Two Product Hierarchies ?

Hi Gurus,
Kindly can any of had used two product hierarchies in same instance one for global & another for local country, if yes then hw was it maintained and what is the implications in planning & finance etc.
Thank you very much in Advance
and answers will rewarded with points.
Kind Regards
RK

Same instance means same client too, right?
Actually this question should belong to CO or SD forum since product hierarchy is mainly used there.
Baseline; it is possible to maintain globally (at basic data view) and locally (at sales view) differently. Most of the data used for sales reporting, pricing, and COPA reporting will use at local. You can also do the map using derivation in COPA to obtain "global" product hieararchy.
Hope it offer few helps.

Similar Messages

Product Hierarchies

Hi, I have two levels of Product Hierarchies. I am trying to find the PROD1 and PROD2 separately. In SAP the table T179 can show the hierarchies. But it shows the entire product hierarchy.
Can any one let me know the tables to find PROD1 and PROD2 separetely? I mean when I pass the product hierarchy to that table then it should show two levels.
Regards,
Raman

Can you check table V_T179?
Regards,

Performance issue with two unbanalnced hierarchies in a single report

Hi All
We are facing the performance issue with one of the report which houses two unbalanced hierarchies (having 18 levels) - skipped & ragged. Basically its a part of OBIAPPS financila analytics .
The query is below :
Could anyone let me know how to improve the performane. Any parameter that should be looked at while using unbalanced hierarchies.
WITH SAWITH0
AS ( SELECT SUM (T91707.OTHER_LOC_AMT) AS c1,
MAX (T314768.HIER2_CODE) AS c2,
MAX (T314768.HIER3_CODE) AS c3,
MAX (T314768.HIER4_CODE) AS c4,
MAX (T314768.HIER5_CODE) AS c5,
MAX (T314768.HIER6_CODE) AS c6,
MAX (T314768.HIER7_CODE) AS c7,
MAX (T314768.HIER8_CODE) AS c8,
MAX (T314768.HIER9_CODE) AS c9,
MAX (T314768.HIER10_CODE) AS c10,
MAX (T314768.HIER11_CODE) AS c11,
MAX (T314768.HIER12_CODE) AS c12,
MAX (T314768.HIER13_CODE) AS c13,
MAX (T314768.HIER14_CODE) AS c14,
MAX (T314768.HIER15_CODE) AS c15,
MAX (T314768.HIER16_CODE) AS c16,
MAX (T314768.HIER17_CODE) AS c17,
MAX (T314768.HIER18_CODE) AS c18,
MAX (T314768.HIER19_CODE) AS c19,
MAX (T314768.HIER20_CODE) AS c20,
T314768.HIER1_NAME AS c21,
T314768.HIER1_CODE AS c22,
T314914.HIER1_NAME AS c24,
T314914.HIER10_NAME AS c25,
T314914.HIER11_NAME AS c26,
T314914.HIER12_NAME AS c27,
T314914.HIER13_NAME AS c28,
T314914.HIER14_NAME AS c29,
T314914.HIER15_NAME AS c30,
T314914.HIER16_NAME AS c31,
T314914.HIER17_NAME AS c32,
T314914.HIER18_NAME AS c33,
T314914.HIER19_NAME AS c34,
T314914.HIER2_NAME AS c35,
T314914.HIER20_NAME AS c36,
T314914.HIER3_NAME AS c37,
T314914.HIER4_NAME AS c38,
T314914.HIER5_NAME AS c39,
