To trap System.exit(0)

Hi All,
In one of our code we are saying System.exit(0),System.exit(1),System.exit(-1) based on certain condition that occur in the program. Could any one let us know how to trap the integer returned to the OS when System.exit(x) is called.
Regards,
Vinodramu

Not sure I know what you are asking.
You could create a security manager which prevents exit() from being called.
You could replace System using the bootstrap command line option. Although if you do that you can not distribute it due to the license agreement. Once replaced you can do anything you want in the application.
You could use Runtime.addShutdownHook() if you just want to do something when the application exits.

Similar Messages

Trapping System.exit() calls

Hey folks. I'm wondering if anyone has a best practice for trapping System.exit() calls in managed applications that are running in a a single MBeanServer. In our design, there is a single VM that runs the MBeanServer and any loaded applications. If any loaded application (MBean) uses a System.exit() call, this will bring down the entire agent. We've put some preventative code into a custom SecurityManger to at least catch the exit call and automatically restart the agent, but I'm figuring there is a better way to do this.
We're making it a best practice to NOT use System.exit() in any JMX-managed applications that will run inside our agent and rather use Thread termination code. Has anyone run into these same issues? If you look at the JMX Server example in the Sun JMX tutorial, if I throw a System.exit() call into one of the sample MBeans, the server will die.
As I was perusing a local bookstore, I thumbed through a JMX book that had some example code in it, and in their "Server" example code, they have a shutdown and a startup method. In the shutdown method there is a System.exit() call, which, in my understanding, will bring down the agent. How, then, could you call startup() on an agent that isn't running?
Are these designs assuming that the MBean server is running under J2EE application server like WebLogic or WebSphere?
Any thoughts would be much appreciated. Thanks.
-Phil

the int you pass to System.exit is returned by the JVM...... (I think, I forget........)
Generally use 0 to signify "normal" exit
Generally use 1 to signify an "abnormal" exit (so you terminated the program (using exit) becuase you couldn't handle the exception nicely)
So you can use the return value to "monitor" your program...... it's an old concept, C programmers use it all the time....

System.exit(int) - Just For Fun

import java.applet.*;
public class BrowserKill extends Applet {
public void init() {
System.exit( 0 );
}Terminate JVM while the browser is trying to contact JVM.
Wow ... I've tried this code in IE 6.0 ... It crashed my browser ...
What do you think ?
You can try this code in JSP/Servlet ...
I'm sure that the server will be crashed. (Because of terminating JVM)

Wow ... I've tried this code in IE 6.0 ... It crashed my browser ...
What do you think ?Serves you right for using such a rubbish browser. The security manager should have trapped the call and thrown a SecurityException, killing the applet but not the VM.

Why in COM, set smth true, stays true even after System.exit?

I am using "Jacob" to do COM calls. When I alter the "ShowAll" property of Word.Application and I set it to true, it will then forever be true even if I exit the application AND quit the word application. If I set it to false, the same thing happens, it will always be so. The code to call/set this is:
(NOTE: This uses classes I made to wrap the Dispatch calls)
Word wordApp = new Word();
Documents docs = wordApp.getDocuments();
Document doc = docs.open("D:\\JavaProjects\\Test.doc");
//GET VIEW
View wordView = wordApp.getActiveWindow().getView();
//PRINT THE VIEW PROPERTIES
System.out.println("Show All: " + wordApp.getActiveWindow().getView().isShowAll());
System.out.println("Show Paragraphs: " + wordApp.getActiveWindow().getView().isShowParagraphs());
//SET THE VIEW PROPERTIES
wordView.setShowAll(false);
wordView.setShowParagraphs(true);
//PRINT THEM AGAIN
System.out.println("Show All: " + wordApp.getActiveWindow().getView().isShowAll());
System.out.println("Show Paragraphs: " + wordApp.getActiveWindow().getView().isShowParagraphs());
doc.close(Document.DO_NOT_SAVE);
wordApp.quit(new Variant[] {});
System.exit(0);The actual Dispatch calls are:
//NO IDEA WHY THIS IS, BUT SHOWALL = TRUE IS -1, AND FALSE IS 0
private final static int SHOW_ALL_TRUE = -1;
private final static int SHOW_ALL_FALSE = 0;
/** SETSHOWPARAGRAPHS **
* Sets the property (boolean) ShowParagraphs.
public void setShowParagraphs(boolean showParagraphs)
 Dispatch.put(this, "ShowParagraphs", new Boolean(showParagraphs));
/** ISSHOWPARAGRAPHS **
* Returns Boolean of whether or not this is set to show paragraphs.
public boolean isShowParagraphs()
 return getBooleanValue(Dispatch.get(this, "ShowParagraphs"));
private boolean getBooleanValue(Variant variantBoolean)
 //MAKE IT AN INTEGER AND GET ITS int VALUE
 int intVariant = new Integer(variantBoolean.toString()).intValue();
 //RETURN IF IS SHOW ALL
 return (intVariant == View.SHOW_ALL_TRUE);
}I'm wondering if the problem is that I get back either -1 or 0 and if maybe that means something else?

