Urgent help needed for XML Tags using XMLForest()

Question

Folks
I need some urgent help regarding getting use defined tag in your
XML output.
For this I am using XMLElement and XMLForest which seems to work fine
when used at the SQL prompt but when used in a procedure throws and error
SQL> Select SYS_XMLAGG(XMLElement("SDI",
                                   XMLForest(sdi_num)))
     From sdi
     where sdi_num = 22261;- WORKS FINE
But when used in a procedure,doesnt seem to work
Declare
    queryCtx  DBMS_XMLQuery.ctxType;
    v_xml     VARCHAR2(32767);
    v_xmlClob CLOB;
    BEGIN
    v_xml:='Select SYS_XMLAGG(XMLElement("SDI",
                                         XMLFOREST(sdi_num)))
    From sdi
    where sdi_num = 22261';
    queryCtx :=DBMS_XMLQuery.newContext(v_xml);
    v_xmlClob :=DBMS_XMLQuery.getXML(queryCtx);
    display_xml(v_xmlClob);
End;
CREATE OR REPLACE PROCEDURE  display_xml(result IN OUT NOCOPY CLOB)
AS
     xmlstr varchar2(32767);
     line varchar2(2000);
BEGIN
     xmlstr:=dbms_lob.SUBSTR(result,32767);
     LOOP
     EXIT WHEN xmlstr is null;
     line :=substr(xmlstr,1,instr(xmlstr,chr(10))-1);
     dbms_output.put_line('.'||line);
     xmlstr := substr(xmlstr,instr(xmlstr,chr(10))+1);
     END LOOP;
end;
SQL> /
.<?xml version = '1.0'?>
.<ERROR>oracle.xml.sql.OracleXMLSQLException: Character ')' is not allowed in an
XML tag name.</ERROR>
PL/SQL procedure successfully completed.
SQL>HELP is appreciated as to where I am going wrong?

Answer 1

Hi,
if you want to transform something to something else, you should declare, what is your source.
I would prefer to use plain XSL-Transformations, because you have a lot more options to transform your source and you can even better determine, how your output should looks like.
Kind regards,
Hendrik