Upload files using JSP

i am creating an application that allow user from client-side to upload their files to a particular folder in the server-side. But my application isnt functioning as the application cannot get the files into that folder.
Is there any extra coding needed? Urgent help in this area...
Thanks...

Dear,
I tried request.getInputStream() method to get content
PrintWriter pw = new PrintWriter(
new BufferedWriter(new FileWriter("c:\\Demo.out")));
ServletInputStream in = request.getInputStream();
int i = in.read();
while (i != -1) {
pw.print((char) i);
i = in.read();
pw.close();
but u need to modify it..

Similar Messages

Need to send mail & upload files using JSP

hi, got a lot of issues,.. just starting out as a developer.. so here goes.
1st Need to send mail & upload files to server using JSP(tomcat).. an example to demo it would be nice.
thanx in advance

Look at this for email:
http://forum.java.sun.com/thread.jspa?forumID=45&threadID=285950
and go to:
http://servlets.com/cos/
for a package to upload files.

Upload file using jsp

hi all i am trying a code that uploads file to the server using jsp the code goes like this
<%@ page import = "java.io.*" %>
<%
String contentType = request.getContentType();
String file = "";
String saveFile = "";
FileOutputStream fileOut = null;
if((contentType!=null)&&(contentType.indexOf("multipart/form-data")>=0))
   DataInputStream in = new DataInputStream(request.getInputStream());
   int formDataLength = request.getContentLength();
   byte dataBytes[] = new byte[formDataLength];
   int byteRead = 0;
   int totalBytesRead = 0;
   while(totalBytesRead<formDataLength)
      byteRead = in.read(dataBytes,totalBytesRead,formDataLength);
      totalBytesRead +=byteRead;
   try
      file = new String(dataBytes);
      saveFile= file.substring(file.indexOf("filename=\"")+10);
      saveFile = saveFile.substring(0,saveFile.indexOf("\n"));
      saveFile =
      saveFile.substring(saveFile.lastIndexOf("/")+1,saveFile.indexOf("\""));
      int lastIndex = contentType.lastIndexOf("=");
      String boundary =
      contentType.substring(lastIndex+1,contentType.length());
      int pos;
      pos = file.indexOf("filename=/" +1);
      pos = file.indexOf("\n",pos)+1;
      pos = file.indexOf("\n",pos)+1;
      pos = file.indexOf("\n",pos)+1;
      int boundaryLocation = file.indexOf(boundary,pos) - 4;
      int startPos = ((file.substring(0,pos)).getBytes()).length;
      int endPos =
      ((file.substring(0,boundaryLocation)).getBytes()).length;
      String folder = "07ics01/jsp/"; //is this the folder where i intend to save the file?
      fileOut = new FileOutputStream(folder + saveFile);
      fileOut.write(dataBytes);
      fileOut.write(dataBytes,startPos,(endPos-startPos));
      fileOut.flush();
   catch(Exception e)
      out.println(e);
   finally
      try
         fileOut.close();
      catch(Exception err)
%> i have been trying to use this code but i can't understand the code. is String folder = "07ics01/jsp" the folder where i intend to save the page on the server? because when i do that i get an exception like
java.io.FileNotFoundException: 07ics01/jsp/C:\Documents and Settings\s9sharma\Desktop\tt\commons-digester-1.8\commons-digester-1.8.jar (No such file or directory) where C:\Documents and Settings\s9sharma\Desktop\tt\commons-digester-1.8\commons-digester-1.8.jar is the file i am trying to upload to the directory 07ics01/jsp which is a unix directory.
Can anyone please help..

So you've copypasted this code from somwhere and are expecting our support on the code, instead of the author's support? That's sad.
I recommend you to look to the Apache Commons FileUpload API [1]. Then you don't need to write (or copypaste) a multipart parser yourself. Putting business logic in JSP files is also bad practice by the way. Use Java classes for it instead (Servlets, Filters, Beans, Utilityclasses, etc).
[1] http://commons.apache.org/fileupload/
To understand the actual code, it might help a lot to first read and understand the HTML spec about multipart request data and read the API documentations of the Java classes involved, e.g. the java.io API.

