ThreadStateException Error in openfiledialog

Question

I got this error in a thread that is called by my login form by this code:
        public static void ThreadProc()
            Application.Run(new aplicacao());
        private void button1_Click(object sender, EventArgs e)
            if (textBox1.Text == textBox2.Text)
                System.Threading.Thread aplicacao = new System.Threading.Thread(new System.Threading.ThreadStart(ThreadProc));
                aplicacao.Start();
                this.Close();
            else
                MessageBox.Show("Password Errada.", "Erro de Password",
               MessageBoxButtons.OK, MessageBoxIcon.Error);
In the form aplicacao that that has the openfiledialog code
private void button1_Click_2(object sender, EventArgs e)
            openFileDialog1.InitialDirectory = "C:\\amigisc\\fotos";
            openFileDialog1.Filter = "ficheiros jpg (*.jpg)|*.jpg";
            openFileDialog1.ShowDialog();
            string a = openFileDialog1.FileName.ToString();
            imagem.Text = a;
I have tried to put the [STAThreadAttribute] attribute in the login form but it did't work...

Answer 1

 Matrix79 wrote:
I got this error in a thread that is called by my login form by this code:
      private void button1_Click_2(object sender, EventArgs e)
            openFileDialog1.InitialDirectory = "C:\\amigisc\\fotos";
            openFileDialog1.Filter = "ficheiros jpg (*.jpg)|*.jpg";
            openFileDialog1.ShowDialog();
            string a = openFileDialog1.FileName.ToString();
            imagem.Text = a;
I have tried to put the [STAThreadAttribute] attribute in the login form but it did't work...
What is openFileDialog1? It does not seem to be defined anywhere? I could not see it. Perhaps you posted a snippet?
string a = openFileDialog1.FileName.ToString(); File name is already a string, you don't have to do it again.
OpenFileDialog openFileDialog1 = new OpenFileDialog ( );
openFileDialog1.InitialDirectory = Globals.cur_drive + @"\VCsharp_Projects\ComeAndGet\ComeAndGet\RTF Files\";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
DialogResult res = openFileDialog1.ShowDialog ( );
If the above won't work, thry to do it with no filter, just to open the directory.