T314914.HIER6_NAME AS c40,
T314914.HIER7_NAME AS c41,
T314914.HIER8_NAME AS c42,
T314914.HIER9_NAME AS c43,
T314914.HIER20_CODE AS c44,
T314914.HIER1_CODE AS c45,
T314914.HIER10_CODE AS c46,
T314914.HIER11_CODE AS c47,
T314914.HIER12_CODE AS c48,
T314914.HIER13_CODE AS c49,
T314914.HIER14_CODE AS c50,
T314914.HIER15_CODE AS c51,
T314914.HIER16_CODE AS c52,
T314914.HIER17_CODE AS c53,
T314914.HIER18_CODE AS c54,
T314914.HIER19_CODE AS c55,
T314914.HIER2_CODE AS c56,
T314914.HIER3_CODE AS c57,
T314914.HIER4_CODE AS c58,
T314914.HIER5_CODE AS c59,
T314914.HIER6_CODE AS c60,
T314914.HIER7_CODE AS c61,
T314914.HIER8_CODE AS c62,
T314914.HIER9_CODE AS c63
FROM W_HIERARCHY_D T314768 /* Dim_W_HIERARCHY_D_Segment11 */
W_GL_SEGMENT_D T315677 /* Dim_W_GL_SEGMENT_D_Segment11 */
W_HIERARCHY_D T314914 /* Dim_W_HIERARCHY_D_Segment13 */
W_GL_SEGMENT_D T315731 /* Dim_W_GL_SEGMENT_D_Segment13 */
W_GL_ACCOUNT_D T91397 /* Dim_W_GL_ACCOUNT_D */
W_GL_OTHER_F T91707 /* Fact_W_GL_OTHER_F */
WHERE ( T91397.ROW_WID = T91707.GL_ACCOUNT_WID
AND T91397.ACCOUNT_SEG11_CODE = T315677.SEGMENT_VAL_CODE
AND T91397.ACCOUNT_SEG13_CODE = T315731.SEGMENT_VAL_CODE
AND T91397.ACCOUNT_SEG11_ATTRIB = T315677.SEGMENT_LOV_ID
AND T91397.ACCOUNT_SEG13_ATTRIB = T315731.SEGMENT_LOV_ID
AND T314768.HIER_CODE = T315677.SEGMENT_LOV_ID
AND T314768.HIER_NAME = T315677.SEGMENT_LOV_NAME
AND T314768.HIERARCHY_ID = T315677.SEGMENT_VAL_CODE
AND T314914.HIER_CODE = T315731.SEGMENT_LOV_ID
AND T314914.HIER_NAME = T315731.SEGMENT_LOV_NAME
AND T314914.HIERARCHY_ID = T315731.SEGMENT_VAL_CODE
AND T315677.SEGMENT_LOV_NAME =
'Responsibility_Centre_Functional'
AND T315677.SEGMENT_LOV_ID = 1000163
AND T315731.SEGMENT_LOV_NAME = 'Account_Master'
AND T315731.SEGMENT_LOV_ID = 1000165
AND ( T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER11_CODE IS NULL)
AND (T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER12_CODE IS NULL)
AND ( T314914.HIER8_CODE IN ('S000005160')
OR T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER8_CODE IS NULL)
AND ( T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER9_CODE IS NULL)
AND ( T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER10_CODE IS NULL)
AND ( T314914.HIER1_CODE IN ('ALL_LI')
OR T314914.HIER2_CODE IN ('S000000001')
OR T314914.HIER3_CODE IN ('S000005150')
OR T314914.HIER4_CODE IN ('S000005151')
OR T314914.HIER5_CODE IN ('S000005153')
OR T314914.HIER6_CODE IN ('S000005154')
OR T314914.HIER7_CODE IN ('S000005062')
OR T314914.HIER8_CODE IN ('S000005160')
OR T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022'))
AND ( T314914.HIER2_CODE IN ('S000000001')
OR T314914.HIER3_CODE IN ('S000005150')
OR T314914.HIER4_CODE IN ('S000005151')
OR T314914.HIER5_CODE IN ('S000005153')
OR T314914.HIER6_CODE IN ('S000005154')
OR T314914.HIER7_CODE IN ('S000005062')
