Trying to build a random generator

Question

Hi, I am quite new to java and was wondering how do I complete building this program.
The objective of the program is to randomly generate 100 2 digit odd integer values.
I can generate the values but I don't know how to sieve only 100 odd integers.
I am also supposed to find the maximum, minimum and average of all the numbers generated. I can find the average but can't seem to find maximum and minimum.
I also need to point out the location of the maximum and minimum which I do not have a clue on how to do.
Lastly, my program is suppose to loop when keyed in 'y' or 'Y'. I think I have done that.
My codes are as below
import java.io.*;
class Question2
     public static void main (String args []) throws IOException
          BufferedReader stdin = new BufferedReader (new InputStreamReader(System.in));
          Question2 theClass = new Question2();
          String strValue = "";
          int value = 0;
          int random [] = new int [100];
          int l= random.length;
          int max=0, min=0;
          int sum = 0;
          do {
          System.out.print("Enter 'Y' to Start / Begin ");
          strValue = stdin.readLine();
          if (strValue.equalsIgnoreCase("Y")){
          for(int i = 0; i<l ; i++)
               if (i%10==0)
                    System.out.println("");
               random[i] = randomNumber(value);//recall method to generate numbers
               System.out.print(random[i] + " ");
               int maximum = random;
               max = findMaximum(maximum);//recall method for maximum
               int minimum = random[i];
               min = findMinimum(minimum);//recall method for minimum
               sum = sum + random[i];
          else
          break;
          int average=0;
          average = findAverage(sum);//recall method for average
          System.out.println("\nThe average is " + average);
          System.out.println("The Maximum Number is " + max);
          System.out.println("The Minimum Number is " + min);
     }while (strValue.equalsIgnoreCase("Y"));     
          //random number generator
     public static int randomNumber (int value)
          int choose=0;
          choose = 10 + (int)(Math.random()*89);
          return choose;
     //maximum number generator
     public static int findMaximum(int maximum)
          int maxi = 0;
          if (maximum>maxi)
          maxi=maximum;
          return maxi;
     //average generator
     public static int findAverage (int sum)
          int avg = 0;
          avg = sum/100;
          return avg;
//minimum generator
     public static int findMinimum(int minimum)
          int mini = 0;
          if (minimum<mini)
          mini = minimum;
          return mini;
Thank you.

Answer 1

Yes, but it guarantees that the process will be
complete after 100 iterations. The discarding
strategy will be completed in 200 iterations, on
average, and there is no guarantee that once in a
while, it will not take 1000 iterations.Pshaw. It's not that expensive to generate a new
number. Heck, Random.nextInt(int) numbers are
generated by throwing away numbers. There's a chance
that it will never return.
And if you are worried about that, I've got a server
to sell you.
~CheersI myself (almost) always prefer clarity over performance. In this case,
I think 2 * n + 1 produces both. You may say that I overdo it, for such
a simple exercise. This I don't dispute. By the way, the way nextInt() is
implemented is irrelevant, don't we like encapsulation anymore?