The instance name of em instance
I tried to install the OCS R2(9.0.4.1) into a Suse SLE 8 (United linux 1.0). The kernel hostname=infraocs.synervision.cc, kernel.domainname=synervision.cc. After finished install, the instance name in the em become infra.128.1.0.150, instead of infra.infraocs.synervision.cc. When I try to query the em status by issue the command 'emctl status', it prompt me 'Could not contact EMD at http://128.1810.....". I wonder why the installation capture the server IP instead of the hostname I set?? Is there any way to change it??
WAs your host file setup correctly prior to the installation.
Similar Messages
-
A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that
the instance name is correct and that SQL Server is configured to allow remote connections. (provider: Named Pipes Provider, error: 40 - Could not open a connection to SQL Server)(Microsoft SQL Server, Error: 2)
The system cannot find the file specified
Cannot connect to COWBOYS.
Here are the technical details===================================
A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider:
Named Pipes Provider, error: 40 - Could not open a connection to SQL Server) (.Net SqlClient Data Provider)
For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft%20SQL%20Server&EvtSrc=MSSQLServer&EvtID=2&LinkId=20476
Error Number: 2
Severity: 20
State: 0
Program Location:
at System.Data.SqlClient.SqlInternalConnection.OnError(SqlException exception, Boolean breakConnection, Action`1 wrapCloseInAction)
at System.Data.SqlClient.TdsParser.ThrowExceptionAndWarning(TdsParserStateObject stateObj, Boolean callerHasConnectionLock, Boolean asyncClose)
at System.Data.SqlClient.TdsParser.Connect(ServerInfo serverInfo, SqlInternalConnectionTds connHandler, Boolean ignoreSniOpenTimeout, Int64 timerExpire, Boolean encrypt, Boolean trustServerCert, Boolean integratedSecurity, Boolean withFailover)
at System.Data.SqlClient.SqlInternalConnectionTds.AttemptOneLogin(ServerInfo serverInfo, String newPassword, SecureString newSecurePassword, Boolean ignoreSniOpenTimeout, TimeoutTimer timeout, Boolean withFailover)
at System.Data.SqlClient.SqlInternalConnectionTds.LoginNoFailover(ServerInfo serverInfo, String newPassword, SecureString newSecurePassword, Boolean redirectedUserInstance, SqlConnectionString connectionOptions, SqlCredential credential, TimeoutTimer
timeout)
at System.Data.SqlClient.SqlInternalConnectionTds.OpenLoginEnlist(TimeoutTimer timeout, SqlConnectionString connectionOptions, SqlCredential credential, String newPassword, SecureString newSecurePassword, Boolean redirectedUserInstance)
at System.Data.SqlClient.SqlInternalConnectionTds..ctor(DbConnectionPoolIdentity identity, SqlConnectionString connectionOptions, SqlCredential credential, Object providerInfo, String newPassword, SecureString newSecurePassword, Boolean redirectedUserInstance,
SqlConnectionString userConnectionOptions, SessionData reconnectSessionData)
at System.Data.SqlClient.SqlConnectionFactory.CreateConnection(DbConnectionOptions options, DbConnectionPoolKey poolKey, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningConnection, DbConnectionOptions userOptions)
at System.Data.ProviderBase.DbConnectionFactory.CreateNonPooledConnection(DbConnection owningConnection, DbConnectionPoolGroup poolGroup, DbConnectionOptions userOptions)
at System.Data.ProviderBase.DbConnectionFactory.TryGetConnection(DbConnection owningConnection, TaskCompletionSource`1 retry, DbConnectionOptions userOptions, DbConnectionInternal oldConnection, DbConnectionInternal& connection)
at System.Data.ProviderBase.DbConnectionInternal.TryOpenConnectionInternal(DbConnection outerConnection, DbConnectionFactory connectionFactory, TaskCompletionSource`1 retry, DbConnectionOptions userOptions)
at System.Data.ProviderBase.DbConnectionClosed.TryOpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory, TaskCompletionSource`1 retry, DbConnectionOptions userOptions)
at System.Data.SqlClient.SqlConnection.TryOpenInner(TaskCompletionSource`1 retry)
at System.Data.SqlClient.SqlConnection.TryOpen(TaskCompletionSource`1 retry)
at System.Data.SqlClient.SqlConnection.Open()
at Microsoft.SqlServer.Management.SqlStudio.Explorer.ObjectExplorerService.ValidateConnection(UIConnectionInfo ci, IServerType server)
at Microsoft.SqlServer.Management.UI.ConnectionDlg.Connector.ConnectionThreadUser()
===================================
The system cannot find the file specified
I have tried from so many forms. This is so frustrating. Thank for everyone/anyone who wants to help. So this is what happened: I had to uninstall my previous sqlserver 2012(which worked great) for some reason, and I uninstalled everything from that download.