OR T314914.HIER8_CODE IN ('S000005160')
OR T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER2_CODE IS NULL)
AND ( T314914.HIER3_CODE IN ('S000005150')
OR T314914.HIER4_CODE IN ('S000005151')
OR T314914.HIER5_CODE IN ('S000005153')
OR T314914.HIER6_CODE IN ('S000005154')
OR T314914.HIER7_CODE IN ('S000005062')
OR T314914.HIER8_CODE IN ('S000005160')
OR T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER3_CODE IS NULL)
AND ( T314914.HIER4_CODE IN ('S000005151')
OR T314914.HIER5_CODE IN ('S000005153')
OR T314914.HIER6_CODE IN ('S000005154')
OR T314914.HIER7_CODE IN ('S000005062')
OR T314914.HIER8_CODE IN ('S000005160')
OR T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER4_CODE IS NULL)
AND ( T314914.HIER5_CODE IN ('S000005153')
OR T314914.HIER6_CODE IN ('S000005154')
OR T314914.HIER7_CODE IN ('S000005062')
OR T314914.HIER8_CODE IN ('S000005160')
OR T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER5_CODE IS NULL)
AND ( T314914.HIER6_CODE IN ('S000005154')
OR T314914.HIER7_CODE IN ('S000005062')
OR T314914.HIER8_CODE IN ('S000005160')
OR T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER6_CODE IS NULL)
AND ( T314914.HIER7_CODE IN ('S000005062')
OR T314914.HIER8_CODE IN ('S000005160')
OR T314914.HIER9_CODE IN ('S000000187')
OR T314914.HIER10_CODE IN ('S526003000')
OR T314914.HIER11_CODE IN ('S526002012')
OR T314914.HIER12_CODE IN ('S000001022')
OR T314914.HIER7_CODE IS NULL)
AND T314768.HIER1_CODE IS NOT NULL
AND T314914.HIER20_CODE IS NOT NULL
AND T314914.HIER13_CODE IS NULL
AND T314914.HIER14_CODE IS NULL
AND T314914.HIER15_CODE IS NULL
AND T314914.HIER16_CODE IS NULL
AND T314914.HIER17_CODE IS NULL
AND T314914.HIER18_CODE IS NULL
AND T314914.HIER19_CODE IS NULL)
GROUP BY T314768.HIER1_CODE,
T314768.HIER1_NAME,
T314914.HIER1_CODE,
T314914.HIER1_NAME,
T314914.HIER2_CODE,
T314914.HIER2_NAME,
T314914.HIER3_CODE,
T314914.HIER3_NAME,
T314914.HIER4_CODE,
T314914.HIER4_NAME,
T314914.HIER5_CODE,
T314914.HIER5_NAME,
T314914.HIER6_CODE,
T314914.HIER6_NAME,
T314914.HIER7_CODE,
T314914.HIER7_NAME,
T314914.HIER8_CODE,
T314914.HIER8_NAME,
T314914.HIER9_CODE,
T314914.HIER9_NAME,
T314914.HIER10_CODE,
T314914.HIER10_NAME,
T314914.HIER11_CODE,
T314914.HIER11_NAME,
T314914.HIER12_CODE,
T314914.HIER12_NAME,
T314914.HIER13_CODE,
T314914.HIER13_NAME,
T314914.HIER14_CODE,
T314914.HIER14_NAME,
T314914.HIER15_CODE,
T314914.HIER15_NAME,
T314914.HIER16_CODE,
T314914.HIER16_NAME,
T314914.HIER17_CODE,
T314914.HIER17_NAME,
T314914.HIER18_CODE,
T314914.HIER18_NAME,
T314914.HIER19_CODE,
T314914.HIER19_NAME,
T314914.HIER20_CODE,
T314914.HIER20_NAME),
SAWITH1
AS (SELECT SUM (D1.c1) OVER () AS c1,
MAX (D1.c2) OVER (PARTITION BY D1.c22) AS c2,
MAX (D1.c3) OVER (PARTITION BY D1.c22) AS c3,
MAX (D1.c4) OVER (PARTITION BY D1.c22) AS c4,
MAX (D1.c5) OVER (PARTITION BY D1.c22) AS c5,
