Utl_smtp - time difference on e-mails
I'm using utl_smtp to send automated e-mails. However, the sent time shown on the actual e-mail is one hour ahead of the time it was actually sent. The mail server seems to have the correct time. Any ideas where the problem could be?
The issue is clock related. Check machine time, operating system time, etc.
If it is exactly one hour consider something just as a timezone or daylight savings time adjustment.
Similar Messages
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When I look at my e-mail before opening it, the part you see on the list shows the correct time on the e-mail. But when I open the e-mail, the time stamp in it shows an hour earlier.
What accounts for the descrepancy? And how do I fix it?
(I recently traveled from Eastern Standard Time location to Central Time location and back. The clock on my iPhone changed back and forth successfully. So wouldn't the time stamps match up as well? )Just had this issue. Was in Montreal (my home base) and flew out to Vancouver -3 hour time zone difference. Placed the phone in airplane mode and when landed, reconnected to Rogers. The phone time reset accordingly. My emails (Exchange) where showing new correct time in the email list but when opening the email it would still be showing Eastern time (Montreal time) for all previous and new emails... a hard reset actually fixed this issue and now time inside the email and in the email list are correctly showing Pacific time... my guess is something is not properly being reset when you reconnect following a timezone change when airplane mode is enabled. Some sort of bug with 3.x...
For now, my advise would be hard reset when you land.
Cheers,
David -
Time Difference in received email.
My Java application is using Oracle API to send email using the company SMPT server.
When the email is sent to employees of a particular company (they are using company email server) , email is delivered instantly but the received time is showing 4 hours difference that is minus 4 hours.
If anyone have faced this similar issue or any information on what is causing the time difference can provide me some information will be appreciated.
Please let me know if you need more information.
System Time Actual Time Sent From To Received Time in the email
when application
* is accessed.*
1:00:00 PM EST 1:00:00 PM EST Application User ,to his company mail 9:00 AM
1:00:00 PM EST 1:00:00 PM EST Application Myself ,same as the application mail server 1:00 PM
1:00:00 PM EST 1:00:00 PM EST Application my personal Gmail account 1:00 PM
1:00:00 PM EST 1:00:00 PM EST Gmail User ,Different than the application mail server 1:00 PMuser10982140 wrote:
My Java application is using Oracle API to send email using the company SMPT server.
When the email is sent to employees of a particular company (they are using company email server) ,So you send email to one (or more) group of people with no problem but with one single different group of people they have a different experience?
If anyone have faced this similar issueMy experience would be that given that the answer to the above is yes then the question has nothing to do with java - nor your code.
It has something to do with their server/environment.
You could get a SMTP email client and use it to send an email to them. You should strive to do the following
1. Make sure the client is not written in java.
2. Test it from your company using the same SMTP server you use above.
3. Test it from somewhere else using a different SMTP server. -
I purchased the iphone while out on the west coast and returned home and when I sync my phone to my computer there is a 3 hour time difference from what I have typed on my appointments on the phone to what appears on my icalendar. When I try and correct the time on either device it changes the appointment on the other by the three hours. Oh what to do?
If you are syncing your iPhone calendar events with iCal, do you have Time Zone Support enabled with iCal, and do you have Time Zone Support enabled with your iPhone?
If yes, confirm your time zone settings on your Mac at System Preferences > Date & Time under the Time Zone tab.
And on your iPhone at Settings > Mail > Contacts > Calendars under the Calendars section > Time Zone Support. -
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no, I didn't ask to burn a picture....this is why I am confused to how the picture got on there.
I understand what you are saying regarding the multi-session thing (how do I avoid this if my other cds with photos on them have this, and I don't know they do?)
but what I do know is that cd had photos on it (it definately wasn't full, and maybe that is why I haven't had a problem with others...they have all been full) and no one else uses my Mac, so I know no one else put the picture on that cd. I may have inadvertantly burned the picture, but if I did, I don't know what I did to make it burn the picture onto the cd.....
The only thing that happened was I opened iphoto so I could save some of the pictures that were already on the disc, but when I went to look for the pictures on the cd, the only thing that was on it, was an iphoto picture....which I didn't ask to be put there.....