Then I installed the trial edition of sql server 2012 (64 Bit) and It wouldn't connect to the database. (Error mentioned above.) My local DB is COWBOYS. (COWBOYS is also my computer name.) After this, I have tried downloading sqlexpress and sqlserver 64bit
many times and cannot connect to my local DB.
How do I connect to my Local DB?
Also, I think this might help: (When I run sqlserve.exe, which I was able to find in C:\Program Files\Microsoft SQL Server\110\LocalDB\Binn, I get an error: Your SQL server installation is either corrupt or has been tampered with(Error getting
instance ID from name). Please uninstall then re-run setup to correct this problem.
I would happily re install it, if it wasn't my 20th time.
I don't have any remote connections, I don't use username/password, only window authentication. I work mostly on visual studio, but without able to store /retrieve data, I don't know how to survive.
May be the solution is very simple, but I am too frustrated.
Some of the things I have tried:
From a command prompt, enter one of the following commands:
net start "SQL Server Agent (MSSQLSERVER)" OR
net start "SQL Server Agent(instancename)"(for instance)
on my sql configuration, I cannot start anything because there is nothing there to start. I can post more details, if that would help. Also, some more details about the error:
Details
Product:
SQL Server
ID:
2
Source:
MSSQLServer
Version:
10.0
Component:
SQLEngine
Message:
An error has occurred while establishing a connection to the server. When connecting to SQL Server, this failure may be caused by the fact that under the default settings SQL Server does not allow remote connections. (provider: Named Pipes Provider, error:
40 - Could not open a connection to SQL Server) (.Net SqlClient Data Provider)
Explanation
SQL Server did not respond to the client request because the server is probably not started.
User Action
Make sure that the server is started.
Version:
9.0
Component:
SQLEngine
Message:
An error has occurred while establishing a connection to the server. When connecting to SQL Server 2005, this failure may be caused by the fact that under the default settings SQL Server does not allow remote connections. (provider: Named Pipes Provider, error:
40 - Could not open a connection to SQL Server) (.Net SqlClient Data Provider)
Explanation
SQL Server did not respond to the client request because the server is probably not started.
User Action
Make sure that the server is started.
Any one that can help me, I will be greatful. Thank you so much. p.s. please ask me anything if you have any questions.It sounds like there are a couple things going on here. First check if you have a successful install of SQL Server, then we'll figure out the connection issues.
Can you launch SQL Server Configuration Manager and check for SQL Server (MSSQLSERVER) if default instance or SQL Server (other name) if you've configured your instance as a named instance. Once you find this, make sure the service is started.
If not started, try to start it and see if it throws an error. If you get an error, post the error message your hitting. If the service starts, you can then launch SSMS and try to connect. If you have a default instance, you can use the machine
name in the connection dialog. Ex: "COWBOYS" where Cowboys is the machine name. However, if you named the SQL Server instance during install, you'll need to connect using the machine\instance format. Ex: COWBOYS\Romo (where Romo
is the instance name you set during install).
You can also look at the summary.txt file in the SQL Server setup error logs to see what happened on the most recent install. Past install history is archived in the log folder if you need to dig those up to help troubleshoot, but the most
recent one may help get to the bottom of it if there is an issue with setup detecting a prior instance that needs to be repaired.
