Usage of "consolidate all"

“Force calculate” to base entities and consolidate to the
organisation give the same final result than “consolidate all” to the
organisation’s top level.
But after “consolidate all” the database is somewhat bigger –
why? Where is the difference?
Is it possible to build application so that “consolidate all” is
not used if we must
-       Fetch data from other entities
-       Fetch data from previous years
-       Fetch data from other scenarios
How?
Is the only solution to use two steps 1) “force calculate” to
base entities 2) consolidate

Hi there,
That's a really interesting topic that I believe the majority of the users confuses.
The first option available in every entity is the Calculate option. This option will run all the calculation rules for the specific scenario, year, period, entity and value. Any periods before the current one will also be calculated. In order to trigger the Calculate option, the status of the entity should be CH or CH ND. If the status of the entity is OK then the available option will be the Force Calculate. Based on this, the system will not calculate an entity if it has been already calculated except if you deliberately click Force Calculate.
The next option is in every entity is the Translate option.This option will run all the translation rules in order to convert the values from the local currency to parent currency or any other selected Value dimension member. In order to run the Translate option, the value dimension member should either be the <Parent Currency> or any other currency excluding the local currency. The Translate and the Force Translate options have similar functionality as the Calculate and the Force Calculate.
The next option is the Calculate Contribution option. This option will run the calculation rules, the translation rules and the consolidation rules on a specific node (parent & entity). So, if you are in an entity with status CH and you select the Calculate Contribution, the system will run the calculation rules at <Entity currency>, the translation rules at <Parent currency> and finally will populate the value member [Proportion] and [Elimination] based on the consolidation rules. However, this rule will not affect the parent entity.
Finally, there are the options Consolidate, Consolidate all with data and Consolidate all. The Consolidate option runs only on parent entity. This option will aggregate the data from [Contribution] value member of the base entity and it will populate the <Entity Currency> member of the specific parent entity. If the calculation status of the base entity at [Contribution] value member is OK then the Consolidate option will not run the calculation or translation rules. If the status of the base entity is not CH or TR, the Consolidate option will run either the calculation and/or the translation rules on the base entity. If the child of the specific parent entity is another parent, the Consolidate command will also consolidate the child parent entity if the status is CN.
On the other hand, the Consolidate all with data option will trigger the Calculate Contribution option in every entity that has data regardless the status of the base entity. If the child of the specific parent entity is another parent, the Consolidate command will also consolidate the child parent entity regardless the status.
Finally, the Consolidate all option will trigger the Calculate Contribution or Consolidate command in every entity of the specific hierarchy. This is the reason why your database is bigger when you use the Consolidate all option. The system will run the rules in entities that have no data and the database size will increase with zeros. A way to fix this is to write rules that are not triggered if there are no data.
Based on all the above... I prefer either the Consolidate or the Consolidate all with data... The Consolidate all is only for extreme unique cases.
I hope that the above make sense and answer your question...
Regards,
Thanos
One Truth about...: ...HFM Application Copy Utility

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I have three versions of itunes backed up between 2 different external hard drives and a macbook pro. I recently got a new macbook pro and want to consolidate all music into one library on my new computer. How can I do this?

Because each library is named "iTunes Music" anytime I go to bring one library on to the same external harddrive as another it asks me if I want to REPLACE one library with the other. I don't want to do this because each file has different variations of music files. Ideally, I'd like all three "iTunes Music" music files to live on the same computer or at least the same external harddrive. Thanks for the help!

Hello cmc313,
Thanks for using Apple Support Communities.
For more information on this, take a look at:
iTunes 10 for Mac: Consolidate your iTunes library
http://support.apple.com/kb/ph990
You can consolidate all the files in your library in the iTunes folder so that, for example, it’s easier to move your library to a new computer.
Best of luck,
Mario

What is the usage of for all entries ?

