Unzipping action files?
I attempted to download some action files, what I got was .zip file not a .atn file. this .zip file does not a zipper just looks like a pdf and has no extraction option. I believe those awesome actions are in there but how do I extract them?
Try downloading them again. A zip file should extract. What made you think the zip file you download was a PDF? Actions are not awesome they are just recorded Photoshop steps.
Similar Messages
-
NI unzip changes file date and time stamp
A coworker this morning asked me about the NI-Unzip VI.
It turns out that when the NI unzip VI unzips a file it changes the file dates to the date the file was unzipped.
He also noted that NI-Unzip seems to be calling the Windows touch.exe to do this.
The diagram for NI unzip is locked and password protected so his attemp to change this action blocked.
Does anyone know a way around this? Either to make the NI Unzip stop changing the file date or the passwork to teh unzip vi?
Message Edited by RTSLVU on 03-22-2010 08:01 AMHi,
I don't think NI will give you a password for it's protected functions...
So you can:
- use "System Exec" with a command line version of a ZIP tool of your choice to unzip files
- make your own "Unzip" VI with calls to a "unzip"-DLL of your choice
Choose the one that is easier to implement for you
Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome -
Can I have an Action file install when a ZXP is opened in Extension Manager for CC 2014?
I have an extension that I'm packaging as a .zxp file. I'm using Adobe Exchange Packager and setting to the proper install location for the files for the extension.
However, my extension requires an action file (.atn) is installed in the user's Actions panel. Of course, I can include the .atn file in my package and copy it to a folder on the user's computer.... BUT, is there any way I can include that .atn file in the .zxp package and when Extension Manager unpacks the files, it INSTALLS the included .atn file into the user's version of Photoshop? So, this way the .atn file is already installed in the user's Actions panel after the extension installs through Extension Manager...so the user doesn't have to worry about installing the .atn file as well?
(If there were a folder to place the .atn file into, I could do that, but I do not believe that there are any folders for CC 2014 that hold .atn files in which the panel will read, if at first not installed in the normal way. I believe this is new for CC, and that the actions are held in a .psp file.)I am not sure about the .atn file location but it sounds like you want to create a 'hybrid' extension.
You create a .ZXP containing your CS extension and then create an MXI file which includes the .ZXP and .atn file.
You would then wrap this into another .ZXP which will be used as the installer.
Further information can be found at http://www.adobeexchange.com/resources/7 -
Missing information in Actions file specification
I wrote some code that parses the Photoshop Actions palette file. I used the Photoshop CS2 File Formats Specification PDF (dated June 2005) to understand its format. However, the following OSType keys of the "Reference Structure" type are not documented:
'Idnt' (Identifier)
'indx' (Index)
'name' (Name)
They are mentioned in Table 3.4, page 62 of the PDF.
This seems to be a lack in the document since all the other many elements are explained in great detail. Can anybody provide details of these missing fields? What I need is information on their size (length in bytes) and/or the description of their physical structure in the Actions file. I searched this forum for more info to no avail.
Thanks in advance,
Ettore PasquiniName, Index, and Identifier (along with all other reference types) have a value
structured like
'unicode string' - 'desired classID' - 'actual value'
The initial unicode string is not meaningful, as near as I can tell. It does get
populated by actions on very rare occasions, but does not appear to be used
anywhere. I always write it out as an empty unicode string and the action
behaves the same.
You've accurately deduced the classID part.
I should have mentioned all of this in the previous email.
For Name, the value is a Unicode string.
For Index, the value is a simple 4 byte word.
For Identifier, values a simple 4 byte key-classID.
I have a test script that generates writes/read/writes and verifies descriptors
in Javascript. This includes the code for ieee754 floats, Alias (pth or alis),
and raw (tdta) data types. I haven't tested my Alias code out on an action
created on a Mac, though. The only one I haven't figured out at all is
ObjectArray (ObAr). I can't create it with the JS API nor have I found it in my
largish collection of Action files.
If you'd like, I can send you the script(s) that I use for my implementation and
testing. You might find it of some use in your work. I also have a partial perl
implementation if that's more your speed.
