rename them on the destination drive.
If it is more then you can do manually and you can't change the name on the source you will have to reformat the destination as case sensitive.
Btw this group is for discussion of the Support Communities itself, you;d do better posting to Lion group. I'll see if a host will move it. -
When I used Quark to make a PDF, the title area in the PDF was automatically populated with the file name, there in the properties tab. We like use this area to confirm file names of original files, so we can keep track of drafts, (in case the file name of the PDF is changed, which our boss often does). Is there any way to set up InDesign to do the same?
@stadlock – I think I know what you mean…
You exported to PDF and changed the file name in the export dialog to a different one from the document name presented there the first time you exported that document. And in exports after that the new name will be presented in the dialog instead of the name of the document.
What you can do against that?
1. First time you want to export: Save before the document is exported. And do not save after it's exported with a new file name.
2. After the new file name is already there in the export dialog:
Type in the document name in the dialog. Export. Or abort after chosing a export preference. Save. Check again, if the document's file name is in the export dialog. If yes, procede like in suggestion #1. If not do a full export with the document's file name, save and then procede with suggestion #1.
Uwe -
Is there an easy way to run an Ajax function from input type=file to test the file name in DB?
I've had the <input type="file"> ... <cffile ...> thing going for a few years now.
There is a database where the uploaded file names are stored once the files are uploaded to the server. It sees things in terms of problems and stores uploaded file name accordingly with the ProbID prepended onto the file name; e.g., MyPicture.jpg would end up in the designated directory and databawe as P416_MyPicture.jpg. This allows user to store pictures with the same name in different problems without a conflict. There has been an issue with certain characters (e.g., spaces, +, #, etc.) causing problems when they are in file names so we have come up with a way using the <cffile ... rename> to replace these chars with _. This means that MyPic+.jpg would end up being P416_MyPic_.jpg.
This is where the problem appears. If someone were to upload MyPic+.jpg after someone else uploaded MyPic_.jpg in the same problem, then the + file would overwrite the _ file before the system knew they had a problem. And there is now way to restore the original file without going to the system backup and doing so – which is a whole other story … especially, if the person doesn’t tell anyone.
The logical solution would be to be able to test the new final file name (the name after making the substitutions mentioned above) against the existing files in the database before you went from the page where the <input type=file> control to the associated _action.cfm page where the <cffile> object is located. Given that this seems to be the province of Ajax, this would seem like a natural use of the really interesting technology. I have can determine the file name from the onChange action on the <input type=File> so that this would be the place for Ajax to come to the rescue by looking up the final file name and then letting the user know whether the resultant name is a unique within the database or not. If so, I'll just enable the Add button which sets right next to the <input > control and let them upload it. If not, I'll put up an error message telling them that this file already exists in the system.
This would be the perfect solution. It would let me do some Ajax stuff like I've wanted to do for the past year, but never have had the time to do because this is the project that won't go away. This is, in fact, the last thing of any consequence that remains to do on this 2-1/2 year nightmare – be careful what you wish for. If I can get this done this week, then maybe I can finally take a weekend off … maybe it will finally come to an end.
Which finally leads to my question: I'm looking for some tips on how to get this thing going since I can barely spell Ajax. I've got a book and looked at some stuff online about CF and Ajax, but a good example or two or three would be worth a day's worth of poking around on the web and in my books.
Thanks in advance for any suggestions, ideas, help, whatever.
LenAdam,
Thank you for your suggestion, but, after spending the night working with Ben Forta's CF8, vol 2, Chap 34, working with <cfajaxproxy>, I was able to do exactly what I wanted and it appears, after some testing, to work exactly as I had envisoned it should.
I am now calling a JavaScript function (testFileName) from the onChage event on the <input type="file"> or Browse button, which calls my proxy.cfc that contains the server side of the equation. This funciton testFileName (I've run out of cleaver function/file names). The query contained therein hits the database to see if the passed in parameters can pull up an existing file. If they do, the particulars (file name, data attahced, etc.) are returned to the JavaScipt procedure that puts up the error notice. The user can then chose to either overwrite the file or quit. Quiting leaves the your on the Attachment PopUp where he/she started with nothing being uploaded.