What is the Usage of read table after using for all entries ?
In the following example what exactly it is doing ?
Usage of 'for all entries' in Select Statement
FORM data_retrieval.
DATA: ld_color(1) TYPE c.
DATA: BEGIN OF T_VBAP OCCURS 0,
        VBELN LIKE VBAP-VBELN,
        MATNR LIKE VBAP-MATNR,
        POSNR LIKE VBAP-POSNR,
        END OF T_VBAP.
DATA: BEGIN OF T_VBFA OCCURS 0,
        VBELV LIKE VBFA-VBELV,
        VBELN LIKE VBFA-VBELN,
        VBTYP_N LIKE VBFA-VBTYP_N,
        END OF T_VBFA.
DATA: BEGIN OF T_VBAK OCCURS 0,
        VBELN LIKE VBAK-VBELN,
        IHREZ LIKE VBAK-IHREZ,
        END OF T_VBAK.
DATA: BEGIN OF T_KNA1 OCCURS 0,
        KUNNR LIKE KNA1-KUNNR,
        NAME1 LIKE KNA1-NAME1,
        END OF T_KNA1.
   DATA: BEGIN OF T_MAKT OCCURS 0,
        MATNR LIKE MAKT-MATNR,
        MAKTX LIKE MAKT-MAKTX,
        END OF T_MAKT.
SELECT likpvbeln likplifex likpbldat likpwadat likpwadat_ist likpkodat likp~lfart
         likpkunnr likpvstel lipsposnv lipslfimg lipsvrkme lipslgmng lips~meins
         lipswerks lipslgort lipscharg lipsvbelv lipsposnr lipsmatnr
         lipsvbeln LIPSVGBEL LIPSVGPOS vbupkosta vbupwbsta vbupposnr vbup~vbeln
          VBAKIHREZ VBAKVBELN VBAP~VBELN
     INTO CORRESPONDING FIELDS OF TABLE it_itab
    FROM ( likp
           INNER JOIN lips
           ON lipsvbeln = likpvbeln
           INNER JOIN vbup
           ON vbupposnr = lipsposnr
           and VBUPVBELN = LIPSVBELN )
          left outer join VBAK
          on VBAKVBELN = LIPSVGBEL
          inner join VBAP
          on VBAPVBELN = VBAKVBELN )
         WHERE likp~vbeln IN so_vbeln
           AND likp~lifex IN so_lifex
           AND likp~lfart IN so_lfart
           AND likp~kunnr IN so_kunnr
           AND likp~vstel IN so_vstel
           AND likp~bldat IN so_bldat
           AND likp~wadat_ist IN so_wadat
           AND vbup~kosta IN so_kosta
           AND vbup~wbsta IN so_wbsta
           AND LIPS~LFIMG NE 0.
SELECT VBELN IHREZ INTO TABLE T_VBAK
FROM VBAK
FOR ALL ENTRIES IN IT_ITAB
WHERE VBELN = IT_ITAB-VGBEL.
APPEND T_VBAK.
ENDSELECT.
SELECT VBELN MATNR POSNR INTO TABLE T_VBAP
FROM VBAP
FOR ALL ENTRIES IN IT_ITAB
WHERE VBELN = IT_ITAB-VGBEL AND
        MATNR = IT_ITAB-MATNR AND
        POSNR = IT_ITAB-VGPOS.
APPEND T_VBAP.
ENDSELECT.
SELECT VBELV VBELN VBTYP_N INTO TABLE T_VBFA
FROM VBFA
FOR ALL ENTRIES IN IT_ITAB
WHERE VBELV = IT_ITAB-VBELN AND
        VBTYP_N = 'M' .
SELECT KUNNR NAME1 INTO TABLE T_KNA1
FROM KNA1
FOR ALL ENTRIES IN IT_ITAB
WHERE KUNNR = IT_ITAB-KUNNR.
APPEND T_KNA1.
ENDSELECT.
SELECT MATNR MAKTX INTO TABLE T_MAKT
FROM MAKT
FOR ALL ENTRIES IN IT_ITAB
WHERE MATNR = IT_ITAB-MATNR.
APPEND T_MAKT.
ENDSELECT.
*Populate field with color attributes
LOOP AT it_itab INTO wa_ITAB.
Populate color variable with colour properties
Char 1 = C (This is a color property)
Char 2 = 3 (Color codes: 1 - 7)
Char 3 = Intensified on/off ( 1 or 0 )
Char 4 = Inverse display on/off ( 1 or 0 )
i.e. wa_ekko-line_color = 'C410'
    REFRESH color.
    colourize 'VBELN' 0. " .
    WA_ITAB-farbe = color[].
    ld_color = ld_color + 1.
Only 7 colours so need to reset color value
    IF ld_color = 3. "8
      ld_color = 1.
    ENDIF.
    CONCATENATE 'C' ld_color '10' INTO wa_ITAB-line_color.
    WA_ITAB-NAME1 = ''.
    WA_ITAB-MAKTX = ''.
    WA_ITAB-IHREZ = ''.
    WA_ITAB-VBELV = ''.
    READ TABLE T_KNA1 WITH KEY KUNNR = WA_ITAB-KUNNR.
    IF SY-SUBRC = 0.
       WA_ITAB-NAME1 = T_KNA1-NAME1.
    ENDIF.
    READ TABLE T_MAKT WITH KEY MATNR = WA_ITAB-MATNR.
    IF SY-SUBRC = 0.
    WA_ITAB-MAKTX = T_MAKT-MAKTX.
    ENDIF.
    READ TABLE T_VBAK WITH KEY VBELN = WA_ITAB-VGBEL.
    IF SY-SUBRC = 0.
    WA_ITAB-IHREZ = T_VBAK-IHREZ.
    ENDIF.
    READ TABLE T_VBFA WITH KEY VBELV = WA_ITAB-VBELN.
    IF SY-SUBRC = 0.
    WA_ITAB-VBELVA = T_VBFA-VBELN.
    ENDIF.
   READ TABLE T_VBAP WITH KEY VBELN = WA_ITAB-VGBEL
                              POSNR = WA_ITAB-VGPOS
                              MATNR = WA_ITAB-MATNR.
   IF SY-SUBRC = 0.
   WA_ITAB-IHREZ = T_VBAK-IHREZ.
   ENDIF.
wa_ekko-line_color = 'C410'.
    MODIFY it_itab FROM wa_itab.
ENDLOOP.
ENDFORM. " data_retrieval

