Uninstalling java apps.

Hello...
I'm having a bad experience over here cause I cant use or Uninstall ANY java app on My nokia 5530.
"Internal Errorending stop app request to JavaCaptain Failed"
I have been trying all to solve this but I cant.
Please help me!
Thanks.
Solved!
Go to Solution.

I am presuming you have installed this software on a memory card - this error is mainly caused to removing the memory card when apps etc are on there
first try a soft reset (only resets settings no data deleted) *#7780#
however if that doesn't work you may have to format your memory card
CJSS IT & Multimedia Solutions
http://cjss.eu.org
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Version:               ???
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Parent Process:        ??? [1]
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User ID:               501
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Report Version:        11
Anonymous UUID:        EA1D0E4A-3CF8-8A05-1534-23A3AE6FEC43
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Try re-installing over the existing install. Adobe CC 2014 Direct Download Links: Creative Cloud 2014 Release | ProDesignTools

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<pre>
import java.util.Properties;
import java.io.FileInputStream;
import java.io.IOException;
import java.lang.reflect.Method;
import java.lang.reflect.InvocationTargetException;
import java.util.Enumeration;
import java.util.NoSuchElementException;
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private String iProg;
private String iArgs[];
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try
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p[0] = String[].class;
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System.out.println(iProg + "NoSuchMethodException");
catch(InvocationTargetException e)
System.out.println(iProg + "NoSuchMethodException");
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System.out.println(iProg + "NoSuchMethodException");
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* inner-class to analyze StringTokenizer. This class is enhanced to check double Quotation marks
protected class StringTokenizer implements Enumeration
private int currentPosition;
private int maxPosition;
private String str;
private String delimiters;
private boolean retTokens;
* Constructs a string tokenizer for the specified string. All
* characters in the <code>delim</code> argument are the delimiters
* for separating tokens.
* <p>
* If the <code>returnTokens</code> flag is <code>true</code>, then
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* @return <code>true</code> if and only if there is at least one token
* in the string after the current position; <code>false</code>
* otherwise.
public boolean hasMoreTokens()
skipDelimiters();
return(currentPosition < maxPosition);
* Returns the next token from this string tokenizer.
* @return the next token from this string tokenizer.
* @exception NoSuchElementException if there are no more tokens in this
* tokenizer's string.
public String nextToken()
skipDelimiters();
if(currentPosition >= maxPosition)
throw new NoSuchElementException();
int start = currentPosition;
boolean inQuotation = false;
while((currentPosition < maxPosition) &&
(delimiters.indexOf(str.charAt(currentPosition)) < 0 || inQuotation))
if(str.charAt(currentPosition) == '"')
inQuotation = !inQuotation;
currentPosition++;
if(retTokens && (start == currentPosition) &&
(delimiters.indexOf(str.charAt(currentPosition)) >= 0))
currentPosition++;
String s = str.substring(start, currentPosition);
if(s.charAt(0) == '"')
s = s.substring(1);
if(s.charAt(s.length() - 1) == '"')
s = s.substring(0, s.length() - 1);
return s;
* Returns the next token in this string tokenizer's string. First,
* the set of characters considered to be delimiters by this
* <tt>StringTokenizer</tt> object is changed to be the characters in
* the string <tt>delim</tt>. Then the next token in the string
* after the current position is returned. The current position is
* advanced beyond the recognized token. The new delimiter set
* remains the default after this call.
* @param delim the new delimiters.
* @return the next token, after switching to the new delimiter set.
* @exception NoSuchElementException if there are no more tokens in this
* tokenizer's string.
public String nextToken(String delim)
delimiters = delim;
return nextToken();
* Returns the same value as the <code>hasMoreTokens</code>
* method. It exists so that this class can implement the
* <code>Enumeration</code> interface.
* @return <code>true</code> if there are more tokens;
* <code>false</code> otherwise.
* @see java.util.Enumeration
* @see java.util.StringTokenizer#hasMoreTokens()
public boolean hasMoreElements()
return hasMoreTokens();
* Returns the same value as the <code>nextToken</code> method,
* except that its declared return value is <code>Object</code> rather than
* <code>String</code>. It exists so that this class can implement the
* <code>Enumeration</code> interface.
* @return the next token in the string.
* @exception NoSuchElementException if there are no more tokens in this
* tokenizer's string.
* @see java.util.Enumeration
* @see java.util.StringTokenizer#nextToken()
public Object nextElement()
return nextToken();
* Calculates the number of times that this tokenizer's
* <code>nextToken</code> method can be called before it generates an
* exception. The current position is not advanced.
* @return the number of tokens remaining in the string using the current
* delimiter set.
* @see java.util.StringTokenizer#nextToken()
public int countTokens()
int count = 0;
int currpos = currentPosition;
while(currpos < maxPosition)
* This is just skipDelimiters(); but it does not affect
* currentPosition.
while(!retTokens &&
(currpos < maxPosition) &&
(delimiters.indexOf(str.charAt(currpos)) >= 0))
currpos++;
if(currpos >= maxPosition)
break;
int start = currpos;
boolean inQuotation = false;
while((currpos < maxPosition) &&
(delimiters.indexOf(str.charAt(currpos)) < 0 || inQuotation))
if(str.charAt(currpos) == '"')
inQuotation = !inQuotation;
currpos++;
if(retTokens && (start == currpos) &&
(delimiters.indexOf(str.charAt(currpos)) >= 0))
currpos++;
count++;
return count;
</pre>
RunProg.properties like this:
Prog1=GetEnv 47838 837489 892374 839274
Prog0=GetEnv "djkfds dfkljsd" dsklfj

