Urgent help needed.....any help appreciated....

Question

q, Design and implement a java class called statistics that computes the mean, median, standard deviation. Design and implement a java application called statisticsDriver that generates a list of 50 integers (generated randomly) and prints the statistical measures which are calculated using the Statistis Class. Assume there will be no more then 50 input values. Compute all statical values as floating values.
The above was the question, and below is what i have done so far for the mean part, but it seems to have errors, any help???
p.s I am also confused what it means by driver class, and do i have to do individual classes for the different statistical measures....please helppppp !!!!!!!!!!, any help would be appreciated...thanks.
The class say Mean contains the following method:
public static double mean(double[] data)
double sum=0.0;
for (int index=0; index sum=sum+data[index];
sum=sum/data.length;
return sum;
The driver for this class:
public static void main(java.lang.String[] args) {
double[] myData={2,5,4,6,7,13};
System.out.println("The mean of myData");
System.out.println(Mena.mean(myData));

Answer 1

This is my method to work out the mean,median and mode of a set of numbers.
But what i need to do is find the mean, median and mode from a driver class, which generates a list of random numbers, no more then 50. I don't know where to fit this in my method...please help!!!!!!
main:
public static void main(String[] args) {
int[] mainArray = {2,3,6,6,6};
//outputArray( "Original Array: ",mainArray );
System.out.println("average is " + mean( mainArray ));
System.out.println("median is " + median( mainArray ));
System.out.println("mode is " + mode( mainArray ));
//mean
public static double mean(int[] mainArray) {
int sum = 0;
for (int i = 0; i < mainArray.length; i++) {
sum = sum + mainArray;
double average = sum / mainArray.length;
return average;
//median
public static int median(int[] mainArray) {
//double sortList = sort(mainArray);
final int EVEN_NUMBER_OF_ELEMENTS = 0;
int result = mainArray.length % 2;
int median = 0;
// Definition: Median is the Middle number in an odd number of entries array
// Median is the avg of the two number in the center of an even number array
if (result == EVEN_NUMBER_OF_ELEMENTS) {
int rightNumber = mainArray.length / 2;
int leftNumber = rightNumber - 1;
median = (mainArray[rightNumber] + mainArray[leftNumber]) / 2;
else { // Odd number of items, choose the center one
int rightNumber = mainArray.length / 2;
median = mainArray[rightNumber];
return median;
//mode
public static double mode(int[] mainArray)
int mode = 0;
int elements = 0;
int tempMode = mainArray[0];
int temp = 1;
int x;
for( x = 1; x < mainArray.length; x++)
if(mainArray[x-1] == mainArray[x])
temp++;
else
if(temp > elements)
tempMode = mainArray[x-1];
elements = temp;
temp = 1;
else
temp = 1;
if (temp> elements)
     tempMode = mainArray[x-1];
mode = tempMode;
return mode;
any help appreciated..