Timout dump when accessing BSIS

Question

Hello frnds,
I m accessing bsis table with this query.
    select bukrs hkont augdt augbl zuonr gjahr  belnr buzei bschl
    dmbtr prctr
    from bsis into table i_temp2
    for all entries in i_belnr2
    where bukrs eq company
    and hkont in r_hkont
    and belnr = i_belnr2-belnr
    and budat in date.
i_belnr2 contains some 3k records.
I m getting a time out dump after 25 mins...
Can anyone pls suggest me is there any way that
i can make this query optimized ?
or  any function modules for this specific i/p and o/p parameters?
or any logical database ?
Rgds,
Santhosini K

Answer 1

Hi,
Check the sample code and proceed accordingly to optimize the Query on BSIS Table.
REPORT ztest NO STANDARD PAGE HEADING LINE-SIZE 80 MESSAGE-ID 00.
TABLES: bkpf, bseg, bsis.
DATA: bkpf_int TYPE TABLE OF bkpf WITH HEADER LINE,
bseg_int TYPE TABLE OF bseg WITH HEADER LINE,
bsis_int TYPE TABLE OF bsis WITH HEADER LINE,
BEGIN OF i_indata1 OCCURS 0,
t_pdate TYPE bkpf-budat,
t_kioid TYPE bseg-zuonr,
END OF i_indata1.
SELECT bukrs belnr gjahr budat
FROM bkpf INTO CORRESPONDING FIELDS OF TABLE bkpf_int
FOR ALL ENTRIES IN i_indata1
WHERE bukrs = 'BP01' AND
bstat IN (' ', 'A', 'B', 'D', 'M', 'S', 'V', 'W', 'Z') AND
gjahr = sy-datum+0(4) AND
budat = i_indata1-t_pdate.
SELECT bukrs belnr gjahr buzei zuonr wrbtr shkzg
FROM bseg INTO CORRESPONDING FIELDS OF TABLE bseg_int
FOR ALL ENTRIES IN bkpf_int
WHERE bukrs = bkpf_int-bukrs AND
belnr = bkpf_int-belnr AND
gjahr = bkpf_int-gjahr AND
koart = 'S'. "GL Accounts
SORT: bkpf_int BY bukrs belnr gjahr,
bseg_int BY bukrs belnr gjahr buzei,
i_indata1 BY t_kioid.
LOOP AT bseg_int.
READ TABLE i_indata1 WITH KEY
t_kioid = bseg_int-zuonr
BINARY SEARCH.
CHECK sy-subrc = 0.
READ TABLE bkpf_int WITH KEY
bukrs = bseg_int-bukrs
belnr = bseg_int-belnr
gjahr = bseg_int-gjahr
BINARY SEARCH.
CHECK sy-subrc = 0.
MOVE: bkpf_int-budat TO bsis_int-budat,
bseg_int-zuonr TO bsis_int-zuonr,
bseg_int-wrbtr TO bsis_int-wrbtr,
bseg_int-shkzg TO bsis_int-shkzg.
APPEND bsis_int.
ENDLOOP.
[/code]
Regards,
Raj