Trivial Catch block question

Question

In a test harness I wanted to put some debugging output to System.out and keep one line per thread execution so I could read it more easily.
I have a try catch block, and in both sections my debugging prints out with System.out.print, so they should appear on the same line. The strange thing I have noticed is that when ever the catch block is entered the code prints on a new line and I dont know why.
Below is a snippet of code, its pretty simple but illustrates this:
try {
   System.out.println("starting test - ");
   //at this line the test code runs
   System.out.println("success");  
} catch(Exception e) {
   System.out.println("fail");
}The output for a successful test is like:
starting test success
And for a fail:
starting test -
fail
I am just curious to know the answer, its like a new line character is output when the print statement is within the try catch block.

Answer 1

MarksmanKen wrote:
You want to use System.out.print not System.out.println
Notice the difference?
One automatically starts a new line and one just carrys on the current line.Wrong: One automatically ends the current line, while the other one does not!
A subtle difference, but important:
This code will print "foo" and "bar" on two separate lines:
System.out.println("foo");
System.out.print("bar");This code will print "foobar" on one line:
System.out.print("foo");
System.out.println("bar");