MAX (D1.c6) OVER (PARTITION BY D1.c22) AS c6,
MAX (D1.c7) OVER (PARTITION BY D1.c22) AS c7,
MAX (D1.c8) OVER (PARTITION BY D1.c22) AS c8,
MAX (D1.c9) OVER (PARTITION BY D1.c22) AS c9,
MAX (D1.c10) OVER (PARTITION BY D1.c22) AS c10,
MAX (D1.c11) OVER (PARTITION BY D1.c22) AS c11,
MAX (D1.c12) OVER (PARTITION BY D1.c22) AS c12,
MAX (D1.c13) OVER (PARTITION BY D1.c22) AS c13,
MAX (D1.c14) OVER (PARTITION BY D1.c22) AS c14,
MAX (D1.c15) OVER (PARTITION BY D1.c22) AS c15,
MAX (D1.c16) OVER (PARTITION BY D1.c22) AS c16,
MAX (D1.c17) OVER (PARTITION BY D1.c22) AS c17,
MAX (D1.c18) OVER (PARTITION BY D1.c22) AS c18,
MAX (D1.c19) OVER (PARTITION BY D1.c22) AS c19,
MAX (D1.c20) OVER (PARTITION BY D1.c22) AS c20,
D1.c21 AS c21,
D1.c22 AS c22,
SUM (
D1.c1)
OVER (
PARTITION BY D1.c46,
D1.c47,
D1.c48,
D1.c49,
D1.c50,
D1.c51,
D1.c52,
D1.c53,
D1.c54,
D1.c55,
D1.c45,
D1.c44,
D1.c56,
D1.c57,
D1.c58,
D1.c59,
D1.c60,
D1.c61,
D1.c62,
D1.c63,
D1.c22)
AS c23,
D1.c24 AS c24,
D1.c25 AS c25,
D1.c26 AS c26,
D1.c27 AS c27,
D1.c28 AS c28,
D1.c29 AS c29,
D1.c30 AS c30,
D1.c31 AS c31,
D1.c32 AS c32,
D1.c33 AS c33,
D1.c34 AS c34,
D1.c35 AS c35,
D1.c36 AS c36,
D1.c37 AS c37,
D1.c38 AS c38,
D1.c39 AS c39,
D1.c40 AS c40,
D1.c41 AS c41,
D1.c42 AS c42,
D1.c43 AS c43,
D1.c44 AS c44,
D1.c45 AS c45,
D1.c46 AS c46,
D1.c47 AS c47,
D1.c48 AS c48,
D1.c49 AS c49,
D1.c50 AS c50,
D1.c51 AS c51,
D1.c52 AS c52,
D1.c53 AS c53,
D1.c54 AS c54,
D1.c55 AS c55,
D1.c56 AS c56,
D1.c57 AS c57,
D1.c58 AS c58,
D1.c59 AS c59,
D1.c60 AS c60,
D1.c61 AS c61,
D1.c62 AS c62,
D1.c63 AS c63
FROM SAWITH0 D1)
SELECT DISTINCT
38 AS c1,
D1.c24 AS c2,
D1.c25 AS c3,
D1.c26 AS c4,
D1.c27 AS c5,
D1.c28 AS c6,
D1.c29 AS c7,
D1.c30 AS c8,
D1.c31 AS c9,
D1.c32 AS c10,
D1.c33 AS c11,
D1.c34 AS c12,
D1.c35 AS c13,
D1.c36 AS c14,
D1.c37 AS c15,
D1.c38 AS c16,
D1.c39 AS c17,
D1.c40 AS c18,
D1.c41 AS c19,
D1.c42 AS c20,
D1.c43 AS c21,
D1.c21 AS c22,
NULL AS c23,
NULL AS c24,
NULL AS c25,
NULL AS c26,
NULL AS c27,
NULL AS c28,
NULL AS c29,
NULL AS c30,
NULL AS c31,
NULL AS c32,
NULL AS c33,
NULL AS c34,
NULL AS c35,
NULL AS c36,
NULL AS c37,
NULL AS c38,
NULL AS c39,
NULL AS c40,
NULL AS c41,
D1.c44 AS c42,
D1.c45 AS c43,
D1.c46 AS c44,
D1.c47 AS c45,
D1.c48 AS c46,
D1.c49 AS c47,
D1.c50 AS c48,
D1.c51 AS c49,
D1.c52 AS c50,
D1.c53 AS c51,
D1.c54 AS c52,
D1.c55 AS c53,
D1.c56 AS c54,
D1.c57 AS c55,
D1.c58 AS c56,
D1.c59 AS c57,
D1.c60 AS c58,
D1.c61 AS c59,
D1.c62 AS c60,
D1.c63 AS c61,
NULL AS c62,
D1.c22 AS c63,
NULL AS c64,
NULL AS c65,
NULL AS c66,
NULL AS c67,
NULL AS c68,
NULL AS c69,
NULL AS c70,
NULL AS c71,
NULL AS c72,
NULL AS c73,
NULL AS c74,
NULL AS c75,
NULL AS c76,
NULL AS c77,
NULL AS c78,
NULL AS c79,
NULL AS c80,
NULL AS c81,
D1.c23 AS c82,
CASE WHEN 1 = 1 THEN 1 ELSE 0 END AS c83,
CASE
WHEN D1.c2 IS NULL
AND D1.c3 IS NULL
AND D1.c4 IS NULL
AND D1.c5 IS NULL