Thanks again for your suggestion. I appreciate your taking the time to do so.
Len -
Import From Folder: How to Extract the File Name in a Custom Column.
Hello All
Here´s what we´re trying to do:
We have a folder with csv files named like this:
Sales_2013-02-05.csv
Sales_2013-02-04.csv
Sales_2013-02-03.csv
Sales_2013-02-02.csv
Sales_2013-02-01.csv
And in the csv files there are the sales columns but not the date column.
So we want to extract the date from the file name.
I´ve tried entering = Source[Name] in a custom column, but it adds a "LIST" link, and on a click on expand, it adds ALL file names from the folder in each row, instead of just the needed one.
If we could get the proper file name in each row (from where they got extracted), we could split the column and get the date from there. But I don´t know how put the filename there properly.
Can you help?This isn't entirely straightforward, but it's definitely possible. What you need to do is to apply all of your transforms to each individual file instead of the combined files. I do that as follows:
1) Use Folder.Files as generated by the GUI to look at the list of my files.
2) Pick one file and do all the transformations to it that I want to apply to all of the files. Sometimes, this just amounts to letting the autodetection figure out the column names and types.
3) Go into the advanced editor and edit my code so that the transformations from step 2 are applied to all files. This involves creating a new function and then applying that function to the content in each row.
4) Expand the tables created in step 3.
As an example, I have some files with names that match the ones you suggested. After steps 1 + 2, my query looks like the following:
let
Source = Folder.Files("d:\testdata\files"),
#"d:\testdata\files\_Sales_2013-02-01 csv" = Source{[#"Folder Path"="d:\testdata\files\",Name="Sales_2013-02-01.csv"]}[Content],
#"Imported CSV" = Csv.Document(#"d:\testdata\files\_Sales_2013-02-01 csv",null,",",null,1252),
#"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
#"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
in
#"Changed Type"
For step 3, I need to take steps 3-5 of my query and convert them into a function. As a check, I can apply that function to the same file that I chose in step 2. The result looks like this:
let
Source = Folder.Files("d:\testdata\files"),
Loader = (file) =>
let
#"Imported CSV" = Csv.Document(file,null,",",null,1252),
#"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
#"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
in
#"Changed Type",
#"d:\testdata\files\_Sales_2013-02-01 csv" = Source{[#"Folder Path"="d:\testdata\files\",Name="Sales_2013-02-01.csv"]}[Content],
Loaded = Loader(#"d:\testdata\files\_Sales_2013-02-01 csv")
in
Loaded
Now I apply the same function to all of the rows, transforming the existing "Content" column into a new value:
let
Source = Folder.Files("d:\testdata\files"),
Loader = (file) =>
let
#"Imported CSV" = Csv.Document(file,null,",",null,1252),
#"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
#"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
in
#"Changed Type",
Transformed = Table.TransformColumns(Source, {"Content", Loader})
in
Transformed
Finally, I need to expand out the columns in the table, which I can do by clicking on the expand icon next to the Content column header. The resulting query looks like this:
let
Source = Folder.Files("d:\testdata\files"),
Loader = (file) =>
let
#"Imported CSV" = Csv.Document(file,null,",",null,1252),
#"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
#"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
in
#"Changed Type",
Transformed = Table.TransformColumns(Source, {"Content", Loader}),
#"Expand Content" = Table.ExpandTableColumn(Transformed, "Content", {"One", "Two", "Three"}, {"Content.One", "Content.Two", "Content.Three"})
in
#"Expand Content"
From here, you should be able to get to what you want. -
How is it posible to get the File name, size and type from a File out the H
How is it posible to get the File name, size and type from a File out the HttpServletRequest. I want to upload a File from a client and save it on a server with the client name. I want to conrole before saving the name, type and size of the file.How is it posible to get the File name, size and type from a File out the HttpServletRequest.
