Variable customer exit
Hi all,
I created a query with customer exit variable that is filled from another variable manual entry.
When i start a query I receive this error message:
Error for variable in the customer exit
and in debug I find this message:
System error in the program CL_RSR_REQUEST and Form GET_SETXX_WA
How can I do?
Thanks
Gianmarco
when 'ZODACE'.
tables: /BIC/AZSD_O0100,
/BIC/AZSD_O0200.
ranges: r_createdon for /BIC/AZSD_O0100-CREATEDON.
break-point.
if i_step = 2.
loop at i_t_var_range into loc_var_range
where vnam = 'ZDATADOC'.
clear r_createdon.
r_createdon-low = loc_var_range-low.
r_createdon-high = loc_var_range-high.
r_createdon-sign = 'I'.
r_createdon-option = 'BT'.
append r_createdon.
exit.
endloop.
select DOC_NUMBER into
/BIC/AZSD_O0100-DOC_NUMBER
from /BIC/AZSD_O0100
where /BIC/ZAUDAT in r_createdon.
select single * from /BIC/AZSD_O0200
select * from /BIC/AZSD_O0200
where refer_doc = /BIC/AZSD_O0100-DOC_NUMBER.
clear l_s_range.
l_s_range-low = /BIC/AZSD_O0200-refer_doc.
l_s_range-sign = 'I'.
l_s_range-opt = 'EQ'.
append l_s_range to e_t_range.
endselect.
endselect.
endif.
The variable are:
ZODACE based on IO 0REFER_DOC with customer exit
ZDATADOC based on IO ZDATU with manual entry
After wich end-user digit a data in ZDATADOC popup I take ODOC_NUMBER in order item ODS ZSD_O01 where ZDATADOC=CREATEDON.
With 0DOC_NUMBER I go to delivery item ODS ZSD_O02 and I take the corresponding 0REFER_DOC and then I fill variable ZODACE.
0REFER_DOC is in row of the query.
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Hi developers,
we have problem because we have created a variable time on 0CALDAY who is mapped in the cube of the stock with posting date.We launch the query for example with range 01/8/2005 31/8/2005 and the resul is OK.
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Thanks DomenicoHi,
I think, this approach does not work. Because customer exit will be finished before displaying the result set of 1st report. So the assignment to VAR2 from VAR1 does not execute then after.
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Take help.sap.com help for further information.
With rgds,
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Message was edited by: Anil Kumar Sharma -
No Query Result After Using Hierarchy Node Variable (Customer Exit)
Hi
I have problem at my query. It doesn't show anything in BEx but when i check the data in BW using tcode LISTCUBE i can display the data.
This problem happen when i change the restrictions for one of characteristic in filter value.
The characteristic is custom Infoobject (ZCPARTNER), which like Infoobject Partner Unit.
Previously I set the restriction with constant value, example : A500,A700,A710,A720,A730,A740 and it worked before.
But when I change it using hierarchy node variable (customer exit), this problem is arise.
Here is my code at ZXRSRU01
WHEN 'ZHIEPART'. --> hierarchy node variable
BREAK-POINT.
IF i_step = 2.
Read from ZZCONSGR information
LOOP AT i_t_var_range INTO loc_var_range
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CLEAR l_s_range.
CLEAR l_s_range-low.
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l_s_range-low = 'MEZBUNITMDI'.
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ELSEIF loc_var_range-low EQ '000000000000040000'
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ENDIF.
l_s_range-sign = 'I'.
l_s_range-opt = 'EQ'.
APPEND l_s_range TO e_t_range.
EXIT.
ENDLOOP.
ENDIF.
Here the hierarchy in BW system:
XXX Cons Unit Hierarchy Set; InfoObject ; Node Name
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Anyone can help my problem? Thank you
Regards,
Satria B TandyonoHi Satria,
Instead of following code ---
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IF loc_var_range-low EQ '000000000000030000'
OR loc_var_range-low EQ '000000000000010130'.
l_s_range-low = 'MEZBUNITMDI'.
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OR loc_var_range-low EQ '000000000000010160'.
l_s_range-low = 'MEZBUNITMPI'.
l_s_range-high = '0HIER_NODE'.
ENDIF.
try this ---
IF loc_var_range-low EQ '000000000000030000'
OR loc_var_range-low EQ '000000000000010130'.
l_s_range-low = 'MEZBUNITMDI'.
ELSEIF loc_var_range-low EQ '000000000000040000'
OR loc_var_range-low EQ '000000000000010160'.
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ENDIF.
Note : whenver the option is EQ, the system takes only low value. -
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http://wiki.sdn.sap.com/wiki/display/BI/Sample+user+exits+for++Bex+Variables+in+SAP+BW
SINGLE VARIABLE
WHEN 'VAR_SINGLE'.