AND D1.c6 IS NULL
AND D1.c7 IS NULL
AND D1.c8 IS NULL
AND D1.c9 IS NULL
AND D1.c10 IS NULL
AND D1.c11 IS NULL
AND D1.c12 IS NULL
AND D1.c13 IS NULL
AND D1.c14 IS NULL
AND D1.c15 IS NULL
AND D1.c16 IS NULL
AND D1.c17 IS NULL
AND D1.c18 IS NULL
AND D1.c19 IS NULL
AND D1.c20 IS NULL
THEN
1
ELSE
0
END
AS c84
FROM SAWITH1 D1
WHERE ( D1.c44 IS NOT NULL
AND D1.c50 IS NULL
AND D1.c49 IS NULL
AND D1.c22 IS NOT NULL
AND D1.c51 IS NULL
AND D1.c52 IS NULL
AND D1.c53 IS NULL
AND D1.c54 IS NULL
AND D1.c55 IS NULL)
/* Formatted on 12/17/2012 7:49:44 PM (QP5 v5.139.911.3011) */
WITH OBICOMMON0
AS (SELECT T156337.ROW_WID AS c2,
T156337.MCAL_PERIOD_WID AS c3,
ROW_NUMBER ()
OVER (PARTITION BY T156337.MCAL_PERIOD_WID
ORDER BY T156337.MCAL_PERIOD_WID DESC)
AS c4,
T156337.MCAL_PERIOD_NAME AS c5,
T156337.MCAL_PER_NAME_YEAR AS c6
FROM W_MCAL_DAY_D T156337 /* Dim_W_MCAL_DAY_D_Fiscal_Day */
WHERE (T156337.MCAL_CAL_NAME = 'Accounting')),
SAWITH0
AS (SELECT CASE
WHEN CASE D1.c4 WHEN 1 THEN D1.c2 ELSE NULL END
IS NOT NULL
THEN
RANK ()
OVER (
ORDER BY
CASE D1.c4 WHEN 1 THEN D1.c2 ELSE NULL END ASC NULLS LAST)
END
AS c1,
D1.c2 AS c2,
D1.c3 AS c3
FROM OBICOMMON0 D1),
SAWITH1
AS (SELECT DISTINCT
MIN (D1.c1) OVER (PARTITION BY D1.c3) AS c1, D1.c2 AS c2
FROM SAWITH0 D1),
SAWITH2
AS (SELECT CASE
WHEN CASE D1.c4 WHEN 1 THEN D1.c2 ELSE NULL END
IS NOT NULL
THEN
RANK ()
OVER (
ORDER BY
CASE D1.c4 WHEN 1 THEN D1.c2 ELSE NULL END ASC NULLS LAST)
END
AS c1,
D1.c3 AS c2,
D1.c5 AS c3,
D1.c6 AS c4
FROM OBICOMMON0 D1),
SAWITH3 AS (SELECT DISTINCT MIN (D1.c1) OVER (PARTITION BY D1.c2) AS c1,
D1.c2 AS c2,
D1.c3 AS c3,
D1.c4 AS c4
FROM SAWITH2 D1),
SAWITH4
AS ( SELECT SUM (T91707.TD_OTHER_REP_AMT) AS c1,
T314914.HIER1_NAME AS c2,
D2.c3 AS c3,
T314914.HIER1_CODE AS c4,
D2.c2 AS c5
FROM W_HIERARCHY_D T314914 /* Dim_W_HIERARCHY_D_Segment13 */
W_GL_SEGMENT_D T315731 /* Dim_W_GL_SEGMENT_D_Segment13 */
W_GL_ACCOUNT_D T91397 /* Dim_W_GL_ACCOUNT_D */
W_GL_OTHER_F T91707 /* Fact_W_GL_OTHER_F */
SAWITH1 D4,
SAWITH3 D2
WHERE ( T314914.HIER_CODE = T315731.SEGMENT_LOV_ID
AND T314914.HIER_NAME = T315731.SEGMENT_LOV_NAME
AND T91397.ROW_WID = T91707.GL_ACCOUNT_WID
AND T91707.ACCT_PERIOD_END_DT_WID = D4.c2
AND T314914.HIERARCHY_ID = T315731.SEGMENT_VAL_CODE
AND T91397.ACCOUNT_SEG13_CODE = T315731.SEGMENT_VAL_CODE
AND T91397.ACCOUNT_SEG13_ATTRIB = T315731.SEGMENT_LOV_ID
AND T315731.SEGMENT_LOV_NAME =
'Account_Retail_Distribution'
AND T315731.SEGMENT_LOV_ID = 1000165
AND D2.c1 = D4.c1
AND (D2.c4 IN ('2011', '2012')))
GROUP BY T314914.HIER1_CODE,
T314914.HIER1_NAME,
D2.c2,
D2.c3)
SELECT D1.c1 AS c1,
D1.c2 AS c2,
D1.c3 AS c3,
D1.c4 AS c4,
D1.c5 AS c5,
D1.c6 AS c6
FROM ( SELECT DISTINCT 0 AS c1,
D1.c2 AS c2,
D1.c3 AS c3,
D1.c4 AS c4,
D1.c1 AS c5,
D1.c5 AS c6
FROM SAWITH4 D1
ORDER BY c2 NULLS FIRST, c4 NULLS FIRST, c3) D1
WHERE ROWNUM <= 65001