I have previously burned pictures onto CD using my Mac with no problem, and I've pulled pictures off CD that were burned using a PC. So I guess I need to know how to determine if the cds have this multi-session thing going on?
iMac Intel Core Duo Mac OS X (10.4.7) -
How to calculate the % of time difference between different state
Hi there,
The below query returns the follwoign outptut. I need to calculate the % of time period that a specific state ( state ex: open or closed or all report )exists.
I have to find the time difference between the 2 states . How could I do that ?
The first row shows null for the previous state . How could get actual previous state for the first row?
SELECT si.station_name,
vppstation.avi_control_state_code.STATE_SHORT_NAME,
ash.state_id ,
lag(ash.state_id) over (order by ash.STATE_EFF_DATE desc) previous_state,
TO_NUMBER(TO_CHAR(ash.state_eff_date, 'SSSSS')) "periods in sec",
TO_CHAR(ash.state_eff_date, 'dd-mon-yyyy hh24:mi:ss am') "Date"
from vppstation.avi_state_history ash
left outer join vppstation.avi_control_state_code
on ash.state_id = vppstation.avi_control_state_code.state_id
LEFT OUTER JOIN vpproadside.stations_installed si
ON ash.station_id = si.station_id
where ash.state_eff_date >= to_date('28/02/2010', 'dd/mm/yyyy')
and ash.state_eff_date <= to_date('03/03/2010', 'dd/mm/yyyy') ;
group by si.station_name
ash.state_id
order by ash.state_eff_date asc ;
STATION_NAME STATE_SHORT_NAME STATE_ID PREVIOUS_STATE periods in sec Date
IRDNCST02 Open 1 NULL 85166 01-mar-2010 23:39:26 pm
IRDNCST02 All Report 3 1 85159 01-mar-2010 23:39:19 pm
IRDNCMT01 Closed 2 3 81376 01-mar-2010 22:36:16 pm
IRDNCST02 Open 1 2 78723 01-mar-2010 21:52:03 pm
IRDNCST02 All Report 3 1 76023 01-mar-2010 21:07:03 pm
IRDNCMT01 Open 1 3 55922 01-mar-2010 15:32:02 pm
IRDNCMT01 Closed 2 1 54931 01-mar-2010 15:15:31 pm
IRDNCHA01 Closed 2 2 41291 01-mar-2010 11:28:11 am
IRDNCAS01 Open 1 2 38847 01-mar-2010 10:47:27 am
IRDNCAS01 All Report 3 1 37947 01-mar-2010 10:32:27 am
IRDNCST02 Open 1 3 35332 01-mar-2010 09:48:52 am
IRDNCST02 All Report 3 1 32632 01-mar-2010 09:03:52 am
IRDNCST02 Open 1 3 31502 01-mar-2010 08:45:02 am
IRDNCST02 All Report 3 1 28802 01-mar-2010 08:00:02 am
IRDNCHI01 Open 1 3 25368 01-mar-2010 07:02:48 am
IRDNCHI02 Open 1 1 23939 01-mar-2010 06:38:59 am
IRDNCMT01 Open 1 1 20696 01-mar-2010 05:44:56 am
IRDNCCH02 Open 1 1 13452 01-mar-2010 03:44:12 am
Edited by: Indhu Ram on Mar 11, 2010 1:34 PM
Edited by: Indhu Ram on Mar 11, 2010 2:20 PMIf you look at the table which is output of the given query , there is column called "STATE_ID" It shows the current state ie open or closed or all report.
The column 'PREVIOUS_STATE' shows the state before the current state. .In the table in 2nd row in previous_state column there is state_id = 1 (open)which is the state before 'all report state' -
I have a 50Hz sine wave and a pulse signal on a same graph. The phase difference between two is between 0-90 degrees.
Now I need to calculate the time difference between (when the sine wave crosses zero volts) and (when the pulse rises). The frequency will stay approximately same for both signals.
The application is for a three phase generator. In simple words, when the time difference between the zero-crossing of sine wave and the pulse rises increases, that means that the load on the generator has increases.
