Unzip files

Can someone please tell me if there is an easy way to unzip files with the hardware/software that comes with an Apple OSX SnowLeopard? If so, I would appreciate very simple step by step instructions as to how to do this as I am fairly ignorant about the Mac systems. I've used PC's for years and this Mac is new to me. Thanks very much for any help.
Respectfully
Jim

You mean that's all there is to it?
Wow, that was easy enough. Thanks a million Neil I sure appreciate the help.
Jim

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Unzipping Files in the wrong folder

Hi
I am trying to unzip files. It works fine except that it unzips the files at the root. So i have tried specifying the path for making the directory (in which the unzipped files are stored). But that doesnt seem to work. Now i am unable to find the unzipped files. CAN ANYONE HELP PLEASE
public static void unzipFile(String zFile)
        Enumeration entries;
        ZipFile zipFile;
       try {
            zipFile = new ZipFile(zFile);
            File file = new File(zipFile.getName());
            String fname = file.getName();
           String substr1 = fname.substring(0, fname.indexOf("."));
            String filepath = "/data/psawant/temp";
            File dir = new File(filepath, substr1);
            try {
                    dir.mkdir();
            catch (Exception fe)
                  System.err.println("Unhandled exception:");
                    fe.printStackTrace();
                    return;
            entries = zipFile.entries();
            while(entries.hasMoreElements()) {
                ZipEntry entry = (ZipEntry)entries.nextElement();
                if(entry.isDirectory())
                     // Assume directories are stored parents first then children.
                    System.err.println("Extracting directory: " + entry.getName());
                                      (new File(entry.getName())).mkdir();
                    continue;
                } //end of if
                System.err.println("Extracting file: " + entry.getName());
                copyInputStream(zipFile.getInputStream(entry),
                    new BufferedOutputStream(new FileOutputStream(entry.getName())));
             } //end of while
            zipFile.close();
               } catch (IOException ioe) {                 }
         } //end of unzip function
public static final void copyInputStream(InputStream in, OutputStream out)
    throws IOException
        byte[] buffer = new byte[1024];
        int len;
        while((len = in.read(buffer)) >= 0)
        out.write(buffer, 0, len);
        in.close();
        out.close();
Any help is apprciated
Thanx

Sorry I got it this time. I had overlooked the new File. I added that & it works fine but there seems to be some problem
If the folder has another folder inside . it doesnt show that one. or rather just unzips one folder & no folders inside it. But i guess i can check for that
Thanx for u r help
Have a nice day

UNZIP file from ABAP

Hi,
I have a requirement to retrieve a zip file from the FTP Server, unzip it to the SAP Server and process the unzipped files. Retrieving the data from the FTP server should work via FTP commands which can be executed from within an ABAP program. However, the problem is unzipping these files via ABAP and put them on the server as well. 1. How to do this from within an ABAP Program? (unix commands?)
2. Can I unzip these files with or without using the folder structure? (additional parameter for unix command?)
Kind regards,
Micky.

REPORT ZTESTUNIX line-size 400
                no standard page heading.
selection-screen begin of block ucmd with frame title text-001.
parameters: unixcom like   rlgrap-filename.   " ...SAP Interface file
selection-screen end of block ucmd.
data: begin of tabl occurs 500,
        line(400),
      end of tabl.
data: lines type i.
start-of-selection.
refresh tabl.
call 'SYSTEM' id 'COMMAND' field unixcom
                id 'TAB'     field tabl[].
describe table tabl lines lines.
loop at tabl.
    write:/01 tabl-line.
endloop.
skip 2.
if lines = 0.
    write:/ 'NO Occurances were found'.
else.
    write:/ 'Command was successfully executed' color col_total.
    write:/ 'Number of entries in Search' color col_total,
             lines color 6.
endif.
end-of-selection.
while running give the command as
<b>unzip test.zip -x dir</b>
then it will unzip test.zip file to dir called dir.
you can specify the filepath instead of file...
regards
vijay

Unable to unzip files , unable to move apps into the app foldercant update

I cannot unzip files. Also if i try to install a new app by dragging it to the applications folder it says "that files already exists".
also if i try to update with software update it gives an error. i tried running verify disk permissions and repair disk permissions but this did nothing please help i am scared cuz my last time machine was along time ago.

Not to worry.
A few clarification questions first.
What exactly does the dialog say when you try to drag a new app to the applications folder? Is it something like, "an older version of this already exists in this location, do you want to replace it with the version you are moving?"
And, what application are you attempting to use to unzip files?