Hello Gurus, Experts
Any help/tips here ...

How to sort two different hierarchies in one dimension

Does anyone know of a way to sort two different hierarchies in one dimension and still make drilling work correctly? We have two hierarchies in our item dimension; one called category and the other origin. Simplified, it looks like this:
CATEGORY
Hardware (100)
..PCs (100.100)
....PC 1
....PC 2
....PC 3
..Monitors (100.200)
....Monitor 1
....Monitor 2
....Monitor 3
Software (200)
..Big (200.100)
....ERP package
....CRM package
..Small (200.200)
....Solitaire
....Mine Sweeper
ORIGIN
Vendor A (10)
..Site A1 (10.10)
....ERP package
..Site A2 (10.20)
....PC 1
....Monitor 3
Vendor B (20)
..Site B1 (20.10)
....PC 2
....PC 3
....Monitor 1
....Monitor 2
....Solitaire
....Mine Sweeper
..Site B2 (20.20)
....CRM package
We have numeric codes at each level above item which I represents the sort order (the number in parentheses at each level), and the items themselves should be sorted according to item number. I have implemented this (level code/item number) as an attribute in AWM making this the default sort order. However, as item is the lowest level in each hierarchy, I have only been able to list the items under the correct level in one hierarchy. As soon as I drill using the other hierarchy, the levels above item are sorted correctly, but the items appear at very odd places...
The AWM documentation states that if default order is not selected on any attribute, hierarchies are sorted in the order they are created. Is there a way to control this order?
Any input will be greatly appreciated!

Hi,
thank you for your answer. Yes, now I also find the class CL_SALV_WD_MULTI_CELL_EDITOR which could be used to set different UIE in one cell. But it is quite limited, just the following UIE could be used
- LinkToAction
- LinkToURL
- FileDownload
- Button
- ToggleButton
best regards,
Wenwen

How to use Multiple Product Hierarchies in Shopping Cart creation

Dear SRM Experts,
We have an issue in using multiple Product Hierarchies while creating a shopping cart. Need your help to resolve this.
Our SRM system is integrated with 2 ERP back-end systems. In material replication we have created 2 hierarchies for different ERPs and their product categories are stored in respective hierachies.
Example:
EBPMATCLAS is for ERP1
EBPSERVCAT is for ERP2
Now when I create shopping cart, it allows only those products which are part of EBPMATCLAS because of below configuration..
We cant configure multiple hierarchies for purchasing so we are not able to use both Hierarchies simultaneously.
Request you to help with the possible solution to use multiple hierarchies.
Thanks
Rajan

Hi Rajan,
You not need to create 2 hierarchy ID. Inside the R3MATCLASS you can see the reference with both banckends.
Ex:
R3MATCLASSECCCLNT001
R3MATCLASSECCCLNT002
Rgs,
Pedro Marques

Can a same member be in two product group?

