WebLogic Workship shell script
./Workshop.sh: /export/home/bea/weblogic700b/workshop/jdk1.4/jre/bin/java: not
found
I don't see any jdk1.4 directory installed in workshop directory. The installation
script has installed only jdk131 in bea home directory. Can I change the script
to point to jdk131 or jdk1.4
Please help how do I get started after installing weblogic workshop.
Thanks
You can use WLST to get information on the state of your deployments, for example,
the python script can be used
class DeploymentInfo:
def __init__(self,name,target):
self.name = name;
self.target = target;
def getName(self):
return self.name;
def getTarget(self):
return self.target;
print 'CONNECT TO ADMIN SERVER';
connect('weblogic', 'transfer11g');
print 'OBTAINING DEPLOYMENT INFORMATION';
deploymentsInfo = [];
applications = cmo.getAppDeployments();
for application in applications:
name = application.getName();
target = application.getTargets()[0].getName();
deploymentsInfo.append(DeploymentInfo(name, target));
print 'CHANGE TO DOMAIN RUNTIME ENVIRONMENT';
domainRuntime();
print 'APPLICATION LIFE CYCLE INFORMATION';
applicationRuntime = cmo.getAppRuntimeStateRuntime();
for deploymentInfo in deploymentsInfo:
state = applicationRuntime.getCurrentState(deploymentInfo.getName(), deploymentInfo.getTarget())
print 'Application: ' + deploymentInfo.getName() + ', State: ' + state;
if (state != 'STATE_ACTIVE'):
startApplication(deploymentInfo.getName());In the example above the application gets started when it is not running, you can also
send an e-mail by using the smtplib package, for example
import smtplib;
server = smtplib.SMTP('email-server-host');
server.set_debuglevel(1);
server.sendmail(fromaddress, toaddress, message);
server.quit();More information on the package smtplib can be found here:
http://www.jython.org/docs/library/smtplib.html
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ThanksYou can use WLST to get information on the state of your deployments, for example,
the python script can be used
class DeploymentInfo:
def __init__(self,name,target):
self.name = name;
self.target = target;
def getName(self):
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def getTarget(self):
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connect('weblogic', 'transfer11g');
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domainRuntime();
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Do someone have, know and help to find the jbfbs examples
with NT shell scripts. Currently I found examples with
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Passing paramter from ANT to shell script doesn't seems to work for me;Help
Hi,
what iam "trying" to do is to pass some variables from my ANT script to a shell script. This is what iam doing with my 3 files. Iam getting errors when iam doing this.
1) build.xml file:
<?xml version="1.0" encoding="iso-8859-1"?>
<project name="dev" default="all" basedir=".">
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2) myAnt.properties file:
general.script=deployScript.sh
ANTPATCH=/opt/bea/wlserver6.1/lib/latest_deploy.jar
WEBLOGICJAR=/opt/bea/wlserver6.1/lib/weblogic.jar
ADMINPORT-NUMBER1=7001
HOSTNAME=reliant2-----------------------------------------
3) deployScript.sh file:
export ANTPATCH=$1
export WEBLOGICJAR=$2
export ADMINPORTNUMBER=$3
export HOSTNAME=$4
java -cp "$ANT-PATCH":"$WEBLOGIC-JAR" weblogic.deploy -port
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weblogic testMon /export/home/san5sxs/applications/beamon/myfile.war-------------------
and the Exception is:
[echo] This is the TESTNET box
[exec] /opt/bea/weblogic81/server/bin/applications/deployScript.sh: ANTPATCH=: is not an identifier
[exec] Result: 1
BUILD FAILED
file:/opt/bea/weblogic81/server/bin/build.xml:30: Could not create task or type of type: arg.
Ant could not find the task or a class this task relies upon.
any help in this matter ??
regards,
sangitaHave you looked at [url http://ant.apache.org/]ant's website
That's apache's ant. I'm not sure if there are others or not.
if so, here is the mailing list [url http://ant.apache.org/mail.html]info -
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What I did so far is to do it in automator with Apple Script which goes like the following:
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What's the correct syntax for that line
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Also this requires the terminal app to be open in the background.
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I have a program that I run via Terminal, but I don't want a terminal window open while I run it (Just personal preference). I have an applescript set up to run the Terminal command, but the thing is that the command is "on" while the program is running, Is there some way that I can have the command go and then end the script wihtout closing the program? Or am I out of luck and have to have the Terminal window open?