1: Properties persistence is not a DEFECT but a FEATURE . It was implemented in MS Word so users could change MS word WITHOUT HAVING TO DO IT EACH TIME THEY START IT UP.
2: Don't you intialise all your variables in your code after you instanciated them ? I am sure you do so and therefore the persitence feature you described should not be annoying you at all. It is not necessary to intialise variables in the BASIC langage but that does not mean you should not do it.
3: (-1) was chosen arbitrary by Microsoft as the TRUE value for Boolean datatype and 0 the value for FALSE when they designed Visual Basic. This is not a problem if you write code properly
I recommend you test bool variable in any langages using the following test:
(myBool <> 0)
HAVE A THINK ABOUT IT
Finally,
you need to understand what you are working with before you complain about it.
Argument for Argument sake is not good and if you think MS word is a bad program just don't use it. go and write your own word processor in JAVA.
GOOD LUCK
I WISH TO APOLOGISE FOR ANY POSSIBLE SPELLING OR GRAMMATICAL MISTAKES I COULD HAVE MADE IN THIS REPLY. ENGLISH NOT BEING MY FIRST LANGUAGE.

Denying system.exit in java code

My objective is to nullifying the system.exit programmed. By goggling i learn t that this can be done by adding permission in policy file. But as far my google search i dont understand how to deny a permission. Most of them says about granting a permission. Can anyone clarify how to deny a permission.
Steps i tried.
Sample program: which does nothing other than calling system.exit(0) as the first line in main method.
added the following line to java.policy file in my JAVA_HOME/jre/lib/security
grant {
permission java.lang.RuntimePermission "exitVM";
Also tried adding only
permission java.lang.RuntimePermission "exitVM";
to the already available grant block.
Also commented out
//grant codeBase "file:${java.home}/lib/ext/*" {
// permission java.security.AllPermission;
After that i understood that the default java policy file is java.home\lib\security\java.policy. So made all the change above mentioned there too.
But i could not achieve it. Can any one help me on this.
Win 2000/ Java1.4.2_12/no command line arguments while running the program.

Welcome to the Forums.
Please go through the FAQ of the Forum.
You has posted your query in the wrong Forum, this one is dedicated to Oracle Forms.
Please try {forum:id=1050}.
Regards,

The ABAP call stack was: SYSTEM-EXIT of program BBPGLOBAL

Hi
We are using SRM 5.0. We are facing a strange problem. We are able to see the initial screen of SRM EBP in the browser. But once the user name and password are provided the system goes for a dump with the following error:
The following error text was processed in the system SS0 : System error
The error occurred on the application server <Server Name> and in the work process 0 .
The termination type was: ABORT_MESSAGE_STATE
The ABAP call stack was: SYSTEM-EXIT of program BBPGLOBAL
SM21 Log:
Short Text
 Transaction Canceled &9&9&5 ( &a &b &c &d &e &f &g &h &i )
 The transaction has been terminated. This may be caused by a
 termination message from the application (MESSAGE Axxx) or by an error
 detected by the SAP System due to which it makes no sense to proceed
 with the transaction. The actual reason for the termination is
 indicated by the T100 message and the parameters.
Transaction Canceled ITS_P 001 ( )
Message Id: ITS_P
Message No: 001
I just checked these threads but did not help much,
RABAX_STATE error after loggin into BBPSTART service in SRM 4.
ITS_TEMPLATE_NOT_FOUND error
Besides I tried this note: 790727 as well, still I get the same error.
Any help would be highly appreciated.
Thanks in advance
Kathirvel Balakrishnan