hi,
Can we plan for a member which is part of two Product group. Right now I see when transfer demand from Second PG, the calculations and PIR out of first PG is getting overwritten. My requirement is to add to existing PIR rather than overwriting it. Is it possible?
regards
Rav

I think you're confusing Albums and Projects.
each time i connect my camera to the laptop, i import the photos to a new album,
No you don't. You can't import to an Album, you import to a Project. A Project has a Box like icon. Projects are a reflection of the organisation if the originals on the HD. Move a shot from one project to another and the file moves too. You cannot have a photo in more than one project +without duplicating the file+.
Albums, on the other hand, have an icon like a Blue Book. You can have Albums that refer within a single project and Albums that refer all over the Library. Create an album (File -> New -> Album) and drag the images you want to it. The Files remain in their respective projects and are simply linked to the Album. Photos can be in 100's of Albums with no duplication.
I have previously created an album called 'the best shots of 2010',i now want to add some photos to this album
Use ratings and a Smart Album and do this automatically.
Regards
TD

Free goods secquence with customer hierarchie and product hierarchie

Hi guru's,
I'm currently working with a secquency for free goods with customer hierarchie ans product hierarchie, but is giving me a lot of problems of dums , I think that SAP standard doesn't allow it because the customicing is diferent than the secquence for pricing that has 2 more fields open: V_T682Z-FSTST and V_T682Z-MBWRT that could allow me to set the levels of the hierarchie. Despite it works with the same table T682Z.
Has anybody had the same problem as me? Can you help me please.
Marta Gallego

Maintain your entries in " Determine Item Category For Free Goods Item"
For the combination of Order Type-ItemCatgrp(ERLA)-Usage(Free)-Item Category(Tan)
Lets see if it works for you.

Same logical system name for two productive systems - BW, PI issues

Dear all,
we have a productive system which serves two companies (different company codes). This system is connected both to BW and PI for both companies.
There is a requirement that these two companies must use their own system, so the whole landscape (dev,qa,prd) will be copied to different systems (different server with different system id).
As a result of the above procedure we wll have two different productive systems, as required, but we wll have the same logical system name for the two productive systems, which must be both connect to bw and PI.
However as far as I know:
- we cannot connect systems with same logical system name to BW,PI
- we cannot convert logical system name of the one of the two productive systems as they are productive and so this is not supported.
How can we overcome the problem?
Please advice.

> However as far as I know:
> - we cannot connect systems with same logical system name to BW,PI
> - we cannot convert logical system name of the one of the two productive systems as they are productive and so this is not supported.
Right.
> How can we overcome the problem?
Since you split up systems (or plan to) I highly recommend booking an SLO service (http://service.sap.com/slo). Those people have to the tools and the knowlege to help you. I would not do this on my own.
Markus

Two production orders at the header level one for one single requirement

Hi Gurus, Please provide me your valuable suggestion on the issue.
*Client wants to have a only two production orders at the header level one for one single requirement .*
1) Manufacturing Order u2013 In this order for Finsihed prodcut system should pick all the assemblies whcih are manufactured inside i.e depending on the material type.\
2) Assembly order u2013 In this order system should pick all the assemblies whicih need to be assembled also procured or subcontracted items in this order against depending on the material type.
It means for Sales order of 5 EA there is going to be only 2 order ( MFG & assy order).
For Example.
L45-7000 is the header material now client wants only two production orders one Manufacture order and anothe Assmebly order , thet dont want to use Phantom assembly concept and also multiple production orders for SFG.
Please confirm if this requirement can be mapped in SAP ?
Thanks...

Hi Shishir,
As soon as each order is related to only one material, if your manufactured (or purchased) assemblies are of different materials, you will have a separate order for each material rather than a single order for all manufactured assemblies. I don't thing all your assemblies are of the same material - thus I would say no, it is not possible to map your requirement.
Regards,
Sergiy

Product Hierarchies in COPA

Folks,
I'm trying to figure out how to configure the product hierarchies in CO-PA in ECC 6.0 version. I saw an OSS note -62690- that talks about an "automated" solution for the more current releases. However, it doesn't give specifics around how it works.
Could someone please explain how it works step by step. I also keep getting this information message that says :
Product hierarchy field PAPH1 cannot be adapted to the new structure Message no. KE691
When I try to add the hierarchy characteristics from Table MARA, (like PAPH1, PAPH2 etc.), I realize that they are not available anymore. What could be causing this problem? Any ideas on a solution?
Your help will be greatly appreciated
Baris