Ettore Pasquini wrote:
> thanks for the reply xbytor.
>
> 'indx' - a 4 byte word/integer
> 'name' - a unicode string
>
>
>
>
> According to my tests those mappings don't work. I have some actions files with those elements and the file is not correctly parsed if I adopt the formats above. However I found out the following seems to work:
>
> 'indx' :
> Variable - Unicode string;
> Variable - 4 bytes of length followed by ASCII string;
No. This is a classID.
> 4 - 4 additional bytes of unknown meaning.
This is the actual value of the index. I see it used a lot when indexing a
document's layers.
>
> 'name' :
> Variable - Unicode string;
> Variable - classID: 4 bytes (length), followed either by string or (if length is zero) 4-byte classID;
> Variable - Unicode string.
Exactly right.
>
> This is based entirely on empirical observations and of course it could be wrong. But so far these formats seems to satisfy the data in all my actions files.
>
> For the 'Idnt' element I haven't the slightest idea of what it could be, since I never saw one in an Actions Palette file.
I can create Idnt's but I don't recall having seen them either.
> Can anyone from Adobe please provide this information and verify the above hypotheses? It would be extremely helpful. Thanks!
>
> -Ettore
Let me know if you want the scripts.
for photoshop scripting solutions of all sorts
contact: [email protected] -
I regularly download zipped files from Survey Monkey. Since the latest security update, the zipped files download to my computer, but when I try and unzip them I get a message telling me the file is in use by another application. If I reboot, I can unzip the file, or if I'm in Safe Mode when I download the file it unzips fine.
I have tried three different unzip apps and all have the same trouble. Everything was working well after the September 5 update.
I'm running Windows XP with McAfee antivirus, Spybot, Ad-Aware and Malbytes Anti-malware. All are up to date.The URL below is to Adobe's Acrobat update page.
There you'll find each of the incremental updates to Acrobat 10.
They must be installed one at a time in sequence.
http://www.adobe.com/support/downloads/product.jsp?product=1&platform=Windows
Now, if after attempted updates fail then you'll need to speak with your IT Department.
You need your install of Acrobat 10 updated to dot version 10.1.7.
Be well...
Message was edited by: CtDave -
Easy way to unzip zipped files?
I'm trying to figure out an easy way to unzip zipped files. I'm using C# in VS 4.5.
I download this:
http://dotnetzip.codeplex.com/
I couldn't get any dlls installed. I couldn't set any reference to anything.
I also tried to follow the example here:
http://www.danderson.me/posts/zipfile-class-system-io-compression-filesystem/
I can't find anything titled 'System.IO.Compression.dll'. I set a reference to these two:
System.IO.Compression.FileSystem
System.IO.Compression
That did nothing at all.
For instance, I think this should work:
using System;
using System.IO;
using System.IO.Compression;
namespace ConsoleApplication
class Program
static void Main(string[] args)
string startPath = @"c:\example\start";
string zipPath = @"c:\example\result.zip";
string extractPath = @"c:\example\extract";
ZipFile.CreateFromDirectory(startPath, zipPath);
ZipFile.ExtractToDirectory(zipPath, extractPath);
However, i keep getting an error message that says 'The name 'ZipFile' does not exist in the current context'.
Knowledge is the only thing that I can give you, and still retain, and we are both better off for it.Hi
Please include the below namespace and try it out.
System.IO.Compression.FileSystem
The code would be like this.
using System;
using System.IO;
namespace ConsoleApplication
class Program
static void Main(string[] args)
string startPath = @"c:\example\start";
string zipPath = @"c:\example\result.zip";
string extractPath = @"c:\example\extract";
System.IO.Compression.ZipFile.CreateFromDirectory(startPath, zipPath);
System.IO.Compression.ZipFile.ExtractToDirectory(zipPath, extractPath);
Please note that you need to add a DLL reference to the framework assembly
System.IO.Compression.FileSystem.dll
Please let me know in case of any questions you may have around this. Thank you. -
does any body know any transaction code to unzip a file.
iam already using a fn module SXPG_CALL_SYSTEM which uses a unix command.
and i know uncompress in open dataset.
but i need a transaction code but not the abobve two solutions.Don't know of a way to create a Keyboard shortcut since the menu item name changes with whatever is selected, but you could make an Automator script and then map that Automator script to a keyboard shortcut. Or just make a Automator Application that sits on your desktop or dock and drag and drop files onto it.