I would like to upload a excel file using jsp

Hi,
I would like to upload the excel file using jsp in my netbeans ide. Please help.
I don Know what is the error in this jsp file. It is not showing any thing and the file is also not getting uploaded.
Please gothru the code below.
<%@ taglib uri="/WEB-INF/struts-bean.tld" prefix="bean" %>
<%@ taglib uri="/WEB-INF/struts-html.tld" prefix="html" %>
<%@ taglib uri="/WEB-INF/struts-logic.tld" prefix="logic" %>
<%@ page import="java.io.*" errorPage="err.jsp"%>
<%@page contentType="text/html"%>
<%@page pageEncoding="UTF-8"%>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<link href="<html:rewrite page="/design.css" />" rel="stylesheet" type="text/css">
<title>Upload Page</title>
</head>
<body onKeyDown="DisablingBackFunctionality()" onLoad="DisablingBackFunctionality()">
<html:form action="download" >
<div style="position:absolute; left:100;top:200;">Select an excel File :<input type="file" name="uploadfile"></div>
<div style="position:absolute; left:190;top:250;"><input type="submit" name="Submit" value="Read"></div>
<div style="position:absolute; left:336;top:250;"><input type="reset" name="Reset" value="Clear"></div>
mainmenu
</html:form>
</body>
</html>
<%
String contentType = request.getContentType();
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) {
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength) {
byteRead = in.read(dataBytes, totalBytesRead, formDataLength);
totalBytesRead += byteRead;
String file = new String(dataBytes);
//out.println("<br> file :"+file);
String saveFile = file.substring(file.indexOf("filename=\"") + 10);
//out.println("<br> savefile :"+saveFile);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
//out.println("<br> now file1 :"+saveFile);
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1, saveFile.indexOf("\""));
//out.println("<br> now file2 :"+saveFile);
//out.print(dataBytes);
String ext = "";
if (saveFile.indexOf(".") != -1) {
ext = saveFile.substring(saveFile.lastIndexOf("."));
int lastIndex = contentType.lastIndexOf("=");
//out.println("<br>lst index of"+lastIndex);
String boundary = contentType.substring(lastIndex + 1, contentType.length());
//out.println("<br> boundary"+boundary);
//out.println("<br> file :"+file);
int pos;
pos = file.indexOf("filename=\"");
//out.println("<br> now 0 :"+pos);
pos = file.indexOf("\n", pos) + 1;
//out.println("<br>now 1 :"+pos);
pos = file.indexOf("\n", pos) + 1;
//out.println("<br>now 2 :"+pos);
pos = file.indexOf("\n", pos) + 1;
//out.println("<br>now 3"+pos);
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
FileOutputStream fileOut = new FileOutputStream("D:\\" + saveFile);
//FileOutputStream fileOut = new FileOutputStream(saveFile);
//fileOut.write(dataBytes);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
session.setAttribute("fil", saveFile);
//out.println("File saved as " +saveFile);
%>
<script type="text/javascript" >
function DisablingBackFunctionality()
var URL;
var i ;
var QryStrValue;
URL=window.location.href ;
i=URL.indexOf("?");
QryStrValue=URL.substring(i+1);
if (QryStrValue!='X')
window.location=URL + "?X";
</script>
Please let me know the result as soon as possible. Its my very urgent.
Thanking Yu,
Muthu Kumar.R

