The remote server returned an error: (405) Method Not Allowed.

Question

Hello
I wrote this code for search in Google and retrieved the result. But I have the error on Bold part of the code.
I got this code from: http://revenmerchantservices.com/post/2009/05/26/HttpWebRequest-Post-method.aspx 
private void button1_Click(object sender, EventArgs e)
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("https://www.google.com/?gws_rd=ssl");
request.Timeout = 9 * 1000; // set request timeout = 9 second. if yahoo api failed to respond in 9 second request would get timed out.
request.Method = "Post"; // we will post the data using post method
//string postData = "u=" + TextBox1.Text + "&m=s&t=8";
string postData = "u=" + "My Search data" + "&m=s&t=8";
// data to be posted using HttpWebrequest post method
// we will post parameter u , m and t
// Convert this string into stream of bytes
byte[] arrPostDAta = System.Text.Encoding.GetEncoding("utf-8").GetBytes(postData);
// set request content length = post data length
request.ContentLength = arrPostDAta.Length;
System.IO.Stream strmPostData = request.GetRequestStream();
// get request stream
// write post data to stream of request
strmPostData.Write(arrPostDAta, 0, arrPostDAta.Length);
strmPostData.Close();
// upload post data and Get Response from server
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
StreamReader reader = new StreamReader(response.GetResponseStream());
label1.Text = reader.ReadToEnd();
reader.Close();
response.Close();

Answer 1

I found a code and do not have such an error: http://stackoverflow.com/questions/25339401/perform-a-search-on-google-and-retrieve-results-on-second-page
private void button2_Click(object sender, EventArgs e)
string uriString = "http://www.google.com/search";
string keywordString = "Site:www.amazon.com Handbook";
WebClient webClient = new WebClient();
NameValueCollection nameValueCollection = new NameValueCollection();
nameValueCollection.Add("q", keywordString);
webClient.QueryString.Add(nameValueCollection);
richTextBox1.Text = webClient.DownloadString(uriString);
richTextBox1.SaveFile(Application.StartupPath+@"\x.txt");
But how can I get a URL from the result?