-
I am remotely logged into a UNIX cluster at the university and attempting to manipulate some files that I have received from a collaborator. He has "tarred" and "zipped" the files. Unzipping the file with the command
<remote host:directory>% gunzip file.tar.gz
(remote host is the machine I am logged into (via ssh -X username): directory is my directory on the remote host)
This creates the unzipped file- file.tar on <remote host:directory>. The problem arises when I attempt to untar the file. I am using the command
tar -xvfp file.tar
After entering this command, I get the message
tar: can't mkdir /net: Permission denied
tar extract: failed mkdir of <:senders directory>
The same error is produced using [tar -xvf] as the bundled-options. I am assuming that it is attempting to make the directory on my collaborators remote host because the listed location of the failed mkdir is the senders directory <:senders directory> on a different UNIX cluster.
I have tried variations on the tar command (-x or -xv) but those produce the error
tar: tape read error: no tape in drive
I am a bit unfamiliar with the syntax for the [[-]bundled-options Args] in the tar command, but I suspect that I need to specify where the untarred archive is going to be written/ copied. Could anyone provide some guidance on this.
Sincerely,
AricHi Aric,
Did you copy the error message verbatim? Does it really want to create the directory, /net? If so then the problem is likely to be in the tarball itself.
There's nothing wrong with your initial syntax. The -x tells tar to unpack the tarball, which is what you're trying to do. The -p says to preserve permissions, which is fine. The 'p' is not supposed to go after the 'f' in the options because the tarball, file.tar, is technically an argument of the -f option. However, most implementations of tar are rather forgiving in that regard. The -v option simply tells tar to be verbose and list the files. Of course there are many implementations of tar and you don't bother to tell us into what kind of machine you're logged.
Tar has the ability to archive many files and preserve the directory structure. However, it has to recreate those directories when unpacking and that's when it had a problem. It seems that tar wants to create a directory named "net" at the root of the boot drive. I assume that the creator of the tarball archived such a directory on his machine.
However, most implementations of tar strip the leading slash, turning an absolute path into a relative path. That way when unpacked, the directory structure starts at the current working directory. Unless you tried to unpack this tarball from the root directory of the boot drive, the tar that created this tarball appears to be different.
Unless you can get the privilege of writing to the root of this boot drive, I would guess that your only recourse is to get the person who created the tarball to redo it using relative paths. See if you can get him to create it with GNU's tar, as that version strips the leading slashes by default.
Gary
~~~~
OK, so you're a Ph.D. Just don't touch anything. -
hai,
Iam trying to unzip a file but its not working.
//Unzip a file
final int BUFFER = 2048;
String zfname=application.getRealPath("/") + "temp/Bulk.zip";
File zf=new File(zfname);
try {
BufferedOutputStream dest = null;
FileInputStream fis = new FileInputStream(zf);
ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis));
ZipEntry entry;
while((entry = zis.getNextEntry()) != null)
System.out.println("Extracting: " +entry);
int count;
byte data[] = new byte[BUFFER];
// write the files to the disk
File outFile=new File(outPath);
//FileOutputStream fos = new FileOutputStream(outFile);
FileOutputStream fos = new FileOutputStream(entry.getName());
dest = new BufferedOutputStream(fos, BUFFER);
while ((count = zis.read(data, 0, BUFFER))!= -1)
dest.write(data, 0, count);
dest.flush();
dest.close();
zis.close();
} catch(Exception e) {
e.printStackTrace();
Bulk.zip folder has the following files:
Bulk/test.txt
Bulk/fm.jsp
I get the following exception
java.io.FileNotFoundException: Bulk\test.txt
(The system cannot find the path specified)
Iam i making mistake in this line
FileOutputStream fos = new FileOutputStream(entry.getName());
dest = new BufferedOutputStream(fos, BUFFER);Thanks,
Thanuja.ok vijay iam so sorry for not mentioning how i rectified it. somehow i missed it. may be was bit excited when i got the result.
anyways below code worked.
