To get the warranty date

Question

hai guys,
               i have a field called mfg date in the format dd/mm/yyyy.from this i have to get warranty date.
the formulae is warranty date = mfg date + 18months + 10days.
can anybody provide me the logic for this.

Answer 1

Hi Mahesh,
Check this:
DATA:
  w_date      LIKE p0001-begda,
  w_days      LIKE t5a4a-dlydy,
  w_months    LIKE t5a4a-dlymo,
  w_years     LIKE t5a4a-dlyyr,
  w_calc_date LIKE p0001-begda.
DATA:
  BEGIN OF w_temp,
    w_mfg LIKE sy-datum,
  END OF w_temp,
  it_temp LIKE TABLE OF w_temp.
w_temp-w_mfg   = '20080102'.             " here mfg date hardcode
APPEND w_temp TO it_temp.
w_days   = '10'.
w_months = '18'.
LOOP AT it_temp INTO w_temp.
w_date = w_temp-w_mfg.
  CALL FUNCTION 'RP_CALC_DATE_IN_INTERVAL'
    EXPORTING
      date      = w_date           " mfg date
      days      = w_days                 " 10 days
      months    = w_months               " 18 month
      signum    = '+'
      years     = w_years
    IMPORTING
      calc_date = w_calc_date.
  WRITE: w_calc_date.
ENDLOOP.
The value for mfg date i have hardcoded and moved into internal table .
Regards
Adil