Hi Maruthi,
thank you for your feedback. But I don't think that answers my question. The product hierarchies are already maintained in the material master. So, I don't think they need to be maintained again using the transaction KEDE. Am I missing something here?
Thanks,

Linking two different Hierarchies

Hi,
i have got two external hierarchies for 0Material. i want to link one of the hierarchy to the other at level 4 as both of them are same after level 3. is there any possible way two link both of them.
Thank you,
Ravi.

Hello Ravi,
no, we can not link two or more external hirarchies.
Reg.
michael

Transferring data between two production servers

HI All,
I have read weblogs in transferring scenarios from Dev to Qual to Prod.
But I have a different requirement in which I have to transfer data from one production server to another production server without distrubing the first production server.
Say A and B are two production servers, I wanted to transfer data from A to B on daily basis.
Please give me some ideas on this....
Thanks
Veni

Hello,
I would suggest to use IDOC for transferring data (master \ transaction ) ... to do that you need to setup logical system (prod b) and RFC connection to connect to system prod b ...
Also distributional model need to setup for pushing the outbound idoc into RFC connection through receiver port.
Thanks
Krish

Two production client on one instance

Hi everyone.!
Can there be two production client on a single instance.
If yes then how ?
Thanks in advance
Puneet

Please see SAP note 31557 for multiple client concept.

Data Guard two Production sites

I am exploring the best (and least expensive) way to configure Data Guard in our environment.
Has anyone had two production environments, each in a different location and set up Standby Data Guard databases across each.
For example -
Site 1 - Prod RAC 1 with database 1 and a standby for database 2
Site 2 - Prod RAC 2 with database 2 and a standby for database 1
Is there any load to the resources in either cluster when also maintaining a standby database along with production?
I searched Metalink and was not able to find information on this type of configuration.
Thanks!

Yes, your understanding is correct. I simplified our environment for the question, actually we have two sites in different geographic locations.
Site 1 is production and Site 2 is Development, but we want to protect each site for Disaster Recovery, etc.
Site 1 has a three node rac cluster with a 'PRD_A' database and Site 2 has a three node rac cluster with a 'PRD_B'.
So, I would like to create, just as you said, a standby for PRD_A in the Site 2 cluster & create standby for PRD_B in the Site 1 cluster.
And, actually, each site has 2-3 databases running that I would like to create standby's for. This is why I am wondering if anyone has done this and if the load would be an issue. Yo Yo got it ;-)
See PRD_A has 3 instances let suppose PRD_A1, PRD_A2, PRD_A3.
PRD_B has 3 instances let suppose PRD_B1, PRD_B2, PRD_B3
So for PRD_A you can create either one standby database as PRD_A_STBY.
or you can create three standby databases as PRD_A1_STBY, PRD_A2_STBY, PRD_A3_STBY on CLUSTER B
For PRD_B you can create either one standby database as PRD_B_STBY.
or you can create three standby databases as PRD_B1_STBY, PRD_B2_STBY, PRD_B3_STBY on CLUSTER A
But Recovery process will be performed any one of the standby of one database, Remaining standby databases will sit idle.
(or)
You can have only one standby database, So the database itself clustered so you can add instances if in case of Switchover/Failover.
Here you will have two database on each instance.
Here the things
1) how much RAM
2) is it server capable to hold two instances?

Photoshop Elements 7. Two product numbers? What's the difference?

I was looking to buy Adobe Photoshop Elements 7.
But it seems like there are two model/product numbers for Elements 7.
One is 65026616 and the other is 65026821.
The 65026616 is listed as Adobe Photoshop Elements 7 - Mini Box - Retail
The 65026821 is listed as Adobe Adobe Photoshop Elements 7 - Retail
Does anyone know what the difference between these two product number is other than one being a mini box?
I found these two versions on newegg. Amazon has the mini box product number.

IIRC, Adobe has two different packages...one for shipping that's smaller
and lighter and the other for store shelves that's bigger and harder to
steal.
Bob

Two Product Hierarchies ?

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