CLEAR L_S_RANGE.
L_S_RANGE-LOW = '40'.
L_S_RANGE-SIGN = 'I'.
L_S_RANGE-OPT = 'EQ'.
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My customer exit:
zpl TYPE char4.
IF i_step = 2.
CASE i_vnam.
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LOOP AT i_t_var_range INTO loc_var_range WHERE vnam = 'ZV_TXT2'.
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l_s_range-high = '0175'.
l_s_range-sign = 'I'.
l_s_range-opt = 'BT'.
ENDCASE.
APPEND l_s_range TO e_t_range.
ENDLOOP.
ENDCASE.
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I would like to do this:
WHEN 'ZPLANT1'.
LOOP AT i_t_var_range INTO loc_var_range WHERE vnam = 'ZV_TXT2'.
CLEAR: l_s_range.
zpl = loc_var_range-low.
CASE zpl.
WHEN 'NORD'.
CLEAR L_S_RANGE.
l_s_range-low = '0010'.
l_s_range-sign = 'I'.
l_s_range-opt = 'EQ'.
APPEND l_s_range TO e_t_range.
l_s_range-low = '0175'.
l_s_range-sign = 'I'.
l_s_range-opt = 'EQ'.
APPEND l_s_range TO e_t_range.
WHEN OTHERS.
l_s_range-low = '0010'.
l_s_range-high = '0175'.
l_s_range-sign = 'I'.
l_s_range-opt = 'BT'.
ENDCASE.
APPEND l_s_range TO e_t_range.
ENDLOOP.
ENDCASE.
ENDIF.
Thx in advance
BatouHi,
DATA : l_s_range TYPE rsr_s_rangesid.
DATA : loc_var_range LIKE rrrangeexit.
Here:
ZPLANT : Is customer Exit variable on Plant
ZV_TXT1: Is Text variable Bcoz I'll gibe input through variable in Report.
ZPL = loc_var_range-low = CHAR 60
WHEN 'ZPLANT'.
LOOP AT i_t_var_range INTO loc_var_range WHERE vnam = 'ZV_TXT1'.
CLEAR: l_s_range.
ZPL = loc_var_range-low.
CASE ZPL.
WHEN 'A'.
l_s_range-low = 'PA01'.
l_s_range-high = 'PA05'.
l_s_range-sign = 'I'.
l_s_range-opt = 'BT'.
WHEN 'B'.
l_s_range-low = 'PB01'.
l_s_range-high = 'PB05'.
l_s_range-sign = 'I'.
l_s_range-opt = 'BT'.
WHEN OTHERS.
l_s_range-low = 'PA01'.
l_s_range-high = 'PZ10'.
l_s_range-sign = 'I'.
l_s_range-opt = 'BT'.
ENDCASE.
APPEND l_s_range TO e_t_range.
ENDLOOP.
ENDCASE.
ENDIF.
Thanks
Reddy -
Variable Customer Exit Is Not Working
Dear all,
I have created two variables to compare current month and previous month:
ZCURMONTH
ZPREVMONTH
However, only column with ZCURMONTH displays the data but not column with ZPREVMONTH.
Can someone tell me what is wrong with this customer exit code?
IF I_STEP = 2.
CASE I_VNAM.
WHEN 'ZCURMONTH'.
CLEAR loc_var_range.
READ TABLE i_t_var_range INTO loc_var_range WITH KEY VNAM = '0P_PER3'.
CLEAR l_s_range.
l_s_range-sign = 'I'.
l_s_range-opt = 'BT'.
IF loc_var_range-low GT '012'.
l_s_range-low = '012'.
l_s_range-high = loc_var_range-low.
ELSE.
l_s_range-low = loc_var_range-low.
l_s_range-high = loc_var_range-low.
ENDIF.
APPEND l_s_range TO e_t_range.
WHEN 'ZPREVMONTH'.
CLEAR loc_var_range.
READ TABLE i_t_var_range INTO loc_var_range WITH KEY VNAM = '0P_PER3'.
CLEAR v_period.
IF loc_var_range-low LT '013'.
v_period = loc_var_range-low - 1.
ELSEIF loc_var_range-low = '013'.
v_period = loc_var_range-low - 2.
ELSEIF loc_var_range-low = '014'.
v_period = loc_var_range-low - 3.
ELSEIF loc_var_range-low = '015'.
v_period = loc_var_range-low - 4.
ELSE.
v_period = loc_var_range-low - 5.
ENDIF.
CLEAR l_s_range.
l_s_range-sign = 'I'.
l_s_range-opt = 'BT'.
IF loc_var_range-low GT '001'.
l_s_range-low = v_period.
l_s_range-high = v_period.
ELSE.
l_s_range-low = '012'.
l_s_range-high = '016'.