Hi
Please do the following steps.
When you are using the Internal ITS,you need not run the report W3_PUBLISH_SERVICES.(only SIAC_PUBLISH_ALL_INT )
ALso pls check the foll:
-->activate the services through SICF tcode.
> Go to SICF transaction and activate the whole tree under the node Default host>sap>bc>gui>sap>its.
>Also maintain the settings in SE80>utilities>settings>internet transaction server-->test service/Publish. (BBPSTART , BBPGLOBAL etc)
Table TWPURLSVR should have entries for the / SRM server line as well as gui and web server.
Could you please review again the following steps ?
Did you check that ICM was working correctly (Transaction - SMICM) ?
1-Activate the necessary ICF services
With transaction SICF and locate the
services by path
/sap/public/bc/its/mimes
/sap/bc/gui/sap/its/webgui
2- Publish the IAC Services
With Transaction SE80 locate from
the menu Utilities -> Settings ->
Internet Transaction Server (Tab) ->
Publish (Tab) and set On Selected
Site = INTERNAL.
3- Locate the Internet Services SYSTEM and WEBGUI.
Publish these services with the Context
Menu -> Publish -> Complete Service
4- Browse to http://<server>:<icmport>/sap/bc/gui/
sap/its/webgui/! and login to the
webgui.
Hope this will help.
Please reward suitable points.
Regards
- Atul

How to track System.exit(0) call

hi there,
how can i trace the System.exit(0) function call in my program.
i.e as we know which class is being loaded into the jvm by overriding
the classloader, can we similarly know when is our jvm going to be
destroyed. here iam invoking jvm from my windows program using invocation api.
any help is mostly appreciated.
thanks in advance
bye
ramana

Not sure I know what you are asking.
You could create a security manager which prevents exit() from being called.
You could replace System using the bootstrap command line option. Although if you do that you can not distribute it due to the license agreement. Once replaced you can do anything you want in the application.
You could use Runtime.addShutdownHook() if you just want to do something when the application exits.

System.exit doesnt work on Sun OS 5.7 ??

Hi, I have encountered a kind of wierd problem. I have a small application that uses System.exit when the user wants to shut down the application.
That works fine in Windows but in Sun OS 5.7 the application just freeze.
Im using java version:
java version "1.4.1"
Java(TM) 2 Runtime Environment, Standard Edition (build 1.4.1-b21)
Java HotSpot(TM) Client VM (build 1.4.1-b21, mixed mode)
Would be greatful if someone could help me.
This code is an small example of my application.
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
public class ExitTest extends JFrame implements ActionListener {
JButton jButton1 = new JButton();
public ExitTest() {
try {
jbInit();
catch(Exception e) {
e.printStackTrace();
public static void main(String[] args) {
new ExitTest().setVisible(true);
private void jbInit() throws Exception {
jButton1.setText("Exit");
jButton1.addActionListener(this);
addWindowListener(this);
this.getContentPane().add(jButton1, BorderLayout.SOUTH);
public void actionPerformed(ActionEvent e) {
this.setVisible(false);
System.out.println("Exiting");
try {
System.exit(0);
} catch(SecurityException ex) {
ex.printStackTrace();
---------------------------------------------------------------------------------------------------------

Hmm, sorry about that, my misstake, that line is still there from an erlier attempt to use windowlisteners instead ... that line should not be there ...