Thanks,
Sam Lester (MSFT)
http://blogs.msdn.com/b/samlester
This posting is provided "AS IS" with no warranties, and confers no rights. Please remember to click
"Mark as Answer" and
"Vote as Helpful" on posts that help you. This can be beneficial to other community members reading the thread. -
Can I create a lot of instance with the same name?
I have, for a project in my studies, to create a map for an adventure game. I must create monsters on this map. For this I use a class that I called Creature. In my class Map i have to initialise the monsters but I
choose their quantity with Math.random() so I don't know how much the map will contain. If in a loop I do: Creature monster = new Creature(); will I have different instances with the same name(I doubt)? Will I have one monster re-created in each iteration of the loop? How can I do to have different monsters in different places (my map is a matrix 2x2)?You would have many Creature references made, but only one variable to hold them, and it would go out of scope outside your loop. You could create a Creature array or use a List (both defined outside your loop) - as
// array
int numCreatures = randomGeneratedCreatureQuantity();
Creature[] monsters = new Creature[numCreatures];
for (int j = 0; j < numCreatures; j++) {
monsters[j] = new Creature();
// Or a list
int numCreatures = randomGeneratedCreatureQuantity();
ArrayList monsters = new ArrayList();
for (int j = 0; j < numCreatures; j++) {
monsters.add(new Creature());
}Good luck
Lee -
Multiple instances of one app of the same name
Hello,
we have few FMS/AMS servers, versions 4, 4.5 and 5, running some kind of internet TV tubes on them.
Each tube is supposed to run as unique instance of a Tube app, with unique settings for publishing to CDN (Akamai).
Sometimes following scenario happens: We reload the stream via administration console or administration API with use of reloadApp command, instance starts closing sequence, even triggers onAppStop event. But as the new instance starts, the old process wakes up again and lives together with the new one - when I check then throught administration API with use of getActiveInstances command, it shows me more instance of the same name as result - for example:
-<data>
<_0>tv_app/tube25</_0>
<_1>tv_app/tube2</_1>
<_2>tv_app/tube21</_2>
<_3>tv_app/tube2</_3>
<_4>tv_app/tube2</_4>
</data>
From logs I can see that each of that instances runs under different process ID (x pid column).
This is quite unpreffered behaviour, as with the same connection settings the multiple instances steals the connection to CDN entry point from each other which causes problems and unpredictable behaviour...
I have following questions related to this:
1. - Why the onAppStop is triggered when using reloadApp and unloadApp commands or buttons in admin console, when documentation says that this event should not be triggered on these ocassions (see http://help.adobe.com/en_US/adobemediaserver/ssaslr/WS5b3ccc516d4fbf351e63e3d11a11afc95e-7 edfSSASLR.2.3.html#WS5b3ccc516d4fbf351e63e3d11a11afc95e-7fe2SSASLR.2.3)
2. - How is it possible that system runs more instances of the same app with the same name? How to avoid such behaviour?
I already noticed following aspects to have influence on the possibility to run multiple instance with the same name and got rid of them but problem still persists:
- case sensivity of app name (one client connects to TV_app/tube2 and other connects to tv_app/tube2)
- using false as return value in onAppStop event handler - when reloaded, new instance is started but the old one persists
I am very eager to hear some explanation or clarification of such logic as it comes to me as some kind of internal bug as I have found everywhere that the instances names should be always unique....
ThanksI just want to note that my recommendations led my clients to purchase more than 5 licences of FMIS/AMIS througt the time.
As I see how low is the passion to react to any problem on Adobe side, I would have probably changed my mind.
This is really pain in the *** as any call to adobe official contact (taken on mind that to find one is a big quest by itself) lead just to reply "pay nasty amount for our consultancy Sir!" and it does not look any better here....
I am no novice on FMS/AMS platform, working with it more than 6 years throught many projects and I would not ask for some stupid questions which could be solved just by looking to documentation or could be solved by some performance eperience.
I am really upset for this :/ -
Is it possible to have 2 instances with the same name but different edition in the same server?
Hi everybody!
I have in a little trouble ....