hi Jyotirmoy,
The explanation below can give u an idea of wat is going in ur code..
Use of FOR ALL Entries
Outer join can be created using this addition to the where clause in a select statement. It speeds up the performance tremendously, but the cons of using this variation are listed below
Duplicates are automatically removed from the resulting data set. Hence care should be taken that the unique key of the detail line items should be given in the select statement.
If the table on which the For All Entries IN clause is based is empty, all rows are selected into the destination table. Hence it is advisable to check before-hand that the first table is not empty.
If the table on which the For All Entries IN clause is based is very large, the performance will go down instead of improving. Hence attempt should be made to keep the table size to a moderate level.
Not Recommended
            Loop at int_cntry.
             Select single * from zfligh into int_fligh
             where cntry = int_cntry-cntry.
             Append int_fligh.
            Endloop.
Recommended
            Select * from zfligh appending table int_fligh
            For all entries in int_cntry
            Where cntry = int_cntry-cntry.
Thankyou,
Regards.

HT1918 Hi - I think I have different apple devices recorded under different apple IDs. Now I would like to consolidate all the devices under one Apple-ID. I have tried to do this going through the manage accoung like, but it timed out - could somebody he

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when I first imported my iPhoto library to Aperture, I choose to store files in their original location.
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File -> Consolidate Masters
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TD

HT1451 A new album purchase downloaded each song as an individual album with its own album cover. How do I consolidate all songs under just one album cover like the rest of my library?

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I would like to get clarified on the differences between "Consolidate" and "Consolidate All" option in HFM while performing a consolidation.

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Usage of "consolidate all"

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