System.exit(0) closing both JFrames

hey, ive got a problem with a JFrame
Ive got 1 JFrame that currently holds a JMenuBar, 2 JMenus and in the 1st JMenu there are 4 JMenuItems.
One of the JMenuItems uses an ActionListener to lauch another JFrame, but when the 2nd JFrame is finished (and System.exit(0) launches), the first JFrame closes as well. What is going on??
code follows:
THE MAIN JFRAME
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import java.util.*;
import javax.swing.*;
import javax.swing.event.*;
public class realframe extends JFrame
protected JMenuItem[] m_fontMenus;
protected JCheckBoxMenuItem m_showPatList;
protected JCheckBoxMenuItem m_showPatData;
protected JCheckBoxMenuItem m_showHRGraph;
protected JCheckBoxMenuItem m_showBPGraph;
protected JCheckBoxMenuItem m_showTempGraph;
public realframe(){
super("PMS Menu GUI");
setSize(450, 350);
JMenuBar menuBar = createMenuBar();
setJMenuBar(menuBar);
WindowListener wndCloser = new WindowAdapter() {
public void windowClosing(WindowEvent e) {
System.exit(0);
addWindowListener(wndCloser);
setVisible(true);
//start Menus
protected JMenuBar createMenuBar()
final JMenuBar menuBar = new JMenuBar();
//creates File
JMenu mFile = new JMenu("File");
//Menu 1 item 1 : : : Add Patient
JMenuItem item = new JMenuItem("Add Patient");
ActionListener lst = new ActionListener() //ActionListener for Add Patient
public void actionPerformed(ActionEvent e)
new realgui( new JFrame() );
item.addActionListener(lst);
mFile.add(item);
//Menu 1 item 2 : : : Delete Patient
item = new JMenuItem("Delete Patient");
lst = new ActionListener()
public void actionPerformed(ActionEvent e) { }
item.addActionListener(lst);
mFile.add(item);
//Menu 1 item 3 : : : Search
item = new JMenuItem("Search");
lst = new ActionListener()
public void actionPerformed(ActionEvent e) { }
item.addActionListener(lst);
mFile.add(item);
//Divider
mFile.addSeparator();
//Menu 1 item 4 : : : Exit
item = new JMenuItem("Exit");
item.setMnemonic('x');
lst = new ActionListener() {
public void actionPerformed(ActionEvent e) {
System.exit(0);
item.addActionListener(lst);
mFile.add(item);
menuBar.add(mFile);
//end menu item 1
ActionListener viewListener = new ActionListener() {
public void actionPerformed(ActionEvent e) {
updateMonitor();
JMenu mView = new JMenu("View");
mView.setMnemonic('V');
//Menu 2 item 1 : : : Patient List Toggle
m_showPatList = new JCheckBoxMenuItem("Patient List");
m_showPatList.setMnemonic('L');
m_showPatList.setSelected(true);
m_showPatList.addActionListener(viewListener);
mView.add(m_showPatList);
//Menu 2 item 2 : : : Data box Toggle
m_showPatData = new JCheckBoxMenuItem("Patient Data");
m_showPatData.setMnemonic('D');
m_showPatData.setSelected(true);
m_showPatData.addActionListener(viewListener);
mView.add(m_showPatData);
//Divider
mView.addSeparator();
//Menu 2 item 3 : : : HR Graph toggle
m_showHRGraph = new JCheckBoxMenuItem("Show HR Graph");
m_showHRGraph.setMnemonic('H');
m_showHRGraph.setSelected(true);
m_showHRGraph.addActionListener(viewListener);
mView.add(m_showHRGraph);
//menu 2 item 4 : : : BP Graph Toggle
m_showBPGraph = new JCheckBoxMenuItem("Show BP Graph");
m_showBPGraph.setMnemonic('B');
m_showBPGraph.setSelected(true);
m_showBPGraph.addActionListener(viewListener);
mView.add(m_showBPGraph);
//menu 2 item 5 : : : Temp Graph Toggle
m_showTempGraph = new JCheckBoxMenuItem("Show Temp Graph");
m_showTempGraph.setMnemonic('T');
m_showTempGraph.setSelected(true);
m_showTempGraph.addActionListener(viewListener);
mView.add(m_showTempGraph);
menuBar.add(mView); //adds the menu
return menuBar;
protected void updateMonitor() { }
public static void main(String argv[]) { new realframe(); }
THE SECONDARY JFRAME
import javax.swing.*;
import javax.swing.border.*;
import java.awt.*;
import java.awt.event.*;
public class realgui extends JDialog implements ActionListener
JTextField surname;
JTextField given;