The program I am using is located here http://sites.google.com/site/sc2gears/
Thanks for the help!The program is distributed (according to the docs) as a .command file, so you can get the efect you want like so:
do shell script "/Users/yourname/further/path/Sc2gears-os-x.command &> /dev/null &"
the &> /dev/null tells applescript that you don't care about any output, so it moves on to the next command, and the closing & sets the process up as a standalone. Note:
If the process doesn't close itself automatically you'll need a separate way of doing that
if the process produces output you want to keep, don't use /dev/null - use an appropriate file path
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Hello!
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Thanks!If you stick the script in the Resources folder you can get it by
path to resource "Bash Script"
If you want to put it in the folder Supporting files you need to construct the path
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Do shell script problem in Applescript
Hi,
I am an Applescript novice and have been trying to write a code to go to a particular folder, look for all files in the folder tree with extension .m2v and run an executable file to decode them. My problem is that when I run my code (containing do shell script), it searches through all files and folders on Mac HD and starts decoding .m2v files elsewhere that I don't want.
Eventually it runs out of space (.m2v file decoding takes a lot of space), because it is dumping all decoded .yuv files onto the HD.
When I run the command on Terminal, it executes the decoding perfectly and stores the decoded files in the same folder.
Please help me about what's going on.
My code is something like:
tell application "Finder"
set DestinationFolder to "xxxxxx:xxxx:xxxx"
set NumFolders to (get count of folders under Destination folder)
repeat for SomeVar from 1 to NumFolders
set FolderinQuestion to folder SomeVar of DestinationFolder
-- Tried tell application "Terminal" here, but did not know --how to export the FolderinQuestion variable from Finder to --Terminal
do shell script " \" cd \" & (POSIX path of (result as text));
for file in `find $pwd \"*.mov\"`
do
/usr/local/bin/decode file
done"
end repeat
end tell
I would greatly appreciate some guidance.The root of the problem is that you're trying to quote the cd command for some reason:
<pre class=command>do shell script " \" cd \" & (POSIX path of (result as text));
...</pre>
In addition to that you're including the & (POSIX path of (result as text)) as part of the shell command whereas this should be OUTSIDE of the quotes in order to get evaluated
If you work that through you'll end up with a shell command that looks like:
<pre class=command>" cd " & (POSIX path of (result as text))</pre>
If you try to run that in a terminal you'll get a cd : command not found error and that's why the rest of it appears to fail.
The solution to that one is simple - just don't bother quoting the cd and put the POSIX path stuff outside of the quotes to get it evaluated at runtime:
<pre class=command>do shell script "cd " & quoted form of POSIX path of (FolderInQuestion as text)) & ";
# rest of shell commands here"</pre>
Now, as for the rest of the script there are a few things I would change.
First, unless you need to know the index, don't do:
>repeat for SomeVar from 1 to NumFolders
set FolderinQuestion to folder SomeVar of DestinationFolder
the issue is that the number of folders to process may change during the script's execution (other processes may create or remove folders). This will, at best, cause some folders to be skipped and, at worst, cause the script to fail.
If you're iterating through a list, the best option is to just:
<pre class=command>repeat with FolderInQuestion in (folders of DestinationFolder)
...</pre>
This automatically sets the iterator (in this case, FolderInQuestion, to the first item in the list and increments it for each iteration through the loop.
Secondly, in your shell script itself, scrub the entire do/done loop. You're already using find, so have that do the hard work using the -exec switch:
<pre class=command>find path -name "*.mov" -exec /usr/local/bin/decode {} \;</pre>
In find's case, {} is substituted with the current file's path.
Putting this together you'd get:
<pre class=command>tell application "Finder"
set DestinationFolder to "xxxxxx:xxxx:xxxx"
repeat with folderInQuestion in (get folders of folder DestinationFolder)
do shell script "cd " & quoted form of POSIX path of folderInQuestion & "; find . -name \"*.mov\" -exec /usr/bin/decode {} \\;"
end repeat
end tell</pre>
Note that I've used 'quoted form of POSIX path' - this takes care of any shell-unsafe characters like spaces in the path name. I've also used \\; for the -exec switch - this is so that AppleScript passes the \ to the shell command rather than using it for its own escaping.
But you're not done yet!
There's still one fatal flaw in this process - and that is the fact that find by default, is recursive - it will walk through every directory that it finds.
This means that if you start at the top folder and iterate through, find will find all .mov files and decode them. Your script then cd's to the first subdirectory and repeats the process - decoding all the .mov files in that directory and all its subdirectories even though they've ALREADY been decoded.