No.
Mylenium

Uploading a file using jsp and com.oreilly.servlet lib package

Sorry to bother you but I need your help folks
I am developing an application to pick up files from a database and sent to a specified location on a different system.
I am presently trying to run this code,I have placed this lib package from oreilly which is supposed to encapsulate the usage of file uploads,which is a jar file called cos.jar into C:\Program Files\Java\jdk1.5.0_03\jre\lib\ext folder .I have a jsp page that calls the bean which does the upload and implement the classes in the oreilly package.I am using tomcat 5
[b]the jsp page that acts as the user interface
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
<head>
<title>Please Choose The File</title>
</head>
<body bgcolor="#ffffff">
<table border="0"><tr>
<form action="Upload.jsp" method="post"
enctype="multipart/form-data">
<td valign="top"><strong>Please choose your document:</strong><br></td>
<td> <input type="file" name="file1">
<br><br>
</td></tr>
<tr><td><input type="submit" value="Upload File"></td></tr>
</form>
</table>
</body>
</html>
this is the jsp page that calls the bean
<jsp:useBean id="uploader" class="com.UploadBean" />
<jsp:setProperty name="uploader" property="dir" value="<%=application.getInitParameter(\"save-dir\")%>" />
<jsp:setProperty name="uploader" property= "req" value="${pageContext.request}" />
<html>
<head><title>file uploads</title></head>
<body>
<h2>Here is information about the uploaded files</h2>
<jsp:getProperty name="uploader" property="uploadedFiles" />
</body>
</html>
[b]this is the bean class
package com;
import java.util.Enumeration;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.ServletRequest;
import com.oreilly.servlet.MultipartRequest;
import com.oreilly.servlet.multipart.DefaultFileRenamePolicy;
import javax.servlet.*;
public class UploadBean {
private String webTempPath;
private HttpServletRequest req;
private String dir;
// private ServletRequest request;
public UploadBean( ) {}
public void setDir(String dirName) {
if (dirName == null || dirName.equals(""))
throw new IllegalArgumentException("invalid value passed to " + getClass( ).getName( )+".setDir");
//webTempPath = dirName;
dir = dirName;
/* public String getDir()
return webTempPath;
public void setReq(ServletRequest request) {
if (request != null && request instanceof HttpServletRequest)
req = (HttpServletRequest) request;
} else {
throw new IllegalArgumentException("Invalid value passed to " + getClass( ).getName( )+".setReq");
public String getUploadedFiles( ) throws java.io.IOException{
//file limit size of 5 MB
MultipartRequest mpr = new MultipartRequest(req,dir,5 * 1024 * 1024,new DefaultFileRenamePolicy( ));
Enumeration enume = mpr.getFileNames( );
StringBuffer buff = new StringBuffer("");
for (int i = 1; enume.hasMoreElements( );i++){
buff.append("The name of uploaded file ").append(i).append(" is: ").append(mpr.getFilesystemName((String)enume.nextElement( ))).append("<br><br>");
}//for
//return the String
return buff.toString( );
} // getUploadedFiles
On running the code I find this error messages
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
javax.servlet.ServletException: javax/servlet/ServletRequest
     org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:848)
     org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:781)
     org.apache.jsp.jsp.Upload_jsp._jspService(org.apache.jsp.jsp.Upload_jsp:73)
     org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:322)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:291)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause
java.lang.NoClassDefFoundError: javax/servlet/ServletRequest
     com.oreilly.servlet.MultipartRequest.<init>(MultipartRequest.java:222)
     com.oreilly.servlet.MultipartRequest.<init>(MultipartRequest.java:151)
     com.UploadBean.getUploadedFiles(UploadBean.java:49)
     org.apache.jsp.jsp.Upload_jsp._jspService(org.apache.jsp.jsp.Upload_jsp:63)
     org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
     org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:322)
     org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:291)
     org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.5.9 logs.
Apache Tomcat/5.5.9
tanks

Hi,
Looks like you are missing a file from the classpath. Make sure servlet.jar is available in your classpath. Ordinarily files in <tomcat_home>/lib directory should be added automatically. You need to check why it hasn't been added in your case. A good place to start would be the bat files in the bin directory viz startup.bat, catalina.bat etc.
cheers,
vidyut

How to upload a image file using JSP

hello to all.
i am in the learning stage please help me to upload a image file
using jsp. give the explanation to the code also if possible.
thanks in advance
sincerely
Chezhian

You may find the following articles useful for the JSP/Servlet part:
Uploading files: http://balusc.blogspot.com/2007/11/multipartfilter.html
Downloading files: http://balusc.blogspot.com/2007/07/fileservlet.html

Read an excel file using JSP in MII 12.1

Hi,
I want to read an excel file using jsp page. I dont want to use the UDS or ODBC for connecting to excel.
I am trying to use org.apache.poi to read the excel file in jsp page.
While running, its showing a compilation error "package org.apache.poi.hssf.usermodel does not exist"
I have the jar files for it, where do we need to upload it so that jsp page works.
Thanks a lot
Regards,
Neha Maheshwari

The user doesn't want to save the excel file in server.
I want to upload file and save its contents in database.
I have the code to read and save excel data in database but not able to get the location to deploy the jar file.
In general, if we are creating a jsp page in MII workbench which is using some jar file.
Whats the location to upload this jar file so that the jsp page works correctly?