I am a beginner user of LabView (version 9, 2009), maybe it is a very simple problem but I've been pulling my hair out for the last few days and coudln't figure anything out. Any help would be greatly appreciated. I am using DAQ USB-6008 to measure these voltages and pulse from the generator and a sensor
I have attached a jpg (a graph that i just made with excel to explain). The time 't' is what I am trying to measure
Cheers
Awais
Message Edited by awais.h on 03-30-2010 11:20 PM
Message Edited by awais.h on 03-30-2010 11:21 PM
Solved!
Go to Solution.Hi
Thanks for the code but I'm afraid it won't work. Like you said the probability of choosing a value that is on both graphs may not happen. This is something that I would like the code to do automatically.
But I did use the previous code posted and made some modifications to it and it seems to work perfectly. Now the next thing is to be able to get just that one value that tells you the first time difference.
Here is what I get using that code.
As you can see from the t Values. I only need the one that is highlighted. If there is a way to filter out the rest it would be great.
I was thinking of a while loop and as soon as the value is higher than 3E-5 it would store the number and stop the loop, but I'm not too familiar with arrays in labview.
Here is the the code modified.
As you can see, it wasn't that big of a modification and it still is your code.
I will keep trying.
Thanks for the help
Attachments:
FinalShockSpeed.vi 55 KB -
Lost connection detection time difference
Having a problem understanding why a broken JDBC connection is detected under Windows much quicker than it is under Linux.
I have an process that opens a connection to MSSQL using JDBC, a Stored Procedure is then executed and the result set
processed, this execute step is repeated every 60 seconds or so. If any exception is thrown then resources are closed, sleep
for 60 seconds, the connection is reopened (if fails then sleeps and repeats), once reopened the process continues. There is logging throughout
the above steps.
On Windows Vista 64bit Sun Java platform the process runs fine, if I deliberately break the connection (stop MSSQL service), the process
logs a problems within 60 seconds and starts handling the error, when the MSSQL comes back then within 60 seonds the connection is remade
and the process continues as expected.
Under Ubuntu 10 64bit both Sun and OpenJDK the process runs fine, until the connectionis broken, as it takes about 17 minutes for the exception to be thrown
for the broken connection (stopped MSSQL) to be detected, as opposed to under Windows taking seconds. Once detected then the process works as expected, retrying
and reconnecting as it should.
The libs and code used are the same the only difference between the windows and linux versions are the logging path parameter, have tried with different versions of Java
and with different MSSQL JDBC drivers.
What could be the reason for the time difference in the lost connection detection between Windows and Linux? Any help tips would be most welcome.
Thanks.The connection is only made once and used throughout, it is only closed if there is a problem. This runs absolutely fine with logging for weeks, the execute and processing take millisecondsIt is pointless to keep the connection in that situation. Create it every time.
Doing that might even fix your problem. But regardless you should still not keep it.
Have jujst checked the timings and if the db connection is broken the on Linux (Ubuntu) the exception generated by step 4. takes up to 15 minutes 35 seconds to move on to step 7. on Windows though it is instant, there is a log message output prior to the execute statement this outputs then the exeception logged.You have an existing connection.
Then you attempt a request which I am guess takes 17 minutes to timeout. (That happens because you are testing by stopping the server.)
That is the problem.
First verify the connection url. It might have timeout values in it.
If not then the next most likely cause is that someone changed the OS (not java) TCP timeout values. Bad idea if they did. And the only way to fix is to change them back to something reasonable. You can code around this by using two threads. One that sets a timer and the other that runs the request. If the timer fires then attempt to cancel the request (see the jdbc api.) -
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Thank you all kindly for any suggestions & your time
Regards,
JCI DO NOT want ANY mail showing in my inboxes when Mail starts UNTIL i enter that password for each account.
That is simply not possible with Mail, and never has been. Anyone who uses your account can see all messages stored in Mail. The only true solution is to not let other people use your account. Let other people use the guest account, or if you share the machine with someone else, set up a separate user account for that person. This will also solve the problem of remembering the password. It will become a non-issue for Mail to remember your password if nobody else has access to your account. -
why does it take a lot of time whenever i open mail icon from yahoo server?