Problem with unzipping file

I am trying to unzip a file using java.util.zip. It is throwing a ZipException in the first line where I instantiate ZipFile object.
ZipFile oFile = new ZipFile("/myzip.zip");java.util.jar is not working either. It fails right here:
JarFile oFile = new JarFile("/myzip.zip");Here is the exception thrown in the above cases:
java.util.zip.ZipException: error in opening zip file
        at java.util.zip.ZipFile.open(Native Method)
        at java.util.zip.ZipFile.<init>(Unknown Source)
        at java.util.jar.JarFile.<init>(Unknown Source)
        at java.util.jar.JarFile.<init>(Unknown Source)
        at ReadZipFile.main(ReadZipFile.java:21)
An interesting observation:
I am able to extract the contents of the zip from the command-line using jar utility.
jar xvf myzip.zipI am stumped! I think jar utility internally uses the same classes for unzipping files. How come it is working with jar utility whereas it is not working from Java program? Also, the myzip.zip appears to be a valid archive - I am able to open it with winzip.
Any pointers will be appreciated.
Thanks in advance,
Ganesh

I think the above reply is correct but didn't explain why you would be getting a file not found. Unless you have your zip file at the root of your harddrive the slash in the filename is improper. Without the slash your code will assume your current working directory and look for the file there.
By putting that forward slash in there you are telling the code to look at the root of the filestructure and NOT at the current working directory.

Unzip file from froms then load

i have form (basically called loader) which read text file and then load it in data base.
Now,there is a user requirement that if text file is in zip format then he can unzip file using form.
Any idea how to do this can some unzip software used at back end.
I mean any idea any suggestion is required.
Forms 6i i am using.

The zip.exe and unzip.exe are shipped with Oracle products, they are found under %ORACLE_HOME%/bin
just type zip or unzip in a command line session and you'll get all the switches and details.
Judging from your first post I understand you are running in C/S mode, if not you need to use CLIENT_HOST from webutil instead of HOST. It's the same concept.
As for HOST built-in example, I told you, there are very nice and detailed examples in the online help of Forms builder.
Open Forms builder and either press Ctrl + H or click on the big blue question mark, or open help menu and click on "Online Help".
Tony
Message was edited by:
Tony Garabedian

Unzip files from a folder which is updating regularly using multithreading

Hi All,
I have acode which unzip all the files from a folder .This code picks up all the zipped files at a time and then unzip it and write them to another folder but now my requirement is changed ,suppose the source folder where all the zipped files are present is refreshed or updated with new zipped files regularly then how can I implement in my code multithreading to get several files by threads and send it for unzipping.
Please suggest with some example or edit my code.
package com.myprojcet;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.OutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
public class Main {
     * Extracts a zip file
     public void extractZipFile() {
          try {
               String zipFileName = "C:\\soft\\test"; //Source folder for zipped files
               //Create input and output streams
               File SourceDir = new File(zipFileName);
               File[] zipFiles = SourceDir.listFiles();
               ZipInputStream inStream = null;
               OutputStream outStream = null;
               ZipEntry entry;
               byte[] buffer = new byte[1024];
               int nrBytesRead;
               //Get next zip entry and start reading data
          for(int i=0; i < zipFiles.length; i++) {
               inStream= new ZipInputStream(new FileInputStream(zipFiles));
               while((entry = inStream.getNextEntry()) != null) {
                    outStream=new FileOutputStream("C:\\soft\\test2\\"+entry.toString()); //destination folder for unzipped file
                    while ((nrBytesRead = inStream.read(buffer)) > 0) {
                         outStream.write(buffer, 0, nrBytesRead);
               //Finish off by closing the streams
               outStream.close();
               inStream.close();
          } catch (IOException ex) {
               ex.printStackTrace();
     * @param args the command line arguments
     public static void main(String[] args) {
          new Main().extractZipFile();
Thanks
Sumit
Edited by: user8687839 on Feb 27, 2012 11:00 PM

But my question is that if in a source folder we have several files which are in zipped format and the folder is getting updated every min (say) with new zipped files (which are dumped from some outside environment).I need to unzip all the files present in the folder ,if new one comes there then also check for the new zipped file and unzip it.You don't need to keep re-stating that.
I had written a code for unzipping a file from a folder (thinking the folder is not updated everytime).Or that.
Now I am thinking of using threads because if I create suppose 5 threads and every threads poll the source folder and pick up a zip file ,send it for unzipping it and again poll the source folder for any new entries?Or that.
If using the threads here hits performace then what should I use?Err, what you presently have?
Provide me any sample code or link that would be more useful.You've already written it.

Unzip files from FTP using ABAP

Hi All,
I have the a requirement to unzip certain files from ftp and transfer the extracted files to another directory in ftp.
Searched (Re: Unzip file;) in SDN but didnt find the perfect solution
Appreciate the help.
Regards
Siva

You can use IndexOf function
see this example
http://visakhm.blogspot.in/2012/05/package-to-implement-daily-processing.html
Please Mark This As Answer if it solved your issue
Please Vote This As Helpful if it helps to solve your issue
Visakh
My Wiki User Page
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Execute Process Task error-Unzip Files

Dear All,
I have a SSIS package, that downloads a Zip file from FTP Server and extract and load that information in Sql Server Table. In my case every time I have only one file in FTP Server. There is no possible to get multiple files from FTP Server.
While at the time of executing SSIS package getting error at Execute Process Task(Unzip Files) i.e
Error Description :In Executing "F:\7z\7z.exe" " x F:\ZipFiles\Sales_010815.zip -oF:\ZipFiles\" at "", The process exit code was "2" while the expected was "0".
This error message getting while unzip my file.
Can some one help on this issue.
Regards,
Praveen C.
Regards, Praveen

