Unable to understand Connect by with this SQL

I have to generate a sequence like this for a record based on the count. For eg., E1 has a value 4, then the SQL below
with tmp as
select 'E1' as emp, 4 as cnt from dual
SELECT emp, LEVEL rn
FROM tmp
CONNECT BY LEVEL < cnt + 1 ;
produces 4 records
E1,1
E2,1
E3,1
E4,1
But, when I have another record E2 also as shown below
with tmp as
select 'E1' as emp, 4 as cnt from dual
union
select 'E2' as emp, 4 as cnt from dual
SELECT emp, LEVEL rn
FROM tmp
CONNECT BY LEVEL < cnt + 1 ;
it produces 30 records. I was expecting only 8. I had to put a distinct to avoid it. So, can I generate 4 for each E1,E2 without using distinct.
The actual table that I have is a huge table and so trying to avoid distinct. Thanks.
Satish

Hi, Satish,
user572405 wrote:
I have to generate a sequence like this for a record based on the count. For eg., E1 has a value 4, then the SQL below
with tmp as
select 'E1' as emp, 4 as cnt from dual
SELECT emp, LEVEL rn
FROM tmp
CONNECT BY LEVEL < cnt + 1 ;
produces 4 records
E1,1
E2,1
E3,1
E4,1Really?
When I run that, I get this output:
EM         RN
E1          1
E1          2
E1          3
E1          4
But, when I have another record E2 also as shown below
with tmp as
select 'E1' as emp, 4 as cnt from dual
union
select 'E2' as emp, 4 as cnt from dual
SELECT emp, LEVEL rn
FROM tmp
CONNECT BY LEVEL < cnt + 1 ;
it produces 30 records. I was expecting only 8. I had to put a distinct to avoid it. So, can I generate 4 for each E1,E2 without using distinct.
The actual table that I have is a huge table and so trying to avoid distinct. Thanks."CONNECT BY LEVEL < x" (with no other conditions) should only be used on one-row tables, like dual.
Perhaps you need to join such a result set to another table (or result set), like this:
WITH     emps     AS
     SELECT     'E1' AS emp,     4 AS cnt     FROM dual
     UNION ALL
     SELECT     'E2' AS emp,     4 AS cnt     FROM dual
,     cntr     AS
     SELECT     LEVEL     AS rn
     FROM     dual
     CONNECT BY     LEVEL     <=
               SELECT     MAX (cnt)
               FROM     emps
SELECT     emp
,     rn
FROM     emps
JOIN     cntr     ON     cntr.rn     <= emps.cnt
;which produces:
EM         RN
E1          1
E2          1
E1          2
E2          2
E1          3
E2          3
E1          4
E2          4Edited by: Frank Kulash on Dec 31, 2008 3:44 PM

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    10                              ' day of '||
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    Entrez une valeur pour dt2 : '2009-02-15'
    ancien   6 : (Y[FOR X FROM DATE  &DT1 TO DATE &DT2 INCREMENT INTERVAL '1' DAY ]=0,
    nouveau   6 : (Y[FOR X FROM DATE  '2008-12-15' TO DATE '2009-02-15' INCREMENT INTERVAL '1' DAY ]=0,
    Entrez une valeur pour dt1 : '2008-12-15'
    Entrez une valeur pour dt2 : '2009-02-15'
    ancien   7 : PP[FOR X FROM DATE  &DT1 TO DATE &DT2 INCREMENT INTERVAL '1' DAY ]=
    nouveau   7 : PP[FOR X FROM DATE  '2008-12-15' TO DATE '2009-02-15' INCREMENT INTERVAL '1' DAY ]=
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    ancien   8 :    DECODE(MOD(CV(X)- TO_DATE(&DT1,'YYYY-MM-DD'),7),0,'First',1,'Second ',2,
    nouveau   8 :    DECODE(MOD(CV(X)- TO_DATE('2008-12-15','YYYY-MM-DD'),7),0,'First',1,'Second ',2,
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    2008-12-15 First day of first week
    2008-12-16 Second  day of first week
    2008-12-17 Third day of first week
    2008-12-18 Fourth day of first week
    2008-12-19 Fifth day of first week
    2008-12-20 Sixth day of first week
    2008-12-21 Seventh day of first week
    2008-12-22 First day of second week
    2008-12-23 Second  day of second week
    2008-12-24 Third day of second week
    2008-12-25 Fourth day of second week
    SO         PATERN
    2008-12-26 Fifth day of second week
    2008-12-27 Sixth day of second week
    2008-12-28 Seventh day of second week
    2008-12-29 First day of first week
    2008-12-30 Second  day of first week
    2008-12-31 Third day of first week
    2009-01-01 Fourth day of first week
    2009-01-02 Fifth day of first week
    2009-01-03 Sixth day of first week
    2009-01-04 Seventh day of first week
    2009-01-05 First day of second week
    SO         PATERN
    2009-01-06 Second  day of second week
    2009-01-07 Third day of second week
    2009-01-08 Fourth day of second week
    2009-01-09 Fifth day of second week
    2009-01-10 Sixth day of second week
    2009-01-11 Seventh day of second week
    2009-01-12 First day of first week
    2009-01-13 Second  day of first week
    2009-01-14 Third day of first week
    2009-01-15 Fourth day of first week
    2009-01-16 Fifth day of first week
    SO         PATERN
    2009-01-17 Sixth day of first week
    2009-01-18 Seventh day of first week
    2009-01-19 First day of second week
    2009-01-20 Second  day of second week
    2009-01-21 Third day of second week
    2009-01-22 Fourth day of second week
    2009-01-23 Fifth day of second week
    2009-01-24 Sixth day of second week
    2009-01-25 Seventh day of second week
    2009-01-26 First day of first week
    2009-01-27 Second  day of first week
    SO         PATERN
    2009-01-28 Third day of first week
    2009-01-29 Fourth day of first week
    2009-01-30 Fifth day of first week
    2009-01-31 Sixth day of first week
    2009-02-01 Seventh day of first week
    2009-02-02 First day of second week
    2009-02-03 Second  day of second week
    2009-02-04 Third day of second week
    2009-02-05 Fourth day of second week
    2009-02-06 Fifth day of second week
    2009-02-07 Sixth day of second week
    SO         PATERN
    2009-02-08 Seventh day of second week
    2009-02-09 First day of first week
    2009-02-10 Second  day of first week
    2009-02-11 Third day of first week
    2009-02-12 Fourth day of first week
    2009-02-13 Fifth day of first week
    2009-02-14 Sixth day of first week
    2009-02-15 Seventh day of first week
    63 ligne(s) sélectionnée(s).
    SQL>  Edited by: Salim11 on 2008-11-19 08:16
    Edited by: Salim11 on 2008-11-19 08:17
    Edited by: Salim11 on 2008-11-19 08:18

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