ENDIF.
APPEND l_s_range TO e_t_range.
ENDCASE.
ENDIF.
Thanks!Hi AL,
I set the variable to represent "Interval" instead of "Multiple Single Values". Which one is correct in my case i.e. Period 12 - Period 16?
Also, I have set the break-point for debug by monitoring the L_S_RANGE structure and E_T_RANGE table. The values are what I expected in EXIT_SAPLRRS0_001 function. However, I lost the plot when it goes to another function i.e. RRS_VAR_VALUES_EXIT_AFTER, the L_S_RANGE has changed to another value and E_T_RANGE becomes invalid.
Appreciate further inputs. -
Formula Variable Customer Exit
Hi Gurus,
I have a requirement where I have to read the one formula variable value ( Replacement path with attribute value ) into customer exit of another characteristic variable .
For example :
I have one characteristic formula variable called VAR1 ( which gives the value ) .This value I want to use it in customer exit of another varable VAR2 ( is it possible to use one formula variable value into another variable ) which I want to use it in Customer exit.
VAR1 - Formula Variable
VAR2 - Simple Variable with out User Input.
Example is as below :
Formula Variable ( VAR1 i.e PLND_DLVRY ) based on this value I want to define another variable APO Version in the Customer
If it is possible please guide me what is the process. Also I want to make sure which I_STEP I need to use...
Please guide the best solution.
Thanks
Ganesh Reddy.Hi Krishnan / Arvind,
Sorry I was thinking 0PLND_DELRY is nav attribute for 0MAT_PLANT. But 0PLND_DELRY is the quantity field so I can't make this field as a nav attribute. Right now I am populating directly in the Cube using master data. my cube data looks like
Fields Description
F1 = Version
F2= Material
F3= Plant
F4= 0PLND_DELRY
F5= Calendar Yr/Month
F6= Concensus Forecast ( Key Figure )
Condition is Combination of Material and Plant will define 0PLND_DELRY ( Delivery Time )
F1 | F2 | F3 | F4 |F5 | F6
201104 | M001 |200 | 30 | 2011/07 | 5100
201104 | M002 |200 | 60 | 2011/07 | 6200
201104 | M001 |300 | 90 | 2011/07 | 4900
201104 | M001 |200 | 30 | 2011/07 | 7900
201105 | M001 |200 | 30 | 2011/07 | 5700
201105 | M002 |200 | 60 | 2011/07 | 6900
201105 | M001 |300 | 90 | 2011/07 | 4300
201105 | M001 |200 | 30 | 2011/07 | 7400
201106 | M001 |200 | 30 | 2011/07 | 5500
201106 | M002 |200 | 60 | 2011/07 | 6700
201106 | M001 |300 | 90 | 2011/07 | 4500
201106 | M001 |200 | 30 | 2011/07 | 7500
201107 | M001 |200 | 30 | 2011/07 | 5000
201107 | M002 |200 | 60 | 2011/07 | 6500
201107 | M001 |300 | 90 | 2011/07 | 4000
201107 | M001 |200 | 30 | 2011/07 | 8000
In Order to bring the variance for F6 for Material M001 and Plant 200 then my result is
Calendar Yr / Mnth = 2011/07
Current Value = 5000
Lead Time = 30, offset = -1
Version = 201107-1 = 201106 Then
Prior Value = 5500
Variance = 5000-5500 = -500
for Material M002 and Plant 200 then my result is
Calendar Yr / Mnth = 2011/07
Current Value = 6500
Lead Time = 60, offset = -2
Version = 201107-2 = 201105 Then
Prior Value = 6900
Variance = 65000-6900 = -200
for Material M001 and Plant 300 then my result is
Calendar Yr / Mnth = 2011/07
Current Value = 4000
Lead Time = 90, offset = -3
Version = 201107-3 = 201104 Then
Prior Value = 4500
Variance = 4000-4900 = -900
for Material M001 and Plant 200 then my result is
Calendar Yr / Mnth = 2011/07
Current Value = 4000
Lead Time = 30, offset = -1
Version = 201107-1 = 201106 Then
Prior Value = 4500
Variance = 8000-7500 = -500
Every month we get same data with different version and different numbers for all months. Please advise me what is the best solution we can do
Thanks
Ganesh Reddy. -
BW Variable Customer Exit I_STEP 3
Can anyone tell me under what circumstances I_STEP 3 is called to validate a variable input.
Thank you,
BeatLet me try to explain you with an example
I have the following scenario our fiscal period starts in Oct so it is 001.2005.
So if a user runs a report in period 003.2005 the report must report for the periods 001.2005, 002.2005 & 003.2005.