form JSP
<form name="form" method="post" action="procesuploading.jsp" ENCTYPE="multipart/form-data">
File: <input type="file" name="filename"/
Path: <input type="text" readonly="" name="path" value="c:"/
Saveas: <input type="text" name="saveas"/>
<input name="submit" type="submit" value="Upload" />
</form>
proces JSP
<%@ page language="java" %>
<%@ page import="java.util.*" %>
<%@ page import="FileUploadBean" %>
<jsp:useBean id="TheBean" scope="page" class="FileUploadBean" />
<%
TheBean.doUpload(request);
%>
BEAN
import java.io.*;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.ServletInputStream;
public class FileUploadBean {
public void doUpload(HttpServletRequest request) throws IOException
String melding = "";
String filename = request.getParameter("saveas");
String path = request.getParameter("path");
PrintWriter pw = new PrintWriter(new BufferedWriter(new FileWriter("test.java")));
ServletInputStream in = request.getInputStream();
int i = in.read();
System.out.println("filename:"+filename);
System.out.println("path:"+path);
while (i != -1)
pw.print((char) i);
i = in.read();
pw.close();
}Thanks it works great.
Here an excample from my code
import org.apache.commons.fileupload.*;
public class FileUploadBean extends Object implements java.io.Serializable{
String foutmelding = "geen";
String path;
String filename;
public boolean doUpload(HttpServletRequest request) throws IOException
try
// Create a new file upload handler
FileUpload upload = new FileUpload();
// Set upload parameters
upload.setSizeMax(100000);
upload.setSizeThreshold(100000000);
upload.setRepositoryPath("/");
// Parse the request
List items = upload.parseRequest(request);
// Process the uploaded fields
Iterator iter = items.iterator();
while (iter.hasNext())
FileItem item = (FileItem) iter.next();
if (item.isFormField())
String stringitem = item.getString();
else
String filename = "";
int temp = item.getName().lastIndexOf("\\");
filename = item.getName().substring(temp,item.getName().length());
File bestand = new File(path+filename);
if(item.getSize() > SizeMax && SizeMax != -1){foutmelding = "bestand is te groot.";return false;}
if(bestand.exists()){foutmelding ="bestand bestaat al";return false;}
FileOutputStream fOut = new FileOutputStream(bestand);
BufferedOutputStream bOut = new BufferedOutputStream(fOut);
int bytesRead =0;
byte[] data = item.get();
bOut.write(data, 0 , data.length);
bOut.close();
catch(Exception e)
System.out.println("er is een foutontstaan bij het opslaan de een bestand "+e);
foutmelding = "Bestand opsturen is fout gegaan";
return true;
} -
Retreiving the file names from directory inside another directory from application server
Hi,
I had a problem in retreiving the file names from a directory inside another directory.
I tried using the FM's SUBST_GET_FILE_LIST, RZL_READ_DIR_LOCAL and EPS_GET_DIRECTORY_LISTING
But here I am getting only one directory details.
Actually my file is located a directory inside one more directory and one more directory and inside the files are located.
i.e total 3 directories inside the 3rd one my files are there.
I need to read the latest file name in the directory.
So that i can do some manipulation after getting the file name.
Is there option like OPEN DATASET , READ DATASET and CLOSE DATASET?
Can anyone please let me know How can i acheive this one.
Regards
RamHi Ram,
Following thread can be helpful for you, were it shows in the tables structure rsfillst a field RSFILLST-TYPE whether its a directory or file..........
http://scn.sap.com/thread/865272
thanks and regards,
narayan -
How to store the File Name from a Unix Directory into a ODI variable?
Hi,
I have built a ODI package with the following steps:
1. ODI is polling for a flat file in a Unix directory. I have used OdiFileWait tool for this purpose. Here the file name is not fixed, so I am using wild character (*) to poll for file. Example: DF*ABC1*.DAT where the first wild character denotes 1 letter and the second wild character denotes 2 digits.
