Urgent.......pls advice

Question

Hi All,
I have a parameter.This calls the function
"CALL FUNCTION 'F4_FILENAME' to get the file from C drive.
After selecting the file the path is displayed in the Parameter field.
My problem is I need to extract only file name from the path.Please advice.
Example : Prameter id C:\folder\file.xls
I shd extract only file.xls from the path.Please advice.

Answer 1

Hi,
after calling the function
"CALL FUNCTION 'F4_FILENAME' to get the file from C drive.
use call another function
CALL FUNCTION 'SO_SPLIT_FILE_AND_PATH' in which you pass the complete path you get from the above function and pass the variable in which you want the filename.
See example below.
CALL FUNCTION 'SO_SPLIT_FILE_AND_PATH'
    EXPORTING
      full_name           = p_file "
   IMPORTING
     STRIPPED_NAME       = v_filename "Filename
     FILE_PATH           = v_path
   EXCEPTIONS
     X_ERROR             = 1
     OTHERS              = 2
  IF sy-subrc <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
  ENDIF.
Reward Points, if useful.
Regards
Manoj Kumar