//Unzip a file
String zip_fname=request.getParameter("zfilename")!=null?request.getParameter("zfilename"):"";
String fromZip=zip_fname;
//out.println("FromZip:"+fromZip);
File zipFname=new File(newFileName);
String toLocation=newFilePath; //path to unzip the file
String seperator = System.getProperty("file.separator");
System.out.println("unzipping zip file to "+toLocation);
try
BufferedOutputStream dest = null;
File zipDir = new File(toLocation);
zipDir.mkdir();
ZipFile zip = new ZipFile(fromZip);
final int BUFFER = 2048;
FileInputStream fin=new FileInputStream(fromZip);
ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fin));
ZipEntry entry;
while((entry = zis.getNextEntry()) != null)
//System.out.println("Extracting: " +entry);
int count;
byte data[] = new byte[BUFFER];
String zip_Fname=entry.getName().substring(entry.getName().lastIndexOf("/")+1);
if(!zip_Fname.equals(""))
zipFiles.add(zip_Fname);
if(!zip_Fname.equals(""))
FileOutputStream fos = new FileOutputStream(toLocation + seperator + entry.getName().substring(entry.getName().lastIndexOf("/")+1));
dest = new BufferedOutputStream(fos, BUFFER);
while ((count = zis.read(data, 0, BUFFER))!= -1)
dest.write(data, 0, count);
dest.flush();
dest.close();
zis.close();
catch (Exception ex)
unZipResult++;
System.out.println(ex);
}Thanks,
Thanuja. -
I need to Unzip a file from Folder 1 and place it in Folder2.
Folder 1 has a zip file, which a txt file embedded in it. PI need to unzip the file and place the file in Folder2 with same name.
I have created a Configuration Scenario for this, no IR objects.
I have used PayloadZipBean with ModuleConfiguration as
ParameterName- zipmode and ParamterValue - unzip in my sender file channel and same is used in receiver channel.
For some reason when I see the payload in sender communication channel log, it is automatically converted to XML with some junk values along with the data.
Another issue is although I have checked the Adapter Specific Properties on both the channels, it expects a name on Receiver file channel. So I have given a dummy name there. File got created in Folder2 but with some junk values in XML format.
Any thoughts please.Thank You both.
Greg - your idea worked.
On the other issue looks like I can not use Adapter Specific Properties on both the channels. when I use ASMA File got created in Folder2 but with some junk values in XML format.
Looks like it expects a name on Receiver file channel. So I have given a dummy name there.
Edited by: Vamsi on Feb 23, 2012 6:15 PM -
Unzip a file preserving the folder structure
Hi guys,
I have create a zip file using java.util.zip and I preserv all directory structure. When I unzip the file using the same library, in the loop of ZipEntry I don't find never a directory. This the code that I use and don't work:
public void dataDecompression(String pathArchivio) {
try {
fileInputStream = new FileInputStream(pathArchivio);
checkedInputStream = new CheckedInputStream(fileInputStream, new Adler32());
zipInputStream = new ZipInputStream(new BufferedInputStream(checkedInputStream));
ZipEntry entry;
while((entry = zipInputStream.getNextEntry()) != null){
if(entry.isDirectory()){
//make dir
else{
//write file
}Maybe I miss something in compression? Excuse for my bad english.
Thanks in advance.three problems with that.
1) you don't recusively create folders.
2) you create a folder with the name of the file you want to write.
3) you don't create files.
File file=new File(entry.getName());
if(file.getParentFile()!=null);
file.getParentFile().mkdirs();
if( !entry.isDirectory() ) {
//code that write file; -
Unzip GZ files using Powershell
I have Windows 2008 Server with some GZ type files in a folder. I would like to script unzipping them using Powershell, can someone tell me if this is possible and how I would do it?
