Very Simple C question - reading input parameters/flags... [SOLVED]

Question

This is an extremely simple question. Please forgive me for being a noob. I am writing an application in C (with GCC) called GAPE and need to be able to pass it parameters through a shell script (/usr/bin/gape) that can determine how it runs. To start with easy stuff, I want the end-user to be able to type "gape -V" to output the version of the program. How do I do that? I understand that I need to put the shell script in /usr/bin...where should I put the actual gcc-compiled gape application? Or do I even need a shell script? Can I just put the GAPE binary in /usr/bin and pass parameters to it directly? If so, how do I do that in C? Any help is greatly appreciated.
Last edited by tony5429 (2008-03-10 12:00:21)

Answer 1

include <stdio.h>
main(int argc, char *argv[])
int i;
for(i = 1; i < argc; i++) //argc = the number of arguments
printf("param nr %d: %s\n", i, argv[i]); // argv[i] contain the arguments, with 0 being the program name (anyone may correct me here)
[jaqob@p238 c++-egna]$ ./a.out 1 2 3
param nr 1: 1
param nr 2: 2
param nr 3: 3
[jaqob@p238 c++-egna]$ ./a.out -h -V -zxvf
param nr 1: -h
param nr 2: -V
param nr 3: -zxvf
A very simple program that prints the parameters
And yes, you can put the program in /usr/bin/ without a shellscript
Last edited by JaQoB (2008-03-05 18:09:34)