The upshot is that you only need to run one loop starting at the top level. You don't need to iterate through all the subdirectories since find will do that for you.
In addition to that, there might not be a need to use cd at all since the first argument to find is the directory to start searching in. Unless there's some reason that you need to start decode from the top level directory (e.g. is that where it saves the files?), you can drop the whole repeat loop altogether and just run with:
<pre class=command>set startFolder to (choose folder)
do shell script "find " & quoted form of posix path of startFolder & " -name \"*.mov\" -exec /usr/bin/decode {} \\;"</pre>
That's the entire script - a radical compression of your original. -
Problem with backtick replacing apostroph in applescript/shell script
I've got a script that appears to be using a backtick instead of an apostrophe which is causing an error in my shell script. For the life of me I can't seem to find where the error is being generated?
The script is attached below. I'm using Exiftool, an app that writes metadata to image files. The shell script
set cmd to "exiftool -CopyrightNotice=" & exifCopyright & " " & thisFilePath & ""
set theResult to do shell script cmd
works fine but the following shell script
set cmd to "exiftool" & space & authorStr & " " & thisFilePath & ""
set theResult to do shell script cmd
returns the error "sh: -c: line 0: unexpected EOF while looking for matching `''
sh: -c: line 1: syntax error: unexpected end of file" number 2. The code in the event log in applescript editor looks exactly the same to me but one fails in the shell script.
It has been suggested by the developer of Exiftool, Phil Harvey, that there is a backtick in the second shell script. I read somewhere in the applescript docs that this is due to a change in OS 10.6? Any suggestions on how to fix this?
Thanks.
PedroYea, the authorStr value has a space like "Joe Smith"
Then you need to use quoted form of this string, too:
set cmd to "exiftool " & quoted form of authorStr & space & thisFilePath
although the format looks wrong to me - shouldn't there be some kind of switch, such as "-author=' before it?
You have to consider how you'd enter this at the command line to work out how best to translate it to AppleScript. For example, if the command line version were:
exiftool -author='John Doe' /path/to/some.jpg
you can see the quotes are around the name, not the entire -author switch. In this case you should be looking at something like:
set authorStr to "John Doe"
set theFilePath to "/path/to/some.jpg"
set theCmd to "exiftool -author=" & quoted form of authorStr & space & quoted form of theFilePath
Now you could, of course, use quoted form when you create the variables (e.g. set authorStr to quoted form of "John Doe"), but that may screw you up later on if/when you try to use authorStr in some other way, so I find it best to use quoted form only where it's needed. -
Shell Script or Applescript to run disk permissions repair
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do shell script "sudo diskutil repairPermissions /" ¬
password "yourAdminPassword" with administrator privileges
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Shell script friendly paths in applescript
I have a python script that resides inside a standalone application bundle. I run this script from the app and call it by getting the path of the application bundle and adding '/Contents/Resources/' to the path. This script sets or gets information from a plist. So, adding a ' --list' to the script name returns the items of the plist.
This is my applescript and RWplist is the python script.
set plInfo to do shell script "/Users/[just me]/Desktop/Test Project/Test App.app/Contents/Resources/RWplist --list'
This fails due the the spaces in the directory and app name. If I change the folder and app name like;
set plInfo to do shell script "/Users/[just me]/Desktop/Test-Project/Test-App.app/Contents/Resources/RWplist --list'
This works... I tried wrapping the path in single quotes, I tried to do a replace all spaces to '\\space' in the path... and adding the 'quoted form of POSIX path of'...
I'm guessing I'm placing the single quotes or using the quoted form... improperly. Can someone please explain how to format a path in this manor. I can't seem to find the proper syntax for this.This fails due the the spaces in the directory and app name
Right, this is a common problem that many people encounter.
I'm guessing I'm placing the single quotes or using the quoted form... improperly. Can someone please explain how to format a path in this manor.
quoted form is the preferred/recommended way of doing this. Here's an example:
set cmdPath to "/Users/just me/Desktop/Test Project/Test App.app/Contents/Resources/RWplist"
do shell script (quoted form of cmdPath) & " --list"
If you want to build the script manually then you should single-quote the entire path, e.g.:
do shell script " '/Users/just me/Desktop/Test Project/Test App.app/Contents/Resources/RWplist' --list"
Note that there are single quotes around the command path but the --list parameter is outside of the single-quoted path. -
Hai all,
I need to write a script to add in the cron
a) exec a procedure
if successful ,then
b) Truncate one schema table in the DB
c) exec a procedure
Can anyone let me know how to do this ? if anyone have any pointers, for the same , please let me know
DB : 11.