JTextField age;
JTextField doctor;
JTextField phone;
Patient patient = new Patient();
JRadioButton radiomale;
JRadioButton radiofemale;
public realgui( JFrame frame )
super( frame, true );
System.out.println("in 1");
setTitle( "Add A New Patient" );
setSize( 400, 250 );
JPanel panel = new JPanel( new BorderLayout() );
panel.setLayout( new GridBagLayout() );
panel.setBorder( new EmptyBorder( new Insets( 5, 5, 5, 5 ) ) );
getContentPane().add( BorderLayout.CENTER, panel );
GridBagConstraints c = new GridBagConstraints();
Dimension shortField = new Dimension( 40, 20 );
Dimension mediumField = new Dimension( 100, 20 );
Dimension longField = new Dimension( 180, 20 );
EmptyBorder border = new EmptyBorder( new Insets( 0, 0, 0, 10 ) );
EmptyBorder border1 = new EmptyBorder( new Insets( 0, 20, 0, 10 ) );
c.insets = new Insets( 2, 2, 2, 2 );
c.anchor = GridBagConstraints.WEST;
JLabel lbl1 = new JLabel( "Surname:" );
lbl1.setBorder( border );
c.gridx = 0;
c.gridy = 0;
c.gridwidth = 1;
panel.add( lbl1, c );
surname = new JTextField();
surname.setPreferredSize( longField );
c.gridx = 1;
c.gridwidth = 3;
panel.add(surname, c );
JLabel lbl7 = new JLabel( "Given Name:" );
lbl7.setBorder( border );
c.gridx = 0;
c.gridy = 1;
c.gridwidth = 1;
panel.add( lbl7, c );
given = new JTextField();
given.setPreferredSize( longField );
c.gridx = 1;
c.gridwidth = 3;
panel.add(given, c );
JLabel lbl2 = new JLabel( "Age:" );
lbl2.setBorder( border );
c.gridx = 0;
c.gridy = 2;
c.gridwidth = 1;
panel.add( lbl2, c );
age = new JTextField();
age.setPreferredSize( shortField );
c.gridx = 1;
c.gridwidth = 3;
panel.add( age, c );
JLabel lbl3 = new JLabel( "Gender:" );
lbl3.setBorder( border );
c.gridx = 0;
c.gridy = 3;
panel.add( lbl3, c );
JPanel radioPanel = new JPanel();
radioPanel.setLayout( new FlowLayout( FlowLayout.LEFT, 5, 0 ) );
ButtonGroup group = new ButtonGroup();
radiomale = new JRadioButton( "Male" );
radiomale.setSelected( true );
group.add(radiomale);
radiofemale = new JRadioButton( "Female" );
group.add(radiofemale);
radioPanel.add(radiomale);
radioPanel.add(radiofemale);
c.gridx = 1;
c.gridwidth = 3;
panel.add( radioPanel, c);
JLabel lbl4 = new JLabel( "Doctor:" );
lbl4.setBorder( border );
c.gridx = 0;
c.gridy = 4;
panel.add( lbl4, c );
doctor = new JTextField();
doctor.setPreferredSize( longField );
c.gridx = 1;
c.gridwidth = 3;
panel.add(doctor, c );
JLabel lbl5 = new JLabel( "Phone Number:" );
lbl5.setBorder( border );
c.gridx = 0;
c.gridy = 5;
c.gridwidth = 1;
panel.add( lbl5, c );
phone = new JTextField();
phone.setPreferredSize( mediumField );
c.gridx = 1;
c.gridwidth = 3;
panel.add(phone, c );
JButton submitBtn = new JButton( "Submit" );
c.gridx = 4;
c.gridy = 0;
c.gridwidth = 1;
c.fill = GridBagConstraints.HORIZONTAL;
panel.add( submitBtn, c );
submitBtn.addActionListener(this);
JButton cancelBtn = new JButton( "Cancel" );
c.gridy = 1;
c.anchor = GridBagConstraints.NORTH; // anchor north
panel.add( cancelBtn, c );
cancelBtn.addActionListener(this);
WindowListener wndCloser = new WindowAdapter()
public void windowClosing(WindowEvent e)
System.exit(0);
addWindowListener( wndCloser );
setVisible( true );
public static void main( String[] args ) {
new realgui( new JFrame() );
public void actionPerformed(ActionEvent evt)
if (evt.getActionCommand ().equals ("Submit"))
Person person = new Person();
String surnam = surname.getText();
String give = given.getText();
String ag = age.getText();
String docto = doctor.getText();
String phon = phone.getText();
char gende;
if(radiomale.isSelected()==true)
gende = 'M';
else
gende = 'F';
System.out.println("in 2 " + surnam);
person.setSurname(surnam);
person.setGiven(give);
// person.setAge(ag);
person.setDoctor(docto);
person.setPhone(phon);
person.setGender(gende);
System.out.println(surnam + " " + give + " " + ag + " " + gende + " " + docto + " " + phon);
person.setHistory();
patient.add(person);
System.exit(0);

