Trouble understanding SplitPane division

Hi all
I wish I could remove or replace a split pane divisions by lines. The scenario I'm doing with FXML in fact ideally be able to do with CSS
Is that possible?
regards

Default css for splitpane, just override it with the css style you want:
.split-pane > * > * > .table-view { -fx-padding: 0px; }
.split-pane > * > * > .list-view { -fx-padding: 0px; }
.split-pane > * > * > .tree-view { -fx-padding: 0px; }
.split-pane > * > * > .scroll-pane { -fx-padding: 0px; }
.split-pane > * > * > .split-pane {
    -fx-background-insets: 0, 0;
    -fx-padding: 0;
.split-pane {
    -fx-skin: "com.sun.javafx.scene.control.skin.SplitPaneSkin";
    -fx-background-color: -fx-box-border, -fx-control-inner-background;
    -fx-background-insets: 0, 1;
    -fx-padding: 1;
.split-pane *.split-pane-divider {
    -fx-padding: 0 2 0 2; /* 0 3 0 3 */
/* horizontal the two nodes are placed to the left/right of each other. */
.split-pane:horizontal > * > .split-pane-divider {
   -fx-border-color: transparent -fx-box-border transparent #BBBBBB;
   -fx-background-color: transparent, -fx-inner-border-horizontal;
   -fx-background-insets: 0, 0 1 0 1;
/* vertical the two nodes are placed on top of each other. */
.split-pane:vertical > * > .split-pane-divider {
   -fx-border-color: #BBBBBB transparent -fx-box-border transparent;
   -fx-background-color: transparent, -fx-inner-border;
   -fx-background-insets: 0, 1 0 1 0;
.split-pane *.horizontal-grabber {
    -fx-padding: 5 1 5 1;
    -fx-background-color: #FFFFFF, -fx-box-border;
    -fx-background-insets: 1 0 -1 0, 0;
    -fx-shape: "M0 0 L0 0 L2 0 L2 2 L0 2 Z M0 4 L0 4 L2 4 L2 6 L0 6 Z M0 8 L0 8 L2 8 L2 10 L0 10 Z";
.split-pane *.vertical-grabber {
    -fx-padding: 1 5 1 5;
    -fx-background-color: #FFFFFF, -fx-box-border;
    -fx-background-insets: 1 0 -1 0, 0;
    -fx-shape: "M0 0 L0 0 L2 0 L2 2 L0 2 Z M4 0 L4 0 L4 2 L6 2 L6 0 Z M8 0 L8 0 L8 2 L10 2 L10 0 Z";
}From: http://hg.openjdk.java.net/openjfx/2.2/master/rt/raw-file/tip/javafx-ui-controls/src/com/sun/javafx/scene/control/skin/caspian/caspian.css

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srinivasaditya wrote:
Hi
I am new to java programming. I have trouble understanding threading concepts.I'd consider it to be an advanced area.
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Thread thread1=new Thread(new RunnableThread(),"thread1");
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>
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Last edited by Triver (2014-11-23 16:13:07)

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Message was edited by:
venture

No. You have to do the factorial.
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etc
You should see a pattern ie 4! = 4 * 3!. In the
question you were given the equation for calculating
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it has been done millions of times before.
Slow! Well it is hard to type with these fins.
Message was edited by:
flounderThat makes sense thank you.

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return getValueAt(0, c).getClass();          // this
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Don't suppose you encountered the same problem?
Mike2z

Trouble understanding static

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    Test testThis = new Test(); //make an instance without a name
    Test testThisWithAName = new Test("nogoodatcoding"); //pass a cool name to the constructor :D
    //theNameMainGets = whatIsMyName(); //will not work since main is static, so even though it is part of the same class, it cannot call a non-static member, whatIsMyName, because a copy of that is with every instance, and when main calls it, the instance may not exist
    theNameMainGets = testThis.whatIsMyName(); //correct way to access the non-static member, by creating an instance and then using that to access it
    System.out.println(theNameMainGets);
    theNameMainGets = testThisWithAName.whatIsMyName();
    System.out.println(theNameMainGets);
    //note, you can't say, testThis.myName; since myName is private to testThis.
Test()
      myName = "No one named me";
Test( String newName )
      myName = newName;
    public String whatIsMyName()
      return myName;
}Hope this helps

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