*** Scenario.
Oracle Enterprise Edition 11gr2 over Oracle Solaris 11
3 instances: PROD, QA, DEV
1 ASM instance
Listener ports: 1520, 1530 & 1540
Those are production system
*** The problem:
Customer can't pay Oracle EE, they want to change to Oracle Std One
Limitations:
I cant have a similar system to test.
*** My idea:
Install Oracle Std One, in the same path:
/u01/app/oracle/product/11.2.0/db <-- EE
/u01/app/oracle/product/11.2.0/db_one <-- Std Ed One
ASM:
/u01/app/11.2.0/grid <-- EE +ASM
/u01/app/11.2.0/grid_one <-- Std Ed One +ASM1
Create databases:
Asign similar disks to +ASM1
Create DGs on +ASM1
Create databases: PROD, QA, DEV for Std Ed one
- is it posible that they have same instance name?
- if not, i suppose create as: PROD1, QA1, DEV1
Configure Listener port : 1521, 1531 & 1541
Migration technique:
Create Tablespaces, schemas
Lock users in EE
down listener: 1520, 1530 & 1540
Import data of final users in a window maintanance
configure and up listener: 1521, 1531 & 1541
Customer should test access and apps in new
Please tell me if my Idea is reallistic, all comments are going to be very apreciated.sol.beach
I suppose end customer use a port per database in order to separate in a logical way the access to the databases,
i mean PROD, QA & DEV has the same users.
Hemant K Chitale
1. I've seen physical servers with 3 ASM instances: +ASM1, +ASM2, +ASM3
on Solaris & Oracle 10g, I suppose is posible on 11g
2. The sever has occupied 2 sockets (2 physical CPU), so I can use Oracle Standard Ed One.
JohnWatson2
Thanks for your comments.
WadhahDaouehi
1. - You cannot run two ASM instance simultaneously on one Server, but you can run many Oracle database simultaneously
on the same server which they use the ASM as storage type.
As a mentioned to Hemant K Chitale, I've seen a system with several instances running
About
"you can run many Oracle database simultaneously on the same server which they use the ASM as storage type."
I'm not sure if i can use the same ASM which is part of a current Enterprise Ed over the new installation with Oracle Std Ed One.
2. - Why you want the same instance name?
If it is about the service name, which has by default the same instance name, just you can create a different instance name
and create the service name with the name that you wish.
SQL> alter system set service_names='instance_name';
Is a similar name, not the same
PROD, QA & DEV
PROD1, QA1 & DEV1
I consider add "1" at the end to refer "Oracle Standar Ed One"
But I agree with you, i can customize throught service_name.
Regards,
Abraham Mtz. -
Hi,
I have taken farm back and restore it in new UAT environment, while access to the main site getting the below error:
Error
An unexpected error has occurred.
Troubleshoot issues with Microsoft SharePoint Foundation.
Correlation ID: 866476f3-23dd-4e1e-97af-bffc62cc2d57
Date and Time: 7/15/2014 11:26:35 AM
When i checked in log i got below error
System.Data.SqlClient.SqlException: A network-related or instance-specific
error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: Named Pipes Provider, error: 40
- Could not open a connection to SQL Server) at System.Data.SqlClient.SqlInternalConnection.OnError(SqlException exception, Boolean breakConnection) at System.Data.SqlClient.TdsParser.ThrowExceptionAndWarning(TdsParserStateObject
stateObj) at System.Data.SqlClient.TdsParser.Connect(ServerInfo serverInfo, SqlInternalConnectionTds connHandler, Boolean ignoreSniOpenTimeout, Int64 timerExpire, Boolean encrypt, Boolean trustServerCert, Boolean integratedSecu...
Thanks in advance
Said Al BalushiHi Wendy,
i have checked all below points, every thing is fine but still i am getting the same error.