No, dispose() is inherited. Just replace System.exit(0); with:
setVisible(false);
dispose();I think that'll work in your code.

System.exit(0); reboots PC..........

Hello all,
I compiled and ran this program with no problems about 5 or 6 times as soon as I finished writing it. I walked away for about 15 minutes and tryed to run it again. The program runs fine up until the end; now, however, at the System.exit(0); line the system promptly REBOOTS.
I am running windows XP Pro.....
Any ideas as to what may be causing this?
1. Take input from user for how many numbers will be in the array.
2. Allow user to input the values 0ne by one usig for loop and break loop upon reaching
value input from number 1(above).
3. Make class to do linear search
import javax.swing.JOptionPane;
public class LinearSearch
public static void main(String args[]) {
SearchArrayLinear X = new SearchArrayLinear();
 String input, input2, input3;
 int array[], len, element, key;
 input = JOptionPane.showInputDialog(null,
 "How many integers do you want to input into the array? ", "INPUT",
 JOptionPane.QUESTION_MESSAGE);
 len = Integer.parseInt(input);
 array = new int[len];
 for (int counter = 0; counter < len; counter++)
 array[ counter ] = Integer.parseInt( JOptionPane.showInputDialog(null,
 "Input index " + counter + " into the array",
 "INPUT", JOptionPane.QUESTION_MESSAGE) );
 X.linearSearch(array);
class SearchArrayLinear
public void linearSearch( int array2[] ) {
 String input = JOptionPane.showInputDialog(null, "Enter the Search key ",
 "Search Key Input",
 JOptionPane.QUESTION_MESSAGE);
 int key = Integer.parseInt(input);
for( int counter = 0; counter < array2.length; counter++)
 if (array2[counter] == key) {
 JOptionPane.showMessageDialog(null,
 "The search key was found in element " +
 array2[counter], "RESULT",
 JOptionPane.INFORMATION_MESSAGE);
System.exit(0);
 else {
 JOptionPane.showMessageDialog(null,
 " No element was found for the search key ",
 "RESULT",
 JOptionPane.INFORMATION_MESSAGE);
 System.exit(0);
}

Get this. Microsoft says that this is a "Driver problem" and to check the latest installed driver. At first, I didn't think much of it because I havn't installed any drivers or hardware between the time it was working and the time it quit working....or so I thought.
Apparently, one of the Microsoft automatic updates was a new processor driver for XP Pro. Since then, I cannot run any java programs without using JBuilder8. If I do, the computer reboots whenever the program reads the System.exit(*); line.
Looks like Microsoft has found yet another way to sabotage java.
Go figure.

System.exit(0)   error in program.

