The rules of Java constructors

Question

A constructor with no parameters will automatically call super(). If I extend an object with a parametered constructor, I need to manually enter that constructor into my subclass constructor "super(a, b)".
What then of non extended objects? In this non-extended object if I make a constructor that takes parameters doesn't it automatically make calls to super(). It has to to construct an Object object no?
I haven't read anything regarding this specific behaviour. I was hoping someone could confirm or deny my suspicions.

Answer 1

jverd wrote:
Constructor rules:
1) Every class has at least one ctor.
1.1) If you do not define an explicit constructor for your class, the compiler provides a implicit constructor that takes no args and simply calls super().
1.2) If you do define one or more explicit constructors, regardless of whether they take args, then the compiler no longer provides the implicit no-arg ctor. In this case, you must explicitly define a public MyClass() {...} if you want one.
1.3) Constructors are not inherited.
2) The first statement in the body of any ctor is either a call to a superclass ctor super(...) or a call to another ctor of this class this(...) 2.1) If you do not explicitly put a call to super(...) or this(...) as the first statement in a ctor that you define, then the compiler implicitly inserts a call to super's no-arg ctor super() as the first call. The implicitly called ctor is always super's no-arg ctor, regardless of whether the currently running ctor takes args.
2.2) There is always exactly one call to either super(...) or this(...) in each constructor, and it is always the first call. You can't put in more than one, and if you put one in, the compiler's implicitly provided one is removed.If that would have been a question I wonder how many responds will provide the correct answer.