Check SQL services are runing
Check remote conenctions are enabled
Check SQL Browser service is runing
Check TCP/IP protocal enabled at SQL server
Check out windows firewall setting
Thanks,
Said
-
hi ,
when generate the schema , i got the below error, please any one put your inputs:
Connecting to the LOB system has failed. A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server
is configured to allow remote connections. (provider: Named Pipes Provider, error: 40 - Could not open a connection to SQL Server).thaks shanky,
but facing another , after generate schema from WCF_SQL, im unable get elements in my schema.
this is schema generate from storeprocduer , but thru WCF-sql im unable get the elements like
id, name
<xsd:schema targetNamespace="urn:schemas-microsoft-com:sql:SqlRowSet2" xmlns:schema="urn:schemas-microsoft-com:sql:SqlRowSet2" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:sqltypes="http://schemas.microsoft.com/sqlserver/2004/sqltypes" elementFormDefault="qualified">
<xsd:import namespace="http://schemas.microsoft.com/sqlserver/2004/sqltypes" schemaLocation="http://schemas.microsoft.com/sqlserver/2004/sqltypes/sqltypes.xsd" />
<xsd:element name="Test.dbo.sample">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="id" type="sqltypes:int" minOccurs="0" />
<xsd:element name="name" minOccurs="0">
<xsd:simpleType>
<xsd:restriction base="sqltypes:nvarchar" sqltypes:localeId="1033" sqltypes:sqlCompareOptions="IgnoreCase IgnoreKanaType IgnoreWidth" sqltypes:sqlSortId="52">
<xsd:maxLength value="1000" />
</xsd:restriction>
</xsd:simpleType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
<Test.dbo.sample xmlns="urn:schemas-microsoft-com:sql:SqlRowSet2">
<id>18</id>
<name>BIRADAR</name>
</Test.dbo.sample>
<Test.dbo.sample xmlns="urn:schemas-microsoft-com:sql:SqlRowSet2">
<id>18</id>
<name>BIRADAR</name>
</Test.dbo.sample>
<Test.dbo.sample xmlns="urn:schemas-microsoft-com:sql:SqlRowSet2">
<id>19</id>
<name>sw</name>
</Test.dbo.sample>
<Test.dbo.sample xmlns="urn:schemas-microsoft-com:sql:SqlRowSet2">
<id>18</id>
<name>BIRADAR</name>
</Test.dbo.sample>
<Test.dbo.sample xmlns="urn:schemas-microsoft-com:sql:SqlRowSet2">
<id>14</id>
<name>swe</name>
</Test.dbo.sample>
<Test.dbo.sample xmlns="urn:schemas-microsoft-com:sql:SqlRowSet2">
<id>13</id>
<name>se</name>
</Test.dbo.sample> -
A network-related or instance-specific error occurred while establishing a connection to SQL Server. The
server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: SQL Network Interfaces, error: 26- Error:Locating Server\instance Specified)
How Can i solve this?1. Make sure SQL Server Service is running
2. If a named instance, make sure SQL Server browser service is running
3. Make sure SQL Server is configured to allow remote connections
4. Examine the SQL Server error log for messages confirming that SQL is listening on the expected network interfaces and ports
5. Test server connectivity with PING from the client machine
6. Test port connectivity using TELNET or PowerShell to the server and port (from step 4) from the client machine. For example
a. TELNET <server-name> 1433
b. PowerShell: 1433 | % { echo ((new-object Net.Sockets.TcpClient).Connect("YourServerName",$_)) "server listening on TCP port $_" }
7. Check firewall settings if step 5 or 6 connectivity test fails
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
MS SQL optimization: MS SQL Development and Optimization
MS SQL Consulting:
Large scale of database and data cleansing
Remote DBA Services:
Improves MS SQL Database Performance
SQL Server Integration Services:
Business Intelligence -
New install Express on Win 8 can see the Server name but cannot see the instance
I am doing this over the phone with a client who is not sure what he is doing we have installed Ok the folders exist and we have enabled TCP/IP
The instance is MSSQLServer when we try to connect all we get is 'ComputerName' I am expecting 'ComputerName \MSSQLServer'
The user does not have administrator rights and he installed SQL Server without the administrator (I think, I am not sure he knows)
I am looking for clues as to what may cause the instance name to not appear
thanks in advance
jncThanks, that is useful but the list of instances just matches the details in SQL Configuration manager
What I need is to understand why, if the server is listed and is running it is not visible when we try to connect
jnc
Hi jnc,
Could you please verify that if the instance name is not listed in “Server name” drop-down list of SQL Server Management Studio (SSMS)? If so, does the instance list in the Local Servers tab in the “Browse for Servers” dialog?