If the user reports in 005.2005 the report must report for the period 004.2005 and 005.2005 which is the second fiscal quarter. Similarly, if the user reports for period 011.2005 it must report for the periods 010.2005 & 011.2005 which is the fourth fiscal quarter.
Now in order to do this task i used variable exits
First create a variable of type customer exit and write the code in Program(Include) ZXRSRU01.
Code looks like this.
In the code try to put this logic
dat1 = fisc period u supplied (say 3.2005)
dat2 = dat1+4(2) " i.e 3
like this for four querters u have to define and supply the values dat3 and dat1 in low and high selections.
WHEN 'ZE_CALMT'.
IF I_STEP = 3.
If Qarter = 1.
Concatenate dat1(4) 01 into dat3. " 200501
dat1 " 200503 which is supplied by user
elseif querter = 2
Concatenate dat1(4) 04 into dat3. " 200501
dat1 " 200503 which is supplied by user
etc
L_S_RANGE-LOW = DAT3
L_S_RANGE-HIGH = DAT1
L_S_RANGE-SIGN = 'I'.
L_S_RANGE-OPT = 'BT'.
APPEND L_S_RANGE TO E_T_RANGE.
ENDLOOP.
ENDIF.
I_STEP = 3
In this call up, you can check the values of the variables. Triggering an exception (RAISE) causes the variable screen to appear once more. Afterwards, I_STEP=2 is also called up again from the authorization check or from the Monitor.
If you have specific problem please do let me know.
Regards
vijay
Message was edited by: sundaresan chander -
Hi,
I need some help for the customer exit. I am explaining you the scenario. Please suggest. point will be assigned to good answers.
I have an infocube with one of the infoobject as 0FISCPER. There is a variable defined on 0FISCPER say ZVAR1. There is a Z table in which there is a number maintained against each record of 0FISCPER ...
Please see the ex below.
005.2008 3
006.2008 4
007.2008 3
008.2008 5.
I need to read the number from the above table against theb user input period.
Suppose the user enters 008.2008 then I have to read the number from the table i.e. 5.
I have to display the report 5 period back to the entered period by the user. i.e query should retrieve the data for period.
003.2008
004.2008
005.2008
006.2008
007.2008
1) Do I have to define 2 variable for this ? Read one variable and in I_STEP = 2 populate the other variable or 2) Can i use the same variable and read the table and then in I_STEP = 2 , I will modify the same variable.
Please suggest.
Regards,
Bill
Edited by: Bill Bryan on Jul 2, 2008 5:21 PM
Edited by: Bill Bryan on Jul 2, 2008 5:23 PMHi Bill,
To elaborate with what Naveen said. You require 2 variables on 0FISCPER.
Let the ZVAR1 be of user input in type and ZVAR2 be the Customer exit type.
In the code for the ZVAR2 follow these steps.
1. Read the value of the User Input value in ZVAR1.
2. Based on the ZVAR1 value read the Z Table for the number.
3. Then build the logic to derive the back periods based on the number read.
4. Then add this to the E_T_RANGE table.
Hope this is clear. Let me know if you need the code.
Regards,
Sudheer -
BEx Variables - Customer Exit - Find Max and Min of two values
Hi Experts, I have two ID's at any given time in my InfoProvider. I'm trying to create two user exit variable on this ID. One should return the max of the two and the other should return only available one (i.e. the Min). The variable should not prompt the user for any value. Any time the variable is used in the report. max should the max of the two ID's and the Min should show the lower of the two values.
I would appreciate if somebody could provide the code that I can use.you could use below:
Variable for Max
SELECT MAX ( ID Field )
FROM <Source>
INTO <wa_id>.
Variable for Min
SELECT MIN ( ID Field )
FROM <Source>
INTO <wa_id>. -
Calculations on customer exit using input variable
hi,
suppose i have a date input variable on my query, and i want to use the input value as an input for a calculation to be done in a different characteristic variable whose value is derived via a customer exit. how could this be done?
as an example - i have an input date field, and say, the user enters 1/15/2005. the other characteristic variable is, for example, sales for a given date, restricted against a characteristic variable (customer exit) which should restrict the KF to say, the start of the month of the input date up to the input date (in this case, 1/1/2005 - 1/15/2005).
thanks in advance. =)
ryan.Hi Ryan,
you have to use parameter I_STEP = 2 in your exit (IF I_STEP = 2. (...))
This second step is called after the processing of the variable pop-up and only for those variables that are not marked as ready for input and are set to mandatory variable entry.
Build your second variable in this way and then you can use this step to see first (pop-up) variable value.
For details see www.service.sap.com/bw -> SAP BW InfoIndex -> Variables -> How to... Derive a Variable value from another variable 2.x (pdf).
Hope it helps (and please don't forget to assign some points by clickin'on the yellow star to the contributors that help you !!!)
Bye,
Roberto
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