The folder is d:\data_files\ and I'd like to uncompress all the .gz files in there
I've searched around on the Net but can't find much that deals with GZ files specifically. The files are all named data-1.gz, data-2.gz etc
Hello
I have Windows 2008 Server with some GZ type files in a folder. I would like to script unzipping them using Powershell, can someone tell me if this is possible and how I would do it?
The folder is d:\data_files\ and I'd like to uncompress all the .gz files in there
I've searched around on the Net but can't find much that deals with GZ files specifically.I also found that .Net 2.0 and above has native code for dealing with gzip files.
Function DeGZip-File{
Param(
$infile,
$outfile = ($infile -replace '\.gz$','')
$input = New-Object System.IO.FileStream $inFile, ([IO.FileMode]::Open), ([IO.FileAccess]::Read), ([IO.FileShare]::Read)
$output = New-Object System.IO.FileStream $outFile, ([IO.FileMode]::Create), ([IO.FileAccess]::Write), ([IO.FileShare]::None)
$gzipStream = New-Object System.IO.Compression.GzipStream $input, ([IO.Compression.CompressionMode]::Decompress)
$buffer = New-Object byte[](1024)
while($true){
$read = $gzipstream.Read($buffer, 0, 1024)
if ($read -le 0){break}
$output.Write($buffer, 0, $read)
$gzipStream.Close()
$output.Close()
$input.Close()
$infile='C:\Temp\DECfpc1new.csv.gz'
$outfile='c:\temp\DECfpc1new.csv'
DeGZip-File $infile $outfile
You can supply the function with the full path of the file to be unzipped, and the full path of the unzipped file.
If you don't supply the unzipped file path, the function will unzip the file into the same folder as the source, and remove the .gz extension.
Inspired by Heineken. -
Problem using payloadZipBean to unzip a file
I would like to run OS command to zip large amount of xml into one zip file before XI pick it up, then use unzip option in payloadZipBean to unzip all the xml files so XI can process them one by one from memory, this will reduce lots file I/O time.
But I am getting this warning message:
Warning Zip: message is empty or has no payload
But if I display this message in RWB, the only payload is this zip file.
Why the payloadZipBean is not unzipping this file as supposed to.Did you check this blog
/people/stefan.grube/blog/2007/02/20/working-with-the-payloadzipbean-module-of-the-xi-adapter-framework
Sameer -
Unzip the file archived by the File adapter
Hi Experts,
we have a scenario where we are archiving a xml file using the File adapter and also it is being zipped by the OS command.
the script not only zips the file, it also rename the file from *.zip to *.xml.
Hence after archiving when I am trying to open it, the content appears to be junk.
Please suggest how to unzip the file as it got a extension *.xml.
And I also tried renaming the file to *.zip and then to uncompress, but it shows below error
Cannot open : it does not appear to be a valid archive
Thanks in advance,
MKhi Mk,
instead of using OS command try using the exesting module provided by the SAP, so your job will be easy.
follow this steps in the module processing for UN ZIP
Processing sequence:
Module name: AF_Modules/PayloadZipBean
Type: Local Enterprise Bean
Module key: 3
u2022 Module configuration:
Module key: 3
Parameter name: zip.mode
Parameter value: unzip.