Open java app and insert text

Hello All!
I'm looking for a little help on an exact problem that seems to have been solved here before (but doesn't work for me).
Here's the original archived thread:
https://discussions.apple.com/thread/2631967?start=0&tstart=0
The question asked is exactly the same....
I have a java app for a Speco Technologies DVR. After opening the app, you must type in a rather long url and then click connect. If you enter the url, then quit the app, when you relaunch it, it does not remember the url that had been entered the previous time.
I would like to create a script that will launch the Java app and then input the url (text string). I cannot get this to work.
I've gotten as far as this:
on run
tell application "Finder" to activate open document file "DVRVIEWER(DO_NOT_DELETE).jar" of folder "Applications" of startup disk
delay 5
set myString to "192.168.0.118"
repeat with currentCharacter in every character of myString
tell application "system events"
keystroke currentCharacter
end tell
delay 0.25
end repeat
tell application "system events"
keystroke return
end run
AppleScript has a Syntax Error of "Expected end of line, etc. but found command name."
Does anyone ( taylor.henderson where are you! ) have a fix, or even a better way to do this? Can I edit the existing .jar to have the info directly in there?
I would actually love to add another section in there that fills in the username and password after entering in the IP address!
Just for clarification on how this goes:
Launch .jar.
Window Launches and prompts for IP address
Enter in IP address
Press RETURN
Windows disappears and new window appears and prompts for username and password
Enter Username
Press TAB
Enter Password
Press RETURN
Thank you guys, I'm sure it's easy, but hey, for me Photoshop and Illustrator are a breeze :-0
-AndyTheFiredog

Hi
andythefiredog wrote:
Is it possible to use similar commands to maximize the java window?
Yes.
You must enable the checkbox labeled "Enable access for assistive devices" in the Universal Access System Preference pane
Add these lines after the last line wich contains "keystroke return"
delay 2
tell (first process whose frontmost is true) to click button 2 of window 1 -- zoom
Here's my test script ( the Speco camera demo), that works without problems here, I use the application "DVRJavaView4.1.jar", this script checks the existence of ui element (more reliable) rather than any delay.
on run
     do shell script "/usr/bin/open '/Applications/DVRJavaView4.1.jar'"
     tell application "System Events" to tell (first process whose frontmost is true)
          repeat until exists window "Please Input DVR address"
               delay 1
          end repeat
          keystroke "millapt.ddns.specoddns.net"
          keystroke return
          repeat until exists button "OK" of window 1
               delay 1 -- wait until the login window is frontmost
          end repeat
          keystroke "user"
          keystroke tab
          delay 0.1
          keystroke "4321"
          delay 0.1
          keystroke return
          repeat until name of window 1 starts with "DVRJavaView"
               delay 1 --wait while the login window is frontmost
          end repeat
          click button 2 of window 1 -- zoom
     end tell
end run

Uninstalled Java 6, installed Java 7, keep getting requests to install Java SE 6 plugin. Why?

Because of the security issues with Java, I uninstalled Java 6 (using various terminal commands) and installed Java 7 from Oracle's website. Looking at /Library/Internet Plug-Ins, I can see that JavaAppletPlugin.plugin is there, and Get Info tells me that it is part of Java 7 Update 09.
However, when I use Safari to try out a Java test page, or use one of the Java-based programs that I need to run for work, I get a message that says, "To open “PluginProcess,” you need a Java SE 6 runtime. Would you like to install one now?" (PluginProcess is replaced by the program name if I am running a Java program.) If I click "Install", the Apple version of Java 6 gets installed.
This doesn't make sense to me. Why would Java 7 need the Apple Java 6 environment? And why doesn't Safari or other Java based programs recognize that the Java 7 JavaAppletPlugin.plugin is on my computer already?
Although I'm not really an IT person, I am pretty handy with the Terminal and command line operations, so if fixing this means using the command line, I'm good with that.
Thanks!

I think I've found a solution to the problem that Java Applications doesn't use Java 7. This seems to work for me. Try it and please confirm if it works for you.
1.
Install Java SE Development Kit 7u9 from Oracle
http://www.oracle.com/technetwork/java/javase/downloads/jdk7u9-downloads-1859576 .html
2.
Execute something that triggers the prompt to install Java SE 6. for example i web site using java applet. And follow through with the installation. (after this you will have three java versions: Java6 32-bit, Java6 64-bit, Java7 64-bit)
3.
Open a new terminal window and execute the following commands.
$ cd /System/Library/Frameworks/JavaVM.framework/Versions
$ sudo rm CurrentJDK
Password: ********
$ sudo ln -s /Library/Java/JavaVirtualMachines/jdk1.7.0_09.jdk/Contents/ CurrentJDK
$ sudo ln -s CurrentJDK 1.7
$ sudo ln -s CurrentJDK 1.7.0
Note: I don't know if the last two lines are necessary, but I just tried to follow the existing pattern.

How do I uninstall an app from my Mac?

Hello,
How do I uninstall an app from my Mac? do I just drag it to the trash?
Thank you

http://guides.macrumors.com/Uninstalling_Applications_in_Mac_OS_X

Uninstalling java apps.

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