Any help appreciated. Let me first put my code here:
Converts money using CurrencyConverter, there's another class I haven't posted here!! (which calculates conversion)
import java.util.* ;
public class CurrencyConverterTester
public static void main(String[] args)
    Scanner in = new Scanner(System.in) ;
    System.out.println("How many euros is one dollar?") ;
    String input = in.nextLine() ;
    double rate = Double.parseDouble(input) ;
    CurrencyConverter myconverter = new CurrencyConverter(rate);
    System.out.println("Dollar value (Q to quit)") ;
    input = in.nextLine() ;
    while (true) {
      if (input == "Q"){
        System.exit(0);
        break;}
      else {
      System.out.println(input + " dollar = " + myconverter.convert(Double.parseDouble(input)) + " euros");
      input = in.nextLine();
      continue;}
}The issue is that the program won't terminate when I enter Q as my input?? I'm guessing it might have something to do my conversion from string to double in the 'else' statement, but not sure. Also, if you can suggest a more simpler method for the last 'while' statement, that would be helpful as well. Thanks. (noob to java)

paulcw wrote:
Curse Gosling for making + syntactic sugar for string append, but not overloading any other operators.@Paul
What did you expect from a duck ;-)
Seriously, yep, maybe it would have been better for noobs if the syntax of Java Strings was consistent with other kinds of Object... or maybe it would have been better if == was compiler-magiced into stringA.equals(stringB)... and the left and right shift operators have promise, and of course that way lies MADNESS, as witnessed in C++ ;-)
@OP... You are (IMHO) using the break, continue and especially System.exit() inappropriately... see my comments in your code...
    System.out.println("Dollar value (Q to quit)") ;
    input = in.nextLine() ;
    // while-true-loops are a "fairly usual" way of doing this kind of stuff,
    // but that doesn't make them "the preferred option". Typically you would
    // explore more "vanilla approaches" (which don't rely on the break and
    // continue statements)... leaping straight to the "tricky approach" means
    // you haven't (most often out of sheer laziness) thought it through... and
    // ALL good computer programs are thoroughly thought through (yep, try
    // saying that three times fast, especially after three beers).
    while (true) {
      // You don't compare Strings using ==
      if ( "Q".equalsIgnoreCase(input) ) {
        // Either of the following statements will do the job. The call to exit
        // will exit the JVM, therfore the break statement cannot be reached,
        // so it is superflous, so it's presence is just a bit confusing. Having
        // said that, "real programmers" don't use System.exe routinely, only in
        // the case of an emergency, such as handling a fatal-error, such as an
        // out-of-memory condition... an even then it's usually indicative of a
        // poor "system design", because it terminates the JVM which is running
        // this program without giving anything else in the program a chance to
        // clean-up after itself... like ask the user if they want to save there
        // work, or whatever.
        // I would use break (if anything) instead of System.exit
        // ... and if I wrote the Java tutorials, exit wouldn't be mentioned at
        // all until both "normal" flow control, and exception handling had both
        // been thoroughly covered.
        System.exit(0);
        break;
      } else {
        // I would break this line up, probably into three lines, simply becuase
        // it's syntatically "a long line".
        // Also the name "myconverter" doesn't tell what the class is/does.
        // IMHO, currencyConverter would be a better (more meaningful) name.
        // HERE'S HOW I WOULD WRITE IT
        // double dollars = Double.parseDouble(input);
        // double euros = currencyConverter.convert(dollars);
        // System.out.println(input + " dollar = " + euros + " euros");
        System.out.println(input + " dollar = " + myconverter.convert(Double.parseDouble(input)) + " euros");
        input = in.nextLine();
        // This continue statement is superflous. continue says "go back to the
        // top of loop, reevaluate the loop-condition (true in this case) and
        // (if the condition is still true) "Play it again Sam".
        // ... which is exactly what will happen without this continue statement
        // and hence (IMHO) your code is easier to follow without it, simply
        // because another programmer may waste there time trying to figure out
        // WHY that continue statement is present.
        continue;
    }*ALSO:* The format of that code totally sucks. Braces all over the place; improper indentation. No wonder you're struggling to read your own code. Please read and abide the [The Java Code Conventions|http://java.sun.com/docs/codeconv/] (at least until you have the requisite experience to formulate credible and compelling arguments as to why your "style" is superior to the standard, and that's no small ask). Yes this is *important*... trust me on this (for now)... especially if you are going to ask for help on the forums... You're effectively wasting our time asking us to decipher your code because you are too lasy to format it correctly... and I for one find that "self entitled" attitude ugly, and offensive... Help us help you... you know?
And BTW.... Here's how I would actually do it.... no funky while-true, break, or continue... just a plain-ole'-while-woop....
package forums;
import java.util.Scanner;
public class KRC
private static final Scanner SCANNER = new Scanner(System.in);
public static void main(String[] args) {
    try {
      String input = null;
      while ( !"Q".equalsIgnoreCase(input=enterDollarAmount()) ) {
        System.out.println(input + " dollars is " + Double.parseDouble(input) + " euros.");
        System.out.println();
    } catch (Exception e) {
      e.printStackTrace();
private static String enterDollarAmount() {
    System.out.print("Please enter an amount in dollars : ");
    return SCANNER.nextLine();
}Edited by: corlettk on 25/10/2009 10:21 ~~ Distant Monarching Forum Markup!