in the commincation channel specify filename.xml
so you can open the file in XML format
Thanks,
Madhav
Note:points if useful
Edited by: madhav poosarla on Aug 14, 2008 8:31 AM -
Native extension to unzip a file crash my air app
Hello,
I have a problem with a native extension for android
I want to unzip a file
my java code
File f = new File("my zip file");
File outputDir = new File ("output folder");
ZipHelper.unzip(f, outputDir);
and
import java.util.zip.*;
import java.io.*;
import java.util.Enumeration;
import org.apache.commons.io.IOUtils;
import android.util.Log;
public class ZipHelper
static public void unzip(File archive, File outputDir)
try {
Log.d("control","ZipHelper.unzip() - File: " + archive.getPath());
ZipFile zipfile = new ZipFile(archive);
for (Enumeration e = zipfile.entries(); e.hasMoreElements(); ) {
ZipEntry entry = (ZipEntry) e.nextElement();
unzipEntry(zipfile, entry, outputDir);
catch (Exception e) {
Log.d("control","ZipHelper.unzip() - Error extracting file " + archive+": "+ e);
static private void unzipEntry(ZipFile zipfile, ZipEntry entry, File outputDir) throws IOException
if (entry.isDirectory()) {
createDirectory(new File(outputDir, entry.getName()));
return;
File outputFile = new File(outputDir, entry.getName());
if (!outputFile.getParentFile().exists()){
createDirectory(outputFile.getParentFile());
Log.d("control","ZipHelper.unzipEntry() - Extracting: " + entry);
BufferedInputStream inputStream = new BufferedInputStream(zipfile.getInputStream(entry));
BufferedOutputStream outputStream = new BufferedOutputStream(new FileOutputStream(outputFile));
try {
IOUtils.copy(inputStream, outputStream);
catch (Exception e) {
Log.d("control","ZipHelper.unzipEntry() - Error: " + e);
finally {
outputStream.close();
inputStream.close();
static private void createDirectory(File dir)
Log.d("control","ZipHelper.createDir() - Creating directory: "+dir.getName());
if (!dir.exists()){
if(!dir.mkdirs()) throw new RuntimeException("Can't create directory "+dir);
else Log.d("control","ZipHelper.createDir() - Exists directory: "+dir.getName());
i copy the file commons-io-2.4.jar (I get at http://commons.apache.org/proper/commons-io/download_io.cgi) in the lib folder of eclipse.
in a native android app, this code work fine
in a native extension for air, my air app crash
LogCat in eclipse return
NoClassDefFoundError: org.apache.comons.io.IOUtils.copy
IOUtils class is not in commons-io-2.4.jar ???
thanksHello,
I have a problem with a native extension for android
I want to unzip a file
my java code
File f = new File("my zip file");
File outputDir = new File ("output folder");
ZipHelper.unzip(f, outputDir);
and
import java.util.zip.*;
import java.io.*;
import java.util.Enumeration;
import org.apache.commons.io.IOUtils;
import android.util.Log;
public class ZipHelper
static public void unzip(File archive, File outputDir)
try {
Log.d("control","ZipHelper.unzip() - File: " + archive.getPath());
ZipFile zipfile = new ZipFile(archive);
for (Enumeration e = zipfile.entries(); e.hasMoreElements(); ) {
ZipEntry entry = (ZipEntry) e.nextElement();
unzipEntry(zipfile, entry, outputDir);
catch (Exception e) {
Log.d("control","ZipHelper.unzip() - Error extracting file " + archive+": "+ e);
static private void unzipEntry(ZipFile zipfile, ZipEntry entry, File outputDir) throws IOException
if (entry.isDirectory()) {
createDirectory(new File(outputDir, entry.getName()));
return;
File outputFile = new File(outputDir, entry.getName());
if (!outputFile.getParentFile().exists()){
createDirectory(outputFile.getParentFile());
Log.d("control","ZipHelper.unzipEntry() - Extracting: " + entry);
BufferedInputStream inputStream = new BufferedInputStream(zipfile.getInputStream(entry));
BufferedOutputStream outputStream = new BufferedOutputStream(new FileOutputStream(outputFile));
try {
IOUtils.copy(inputStream, outputStream);
catch (Exception e) {
Log.d("control","ZipHelper.unzipEntry() - Error: " + e);
finally {
outputStream.close();
inputStream.close();
static private void createDirectory(File dir)
Log.d("control","ZipHelper.createDir() - Creating directory: "+dir.getName());
if (!dir.exists()){
if(!dir.mkdirs()) throw new RuntimeException("Can't create directory "+dir);
else Log.d("control","ZipHelper.createDir() - Exists directory: "+dir.getName());
i copy the file commons-io-2.4.jar (I get at http://commons.apache.org/proper/commons-io/download_io.cgi) in the lib folder of eclipse.
in a native android app, this code work fine
in a native extension for air, my air app crash
LogCat in eclipse return
NoClassDefFoundError: org.apache.comons.io.IOUtils.copy
IOUtils class is not in commons-io-2.4.jar ???
thanks
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