How to upload file using *cl_gui_frontend_services* method

hi
i want to upload an image file using this method
and i want to save it in MIME Repository (/SAP/BC/BSP/SAP/PRASHANT)
DATA:
itab TYPE TABLE OF sflight.
CALL METHOD cl_gui_frontend_services=>gui_upload
EXPORTING
    filename                = 'C:\temp\winter.jpg'
    filetype                = 'ASC'
    has_field_separator     = '|'
CHANGING
    data_tab                = itab
IF sy-subrc = 0.
WRITE:/ 'success'.
ENDIF.
So plz tel me how i set given path to upload file using this method .

Hi Prashant,
Go through the [Link|https://forums.sdn.sap.com/click.jspa?searchID=24477690&messageID=6684222].
Hope this is helpful.
Regards,
Abhinav

How 2 get the path of a file Using jsp

how 2 get the path of a file Using jsp
i have tried getPath...but i'm geting the error
The method getPath(String) is undefined for the type HttpServletRequest
any idea how 2 get the path of a file

You need ServletContext#getRealPath().
API documentation: http://java.sun.com/javaee/5/docs/api/javax/servlet/ServletContext.html#getRealPath(java.lang.String)

Display uploaded file on JSP page

Hi All,
I want to display uploaded file in JSP.
Initially I am displaying File Name after saving the file & click on edit link.
i.e on JSP Page I have File Upload component & save button.With that save button I am saving my file to databse.
So when I click on edit link I am getting that file name from Databse then I am displaying it.
But now I want to display uploaded file name on JSP page before saving to databse.i.e I will have browse & Upload button.When I click on browse button I will open window from where I will select file.
This is working fine as,<x:inputFileUpload id="uploadfile" value="#{errorLotBean.file}" storage="file"></x:inputFileUpload>
But when I click on upload button that uploaded file should be displyed there only.Can anyone please tell me how to do this ?
Thanks
Sandip

Thanks a lot Siefert,
I tried the way mentioned in URL.
But what if I want to display all uploaded file on my screen.
i.e. If user click on browse & select File A then click on upload button.
(Here the File A will be displayed) with code
<h:outputtext value="#{benaName.file.name}"
But what if after displaying File A if user decide to upload another file File B.
How to display that ?
with <h:outputtext value="#{benaName.file.name}" its dispalying one file only.
Thanks
Sandip

Upload File using MDS WCF API

I have a field of File Type in my Entity. How can I upload file using WCF API?
I tried to create a new Entity Member and added the following attribute in the member attributes collection
Attribute att = new Attribute();
att.Identifier = new Identifier();
att.Identifier.Name = "Image";
att.Value = bytes;
In attribute value I tried to pass the bytes array of an image, also tried Encoding.ASCII.GetString(bytes); as attribute value, but none of them works.
With byte array i get the following exception "Conversion failed when converting the nvarchar value 'System.Byte[]' to data type int." and in case of ASCII string i get "A database error has occurred. Contact your system administrator." error.
There is lack of documentation and samples.
Please let me know if someone tried it out.
Thanks!

You need to use the EntityMemberAttributesGet operation to retrieve the contents of a file attribute. EntityMembersGet is designed to retrieve a collection of many members and therefore it would not make sense to retrieve every file for every row retrieved.
In contrast, EntityMemberAttributesGet is designed to work with a single member and specific attributes of that member, and it was designed to retrieve the file content.
Val Lovicz
http://www.profisee.com
[email protected]
As the original creators of Microsoft MDS, Profisee's Master Data Maestro provides a range of enterprise-grade functionality to ensure MDS project success.

Maximum size of upload file using Cross Domain Library

Hi All
I need to know what is the maximum size of file that I can upload using Cross Domain Library from my Provider hosted app. I know that in msdn it is written that usign REST call we can upload upto 2GB but I have doubts if it is true with Cross domain library
REST Calls. Please suggest.
spExecutor.executeAsync(
url: fileCollectionEndpoint,
method: "POST",
contentType: "application/json;odata=verbose",
body: filedata,
binaryStringRequestBody: true,
headers: { "X-RequestDigest": $("#__REQUESTDIGEST").val(), "accept": "application/json;odata=verbose" ........
And Can I pass ArrayBuffer directly or I need to pass only binary string ?
Thanks in Advance

Hi,
According to your post, my understanding is that you want to know the Maximum size of upload file using Cross Domain Library.
Per my knowledge, you can upload files up to 2 GB with the REST API.
You can refer to:
How to: Upload a file by using the REST API and jQuery
In addition, you can pass ArrayBuffer directly. Please refer to:
FileCollection methods
Thanks,
Linda Li
Forum Support
Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact
[email protected]
Linda Li
TechNet Community Support

Upload files using browser

how is posible upload files using a browser (IE5) to BD ?