Hi Praveen,
After testing the issue in my environment, I find the issue is caused by the code in Arguments is incorrect.
To fix this issue, please refer to the code below:
x F:\ZipFiles\Sales_010815.zip -oF:\ZipFiles
The following screenshot is for your reference:
If there are any other questions, please feel free to ask.
Thanks,
Katherine Xiong
Katherine Xiong
TechNet Community Support

Powershell to unzip file having passowrd

hi, i am using the following script to unzip files it works fine with files not having password
$shell=new-object -com shell.application
$CurrentLocation=get-location
$CurrentPath=$CurrentLocation.path
$Location=$shell.namespace($CurrentPath)
$ZipFiles = get-childitem *.zip
$ZipFiles.count | out-default
foreach ($ZipFile in $ZipFiles)
$ZipFile.fullname | out-default
$ZipFolder = $shell.namespace($ZipFile.fullname)
$Location.Copyhere($ZipFolder.items())
# for password protected file it pops up a windows saying password needed, how can i enter the password in script
#what changes i need to make if i have to extract password protected files.
student

AFAIK, you can't do passwords directly with WScript. You may be able to code up a method to imitate key strokes though.
My suggestion would be to call another command-line utility zip/unzip program like 7-zip:
http://www.7-zip.org/download.html

Does my Mac 10.9.5 have a built in compression system to unzip files? If not what utility is best?

Does my Mac 10.9.5 have a built in compression system to unzip files? If not what utility is best?

It does. Select any file you want to compress. CTRL- or RIGHT-click on it and select Compress ... from the context menu. To decompress simply double-click on the compressed file to open it. If you have any problems then get The Unarchiver 3.9.1 for decompressing. Use The Archive Browser 1.9.1 to do both.

Unzip files from SDCARD

HI,
i am trying to unzipping files from external sdcard..
i am using zipme.jar, but when i am deploying this application it give error.
please nay one hep me to unzipping files using 3rd-party jar

But my question is that if in a source folder we have several files which are in zipped format and the folder is getting updated every min (say) with new zipped files (which are dumped from some outside environment).I need to unzip all the files present in the folder ,if new one comes there then also check for the new zipped file and unzip it.You don't need to keep re-stating that.
I had written a code for unzipping a file from a folder (thinking the folder is not updated everytime).Or that.
Now I am thinking of using threads because if I create suppose 5 threads and every threads poll the source folder and pick up a zip file ,send it for unzipping it and again poll the source folder for any new entries?Or that.
If using the threads here hits performace then what should I use?Err, what you presently have?
Provide me any sample code or link that would be more useful.You've already written it.

How can i check the unzip file has finished unzip process?

i am using 7zip to unzip the file. java program can check the unzip file has finished unzip process?
Edited by: rayray2008 on Feb 12, 2008 7:14 PM

Downloading and burning Linux or Windows ISO images for example with a single flipped bit can cause system instability nearly impossible to track down, and not otherwise detectable. An MD5 checksum (OR SHA) check will quickly detect any such transmission errors. Not something anyone I know bothers to use unless it's important data. The temporary fix of changing the about:config setting, then expanding to full screen in downloads was working. But now, based on my interpretation of comments made on the authors Sourceforge page, Firefox has made updates that prevent the MD5 Reborned Hasher from working in Firefox at all. If that's true, I would really like to know the reason. With all this talk of NSA spying, I would think more people would be interested in making sure someone isn't tampering with their downloads. I have no idea. But I do believe the wonderful volunteers at Firefox need to figure out a way to make this valuable piece of security software whole again. Thank You.
PS: For those needing to verify a file, you might want to try the "Microsoft File Checksum Integrity Verifier" kb841290 . It's old, but does large file MD5 from a command prompt.

Should not unzip file under $ORACLE_HOME

OS:AIX 5.2
OS: Linux 86
E.G:
echo $OARCLE_HOME
/opt/oracle/product/10.1.0/database
I am applying Patch 4505133_10105 on my above two servers.
I have downloaded p4505133_10105_LINUX.zip or AIX.zip and move to /opt/oracle.
In my uderstanding , I should not unzip file under $ORACLE_HOME or $ORACLE_HOME.
I need to do as follows:
cd /opt/oracle/Disk1
./runinstalleris it ok?
Please confirm
DN

You can unzip it to any directory, need not be the one under ORACLE_HOME. But during installation, you need to specify the correct ORACLE_HOME path, the one to be patched.

Unzip file with .sar and .car extensions.

Hi,
how unzipping file with .sar .car extensions?
Best regards

Hello,
in the directory in which the SAP kernel is installed there has to be a executable called SAPCAR or sapcar.exe.
Windows: C:usrsapSIDSYSexerunsapcar.exe -xvf archive.sar
Unix: /usr/sap/SID/SYS/exe/run/SAPCAR -xvf archive.sar
or
Windows: C:usrsapSIDSYSexerunsapcar.exe -xvf archive.car
Unix: /usr/sap/SID/SYS/exe/run/SAPCAR -xvf archive.car
Regards, Michael

Unzip files

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