Urgent: How to use xdofx:replace function in xdoxslt
Hi,
I have to replace multiple occurrences of a particular string(#BR#) with the new line character. I tried <?xdoxslt:replace(stringpath,'#BR#',chr(10))?>, but it is giving error.
Later I tried <?xdofx:replace(stringpath,'#BR#',chr(10))?> which works properly.
the problem is that the string in which I have to do this operation is stored in a variable(I have stored it in a variable after doing some other replace operations). So now if I try <?xdofx:replace(xdoxslt:get_variable($_XDOCTX, 'teststring'),'#BR#',chr(10))?>, it does not work.
What should I do to resolve this issue. Is there any way in xdoxslt by which I can replace the string with new line character?
Or if there is any other way of storing the string by which it will work with XDOFX?
Thanks in advance.
I tried the same code <?xdofx:replace(xdoxslt:get_variable($_XDOCTX, 'teststring'),'#BR#',chr(13))?>, but it is not working. It is producing a blank line.
Can anyone tell me what is the new line character in xdoxslt/OBIP. For e.g. if I have to enter a new line after the year in the following code, what I should write in place of xxx
<?concat(xdoxslt:sysdate(‘YYYY’),XXX, "Report for ", FirstName, LastName)?>
I tried chr(10), \n but all of them are giving error.
Thanks and Regards
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