<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by JuanCarlos HorrachCampins (jchorrach@globalia:
how is posible upload files using a browser (IE5) to BD ?<HR></BLOCKQUOTE>
The Form enctype=multipart/formdata and input type=file parameters are needed along with method=post.
You then need a servlet(or MS PostingAcceptor) on the server side to read/store it. The Post data is in multiple parts with the parms on separate lines..
Here is sample HTML Form:
<HTML>
<BODY>
<H2>Uplaod test </H2>
<form enctype="multipart/form-data" action="/examples/servlet/MultipartForm"
METHOD="POST"
NAME="UploadFileForm"
LANGUAGE="JavaScript"
onSubmit="if (!validateForm(document.UploadFileForm))
alert ('Please enter a fileName.');
document.UploadFileForm.my_file.select();
return false;
}">
<input type="text" name="TargetURL" value="/uploads">
<input type="text" name="submitter" value="me">
<FIELDSET> <legend> FileUpload</legend>
<BR>
<table>
<tr>
<td align="left">Fully qualified Filename to upload:</td>
</tr>
<tr>
<td align="left"><input name="file" type="file" size="50"></td>
</tr>
<tr>
<td align="left"><input type="Submit" value="Upload File"></td>
</tr>
<table>
</FIELDSET>
</form>
<SCRIPT LANGUAGE="JavaScript">
// Begin client side helper functions
function validateForm(form)
if (isEmpty(form.file)) return false;
return true;
function isEmpty(textcontrol)
str = textcontrol.value
for (i = 0; i < str.length; i++)
chr = str.substring(i, i + 1);
if (chr != ' ')
return false;
return true;
</SCRIPT>
</BODY>
</HEAD>
null

Uploading Files Using InputFile Component -- Sometimes not working

Hello,
This is the 2nd time I make a post about it!
Because I have more than 1 application using upload, and everything is correct! But it doesn't work as it should!
You can check the original post here: Uploading Files Using InputFile Component - Sometimes not working
I need a solution please!
The only thing we can conclude is that it could be a bug from oracle !!! (???) But I talked with other people and they say that it works fine for them.
There is one important thing: when we put a form to "Uses Upload = true" it seems that the page doesn't work very normal. For exemple: if you use a table in a form that uses upload the table get's "crazy".
Thanks,
JP

I have now access to METALINK!
I can find some problems and patches about inputFile but not mine! I will check better later!
I think the problem is caused because of my framework!

Attempting to upload files using the zend _file_transfer system from cs5 training from the source. [was: Question for David Powers]

I am attempting to upload files using the zend _file_transfer system from cs5 training from the source.
On trying to upload to a remote server I am having trouble with the destination setting (C:/upload_test) in the example, please could you point me in the right direction for the an example of this setting for a remote file transfer
Also do I have to construct a connection file to activate a Ftp file transfer?
David Woolston

>I am on windows platform
Who is your host? When you checked your host path in your host control panel, what did it say?
>i have assumed (may be incorrectly) that the purpose of the exercise was to upload to a remote site (ie my website)
That is correct.
>Of course that upload might take place on a computer that does not have DW installed (an internet cafe for example)
That's irrelevant. DW is just the tool you are using to build your site. The site runs on your hosting accounts servers. This includes the php scripts you are working with.
>I have uploaded all files necessary for the operation, when i click upload it returns no such directory exits.
Do you have a url we can check? What destination are you specifying in zend code?
>This made me suspect that I would need to construct a ftp file transfer connection file to satisfied username, password , connection address etc
The exercise you are dealing with is using http file transfer. This has nothing to do with FTP. You do not need FTP for this, other than using it to move your source code from your local client to your server.

Upload files using JSP

Similar Messages

Maybe you are looking for