2. In the second step, if the file is found, I am moving the file to ODI file server path (../oracledi/demo/file). Here I have used ODIFileMove tool.
3. Then I am using an ODI Interface to Load the file data into a Oracle database table.
4. I am using a Process log table to keep the log for each step I am executing in ODI that is ODIFileWait, ODIFileMove, Interface etc. for each file. In this table a row needs to be inserted after ODIFileWait tool gets the file, with the File Name and File Date. Later on this row will be updated as the consequent steps are executed.
Here is my concern, I need to get the exact File Name of the file after ODIFileWait gets the file and I need to insert that in the Process Log table after the ODIFileWait step gets a file. So if I can store the File Name in a ODI Variable, I can insert it into the Process log table at this point. This I am not able to do.
The files are coming in a different directory (not in ODI file server path), So after getting the file it is moved to ODI file server path (../oracledi/demo/file)
The Files which I am processing are fixed length format. Also, the File name and File Date is stored in the 1st Record(Header record) of the files.
Kindly provide me suggestions to implement this in my code.
Thanks and Regards,
Anik
Edited by: 809820 on Nov 10, 2010 11:36 PMLook at this link -http://odiexperts.com/getting-one-or-several-unknown-files-from-a-directory
change the command to fetch the ls command and write into File and then using either java or jython break the data and fetch the file name and date and insert into log table.
(or)
you can use the os.system command and get the complete ls command into string and then process and insert it.
Let us know if you need any other help. -
How to get the file name from Oracle B2B 10g
Hi My requirement is I am getting a CSV file from Trading partner, I am using oracle 10g b2b to translate the data.
In my BPEL 10g I am using AQ adapter to get the message from IP_IN_QUEUE.
Now I want to get the file name Eg: SampleFile.dat of the CSV file in my BPEL process.
I tried using the b2b.filename property in the receive activity and it is not getting the file name.
<sequence name="main">
<receive name="Receive_Note" partnerLink="GetB2BNote"
portType="ns1:Dequeue_ptt" operation="Dequeue"
variable="Receive_Note_Dequeue_InputVariable"
createInstance="yes">
<bpelx:property name="b2b.fileName" variable="WriteFileName"/>
</receive>
</sequence>
Can you help me to get the file name from Oracle b2b 10g ?
Thanks,
b2b userHi My requirement is I am getting a CSV file from Trading partner, I am using oracle 10g b2b to translate the data.
In my BPEL 10g I am using AQ adapter to get the message from IP_IN_QUEUE.
Now I want to get the file name Eg: SampleFile.dat of the CSV file in my BPEL process.
I tried using the b2b.filename property in the receive activity and it is not getting the file name.
<sequence name="main">
<receive name="Receive_Note" partnerLink="GetB2BNote"
portType="ns1:Dequeue_ptt" operation="Dequeue"
variable="Receive_Note_Dequeue_InputVariable"
createInstance="yes">
<bpelx:property name="b2b.fileName" variable="WriteFileName"/>
</receive>
</sequence>
Can you help me to get the file name from Oracle b2b 10g ?
Thanks,
b2b user -
Setting up the File Name of email Attachment from Received File Name
Hello All,
I have to send the Received File in attachment to an Email if there is any exception. Here I can attach the file, but I cannot set the file name of attachment as the Received File Name. Is there anyway of doing this without using custom pipeline component.
Here I am using the Orchestration and SMTP Adapter.Any help is greatly appreciated.
ThanksIt might work if you use a custom pipeline component on your send port and in the Execute method populate the MIME.FileName property of the body part.