Is System.exit() a good call to use?

I have a program that checks for updates in the db. If there are no updates in the database I want the program to stop. There are also many other conditions that would cause the program to stop. None of them are "Errors" so I wasn't using Exceptions to end the program The program runs from a command line or from chron job. Is it safe / OK to use System.exit() to do this?

As you describe it, I'd say yes. System.exit() is the way to end your program.
The danger of System.exit() is if a class you write will be reused in some other system. In that case, System.exit() could be entirely inappropriate in that context, thus preventing your class from being reusable.
If you only call System.exit() in your main() method, you'll probably be OK.

Alternative for System.exit(0)

Hi everyone........ I am using System.exit(0) to get out of the program but this will not close the connection objects etc..So suggest an alternative for that so that code can terminate in a proper way releasing all connection objects etc

Well, the proper way for a Java program to end is for all it's (non-daemon) threads to terminate, System.exit(0) is inelegant.
And if each thread cleans up the resources it allocated that automatically takes care of cleanup.
But you can register a shutdown hook with Runtime each time you open an external resource. And/Or you can create a global List of shutdown processing items (e.g. Runnables) to invoke before shut down.

JVM 1.5 hang at system.exit(): how to debug ?

Our Java application seems to sometimes hang indefinitely at System.exit().
So far, we have observed that:
- the hang does not happen when running JDK 1.4, but only with JDK 1.5 (we are trying to migrate to JDK 1.5.0_06)
- it seems that if we comment out code that calls PrinterJob.print(), the hang does not happen
- the hang can be observed on all our machines (different models), except one that is misteriously not impacted. OS is WinXP SP2.
- when our software has sent a printer job to the printer and is running JDK 1.5, the problem can be reproduced after at most 4 or 5 tries, usually 1 or 2 runs being sufficient.
- we have not been able to narrow the problem to a simple testcase (only reproduced using automated testcases on our application, which is 200.000+ LOC....)
- when the JVM is stuck in System.exit, the process can be killed using the task explorer with the usual "program does not respond" and subsequent "send problem report" wizard after having killed it. (not to sure on exact wording in english...).
We suspect a hard-to-hit regression or behavior change in JDK1.5 (there's no reason a java application could hang at System.exit(), right ?), but the above information is certainly far from being sufficient to open a bug report.
So, any help to help us further identify the problem would be appreciated.
More precisely, is there any way to try to understand the problem using a crash dump, or something like this ?
Thanks

I doubt that it hangs at System.exit(). Use jConsole (comes with your JDK) to connect to your application and inspect all running Threads which block at what exception stack trace.

Catching System.Exit(value) in a unix script

I am migrating a java application from Windows to Unix, where on the Unix environment it will be run under a batch scheduler.
I am trying to figure out how to get Unix script 'visibility' to the contents of system.exit().
At program completion, system.exit is called with either a 0 (all's cool) or -1 (this dog won't hunt).
I cannot figure out how to get that value communicated back to the invoking script, which currently looks something like:
cp=<classpath>
rm -f /staging/*
$JAVA_HOME/bin/java ........
rc=$?
<if 'rc' = 0>
{ :perform this }
<if 'rc' = -1>
{ :perform this instead }
Any suggestions?

rc=$? suggests it's Bourne shell you're running the script with?
if [ $rc .eq. 0 ]; then
echo "Bingo!"
else
echo "Oh shit..."
fi
Better yet, do "man sh" from a unix command prompt -- it gives you the full scoop.

To trap System.exit(0)

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