Go to Mail Preferences > General Tab > and the second line should say how often it will check for new messages
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How to find out time difference between 2 consecutive characters coming in
Hi
Data is coming on serial port and m taking this data in a input stream.I need to know the time difdference between consecutive characters.Any ideas?What do you mean? If you meassure the time between two characters, you want to calculate how accurate it is? First you would need to find out how accurate the System.currentTimeMillis is on the platform you run on. That may be easy
long start = System.currentTimeMillis();
long end;
while ((end = System.currentTimeMills()) == start);
long delta = end - start;But sometimes (on win98) it reports 50, other times 60. So its not quite accurate. But you could redo that test a couple of times and take the avg or the max.
Then if you get a time difference of 0ms between two characters, you know it will be somewhere 0 and 60ms. If you get 60ms between two characters, you know it will be somewhere between 0 and 120 ms. It's +/- delta seconds accurate.
Would this be a way to calculate the percentage accuracy: 100.0-100.0*delta/(time+delta)
Still better to meassure the time over more than just 2 characters unless it is a very slow stream. -
Execution time difference between SELECT & UPDATE statement in JDBC Sender.
Hi Experts,
In my scenario, I have used the JDBC Sender Adapter with the SELECT and UPDATE statement.
Now the problem is in between the execution of Select and update statement, few more entries are coming in the same DB Table.
So result of this is updation take place for those entries which are not even picked up by the select statement.
Can we avoid this execution time difference between the SELECT & UPDATE statemet on JDBC Sender side???
Thanks & Regards
JageshHi
Use serializable option in additional parameters, now all new entries would also be updated. -
How to find the date and time difference in InfoPath 2013?
Hi All,
My date and time format is like: 2013-12-24T10:47:38 and have three fields Start date, End date and Actual time taken.
If start date and end date filled then actual time taken field should automatically should fill, for example 2 days 12 hours 48 min 3 sec.
How to achieve this?Hi Sam,
I believe we had discussed the same issue in the below thread. Can you please refer the below one?
http://social.msdn.microsoft.com/Forums/sharepoint/en-US/d93e16ff-c123-4b36-b60b-60ccd34f6ca7/calculate-time-differences-in-infopath?forum=sharepointcustomizationprevious
If it's not helping you please let us know
Sekar - Our life is short, so help others to grow
Whenever you see a reply and if you think is helpful, click "Vote As Helpful"! And whenever
you see a reply being an answer to the question of the thread, click "Mark As Answer -
How to get exact date and time difference?
Hi,
When i am using the below sql statement:
SELECT (TO_DATE('7/27/2006 05:00:15 PM','MM/DD/YYYY HH:MI:SS PM') - to_Date('7/27/2006 8:30:13 AM','MM/DD/YYYY HH:MI:SS AM')) * 24 hours FROM DUAL;
the output is:
Hours
8.50055555555556
But Actually it is 8.30
So how can i get exact days and time difference between two dates in Oracle?
Thanks....
Regards,
Suman Sakinala
Edited by: SSN on Sep 19, 2008 1:27 AMOr more clearly (this time I have my date_from and date_to the right way around hehe!)
SQL> ed
Wrote file afiedt.buf
1 WITH t as (select TO_DATE('7/27/2006 05:00:15 PM','MM/DD/YYYY HH:MI:SS PM') as dt_to,
2 TO_DATE('7/27/2006 08:30:13 AM','MM/DD/YYYY HH:MI:SS AM') as dt_from FROM DUAL)
3 ,d as (select (dt_to-dt_from)*24 as diff_hrs from t)
4 -- end of dates
5 SELECT TRUNC(diff_hrs) as hours
6 ,TRUNC(((diff_hrs) - TRUNC(diff_hrs))*60) as mins
7 ,TRUNC(((((diff_hrs) - TRUNC(diff_hrs))*60) - TRUNC(((diff_hrs) - TRUNC(diff_hrs))*60))*60) as secs
8* FROM d
SQL> /
HOURS MINS SECS
8 30 2
SQL>
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