Very challenging Regular Expression(for me atleast) ..HELP

Question

This is a complex situation for me and i would really appreciate if you could help me out with the regular expression that meets my condition
Scenerio:
Lets assume i am reading a file that has only numbers or integers in it. Now i need to read each line by line and print an error message if a condition is met.
Consition is:
If there is a number >= 50 in with  at least 5 zeros in front or 5 zeros back of it
print"error encountered"
Example 1
12454540000000050584
Print "error" because there are atlease 5 consecutive zeros in front of 50
Example 2
24546744500005800000000
Print "Error" because there are atleast 5 consecutive zeros behind 80( which is greater than 50)
Example 3
24546744500005800000000068
Print "error" message because there are atleast 5 consecutive zeros behing 58 BUT 68 does not meet the condition because there are only 4 consecutive zeros infront of it because rest of the zeros are already associated with 58 and cannot be recounted. Zeros are counted in a chunk of five and a chunk could only be counted once.
Please resond to this thread if more clarification is needed.
Appreciate your help. You guys ROCK.

Answer 1

Hiklior wrote:
This is a complex situation for me and i would really appreciate if you could help me out with the regular expression that meets my condition
Scenerio:
Lets assume i am reading a file that has only numbers or integers in it. Now i need to read each line by line and print an error message if a condition is met.
Consition is:
If there is a number >= 50 in with  at least 5 zeros in front or 5 zeros back of it
print"error encountered"
Example 1
12454540000000050584
Print "error" because there are atlease 5 consecutive zeros in front of 50
Example 2
24546744500005800000000
Print "Error" because there are atleast 5 consecutive zeros behind 80( which is greater than 50)
Example 3
24546744500005800000000068
Print "error" message because there are atleast 5 consecutive zeros behing 58 BUT 68 does not meet the condition because there are only 4 consecutive zeros infront of it because rest of the zeros are already associated with 58 and cannot be recounted. Zeros are counted in a chunk of five and a chunk could only be counted once.
That last sentence makes me think that maybe regex is not the way to go here. Well that and what seem to math operations.
I don't think I understand the more than 50 stuff.
So here is I think what I do understand
- more than 5 zeroes in front of a 5 is bad
- I think once you have a pattern of zeros and then a 5 everything trailing the five is part of the zeroes until the END of the next set of zeros
Is that right?