If you cannot see the express instance in the Local Servers tab in the “Browse for Servers” dialog, the reason may due to SQL Server cannot get the appropriate registry entry information in the System Registry (HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Microsoft
SQL Server\Instance Names).
To work around this issue, you can manually input the instance name which will be show in the Local Servers tab. Also make sure that right click on SSMS and then choose “Run As Administrator” to start it.
However, if the express instance is listed in the Local Servers tab in the “Browse for Servers” dialog, but not in the “Server name” drop-down list. Then if you have never connected with the instance name before, its entry will not listed in the drop-downlist.
Or if you have connected to server with a wrong instance name, you cannot see its entry the next time.
Thanks,
Lydia Zhang
If you have any feedback on our support, please click
here.
Lydia Zhang
TechNet Community Support -
How can I make the Instance name the same as the name of the Movie clip in an animation.
Hi, I am an animator for a small game project and I have this really big problem. Even though I used flash for animation for a long time I am a newbie when it comes to something technical. I just received a request to make every movie clip that I use to have a consistent <Instance name> in every frame of the animation. Only if they told me this earlier... Is there an easier way to make the <Instance name> the same as the name of the Movie clip used other than manually entering it. I have 16 characters with 12 body parts with 20 animations each with about 6-7 frames for each body part it will take me months and nightmares evey night to enter everything by hand. Please help me keep my sanity!
I'm not sure if I explain correctly, so here is a picture:
Thank you!Thank you for the fast answer! I found this video on jsfl functionality that deals with a similar problem, I am not a coder so it will take me some time to figure it out, but when I do I will probably post the answer here. Here is the video:
-
Lumira Login Error "Check the Server Name and Instance ID"
Dear Experts
I installed Lumira Desktop and was able to connect to the
HANA Server.
Later while I was working the software hanged and I had to
shut it down.
Now, after re-opening the software I receive error "Check the Server Name and Instance ID"
(though the server credentials are same as error and correct”
Any suggests on how to rectifyI wonder if one of the following KBAs may give you a clue?
1995325 - Error HDB 11009: The dataset could not be published to SAP Lumira Server because publishing to the SAP HANA layer failed. Lumira Server
2134259 - Lumira LaunchPad Logon Hangs
- Ludek
Senior Support Engineer AGS Product Support, Global Support Center Canada
Follow me on Twitter (#SAPLumira)
Got Enhancement ideas? Use the SAP Idea Place -
How do you force instances with the same name on the same layer to update?
Maybe someone can tell me why flash doesn’t redraw
components’ x,y positions if they have the same instance name
and are on adjacent frames? (movieclips work fine, just not
components) If I have a button on frame 1 and a button on frame 2
both with the same instance name but different locations on the
stage, frame 2’s button doesn’t show up in the position
I placed it, it stays at the position of frame 1 but still has the
properties of frame 2’s button. The label changes and
everything. If I stick a button on a frame in between and give it a
different instance name there is no problem. I thought it might be
the style manager bug
http://www.gskinner.com/blog/archives/2007/12/cs3_component_b.html
but it didn’t seem to affect. This happens for textareas too
and probably all components although I haven’t tried them.
I’ve tried using drawNow() and validateNow() with no luck
either
http://www.adobe.com/devnet/flash/articles/creating_as3_components_pt3_05.html
Thank you!
// put this on frame 1 along with a button on the stage with
instance name: b
function doit(event) {
if (currentFrame == 1)
gotoAndStop(2);
else
gotoAndStop(1);
b.addEventListener(MouseEvent.CLICK, doit);
stop();
// put another button on frame 2 along with this code and
also make it’s instance name: b but move it so it’s not
in the same x,y coordinates as the button on frame 1
stop();
Something possibly related. I have a movieclip on a layer,
one instance with name “a” on frame 1 and one instance
with name “a” on frame 2 and it has event listeners
inside it that update something on the movieclip. Unless I put the
movieclips on separate layers the event listeners won’t reset
each frame. (example: a button with a tooltip onmouseover that you
want to change the text of from frame 1 to frame 2) You’d
think if they were on separate keyframes at least but no, they need
to be on separate layers too.