Something like:
public IBaseMessage Execute(IPipelineContext pc, IBaseMessage inmsg)
string filename = inmsg.Context.Read("ReceivedFileName", "http://schemas.microsoft.com/BizTalk/2003/file-properties");
inmsg.BodyPart.PartProperties.Write( "FileName", "http://schemas.microsoft.com/BizTalk/2003/mime-properties", "filename);
return inmsg;
You can take reference from similar post here
SMTP - Setting attachment filename
Anther good article with MIME is here
Setting attachment filename with the SMTP Adapter
For MIME case your SMTP message construct statement would be like below
multipartMessage.MessagePart_1= InMSG;
multipartMessage.MessagePart_2="This is message part2 as a string";
multipartMessage(SMTP.Subject) ="Email From Dynamic Port";
multipartMessage(SMTP.From) ="[email protected]";
multipartMessage(SMTP.SMTPHost) ="yoursmypserver.com";
multipartMessage.MessagePart_2(MIME.FileName) = "Attachment_Name";
multipartMessage(SMTP.SMTPAuthenticate) =0;
Thanks
Abhishek -
Get the File Name received from FTP Adapter
Hi,
How to get the File name reived through the FTP Adpater. I have created a variable with the Message type from ftpAdapterinboundheader.wsdl. from there I mapped the filename attribute to a local string variable.
But I did not receive the file name. The output in the Audit trail is as follows:
<?xml version="1.0" encoding="UTF-8" ?>
- <Invoke_File_Process_FileProcess_InputVariable>
- <part xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" name="InputParameters">
- <InputParameters xmlns="http://xmlns.oracle.com/pcbpel/adapter/db/PIERS/SP_FILE_PROCESS_UPDATE/">
<AS_DIR xmlns="">I</AS_DIR>
<AS_FILE_NAME xmlns="" />
</InputParameters>
</part>
</Invoke_File_Process_FileProcess_InputVariable>
Can any one let me know how to get the recevied file name from FTP adapter.
Thanksyou have to define variable of type InboundHeader_msg. Then in receive activity click on Adapter tab and for header variable chose your newly created variable (InboundHeader_msg). Once you receive message from FTP you should see in this variable fileName.
-
how to hide the file name (the bizarre number assigned by the camera) when exporting an image version in aperture from an album. Pl understand I want to keep the file name in the project library version.
Within Aperture you have Images, which are constructed on-the-fly from two files (the Master and the Version). You get an image-format file _only_ when you export an Image. You select the file name (usually a scheme) when you create an image-format file (that is, when you export). Look under "Aperture→Presets→File Naming" for built-in Presets. You can, of course, create your own or customize any provided.
The Preset is applied to only the file newly created by your "export" command. It is not applied to the Image in Aperture (unless you rename your Versions or your Masters). -
Does anyone know how to use pages so you can export pdfs from the internet and automatically drag words from the document into the file name of the pdf (i.e., author, title of a scientific paper). For example, if I am downloading a paper by smith called "Surgery" that was published in 2002, it will automatically set the file name in the download to smith- surgery 2002. I have heard pages is smart enough to do this.
thank youPages can export only its own documents. They may be exported as PDF, MS Word, RTF or Text files.
Pages can import (ie. Open a file as, or Insert a file into, a Pages document) documents in several formats, but won't rename the document as you describe. Documents that can be Opened (eg. Text, AppleWorks 6 WP, MS Word files) are converted to Pages documents, and retain their original names, with .pages replacing the original file extension. Files that can be Inserted (generally .jpg, .pdf and other image files) become part of the existing Pages file and lose their names.
It may be possible, using AppleScript, to extract the text you want and to Save a Pages file using that text as the filename, but that would depend in part on being able to identify which text is wanted and which is not.
How will the script determine where the author's name begins and where it ends?
How will the script recognize the beginning and of the title, an decide how much of the title to use in the filename?
How will the script recognize the year of publication?
For papers published in a specific journal, with a strict format for placing each of these pieces on information, or containing the needed information as searchable meta data in the file, this might be possible. But it would require knowledge of the structure of these files, and would probably handle only papers published in a specific journal or set of journals.
Outside my field of knowledge, but there are some talented scripters around here who might want to take a closer look.
Best of luck.
Regards,
Barry
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