Os: Solaris 5.10
KaiKai,
Here are 3 function you can use in shell script for executing a statement, sqlfile and procedure
function execStmt {
typeset stmt=$4
echo "
set feedback off
set verify off
set heading off
set pagesize 0
whenever sqlerror exit 1
whenever oserror exit 2
$stmt;
commit;
exit 0
" | sqlplus -s $1/$2@$3
ret=$?
if [ $ret -ne 0 ]
then
return 1;
else
return 0;
fi
function execSql {
typeset sqlfile=$1
if [ ! -f $sqlfile ]
then
echo
echo "File containing extract count doesn't exist...."
echo "Exiting ..."
echo
exit 1;
fi
echo "
set feedback off
set verify off
set heading off
set pagesize 0
whenever sqlerror exit 1
whenever oserror exit 2
@$sqlfile;
exit 0
" | sqlplus -s $2/$3@$4
retcode=$?
if [ $retcode -ne 0 ]
then
return 1;
else
return 0;
fi
function execPkg {
echo "
set feedback off
set verify off
set heading off
set pagesize 0
whenever sqlerror exit 1
whenever oserror exit 2
exec mypkg.procedure_name($4,$5); -- $4,$5 are argument list
exit
" | sqlplus -s $1/$2@$3
ret=$?
if [ $ret -ne 0 ]
then
return 1;
else
return 0;
fi
}Regards -
Find & replace part of a string in Numbers using do shell script in AppleScript
Hello,
I would like to set a search-pattern with a wildcard in Applescript to find - for example - the pattern 'Table 1::$*$4' for use in a 'Search & Replace script'
The dollar signs '$' seem to be a bit of problem (refers to fixed values in Numbers & to variables in Shell ...)
Could anyone hand me a solution to this problem?
The end-goal - for now - would be to change the reference to a row-number in a lot of cells (number '4' in the pattern above should finally be replaced by 5, 6, 7, ...)
Thx.Hi,
Here's how to do that:
try
tell application "Numbers" to tell front document to tell active sheet
tell (first table whose selection range's class is range)
set sr to selection range
set f to text returned of (display dialog "Find this in selected cells in Numbers " default answer "" with title "Find-Replace Step 1" buttons {"Cancel", "Next"})
if f = "" then return
set r to text returned of (display dialog "Replace '" & f & "' with " default answer f with title "Find-Replace Step 2")
set {f, r} to my escapeForSED(f, r) -- escape some chars, create back reference for sed
set tc to count cells of sr
tell sr to repeat with i from 1 to tc
tell (cell i) to try
set oVal to formula
if oVal is not missing value then set value to (my find_replace(oVal, f, r))
end try
end repeat
end tell
end tell
on error number n
if n = -128 then return
display dialog "Did you select cells?" buttons {"cancel"} with title "Oops!"
end try
on find_replace(t, f, r)
do shell script "/usr/bin/sed 's~" & f & "~" & r & "~g' <<< " & (quoted form of t)
end find_replace
on escapeForSED(f, r)
set tid to text item delimiters
set text item delimiters to "*" -- the wildcard
set tc1 to count (text items of f)
set tc2 to count (text items of r)
set text item delimiters to tid
if (tc1 - tc2) < 0 then
display alert "The number of wildcard in the replacement string must be equal or less than the number of wildcard in the search string."
error -128
end if
-- escape search string, and create back reference for each wildcard (the wildcard is a dot in sed) --> \\(.\\)
set f to do shell script "/usr/bin/sed -e 's/[]~$.^|[]/\\\\&/g;s/\\*/\\\\(.\\\\)/g' <<<" & quoted form of f
-- escape the replacement string, Perl replace wildcard by two backslash and an incremented integer, to get the back reference --> \\1 \\2
return {f, (do shell script "/usr/bin/sed -e 's/[]~$.^|[]/\\\\&/g' | /usr/bin/perl -pe '$n=1;s/\\*/\"\\\\\" . $n++/ge'<<<" & (quoted form of r))}
end escapeForSED
For what you want to do, you must have the wildcard in the same position in both string. --> find "Table 1::$*$3", replace "Table 1::$*$4"
Important, you can use no wildcard in both (the search string and the replacement string) or you can use any wildcard in the search string with no wildcard in the replacement string).
But, the number of wildcard in the replacement string must be equal or less than the number of wildcard in the search string.
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