I want the movieclip to update each frame. Any ideas?instances (whether components or not) with the same name may
or may not be the same instance. it depends upon how they were
created.
for example, if you create an instance on frame 1 of your
main timeline, give it an instance name and then create a keyframe
on frame 2, the two instances will be the same.
but if you create an instance on frame 1 of your main
timeline, give it an instance name and then create a blank keyframe
on frame2 and create another, what you think is a duplicate,
instance and give it the same name, it will be a different
instance. -
To Find the instance name in RMAN catalog
Hi ,
I have rman catalog which got registered 150 databases. Am able to get the dbname,id for the 150 databases but not able to get the server name (host name) of the correspoding databases in catalog views as well as in db views.
Kindly revert us if you know any other analyisis or way to find the server names.
Regards
KrishnanWhat does RMAN care if RAC is involved or not?
Oracle provides RMAN for backing up and restoring the database. RMAN enables you to back up, copy, restore, and recover datafiles, control files, SPFILEs, and archived redo logs. RMAN is included with the Oracle server and it is installed by default. You can run RMAN from the command line or you can use it from the Backup Manager in Oracle Enterprise Manager. The procedures for using RMAN in RAC environments do not differ substantially from those for Oracle single-instance environments. Refer to the Oracle Backup and Recovery documentation set for more information about single-instance RMAN backup procedures. -
How to get the ACCOUNTING_FLEXFIELD Name in a Multi Ledger Instance?
Hi,
How to get the <ACCOUNTING_FLEXFIELD> Name in a Multi Ledger Instance from logged-in Responsibility? Is there any profile option available?
SELECT id_flex_num
INTO l_structure_num
FROM apps.fnd_id_flex_structures
WHERE ID_FLEX_CODE = 'GL#'
AND ID_FLEX_STRUCTURE_CODE=<ACCOUNTING_FLEXFIELD>;
TxSMOD->SEUED001->Display componens->double click on EXIT_SAPLEDITOR_002->See the source code...
function exit_sapleditor_002.
*"*"Lokale Schnittstelle:
*" IMPORTING
*" VALUE(PROGRAM) LIKE SY-REPID
*" EXCEPTIONS
*" CANCELLED
include zxseuu22 .
endfunction.
PROGRAM is the importing parameter for the function module.
matt -
How to retreive the instance name of a class
Hello,
Does anyone know how you can retreive the instance name of a
class ?
For example my class is:
class Example{
public static var createdClasses:Array;
function Example() {
createdClasses.push(this);
trace("how can i trace the original name of the class ?");
and in my fla file i have:
var someName:Example = new Example();
var anotherName:Example = new Example();
So, what i would like to know is, the name of the class.. in
this case it is 'someName' and 'anotherName'.
Does anyone know how?
Thanks,
Micheal.there is no instance name of a class. class members can have
instance names and that's an assignable property for classes that
have instance names. -
How to get the Instance Name of Creator
Hi all.
I have an idea but I don't how to implement it. I have tried about two days.
the simplified concept that what I wnat is as follows
class classA {
classB objB = new classB();
class classB {
puclic void showObjName(){
//How can I the Instance Name of Creator here?
//In this Example. The name is objA.
public class showCreator {
public static void main(String[] args) {
classA objA = new classA();
I try to instanciate an Throwable Object and use the getStackTrace method.
but all information in the stack I got Do Not contain the Instances Name.
Does any one have idea to implements this...
Thanks.Yes. hashcode is not absolutely unique. I know this.
I had took this idea into my consideration. But it failed finally.
Thanks
To JN_.
Maybe I still have some misunderstood descripte my question.
neither the name not an "instance name" nor an "object name".
So now, I really do not know how to call this.
Can you tell me? Then I will not make the same fault next time.
thanks.
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